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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 - g, L4 a0 O8 U

    & d& T1 o7 |7 Q解释的不错9 Y' V7 I) _* Z9 S  C" P) S
    $ o0 ^; B& r0 ?+ _/ V0 a
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。5 s+ h5 @$ Y9 E! B$ U
    " I2 @* ?3 R' W( _1 X1 h" _
    关键要素# Z9 k/ ]2 t0 `# m7 v& S
    1. **基线条件(Base Case)**
    . M) T6 t4 }6 V2 i. l! I: d( R9 N; V   - 递归终止的条件,防止无限循环  }  x" {4 i8 |+ e
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    : j) c4 u/ U* z
    6 |/ z3 q" y3 V7 A) X& j8 s( f2. **递归条件(Recursive Case)**
    7 t% c/ B4 E# q6 q& L) j  q; o   - 将原问题分解为更小的子问题2 A! a; C0 n/ X% A& W( Q! @
       - 例如:n! = n × (n-1)!
    " l- y5 H8 l* V) f3 L
    7 o1 Z) U* b& b' l9 E! n0 _- G 经典示例:计算阶乘% f" y: [* j. Z. F2 c
    python
      c5 R( |& c; G$ Tdef factorial(n):
    * Y7 P1 M2 }6 ^0 c) o) Z: b, z    if n == 0:        # 基线条件
    , Z( F5 N5 _' i, C* c* r        return 1
    ( V5 I2 h' Y' J& S& w2 Y+ y8 d8 K    else:             # 递归条件
    6 F4 W  r. I' _$ D. x5 t) i  X0 w        return n * factorial(n-1). d( o# b$ d8 R7 f+ j
    执行过程(以计算 3! 为例):+ s+ x) R1 h2 @" C  c# W
    factorial(3)
    % p- l) h9 ]# Y8 ]$ b7 x3 * factorial(2)/ O" o& u* Q+ p8 ?5 [4 p  g
    3 * (2 * factorial(1))
    ( p( m- E9 P7 e) X( B6 f- q2 c. E' k' n- j3 * (2 * (1 * factorial(0)))
    0 A- |. E! o4 V8 N& V% t) \5 Y4 I3 * (2 * (1 * 1)) = 6
    " R5 T% R& A" @& G! T$ x
    3 _* S1 o& w5 K7 I8 R: j 递归思维要点
    7 `: W9 Z) O" w+ P6 D+ v* y- T1. **信任递归**:假设子问题已经解决,专注当前层逻辑/ [" F6 W8 n% T# _0 I* H6 j6 ?6 \
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    0 q* e" x7 B8 s) G' H3 p# a, g3. **递推过程**:不断向下分解问题(递)/ b8 a2 Z1 X. Q  y  N# Z
    4. **回溯过程**:组合子问题结果返回(归)
    & U9 ~$ j6 F1 D: x4 u9 N9 v" I& s* X
    注意事项
    $ R( Q3 r2 a7 G: B$ l& f3 X必须要有终止条件
    5 ~( q  l' h* L& v. b" l递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    ! w. N" t/ U- H# z* N$ Z; y2 f某些问题用递归更直观(如树遍历),但效率可能不如迭代; C/ \' B( e0 Q1 [' q; y
    尾递归优化可以提升效率(但Python不支持)! o: e, _3 j! B
    ( L, p/ d0 I0 f& M, A1 I9 q
    递归 vs 迭代/ S6 W  g! W* J; e' Z$ n, `/ _
    |          | 递归                          | 迭代               |
    ' l4 F& A4 N) Q4 i  Q|----------|-----------------------------|------------------|% Y6 S6 W: p2 L/ V
    | 实现方式    | 函数自调用                        | 循环结构            |. R+ g/ w* V8 {: p7 g# m- }
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    - u' }( H7 d% b1 q2 R3 `* i| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |4 I8 I6 T- r; g" B6 s
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |2 J9 _# k, v7 n3 `9 H9 W/ [: M
    + ]7 C8 u: r: K* l6 Z& r
    经典递归应用场景8 |; F8 ~. _+ P, i6 V1 o, H
    1. 文件系统遍历(目录树结构)
    9 _4 {) o/ u9 q; |- F2. 快速排序/归并排序算法
    ! d" t) x# J2 @1 i0 L4 J: u3. 汉诺塔问题/ U: a+ F) b8 x) [6 L
    4. 二叉树遍历(前序/中序/后序)
    * m: Q0 c3 F( ~7 A2 u, x  z5. 生成所有可能的组合(回溯算法)
    + z1 C# w) j: _. x/ T7 T- V
    ! B1 M$ X$ z# i; Y$ [5 b" m6 l试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    + V. \4 O( J3 g& Y# @" _我推理机的核心算法应该是二叉树遍历的变种。
    % B( y; e1 \" k$ l+ \8 H另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:$ X! Q4 g$ v0 m2 J( i/ t$ ]! Z3 @! W
    Key Idea of Recursion8 O2 U% j) B% y7 i* \

      C1 R5 t8 v* rA recursive function solves a problem by:9 Q' j* Q2 Q+ x

    7 @* Z" v$ y- ?+ V! @; b, f    Breaking the problem into smaller instances of the same problem./ \8 O: _4 n7 y) h, X: i4 |$ |
    8 Z( F% C% l( D- s" I0 S5 }2 ~
        Solving the smallest instance directly (base case).
    ! f7 {0 N% T8 C, |0 u9 i" P2 l( h9 v  S' C
        Combining the results of smaller instances to solve the larger problem.6 v2 r4 F! ]% R

    ' @% H% h. o! U( o4 O# aComponents of a Recursive Function
    : s1 Y" s+ t' t
    $ h* x3 L/ |/ b  z' m    Base Case:
    3 }# m: s1 @* T; J# Z  j* k
    " p* d" ^4 F8 m* S0 L% d        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.: n5 @+ f$ E; |5 r. j$ b7 A

    9 j4 o) x! }* Z7 C0 l7 Z        It acts as the stopping condition to prevent infinite recursion.
    7 `8 J4 |( E" \. X" I+ J' A2 Q2 {% Z! t- U* U
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    1 p, q) V  g( |: f$ I6 e. N$ b3 Y9 K6 \0 m5 @
        Recursive Case:
    2 t: [! I& l1 a+ m, F! `8 \" a/ i' ~' s' V- h4 @4 D
            This is where the function calls itself with a smaller or simpler version of the problem.& l# I( S, g) a$ G

    & R' L! h6 |0 S3 J* @% f( ^        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)., _4 m) P1 |8 w: i+ c; T; w
    4 e5 B# {3 x! E# f4 `
    Example: Factorial Calculation
      D/ |, Y3 B' D! c* J) L8 M" B* d1 X- f5 [2 Q) |5 m( P. s
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:7 J. S5 Z7 v5 x/ e" Q6 y$ a! H; Z/ ^

    - O* p6 f$ n  k: u8 {    Base case: 0! = 1
      W3 Y; u4 J7 i" l. @7 P9 ^7 |1 D" u% U; w5 n+ [$ U' K4 g
        Recursive case: n! = n * (n-1)!1 S: ^* z/ M. |3 M5 y# h) i2 e
    0 N/ J/ F2 z* f
    Here’s how it looks in code (Python):0 c6 S) P$ [2 |5 @% M3 j2 y
    python
    # U1 H& J6 c1 N. z+ j! l# x& Y# m6 v+ G

    , B# q6 t/ I9 P( ?' d% `def factorial(n):
    8 K+ V4 G0 ?4 E6 Q; m    # Base case7 x( g) ]( C( v' o2 ^- n' q8 k- s4 ?
        if n == 0:
    5 G- v5 a9 V# |0 j" y+ e        return 1- E( {- y: I6 Z3 B+ m# v$ X5 K
        # Recursive case' O1 e9 \/ b! b: s. Z5 a
        else:
    8 M! @; O4 x! C6 u7 y8 Q- |        return n * factorial(n - 1)
    - m, Y, S* W- }! P  ~; B# ^' ~! o7 V- J* U3 p! }
    # Example usage
    ; m4 @/ E( v0 Z( lprint(factorial(5))  # Output: 120+ V" H# U1 J' `# N) R1 i& D5 @
    + c$ b/ l$ Y. |
    How Recursion Works% R# p0 b4 P- J' E# e

    - F& M$ n& Y) n! N% v- a    The function keeps calling itself with smaller inputs until it reaches the base case.
    ( r3 B; Q7 H" y
    , f0 r1 J) B, S' w7 A2 l4 U    Once the base case is reached, the function starts returning values back up the call stack.) _/ a3 N5 z* v3 f% Y: ?
    . L- T+ l3 P0 `( |2 j9 l
        These returned values are combined to produce the final result.- @9 V5 e9 f# K: e
    0 S; \, A( v+ i' X: ]0 Q8 F
    For factorial(5):
    ' a4 ]% E# A# J! w4 M, f+ v6 \
    + S" }4 d! U: F8 x1 w5 M4 |; _8 q
    & T4 C8 _2 f2 j9 u, y* bfactorial(5) = 5 * factorial(4)" d5 ?/ H# g! {. U4 ^( Q; a
    factorial(4) = 4 * factorial(3)/ X' q. l1 z8 ~  I/ G9 I
    factorial(3) = 3 * factorial(2)6 G# Z  k- g# ]- [
    factorial(2) = 2 * factorial(1)- g" W- T( C3 T4 {- Z
    factorial(1) = 1 * factorial(0), l8 W; f( I$ D- ?) c
    factorial(0) = 1  # Base case
    3 D! W. z4 L4 e& D" B: @0 u
    ) a2 J7 C* z7 ~; S1 N5 H8 q* J8 ?Then, the results are combined:$ e' U3 J" H7 T: }3 {; R6 a. u; d( J
    3 R& Y1 j- c  ]6 }2 G4 ^

      M3 y9 D( K$ `# z4 ufactorial(1) = 1 * 1 = 1
    / w. ?4 G5 l, a# x) Zfactorial(2) = 2 * 1 = 2" V3 v( `8 ?6 s6 C
    factorial(3) = 3 * 2 = 6
    5 r: w1 o- o+ ]( lfactorial(4) = 4 * 6 = 24' A8 K# e5 `# O
    factorial(5) = 5 * 24 = 120
    7 U. s/ X6 R4 N" Z0 ~% D/ ^; C- I) W" `, A( b5 [
    Advantages of Recursion
    5 i- K3 j( l4 C+ h/ F2 J) z
    9 l7 a- s( x# {    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).7 H$ R. Y1 o  X, u3 U

    1 R3 `! }4 @1 t  {4 t/ s+ p    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    * n6 ]. h, Y5 U0 x8 ?
    . e! K* y( N/ YDisadvantages of Recursion
    % b8 W* O/ p) @& S* u- I: H; O* o( s- c: ^& u7 G5 H, G
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    2 P0 ^* b! y! `% o( c1 v
    6 Q" ?; {  }4 z7 }2 v9 R, ?    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization)." G- `, x1 X9 f; G0 S/ g

    ' ^8 S8 k( q( [7 aWhen to Use Recursion0 g, L3 Y8 q9 D4 D
    0 f/ U+ c. o. V* h2 i
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).  T' Q5 X( Y! m, L% ~& [2 h

    " O& P7 R$ I  Q( Q7 R& W, W* L    Problems with a clear base case and recursive case.* j* s3 |' H( U& W) c: P8 [' a2 @

    / E/ G4 L' i' s3 L" V% \4 zExample: Fibonacci Sequence
    ! F; |3 w1 w# T& O4 {& q, O& Z0 n7 r; ?6 O
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    ( J1 l5 ~  |. B7 ~1 d1 }" Q7 J9 V' m  u
        Base case: fib(0) = 0, fib(1) = 1
    % ]& Q( G& b9 q( L. e
    ' f5 J5 _/ X# a1 Z5 C    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    9 E# v# U3 F/ O: k, M
    0 y% V9 H5 i- A8 w5 mpython1 V# D! G; l9 G. f. y' x
    3 ]! i7 w  t( f- e  B; {- Q: O- |

    ; z/ n/ _& C: i0 O2 q- x( Odef fibonacci(n):
    6 Y8 K2 V2 l% L6 J    # Base cases
    ; X) t, z1 w5 g2 E+ y$ O    if n == 0:: C1 t- o: p' w5 \# _: e
            return 0
    ; m0 K) a) G5 H) z    elif n == 1:
    0 k$ k' M9 J9 ^! e( g# p        return 1
    ; k( r) r$ F, @$ q    # Recursive case% |" N) l! t9 l! ^4 N; ]. U
        else:
    # p& h- o) c1 E        return fibonacci(n - 1) + fibonacci(n - 2)
    8 j" J) x9 _2 S, N' X8 Q; \7 R; Q/ V2 n. v
    # Example usage
    0 K, J9 f6 H" |5 D& Q8 j) U( _print(fibonacci(6))  # Output: 8
    " H3 e: W5 Z4 B, @7 e8 t! d+ Q
    , Z) U7 X0 }9 {/ G" O/ UTail Recursion
    6 L' M3 w# k% Z) L- G
    % P) d  J" X, O8 I  aTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ' Q. `2 b4 o! U" G- r) H7 |8 }
    5 ^% G7 `( d; M0 e; T' h* }' x+ cIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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