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本帖最后由 Menuett 于 2013-12-22 15:59 编辑 " e( n9 m4 b. m: k% S
煮酒正熟 发表于 2013-12-20 12:05 ![]()
) w- k* D8 r) _$ J0 R/ y" ~2 r基本可以说是显著的。总的来说,在商界做统计学分析,95%信心水平是用得最多的,当95%上不显著时,都会去 ... 3 @$ x1 Y4 C d' C0 m( `( c- t
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这个其实是一种binomial response,应该用Contigency Table或者Logisitic Regression(In case there are cofactors)来做。只记比率丢弃了Number of trial的信息(6841和1217个客户)。 + e+ k7 E0 P Y* ~) c* m
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结果p=0.5731。 远远不显著。要在alpha level 0.05的水平上检验出76.42%和75.62%的区别,即使实验组和对照组各自样本大小相同,各自尚需44735个样本(At power level 80%)。see: Statistical Methods for Rates and Proportions by Joseph L. Fleiss (1981)
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/ t v! M' U/ E2 XR example:
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" D3 p& W& R7 x0 g> M<-as.table(rbind(c(1668,5173),c(287,930)))
0 C2 E$ x( A/ Q) o2 y, p> chisq.test(M)3 q+ ?: h3 M& X4 r
. a; K" D* {' G) _ Pearson's Chi-squared test with Yates' continuity correction
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& B3 l: y/ z: \( r% h, v: oX-squared = 0.3175, df = 1, p-value = 0.5731/ Q( W; I' S7 C+ D. N$ l
* [7 G3 U3 o# ~: C/ a9 Y1 V3 gPython example:
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>>> from scipy import stats1 l: W5 ~2 ?/ S5 Y- ]# d
>>> stats.chi2_contingency([[6841-5173,5173],[1217-930,930]])
6 z/ m0 k; L$ I( o(0.31748297614660292, 0.57312422493552839, 1, array([[ 1659.73628692, 5181.26371308],
, }. S# C$ u1 m3 q& Q [ 295.26371308, 921.73628692]])) |
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