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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ; u3 V- j0 N; H. z* D

    ( b4 l6 e. [  e+ H( b解释的不错
    $ n: a1 Q1 n  ?( a5 A
    ' e: a* I0 I0 ^# d- G7 p递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    # o3 ^! Z- o+ {! b
    * j% F. f3 K2 F7 g 关键要素
    " N2 @8 ^) r! C. x. `, `, b1. **基线条件(Base Case)**
    * o- }- T" F/ M, r; e   - 递归终止的条件,防止无限循环$ h% T. P3 W& `9 p4 M6 M5 k
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    % M; V: c7 n2 |& i9 d
    ; c9 M  l0 ^7 T* F" {4 Y4 X2. **递归条件(Recursive Case)**/ N$ d; y5 ]4 W1 F
       - 将原问题分解为更小的子问题
    ( m; F4 m" s- `& b   - 例如:n! = n × (n-1)!9 \' l7 L, ~3 E# h. t4 Q
    # ~9 V0 d8 `4 P3 H
    经典示例:计算阶乘9 ~; X: z% H$ L* J
    python
    1 o/ [1 x: {# ]# U0 B1 y9 hdef factorial(n):
    3 m4 z" b9 K6 J# D* {" M) {$ E    if n == 0:        # 基线条件9 V: d6 a( n! F$ R+ R/ S
            return 1" ~% p; w+ @9 Q5 i& h" a
        else:             # 递归条件
    3 b. b) \) ]- N3 `        return n * factorial(n-1)
    ) \; `, F: f" ~执行过程(以计算 3! 为例):4 K' ~; @8 e0 c$ G% \
    factorial(3)9 N8 S0 \2 Z& Y4 F
    3 * factorial(2)
      ]( V9 V" h0 q3 * (2 * factorial(1))
    : y8 G9 [1 z4 J3 d3 * (2 * (1 * factorial(0)))
    ' V% ?! |  Q! o7 I  l/ ~1 V/ x) o3 * (2 * (1 * 1)) = 6
    % [% W6 ^$ v* O; N: G. c8 ]
    # V; y: N6 x) m5 z1 b# D 递归思维要点/ ^5 u" M6 H1 k( |
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑  y! r0 T$ J: y% ^- s& u
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间), m6 q6 q  F; [1 B- `( I  |
    3. **递推过程**:不断向下分解问题(递)/ K- S: s1 l  @5 o( i, o! M; P
    4. **回溯过程**:组合子问题结果返回(归)
    2 p0 b- w4 f* r3 G- O2 \# h5 e) D5 P% x# [! T- v- s
    注意事项! X; ?8 Z( s: D. W/ l6 ?
    必须要有终止条件
    * d& n1 F+ \% ?( }) C递归深度过大可能导致栈溢出(Python默认递归深度约1000层)" O* Z' N( O& R: e4 [, K
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    1 X0 \! j+ u% F$ h尾递归优化可以提升效率(但Python不支持)
    3 ]6 l# \1 |7 _( ]' v' [. \* M8 N' H. w9 H3 F. J4 j/ _
    递归 vs 迭代
    1 s: r( ]3 {8 Q* ^4 R|          | 递归                          | 迭代               |
    1 a3 o; h8 v; G6 w+ r: J|----------|-----------------------------|------------------|
    7 r" l, Q) ^5 k* A, H8 B1 L' A| 实现方式    | 函数自调用                        | 循环结构            |
    # \" y3 j! a: ]4 H, S3 D0 r| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |; u% u, r8 `2 H, e; L
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    4 L/ V4 x4 m) ]4 G/ a+ K| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    / K7 |5 E3 n1 U  @8 \) L. N7 ]; T; d& q8 j: V0 k3 `
    经典递归应用场景
    8 }- L/ W1 |' N9 x2 E. Q. B4 o' H1. 文件系统遍历(目录树结构)
    , L( G5 l, B- N" B% A2. 快速排序/归并排序算法
    . S8 g, V, T  Y) F+ P3. 汉诺塔问题
    : O2 d! A) U; F4 m/ X6 \4 a1 E& ~4. 二叉树遍历(前序/中序/后序)
    : n: H/ M! z/ A5. 生成所有可能的组合(回溯算法)
    + h5 u* A$ k. ^, n% i
    . a" l$ T" K' K1 R7 w试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 07:29
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    9 o- H4 h( K, s( z9 c6 |4 U% x) f1 `我推理机的核心算法应该是二叉树遍历的变种。9 s% n6 Q2 n# j- X$ j! r3 l
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    $ w( ?1 t  ~8 h6 w& q/ mKey Idea of Recursion
    . h. ]0 k& S, b) D- n1 ]+ X4 n7 t% A, ^
    , ]" h6 J; k9 _/ aA recursive function solves a problem by:
    % `5 V( X$ U% k& B  v6 [+ ^' m* r
    ! c) J5 ]1 m* i$ q( o* [+ t    Breaking the problem into smaller instances of the same problem.% @* A9 g% x3 H& N
    : e: e# N/ ?6 Q& d
        Solving the smallest instance directly (base case).
    * a5 X$ S4 i1 j( u" N$ [! B" ^4 N* E& F! P. |
        Combining the results of smaller instances to solve the larger problem.7 `7 @- q6 ]0 \3 J
    8 e* Q9 D, }- {3 ]& m: s
    Components of a Recursive Function
    3 K5 d3 m7 O  j- S- _: c6 ?/ X7 K
        Base Case:! g/ j: o2 k  Z+ z
    : K5 U0 C7 j# p* }1 O. \
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.1 j" ^% W8 Y* Q8 f

    ' s( ^- F% d/ @, D1 a: v) g        It acts as the stopping condition to prevent infinite recursion./ X! }7 ?8 u: h& T) c7 X4 G* T

    ! R$ v  @( L7 J) W/ e3 D        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    9 x# q1 l; Z4 y1 G. a  f. K7 E% r* |6 Z# c) Z6 |$ H- }! l& q; `
        Recursive Case:
    + l2 m7 {4 p- p1 I& t7 s, [  w4 i' M3 Z
            This is where the function calls itself with a smaller or simpler version of the problem.
    ! E  G! i2 v" ^$ [, c8 e: c% Z' o# C" C5 H! U7 N2 z
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).* @3 }8 J4 S0 s4 a$ I3 F
    $ A1 J) w/ L9 C. V
    Example: Factorial Calculation
    ; `+ ?! B- I+ N( }: M
    : X" e+ g, e6 oThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    6 M; V! y2 f0 v  y2 d( h$ n+ s- b; v1 R
        Base case: 0! = 1
    - n) ]0 `' V: T+ O! x, F7 u( D
    ) {' y6 d# {' g1 o8 A6 `- o5 O- U    Recursive case: n! = n * (n-1)!# D. [$ Z. V* u8 q
    0 a. J& ~$ E4 L7 ?5 H  {7 Z0 q
    Here’s how it looks in code (Python):
    6 P! f7 S7 r7 v( w; `' {python- {2 U( R0 l' r, _' q; W  F* X
    7 ?: B: E3 w6 U; q6 ^' J" ]' }$ W

    1 b, b. @5 Z# q4 Zdef factorial(n):
    6 l0 i* \: Z/ c3 Y    # Base case* Y& c* C- G0 A, e/ u& k5 B
        if n == 0:/ w0 U' o% T5 ]- G0 ^( u4 [
            return 1& j6 \4 V, y# m( h( E2 }& S
        # Recursive case
    2 t- S! l' _! }    else:
    * s; M. U/ Q! C# I$ X2 |        return n * factorial(n - 1)8 {% q7 S; K7 u+ @8 C. }/ }9 @
    / [9 {+ s7 e" t
    # Example usage
    4 P& `' h+ a% w8 cprint(factorial(5))  # Output: 120+ Z: R4 m4 y1 W- {- Z

    4 @: i' w5 D+ M2 l" QHow Recursion Works8 J% B, w/ j$ C4 ]/ p

    3 c1 V/ d' }+ L8 K    The function keeps calling itself with smaller inputs until it reaches the base case.
    + E% n- e' {, f/ j
    $ u6 T: a7 v" z9 r3 [9 i    Once the base case is reached, the function starts returning values back up the call stack.
    1 d& T1 w: P0 `6 b( h
    / O+ ~$ E4 N3 q' C! F" U, `    These returned values are combined to produce the final result.! z; v' f4 t) X: L) L3 f$ X0 @  b* x  R
    " y* Q, u3 g% ~2 G- A2 n8 s
    For factorial(5):  W$ c# l# W, `) {- F9 a: I) J  u
    8 }4 ?3 y* F9 z. B
    ! w1 h8 U  _: `+ K$ ]5 i
    factorial(5) = 5 * factorial(4)
    . r; {$ r2 d/ g: G3 T& m. [factorial(4) = 4 * factorial(3)
    : Y/ J  ~- m! B( y, lfactorial(3) = 3 * factorial(2)
    ( z7 f" {& ^9 `# ]9 {factorial(2) = 2 * factorial(1)
    * r  Y& X6 M: Afactorial(1) = 1 * factorial(0)4 b( D$ A' b6 v1 L2 d$ u
    factorial(0) = 1  # Base case" r' [( f& U. v% ]- \! v8 g' Z

    ! q0 _& f: G) \Then, the results are combined:
    5 `2 b# H2 W$ B  n/ M7 R" Q  ?
    , D9 I2 U8 g+ l- V2 ]7 l
    ! a% T* ]: z6 }. P: ?3 qfactorial(1) = 1 * 1 = 1: H3 |1 v. V0 d0 P  t' d
    factorial(2) = 2 * 1 = 2
    % \5 S5 u; t0 N( e, }+ w8 A, Y( rfactorial(3) = 3 * 2 = 6
    : @( X* A* ?: n7 E& `  ^# ]+ G' Cfactorial(4) = 4 * 6 = 24
    - X0 B# _& c* s7 {  H% dfactorial(5) = 5 * 24 = 120( x' w( C* F8 |

    . \# \* s$ c% \( g1 zAdvantages of Recursion
    2 T9 H& f( n8 e& f& a- o4 X+ Y9 _: e  x
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    " O, c) i, |9 v+ W! q- x
    4 e. x# z- Y" M. d+ J- e3 X' P9 Q    Readability: Recursive code can be more readable and concise compared to iterative solutions.0 T- [6 |; d& Y8 b1 D) a- V" @( z. h

    $ S( {8 {# K" N6 p% C$ b. {& v" _Disadvantages of Recursion1 m/ q( |" n1 l6 X7 U! j8 ^

    4 q, a0 C& _3 V! B    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    7 A: x' H& e$ E# `5 t4 D, A+ ^6 D; }& I, `5 e+ k5 s
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).  _  m9 C- L' f+ D# G
    6 a- q8 f& L5 y: u
    When to Use Recursion
    ' q0 o/ q0 a# P
    8 I7 z  y( i4 o  [& n+ R    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    0 C. ?7 Z0 n' g3 i
    7 K6 @9 |$ v/ \4 [' u) N    Problems with a clear base case and recursive case., H8 ]* d) R# e2 ]8 q8 y

    ; Z3 f. E& k% [1 BExample: Fibonacci Sequence
    3 U2 x! f& @& a. P5 }  A$ J. b, e  J! H$ |# z; Q7 g: q
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:/ D- d' _) f- P9 ^
    + o' e9 }6 T$ Y8 i) e
        Base case: fib(0) = 0, fib(1) = 1
    # y7 _' P) b4 }# Y, O6 K6 a. q( T5 T' B  \3 a
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    * n# K0 [2 V/ z
    % n( C4 w7 Q5 B! [( u( W+ Y! epython
    8 ^4 S! i( Z+ o8 D2 @$ Q9 e" _3 {
    8 X1 B: w7 {' L0 I; O( p/ `
    ( i4 `, _  N8 S& k$ ^" C9 a( Adef fibonacci(n):2 m. t$ `* M# V; c. Y* f) u
        # Base cases
    , W) `( W- Z; }/ O( [6 p% o8 F% W    if n == 0:- t3 J, H$ R7 g6 a. n% M
            return 0! H- p' |5 G8 ~8 D
        elif n == 1:4 `* I2 {9 j0 p$ M# K5 i' i) I8 h
            return 1: L6 g  e! t; I; ~6 g& m
        # Recursive case, F+ G  o- T7 O1 o3 [
        else:
    # `1 E) z2 A$ E- b* B& {! z/ `        return fibonacci(n - 1) + fibonacci(n - 2)
    , e- p, h, c$ `, L! w7 j8 c. g; R! u9 W: q3 o% T+ C
    # Example usage0 W. {$ {5 v0 ^: n: }
    print(fibonacci(6))  # Output: 8
    , x4 j1 e7 W' \) q9 N# f. S4 @! H* \, ?1 T$ T" d
    Tail Recursion
    , I" m- Q3 y9 N4 N, m
    $ t# U  |( ~4 e3 [2 d1 K+ zTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).  W9 E3 w, A8 x# X( [1 ]2 {
    5 p) q) T, U+ }  P$ V% }9 E
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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