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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    * g6 _5 o1 c1 G) |% T7 @: h, N: w7 x. z- b; Z! C+ n
    解释的不错, x* x1 N- |/ Y& f' s

    : n1 o" S3 Z( t& Q* A递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    * y& j( ]. F8 _" A) O5 \  O/ C
    + J: L8 C2 G3 E  E# ^  X 关键要素
    - i1 e3 r: U2 z  ]" L! C1. **基线条件(Base Case)*** s0 Y* g+ j  v! |; L& j1 o5 `7 Q
       - 递归终止的条件,防止无限循环% {( N* ?( k9 F; C
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    " |% G4 P1 n) p
    . k9 C0 u$ X# I2 J% V. `" \9 ]8 q2. **递归条件(Recursive Case)**
    4 W" M$ H8 T1 C9 q4 F6 P1 r* B: r   - 将原问题分解为更小的子问题# k2 [9 G$ p% Z1 ^
       - 例如:n! = n × (n-1)!
    & b1 n2 G8 y+ Z1 @* j, L
    8 {0 s3 W. @) N$ E, ?- D/ v, k 经典示例:计算阶乘+ i3 J( _+ x/ e$ _: V# `7 r, n. N
    python
    5 S( A% _% f/ adef factorial(n):
    . E  n2 d+ F3 D( S7 C$ h# E5 V, s    if n == 0:        # 基线条件
    ' ?  X- e* y% t4 N        return 13 b' Y$ W  g" `- b
        else:             # 递归条件+ @9 L+ B9 }( [" C
            return n * factorial(n-1)
      n% f2 O5 N6 Z$ A8 b6 M执行过程(以计算 3! 为例):
    8 X( [5 @$ K; b: D5 Ifactorial(3)5 |/ q- d7 H( `. r
    3 * factorial(2)' Q; g4 T8 ?5 X7 b" n5 j) k
    3 * (2 * factorial(1))/ ]) {( o/ P# d8 V  P# B
    3 * (2 * (1 * factorial(0)))0 C: a9 ]2 |/ }
    3 * (2 * (1 * 1)) = 6: T5 b$ c. v: R6 s, X# r
    . q1 O* q* _6 J8 ]1 l% `4 ?) x4 K
    递归思维要点0 j/ y7 E0 ^" p5 _* F
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    ( _: k. _/ |& r: _; V0 ~+ g2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    4 O3 p4 y$ G/ ^: I& [$ ?. J- _3. **递推过程**:不断向下分解问题(递)
    1 s& P! [/ a& |/ W4. **回溯过程**:组合子问题结果返回(归)) e- y, f' b- C/ i) y4 a
    9 E" b; R3 @1 J
    注意事项
    ) E! \( a& X& ~5 `1 w; w必须要有终止条件& V4 \5 f% `4 M. g7 e* x
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)# t8 z5 A: _' p6 A/ ^. n) m" X& X4 s
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    4 v) ?, Y, E4 b尾递归优化可以提升效率(但Python不支持)2 ?' l2 K: H6 m

    6 S) q3 {  M' ~  A( D1 G 递归 vs 迭代' w; ~+ V* E: m
    |          | 递归                          | 迭代               |! X8 E* y5 K- D2 e/ p( ^
    |----------|-----------------------------|------------------|
    1 x7 a! M% a7 l" `7 @$ R" r| 实现方式    | 函数自调用                        | 循环结构            |
    2 H' p7 d2 }; P+ l  Y| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    4 R) }* B' _8 ~+ W7 X| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    6 a# V: {3 d2 u* W! D$ q; _) `| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    * ~; _% d, a$ {$ N: N% d8 W* v  w8 t0 Q9 ~: U8 a
    经典递归应用场景5 M  Y% t5 E, v* I# d% T6 `) |
    1. 文件系统遍历(目录树结构)- ~+ C5 U: x; ], I6 ]. d
    2. 快速排序/归并排序算法: I9 r; @, D+ I3 K6 O2 B  U
    3. 汉诺塔问题
    " Z4 w" d) N% C  t! `( J. X4. 二叉树遍历(前序/中序/后序)
    4 c/ b  `# R  b7 {3 Q5 J5. 生成所有可能的组合(回溯算法)
    2 I$ u3 |2 A& g6 q/ V
    7 C- J7 J+ _+ r# b8 n试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    郁闷
    3 天前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,$ o! T, K$ x. y1 n5 i+ ]: W
    我推理机的核心算法应该是二叉树遍历的变种。
    ( w. K6 d2 N, v0 o1 Z. [另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    6 `& _$ j, x- j7 l7 P7 j4 p% CKey Idea of Recursion
    + k1 z7 }) R/ Y8 j* c
    9 b6 k8 a: K1 M. L( I& D3 f  CA recursive function solves a problem by:& V% q* H# b% B! v
    # G$ U5 M, @, Q" W4 `$ N
        Breaking the problem into smaller instances of the same problem.
    & {9 s; [0 E" c0 M6 I  y, K& Z; b& D9 j3 w% i0 L
        Solving the smallest instance directly (base case).
    ' t  O7 O8 T: F( o# z& R) [3 `
    , W- d0 X0 \' l9 o- h3 M    Combining the results of smaller instances to solve the larger problem.  F7 j& i7 m5 l* g

    ; {' ~/ L% u8 }4 O- LComponents of a Recursive Function
    , j. M# P: {4 M8 o; ~% i# I" k- _2 _8 Y
        Base Case:
    ( C  m5 q3 f: f) F  `! b7 j
    ( Z, l, j+ b, l+ ?* I2 v9 c  D        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.4 s& R4 L$ b, Z

    + r% C5 u5 D9 i        It acts as the stopping condition to prevent infinite recursion.
    - T/ a8 j5 ]; A0 d9 Q/ K) O2 g) n5 n+ U( Y8 C* e
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    4 m+ f8 o; {3 E8 z  C5 q% v( R* u$ z, N8 {- q' E. L( `6 u
        Recursive Case:- Q! {, G+ ]( X, V

    , y, N# q0 m- R' ]4 c0 I6 @        This is where the function calls itself with a smaller or simpler version of the problem.
    5 l, D* h% @% q% F4 x4 X5 Z7 g+ b4 b5 s$ f! w, D
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).- ?. w6 M6 h; l1 U/ N

    7 N0 w3 P) k; v4 |Example: Factorial Calculation1 b8 @9 m7 Y, \$ P
    7 L2 i: F2 H0 U% r( e
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:$ X* L3 H( A. s. C

    2 Z  }. g$ r5 `5 y0 M    Base case: 0! = 1
    3 z8 @' c3 D) C# K3 F3 v; ]" G
    7 h4 \' q3 U! a* e% b, t/ w    Recursive case: n! = n * (n-1)!# G+ r. H# Z6 C2 ^+ J: I

    1 O; x" ~! ?' m; J7 ?Here’s how it looks in code (Python):3 M2 R' p4 F; z, M! H& e
    python# B5 r  t6 H6 C' J. X9 ]! n

    ; o! f, z* p# Z- \, a, R3 l- X4 ]" M2 z: D  K6 s5 Q: @
    def factorial(n):" {1 \! h! C, [
        # Base case# S( E$ {2 Q9 P9 s  X+ X
        if n == 0:
    ( a: P. S7 R+ r2 {* V        return 19 b% P$ {  D- w! d- I2 b3 }
        # Recursive case
    3 H0 |( d) Z) I& i1 G9 \    else:5 }% E2 u# j8 ^: b2 N( ?/ \3 [) G
            return n * factorial(n - 1)
    " z3 S/ X! D8 d6 l, N8 g* _% O2 A; L6 c5 I$ K
    # Example usage; w& x3 c* Q  T2 \% o. p9 q. [
    print(factorial(5))  # Output: 120
    - P! O  m( Z! G. k
    . e7 i) q* a' j1 f9 q! c* F8 Q* d* PHow Recursion Works
    4 Y% X5 q  j- Z! K
    - A% r  D9 H/ @$ o    The function keeps calling itself with smaller inputs until it reaches the base case.
    - r% _( L+ j* M* c4 p; b3 K3 G3 P5 \. S) h! H6 E
        Once the base case is reached, the function starts returning values back up the call stack.
    & P; {& Z; f& G' h" W
    6 V  o+ q9 A: n; Y. X: }' [9 {    These returned values are combined to produce the final result.
    + ]0 h# b* l. h9 c% I7 X1 M
    7 G8 e: d) ~: r$ {3 }" c% @% WFor factorial(5):
    " B* x$ Q+ p. H! t5 d, ^# U! G& G, b4 e2 s

    ! y9 C6 x6 R! ?' _) tfactorial(5) = 5 * factorial(4)
    % A2 M$ N: H1 F$ a2 m( K& J) ufactorial(4) = 4 * factorial(3)8 g6 L; M" b& K8 Q; M6 E5 G
    factorial(3) = 3 * factorial(2)7 P7 `2 ?; U0 O6 U
    factorial(2) = 2 * factorial(1)" J+ _/ J. H; q! w# P% W
    factorial(1) = 1 * factorial(0)/ G1 P7 t4 ~3 h9 _2 H+ {: D
    factorial(0) = 1  # Base case  p! ~, }. o6 b

    0 w$ G  ]: [: J' J& e7 a. wThen, the results are combined:
    1 Q4 ?* q) N% Q- d' J
    2 O1 t% G$ r% G8 h, q9 R6 K
    + z) ^; P* i/ k% h8 ^factorial(1) = 1 * 1 = 1
    - R( f3 Z4 C# u7 ^$ e8 K4 efactorial(2) = 2 * 1 = 2
    4 e' _' G) a) w; x: p+ Ufactorial(3) = 3 * 2 = 67 R. d4 Q9 o2 T5 {5 m
    factorial(4) = 4 * 6 = 249 N( E5 Q* G* K$ S2 d8 e$ ?) m9 s8 e
    factorial(5) = 5 * 24 = 120
    5 h2 e2 `$ l; w9 v! R6 e$ P7 C6 d' T0 X8 W; }+ l: `- d" M
    Advantages of Recursion1 ^) v! Z" [. z) M9 w, |
    2 Q5 z) i$ x0 a* ?
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    6 n- J6 X, G+ L/ V
    $ m( e% x, b6 I1 ]2 }  v    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    ) l+ M1 O4 |* u# |* }; q* e+ ?) N6 G8 S4 X
    Disadvantages of Recursion
    2 n  k$ }' [3 E5 ^9 z4 e5 R3 v0 k& L' g; P! M0 h; A6 U' q
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.* t; m5 T8 T+ G; }0 j
    7 y/ t2 K" ?3 \3 F5 I
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ! j8 N. D5 \6 @( N/ g# T/ |6 q
    When to Use Recursion
    & k4 u" g) V1 y# n# |
    3 m1 c* {! ]* w2 b& G    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ; S# y, D+ |, @+ k$ B
    ' A: I+ N  D$ h( q' n$ Q& Y. x    Problems with a clear base case and recursive case.
    " C9 X3 g, ?8 _" q5 x
    % ?8 F) h/ ]3 E; `& VExample: Fibonacci Sequence
    , x* v7 o9 b# Z: K: ~  W# n5 z/ H3 m+ \3 _3 Z: V
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    ; M( C% q3 L/ E) h" Z! M
    5 |9 o: j8 X( U: z6 r1 p" m8 o    Base case: fib(0) = 0, fib(1) = 1* m: Z/ ^3 G- q" [
    7 ^: p7 N- t4 a  s5 F- H* T
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    . |0 y. _3 F# y7 x
    ; X+ P2 X$ Y, E! ]$ M" X3 `python. W$ F% y5 E4 m3 I, H

    , }! F  i- t% W6 ~3 z) c; \, `/ F% @, q4 Z% m) B
    def fibonacci(n):
    1 r2 t( F- n" h2 l" g' K+ e    # Base cases
    8 W0 g4 v4 T2 z2 c! J4 e3 s+ R' ~    if n == 0:
    6 Q7 q) F6 O4 m- k$ N; E: ~  M        return 0! v* J& @. s$ U4 [6 b
        elif n == 1:( E* M) ^: s) R. h6 k) g3 v
            return 14 Z& t6 E% P; }2 o
        # Recursive case" B/ {' }% U  E% E( b
        else:9 r& ]  R, M. U) J" q
            return fibonacci(n - 1) + fibonacci(n - 2)
    : w% J+ ]/ z# k
    3 C0 w( k9 C5 w" c# Example usage/ y5 g7 x! r. h, q- b3 y; r
    print(fibonacci(6))  # Output: 89 M& J- R( t% k7 @8 t6 O
    ) Q5 z9 B3 {8 u- G) e
    Tail Recursion
    6 b+ ?4 {5 p5 ~, ^( D" Q3 p
    " r8 y! ?& A( q# C, c$ hTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).% O; b# v9 |: q" K) a
      |" M6 q- Y% x9 F- _
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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