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本帖最后由 Menuett 于 2013-12-22 15:59 编辑
" X3 C) h0 l; m3 b, N6 M煮酒正熟 发表于 2013-12-20 12:05 0 u) t( E2 l# v2 B5 Z
基本可以说是显著的。总的来说,在商界做统计学分析,95%信心水平是用得最多的,当95%上不显著时,都会去 ... 6 m' [; Q* A+ m
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这个其实是一种binomial response,应该用Contigency Table或者Logisitic Regression(In case there are cofactors)来做。只记比率丢弃了Number of trial的信息(6841和1217个客户)。 7 a$ m4 E& u' j/ O* T0 S
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结果p=0.5731。 远远不显著。要在alpha level 0.05的水平上检验出76.42%和75.62%的区别,即使实验组和对照组各自样本大小相同,各自尚需44735个样本(At power level 80%)。see: Statistical Methods for Rates and Proportions by Joseph L. Fleiss (1981)1 m: s2 h5 f/ N, k
; R3 \4 @$ p ]7 S8 F" r3 ^R example:! y6 Z1 v. B3 n) Q7 z' k5 O# L1 A# d
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> M<-as.table(rbind(c(1668,5173),c(287,930))); T, k; ]2 B9 Q7 U* t
> chisq.test(M): b2 Y& V- }7 Y; M+ V/ x7 v
& f% E+ w [$ ]& ^- c' y- i Pearson's Chi-squared test with Yates' continuity correction
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6 F/ l& S9 v* x: X. _& j; b' Ndata: M
& Y+ ?& r) Z0 U% V- k4 sX-squared = 0.3175, df = 1, p-value = 0.5731# j! c3 X2 C: S4 Q% c3 E
1 c3 u' D, ^. T, TPython example:
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>>> from scipy import stats
7 w* U/ E& Y' q2 I* t# D" O; K>>> stats.chi2_contingency([[6841-5173,5173],[1217-930,930]])0 i! D1 z! D! }$ N; B
(0.31748297614660292, 0.57312422493552839, 1, array([[ 1659.73628692, 5181.26371308],
2 K( m& G' F% h [ 295.26371308, 921.73628692]])) |
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