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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 3 s& `$ R4 N: {6 g6 Q  k

    3 Z  M4 p2 R2 ^5 N+ E解释的不错% @, B( |% n. z) N7 v$ C
    ) x5 C" N" v' Y0 ]6 c2 M
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。7 X7 i$ X; F' v
    ; M5 Z: z; b) k" C& {
    关键要素* T  Q! N7 k( M, e' J6 z& w
    1. **基线条件(Base Case)**% m* M6 n* `. Q# l* ^7 L
       - 递归终止的条件,防止无限循环
    5 t6 B" A1 H) O   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1/ V7 A+ E: q' ?$ L6 o

    7 C9 w0 ]# J- b- ^6 q$ N% @2. **递归条件(Recursive Case)**
    5 a: U! ]0 t  b0 V! A% H   - 将原问题分解为更小的子问题
    % Y( d- v* {$ w: t, o% T  E   - 例如:n! = n × (n-1)!, f. V& j( z& d" E" m; e
    1 t( c( n2 h1 E* y
    经典示例:计算阶乘8 x, P* t& o5 `3 V3 @0 s& M& H, \$ y
    python8 ?0 E3 t& P5 W( \
    def factorial(n):
    - l* _6 \+ V1 W! R3 `& z9 P( \    if n == 0:        # 基线条件" p/ w* U2 B: @0 k- X2 w' j
            return 1- l% A/ h& {4 Y1 X8 Y
        else:             # 递归条件
    " ~% b% l  @* U8 @# o1 k        return n * factorial(n-1)7 S3 h( H- I0 T# {7 g
    执行过程(以计算 3! 为例):
    4 {4 X' d# X3 r: n% R' I8 cfactorial(3)
    & C) X1 C7 D" t% q3 * factorial(2)6 w  h1 i& W3 Z5 W* N9 Q! b- d1 C
    3 * (2 * factorial(1))& w1 y: {- X" P
    3 * (2 * (1 * factorial(0)))9 r9 M9 a' S: ^5 B1 g, X
    3 * (2 * (1 * 1)) = 6/ j$ u" [6 L/ x, b- K& P

    4 A5 k* N0 e! z! m$ l" {4 V 递归思维要点( z; D' o& K) Z$ x; v0 `$ w
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    * b, @1 G3 E# a; B& O& k2. **栈结构**:每次调用都会创建新的栈帧(内存空间)4 ^# o: S- l' g) F' |+ @7 w9 X
    3. **递推过程**:不断向下分解问题(递)
    , o- v! c& K, M( M; r! d4. **回溯过程**:组合子问题结果返回(归)
    ; Y  J! `# O; I8 {1 ^7 O; v" X4 |# \% h) @- z3 [5 _
    注意事项3 Y! [- f: {) X" m5 H) h9 r8 F
    必须要有终止条件. g- w7 a; h  f. b5 n1 l
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    " M( e: z! T6 Q0 _4 \* }3 l  v# j某些问题用递归更直观(如树遍历),但效率可能不如迭代0 \7 a' X6 l$ t% @) X+ q9 p
    尾递归优化可以提升效率(但Python不支持)) i. j- {  |) x& y8 t( f
    4 _: v+ V4 q7 D
    递归 vs 迭代
      ^4 Q; X' c: f  n  [6 }: ?|          | 递归                          | 迭代               |
    5 y3 _( Z# a0 K( V" y# n|----------|-----------------------------|------------------|3 ]0 d3 x0 }; U( |# P" g7 J! M
    | 实现方式    | 函数自调用                        | 循环结构            |
    3 y* F4 L8 x. M4 k| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |8 d/ [1 g) A( P/ h! U& Y. n
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    9 \9 F, `/ r0 D4 ]! o1 j% B6 P| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |' g0 s& P8 @6 c8 P

    9 [2 v0 P1 G6 S8 v. Y7 ~ 经典递归应用场景
    7 _9 O4 @6 m# @) u$ [1. 文件系统遍历(目录树结构)6 P9 q; A# P) M0 _7 F
    2. 快速排序/归并排序算法/ F) n- e" Q- ]. l# f) Y
    3. 汉诺塔问题* m$ G, R' Q7 A9 T5 o' v
    4. 二叉树遍历(前序/中序/后序)
    8 ]* l# |3 [+ I4 p5. 生成所有可能的组合(回溯算法)0 X) T& \+ n' x# ?9 n3 S
    . I" ]$ O* P; p$ q( s9 Q
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 07:02
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,1 f+ E: r) p: c& i" N/ x5 Z
    我推理机的核心算法应该是二叉树遍历的变种。  u+ }. P3 N& y
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    / c5 w$ ]( N( NKey Idea of Recursion
    9 r- [8 x, y% K% _8 J
    3 D% i! x  Q* x8 d+ a* oA recursive function solves a problem by:
    # ^! f7 i1 B# v4 y; U
      L" Z4 Q( R# U7 L5 {    Breaking the problem into smaller instances of the same problem.% U4 F+ M: g# `$ Q& i0 J7 h; N
    % V3 O) E" f3 P  H  q/ Y# M
        Solving the smallest instance directly (base case).
    * ~$ b0 ^' X4 D/ g' Y
    1 S  q, J" u( w0 P2 j7 @8 n: {    Combining the results of smaller instances to solve the larger problem.
    : F* Y/ b6 S. V- t. |, B* |: f" N% r# K1 q' R( h9 X3 g  l7 ~
    Components of a Recursive Function( P# h4 c% S5 @% S' q# p3 g

    1 s5 j, A& w4 `" T5 \    Base Case:
      v; `  i# c, b/ }8 |8 S; T( @" b0 x6 u! p
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    0 l/ y2 F# S" V, @/ d: c* J+ S( r$ S7 m7 F& w
            It acts as the stopping condition to prevent infinite recursion." X9 x2 S/ W) D/ Y9 m
    - L! O. Q& K, v0 G+ J% v$ n
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.& k/ e* A: h( x% K3 e
    6 w) V$ U7 N5 [4 v& J! Q
        Recursive Case:
    $ y2 \; V3 a# o' |3 \6 X( o0 {$ h/ b; S
            This is where the function calls itself with a smaller or simpler version of the problem.- ~: B0 Z+ R  ?; _2 ?$ a& n9 B
    8 Q6 W3 J3 M) f
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    , U* t3 M2 O, v. R$ p" p7 h$ w7 p# N& R' Q  q8 X' U
    Example: Factorial Calculation
    1 H, z4 P+ m3 f) C$ o
    $ G' F! O( h; u9 ]7 J5 o) \" T0 p' KThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    9 V' ]9 z8 U; G$ m" s: @2 c" {9 ]% g8 @! r9 H0 Q9 \+ \5 f
        Base case: 0! = 1
    % U( F# y$ Y! O6 @5 l2 Z5 w9 x4 h& U
    4 [5 e; K7 Y% U% I    Recursive case: n! = n * (n-1)!
    ; I7 e1 Y( K7 b( I+ @; `
    5 t0 z: u8 U+ y2 F, a& }0 _! RHere’s how it looks in code (Python):
    ( m$ q" f& i: c# L( u5 t- f+ npython" {% t: J/ P! p. ]( w+ s5 k

    " ^7 E3 C' S+ H* r( m) m& c3 j2 K; d# X! F& L, K7 h/ Y
    def factorial(n):; `% d5 ^0 |: O; J% X2 Q% ^6 X
        # Base case! ~- r% t0 ^- Z$ h
        if n == 0:
    - `: C& c# ^& h; i' n! [( {8 g        return 15 b5 u7 g) Y( Z- y1 x3 j! e* K
        # Recursive case0 Q8 N2 O2 \4 [
        else:
    ! K. E3 G; A- P* ^6 g+ m        return n * factorial(n - 1)
    / Q/ O+ ~# W: w- K
    4 J# T3 e9 }8 v# Example usage
    & P! A6 s7 P1 a4 c; ]% b" Uprint(factorial(5))  # Output: 120
    ) \9 Y( V5 w& t$ o. c7 k( S
    / |, D- i2 C1 e" Y) a9 Q, uHow Recursion Works
    1 d2 ?& j% X" W: F: i
    . s) I# N" Y6 C! G0 x) x    The function keeps calling itself with smaller inputs until it reaches the base case.
    3 v* K% M! Q: N* E7 h: [
    ! A6 F$ |% ^% f    Once the base case is reached, the function starts returning values back up the call stack.
    7 j6 z) N+ W0 z# f/ ^3 g  M7 M
    , V( O6 p3 T* S% V2 m2 m# t0 V    These returned values are combined to produce the final result.  j8 w" A6 {- S' f
    5 A$ \  [" S- M4 J2 ]
    For factorial(5):
    8 d6 {. P6 Q; b5 W* b. J
    5 \! J. g) I8 _% _) P- v; k/ U4 [4 g
    ! J$ W. z6 Y3 p) x/ {4 e* vfactorial(5) = 5 * factorial(4)5 L  d+ X; Z9 q, Z1 l9 m/ w
    factorial(4) = 4 * factorial(3)
    + m2 L3 ~% c' R( zfactorial(3) = 3 * factorial(2): v* ~5 r: w  E( L
    factorial(2) = 2 * factorial(1)
    7 J' ^+ d) K" s1 |factorial(1) = 1 * factorial(0)( j& T/ A( t) _- r: j5 o
    factorial(0) = 1  # Base case; N" c- S  e, v* o
    8 E+ v! v3 G$ L3 l) |
    Then, the results are combined:: d  j2 l# _! ~, y/ w

    / T2 c* K. h) A2 M
    , F2 r  j4 [8 V  b2 ifactorial(1) = 1 * 1 = 1
    - F- ^( m: o! K4 ufactorial(2) = 2 * 1 = 2
    % K6 R9 A6 u: {2 g; Nfactorial(3) = 3 * 2 = 6: E( b! X! v% @7 x3 j0 p
    factorial(4) = 4 * 6 = 24- u) @+ f- l; O' P1 \7 C3 z
    factorial(5) = 5 * 24 = 120; g. L2 r  ?8 T5 u& C8 x  E

    % a; c) `5 T: q5 vAdvantages of Recursion7 W! {7 s' C6 \2 b* @% F

    ; n* j0 y& s& z0 J0 D3 F3 s    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    + t* i. Y4 G4 t$ l7 k, w% c0 b6 p+ c
        Readability: Recursive code can be more readable and concise compared to iterative solutions.7 V0 \4 D; y( b

    $ d/ o/ ^5 Y+ _) J# N9 qDisadvantages of Recursion
    ' q3 |3 D$ j: M! j$ C; a+ s$ t  ~2 u- Q( A- z1 r1 i, ?5 ?- f
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    1 z  G; J6 A5 g" g/ I& ?# A
    4 P4 v$ \$ Y- U: {2 {/ i    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    " P) G/ y/ n# c' a+ `) P
    * f2 i' _: T) `% r- V* D! N# RWhen to Use Recursion
    ' p, {5 ^3 A& |- F9 ]  ~
    - L* |2 i1 A* s% S. O& c; M    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).( m& q* D2 l) c9 t5 t7 ]0 a- c

    7 l9 A  ~. Y7 G9 |. \& I. H    Problems with a clear base case and recursive case.3 T5 B2 Q; c% G! L# h4 Z7 ^% s
    . v4 K2 B# K- j& c3 Y
    Example: Fibonacci Sequence
      l9 g5 @1 z" F2 E3 `8 N( X
    ( A" P6 }/ L- \% ZThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    % a7 X+ \& E2 z  k, S& O; E9 J+ {: W) y  f- ?* ]; g
        Base case: fib(0) = 0, fib(1) = 1* S! A* i; M- y9 m

    ! T7 E" q3 R# }. _, g    Recursive case: fib(n) = fib(n-1) + fib(n-2)0 N  Y# v# u. {

    , C9 v9 ~: Q! ]! Gpython+ S6 T+ ~$ l/ Q# h

    : V! Y' V, e; U3 K/ b$ J# l0 b# f4 ~/ ]  u$ K* N1 d" O
    def fibonacci(n):
    * S. H) ~( ~  U- c% j7 t    # Base cases3 }% M. J* J8 _' j& C$ |
        if n == 0:
    / G. h& n6 F* J" m        return 0) a" l5 s3 d1 K+ ~% a
        elif n == 1:: P% g6 o( _* [/ C. u, G: q$ S1 L
            return 1
      z: ?* D8 Z4 v; h6 F    # Recursive case7 ~! B" n2 z/ o0 Y$ S. o
        else:
    : w, l  H1 C9 M0 x# U        return fibonacci(n - 1) + fibonacci(n - 2)
    . ?8 {% Z6 u$ v$ z/ w$ L* a7 M: a: K$ H/ d% @* \
    # Example usage# V: i' G4 T6 A5 o7 n9 k4 a% z
    print(fibonacci(6))  # Output: 8
    * o' @* A! H. ]* x$ h0 _  ?& C0 I$ ^, t7 y
    Tail Recursion+ z; P3 r9 m1 T+ X- p

    : R0 A  X6 C$ }7 ]: y5 KTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    , a) `, @6 F8 g2 |+ Q' W
    5 `1 X9 r9 Z( h* v7 N5 I% XIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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