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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
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      `1 d" }! Q/ P; Y解释的不错
    + b1 j- j! c$ Y4 e: u
    1 k$ z  H' J- U4 v+ T& [递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    2 [9 `% h# F0 y
    & p' s3 u9 n; ?2 T 关键要素
    ( ?) D. x% p" Z1. **基线条件(Base Case)**
    + ?( U! a! V6 ?, |, V! T   - 递归终止的条件,防止无限循环, G4 }6 D8 z( k
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1+ R4 A) X6 z4 g& Z( E6 D7 p

    ( O6 y/ M" [4 A! K2. **递归条件(Recursive Case)**
    . Y/ m# c- S+ X   - 将原问题分解为更小的子问题# g' s) o( ~8 q! [( ]
       - 例如:n! = n × (n-1)!: o' n3 a1 ]: H3 K

    5 v$ U/ I! T9 e7 k. A) m1 d, h' Z% q 经典示例:计算阶乘
    0 K( @: ]/ O; M$ ]& ?python1 z/ }( i& u7 X1 ]9 t& }7 X
    def factorial(n):
    3 [- U5 C! q8 ~1 p( [    if n == 0:        # 基线条件. Y& J& t& Z0 e4 Q  X, @
            return 1# ^# M8 e. s, k/ u
        else:             # 递归条件$ G  g$ n( K1 d; V9 b
            return n * factorial(n-1)
    . @- O4 r1 I; }2 j执行过程(以计算 3! 为例):8 v, i. ?+ E" E- ~
    factorial(3)* s* q: C/ T# L1 d" s0 r' x" [- P
    3 * factorial(2)
    6 d1 p, O- r! p% f7 o5 [3 * (2 * factorial(1))  r- Q8 V- C) q& T! m  K4 \
    3 * (2 * (1 * factorial(0)))
    8 b* [; M0 M( f$ o3 * (2 * (1 * 1)) = 6
    , x. j. R! g/ r  d; W% A- H
    . e: V9 H' Z# M$ _& I# T4 V( y: D 递归思维要点
    2 {! A/ U5 S8 M/ B7 i1. **信任递归**:假设子问题已经解决,专注当前层逻辑3 `2 R( k' I  E2 N
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)! E9 c. }& f" m" h9 e
    3. **递推过程**:不断向下分解问题(递)
    & }; s( K) G* J0 C0 I# g8 n+ m" {4. **回溯过程**:组合子问题结果返回(归)
    ( X; w5 e( J& F, ^8 D9 r" u' ]
    , i9 W: Z( u+ O0 X 注意事项
    + g( [. _& o; K  s. h6 r* w必须要有终止条件
    $ K9 C  k- ^9 ?7 h, q递归深度过大可能导致栈溢出(Python默认递归深度约1000层)! Y3 U9 |( `+ ^
    某些问题用递归更直观(如树遍历),但效率可能不如迭代! q7 I- m. Q: [  k- A$ O
    尾递归优化可以提升效率(但Python不支持)$ u9 b$ q6 M* u# ]) s

    " w1 ^1 p9 e1 ~' _) m 递归 vs 迭代
    " M" A# s8 |3 K' o|          | 递归                          | 迭代               |! k$ W0 x5 u1 W% K
    |----------|-----------------------------|------------------|
    9 [% n9 Q! O6 x' W; N9 o/ s% ~/ h| 实现方式    | 函数自调用                        | 循环结构            |4 X) L) B; U9 q7 q0 F
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |6 h! C6 @' Z1 l# v' J
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |( @7 u  G0 V7 v/ @; P
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    * a& C& X( \! |9 ?3 j/ G& p
    . X+ S0 t8 {6 H 经典递归应用场景
    3 j. X) Q) X! M% g' ^9 l1. 文件系统遍历(目录树结构)4 `, ^" t4 `4 P8 R' f% o  T
    2. 快速排序/归并排序算法- ?! H" q; N$ r0 f/ K. q8 S
    3. 汉诺塔问题
    ( \# k' F6 h$ Z4. 二叉树遍历(前序/中序/后序)9 ]1 T* N+ J$ M8 q8 {
    5. 生成所有可能的组合(回溯算法)
    6 y1 }2 p$ v9 _6 B0 ^  d6 Y% D+ ~6 m  t8 g& j' s5 u
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,: x: ?) t/ w# L$ Z- |+ m
    我推理机的核心算法应该是二叉树遍历的变种。* H7 F& F' F8 a( S: E8 Z! I
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    4 B/ }6 b! ~; \+ |2 dKey Idea of Recursion
    ) Q  \$ U; o; U4 ], j% d8 a3 }
    - P- @! d9 b3 x" m$ v1 t8 iA recursive function solves a problem by:$ D1 k. Z" ~$ u$ p( J# q

    7 w6 z0 z* V" n2 I. ^    Breaking the problem into smaller instances of the same problem.
    # i) h8 r$ U& W( g; }
    7 t3 Y0 v6 Y! y3 c5 i7 g5 V    Solving the smallest instance directly (base case).8 t7 u# K! k; L

    7 W$ u9 e8 M  k$ ~7 `: m/ \: [' Q    Combining the results of smaller instances to solve the larger problem.
    : k7 D' w) K6 [% M" q) v  U- s6 C# T7 J) K
    Components of a Recursive Function
    $ r& S1 {- v( N! |9 }0 j2 w2 {3 P4 O( ]9 d% O8 e
        Base Case:6 i6 v: Q0 q! R1 I8 ]0 N

    " X% g2 ^: z- S* H6 [        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    , T- B' r, e/ l, n7 P' i* d: I: A7 M! X- f) x( ~$ x
            It acts as the stopping condition to prevent infinite recursion.2 U. `8 a' q7 N2 F

    0 g- Y& _1 C" P* D5 n, H        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    * _. u# a! @+ c% [" W; Y8 o6 Q, b* O* D, Z
        Recursive Case:
    2 e( L% Q0 O. b% [# e1 X4 t0 l8 o* u9 H: R$ s0 g
            This is where the function calls itself with a smaller or simpler version of the problem.2 M! b/ k3 ~) k! {5 z
    . D- e" Q2 ~) q" C( c& `' o
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)., V8 j: T* b7 c" I: A
    2 i8 \. {/ k# l* D8 C, ?  b
    Example: Factorial Calculation- Q: i: I+ }8 c% X* _) Q6 x/ J  ]! R

    % N7 @1 V9 b/ F- w$ `The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    . p0 S3 x. K- K, @
    : x& h. p& v% k( }& N    Base case: 0! = 1& R* B: p; j; e9 B

    ( h6 d' @" @: `% Q# E    Recursive case: n! = n * (n-1)!% O& m. c. M7 i% i: _* O

    8 P/ ^. U  A/ R  zHere’s how it looks in code (Python):
    & H0 R0 T6 F! O- P5 fpython
    , |$ |, J- W7 o1 ~3 P- D4 m( d: y  ^& @: ~% g! `6 v

    0 x! f) G" E8 e# mdef factorial(n):' Q' H; Z, ]( S/ b( o
        # Base case
    ' P' w, \) D; z* j    if n == 0:3 m& O" z" \6 D3 I2 v: R  ~
            return 1$ O- e  l7 Q  C: v# ]. {
        # Recursive case: |! U0 o, Z0 ^
        else:  Z5 ?: Z. A4 q* ^
            return n * factorial(n - 1)
    * b2 D+ _5 i9 s0 x4 v3 M
    , [) l- F5 }  M# Example usage% |1 @$ s) ?. b* h- j, L
    print(factorial(5))  # Output: 120- [1 Y6 [( z: d* X' u

    - M) i4 ~, g% ?+ b8 m5 e# GHow Recursion Works
    7 S3 }" c" [& k& t1 Z
    5 [4 O9 L! o1 \+ \! w0 V    The function keeps calling itself with smaller inputs until it reaches the base case.8 v- p2 ?2 e) v5 v, E
    ! f& O+ d2 @- N4 E; O* z. |( M4 L
        Once the base case is reached, the function starts returning values back up the call stack.& D* a* A  y' j$ L: n1 Z

    3 s' C8 E2 K; j) c) W    These returned values are combined to produce the final result.
    8 {6 e' I' _6 Y
    : H7 I+ t1 V9 {3 p: A% N9 `+ {For factorial(5):% ~/ D5 ?: B& U' d5 v* S
    . J3 l, h+ }: b! F
    4 N5 R# b5 [/ j* O+ K. C
    factorial(5) = 5 * factorial(4)
    + Q) }- B: u& ~6 F7 ^% t9 u0 @( qfactorial(4) = 4 * factorial(3)4 V5 V. F( F5 X0 o4 ?
    factorial(3) = 3 * factorial(2)3 T' T* A( q: Q) r) W! z5 U
    factorial(2) = 2 * factorial(1)3 V% q: B# H. c# i# ?+ s" l7 t
    factorial(1) = 1 * factorial(0)9 W/ w8 }; _* W1 F8 t; q
    factorial(0) = 1  # Base case
    - z  G9 q& R5 t0 k! Z' A" q1 {- E' F9 V: m. L% l3 o( z9 G6 X% P# P$ c
    Then, the results are combined:- E2 j7 s- G0 Y6 d

    7 N. d$ p5 v7 y, H5 B5 R9 J9 f  X" F: @2 V, y- p# j
    factorial(1) = 1 * 1 = 1
    7 ~5 V$ Z; E. w  R) D1 Xfactorial(2) = 2 * 1 = 2
    9 s! s- M* u1 v; O. Z# S9 `. q" Vfactorial(3) = 3 * 2 = 6
    7 ^$ Y  [7 v" Y$ D* Dfactorial(4) = 4 * 6 = 24% U& |! o- y  Q: h" C
    factorial(5) = 5 * 24 = 120
    + o& F' ]; b& b, c, R9 D' D+ G, S8 B+ R3 d  S4 q6 M
    Advantages of Recursion& @7 C0 r7 ~$ g3 U) X# R# {  n/ C

    + m0 H5 p8 l5 y! C7 @$ O8 q    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    8 l& _4 x9 J: o8 V- _7 F: m/ f8 q2 S2 q
    1 |7 z% R( [% I  X4 F" Z) A    Readability: Recursive code can be more readable and concise compared to iterative solutions.% ?  }7 j5 y, D

    : ]; [$ D+ @8 e! k9 VDisadvantages of Recursion
    4 q+ p( k2 {5 `! s' F3 }' ]( W
    * C: z6 a) I5 U7 g" g6 g$ b+ P4 B    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.$ S8 g, m- Q% l* G, i- ]

    4 Z3 N( H0 H0 Z6 N# F    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    4 a3 @. g  b) T) N
    ) _" T0 u8 P5 H0 }+ oWhen to Use Recursion- q6 K' |; ^( p# }2 a1 l5 G8 U! {
    ) Z( @3 J! \/ }7 h; e" K  X
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    2 v" r+ z' g( Y; P1 Q5 O& c) x4 g  I1 K7 l9 J1 R' w
        Problems with a clear base case and recursive case.( A3 ~0 S* ?( J+ a" f& J

    6 N0 }: @6 M$ g  \2 B7 d9 iExample: Fibonacci Sequence
    0 J" ]' v! h1 v7 X- a4 f/ v5 D$ Y6 u9 }7 Y3 a  g! G
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    4 W% F& `7 t1 t, K1 u0 E
    - R, x' |) o. ]9 ^    Base case: fib(0) = 0, fib(1) = 1" v$ {/ e9 ^4 z& A0 P$ f
    3 Q4 B# P8 w2 q1 F+ j0 G; Y
        Recursive case: fib(n) = fib(n-1) + fib(n-2)( B9 F3 f0 P; P& a) c. k: n  K

    % J1 t( K3 }) p& U+ J+ `' _9 Mpython
    $ U% K  q. Y4 f- |, ?3 ]( a1 @8 V! i( e- U  H

    * E! m/ u4 j. [  Xdef fibonacci(n):
    1 B' U8 O8 D" o; w6 Y# g    # Base cases( y# d! g, y7 O7 ^& g7 R
        if n == 0:
    0 B8 W7 E! Q/ B& I        return 0
    3 n* O& q& C+ G2 M    elif n == 1:9 X6 V3 D! ~& m5 P4 A
            return 12 ]  O- ?3 E% N: W/ W5 @
        # Recursive case
    ' q+ n& n0 a+ m8 F. [# j- z& h    else:
    7 r7 Z3 ]% C' k, V/ G+ n6 I7 N" d        return fibonacci(n - 1) + fibonacci(n - 2)
    . G7 n- c) S+ n# b3 s- b$ m4 s4 U0 T+ p
    # Example usage
      r5 ?' m( M% {# q% C0 @# Kprint(fibonacci(6))  # Output: 89 G! T. u# f, `1 }7 y' t$ n3 g; |
    3 r" x# {1 Q" T! k' }4 {9 j
    Tail Recursion! G% N) r5 e$ ]9 \/ k! O

    % r$ p( y8 x+ X+ Y7 s. S0 vTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).2 F- n% F, X/ F) a* y7 m

    7 a( k/ I( N$ [+ W( j9 E& iIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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