TA的每日心情 | 擦汗 2016-4-17 12:18 |
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签到天数: 1 天 [LV.1]炼气
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本帖最后由 tingsanguo 于 2014-5-2 14:01 编辑 3 V; t+ \. T& C0 `9 j
水风 发表于 2014-5-2 01:57 ! S0 T* R* X! }0 H, C
再次重温自己与数学天才们之间的差距有多大了。解出来了,我还看不懂思路 ... 1 A% `, x9 A: F7 {8 y) B/ s
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fixed point f(X) = X = (1-n), where n is the number of people who divide the coconut.
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) y7 G' @9 I- T9 yThe least number of coconut before dividing is Z = [n^(n+1) + X], i.e., always divide (n+1) times.9 E# f& W( _' B9 [2 y- d5 U
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After being divided (n+1) times, Z becomes 1, since X is fixed point.
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n n^(n+1)+X, n^(n)+X, n^(n-1)+X, n^(n-2)+X " v' S" d* ^) `' {
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5 15621 3121 621 121 21 1
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