设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2482|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ' D  _# q- W7 j0 L$ t% `3 ~
    * v6 y9 e  h+ K# }5 G# x0 d
    解释的不错
    9 G5 p- s# G2 Q4 G  M& z( ^0 z# d9 M
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。8 S* T/ M/ ]2 T0 _$ j, E
    $ W4 W7 ?) J8 Q; M9 z0 J
    关键要素. m1 ]8 K% y% M" J# x$ C
    1. **基线条件(Base Case)**
    # Y$ d5 h  v+ S   - 递归终止的条件,防止无限循环
    , ]9 ~2 l& C9 _" l   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    * H6 D- P1 j7 o. J. C" L- O5 d/ ~/ J) b/ r3 J
    2. **递归条件(Recursive Case)**; @( U- R1 ]4 a- J7 }
       - 将原问题分解为更小的子问题' G' U/ H. y1 M. d9 c
       - 例如:n! = n × (n-1)!( `3 I9 p" @$ ?1 N+ K# o( E

    . @4 Z6 M4 S, { 经典示例:计算阶乘; N9 B, D  G: l: B1 o) N
    python
    3 o; E* D4 W& h) e. jdef factorial(n):  W0 Y7 L0 @& w$ U
        if n == 0:        # 基线条件
    5 r9 i3 l% A: y  @3 @6 U; s        return 1) _2 ~7 v8 s* r8 f  R% r3 m9 t( S
        else:             # 递归条件& w$ ~$ o, ~& Q* t5 V# f4 O# f" Z
            return n * factorial(n-1), c0 T2 f/ @% l0 C
    执行过程(以计算 3! 为例):1 ~" A1 R0 d1 s( J9 Y( R1 p6 a! F
    factorial(3)
    * \' Z! y, ^! x: |, O5 A9 ]3 * factorial(2)
    + q& W+ ]' R/ [# @4 W% F/ q2 V' N7 ]3 * (2 * factorial(1))' A# j1 i0 ^! N5 @7 m
    3 * (2 * (1 * factorial(0))), r* R+ e9 ^7 v8 E# q, ~
    3 * (2 * (1 * 1)) = 62 E$ Q2 U' }1 V! O! c, N& z
    , v* ?/ Y7 w9 H! U! U5 w! P( s/ s
    递归思维要点+ y0 z% z- e: s* D- Z* j1 a
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    3 h/ e; i# r6 A; P% }0 V7 Q! @- K2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ( A: K! a+ `8 ^( D0 Z3. **递推过程**:不断向下分解问题(递)
    % w5 H$ f+ O( L( B; @4. **回溯过程**:组合子问题结果返回(归): Y& Q; N* F( K: h
    ; E1 w  i6 q! F9 O# C, r
    注意事项9 f5 W1 D7 B6 a: \
    必须要有终止条件
      B4 L  J, H! G" y递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    1 X, x7 T( ?9 Z: \% p3 b. N. v/ |8 p某些问题用递归更直观(如树遍历),但效率可能不如迭代
    4 p# {5 L6 y: x0 A: y) q+ Y尾递归优化可以提升效率(但Python不支持)" j( h: Y, c: R2 u. J: r+ P

    8 b, t6 m8 V1 H! ` 递归 vs 迭代
    ) l9 o$ o' V# e% u8 W8 F% p|          | 递归                          | 迭代               |
    7 T* I! ^- r; B+ B& Q/ H|----------|-----------------------------|------------------|
    0 O; Q* y4 b' b4 @- ^| 实现方式    | 函数自调用                        | 循环结构            |& S7 F0 m8 R3 m9 y: x, \8 e4 @
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |, p. `  ]) Z/ c% ~1 O& `+ q/ Q
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |5 v1 w: {6 r- Z& [/ L. r
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    ! ?1 d3 r2 z, H0 K. o
    3 U. n+ L' |& M5 X 经典递归应用场景
    6 Y7 e4 f! J$ \  J6 V  F8 n/ B4 Q: F1. 文件系统遍历(目录树结构)# d' A. b- @+ D1 i) l4 X7 A, ^& U
    2. 快速排序/归并排序算法
    . y) m% J$ D1 f, s3. 汉诺塔问题. {1 q2 [' w! c" \* w$ u
    4. 二叉树遍历(前序/中序/后序)( [4 m. G. R3 ~% M3 P( Z
    5. 生成所有可能的组合(回溯算法)
      r: D! {/ p9 ]: j+ F% Z+ N& \1 o: x& W) `& A) N  Y/ e
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情

    5 天前
  • 签到天数: 3217 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    : A) O* n2 @2 h: ]  h3 T我推理机的核心算法应该是二叉树遍历的变种。
    7 Y  A& ~$ {* q另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    - H4 f' M8 \, L9 Q9 KKey Idea of Recursion
    6 L  e; C% P3 G; V7 B: v$ [2 k
    / t! e1 n( c- h4 o6 c& dA recursive function solves a problem by:
    ! P# w* X" k+ g3 j% @9 |" W4 R5 u0 _* k/ _
        Breaking the problem into smaller instances of the same problem.
    & B; a* x' H$ Y: C7 {6 x# x7 t9 b8 C. P. Q0 X: u' `
        Solving the smallest instance directly (base case).
    ( E' e( E* m. z) ~- ?1 b$ {/ o3 {9 ]" ?' i. J- R7 K9 A0 \
        Combining the results of smaller instances to solve the larger problem.& O( f9 ?! \3 N, y% c6 x
    1 V4 J. q/ Y$ v. s) ^, f/ _
    Components of a Recursive Function$ N  [/ i* _. T% Z
    ! l, s+ z- b+ R# y
        Base Case:
    ; W* [' M4 B$ B# _5 P+ r8 u, N2 F1 O9 t0 U- u5 o# `8 @4 f! X' q9 |
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.' u  ]6 E& p5 M9 z
    ) l% O; [, B+ f# \
            It acts as the stopping condition to prevent infinite recursion.
    ! Q$ X8 L$ ^# T& y
    ' z/ C6 X: q% g' v& j        Example: In calculating the factorial of a number, the base case is factorial(0) = 1." n& S; z+ N+ x) F9 ^0 g" K

      p- i# M6 u& H    Recursive Case:
    / L" G" t* @- c. X1 v/ m. K  f4 Y& Z; J
            This is where the function calls itself with a smaller or simpler version of the problem.
    , u5 M! Y3 g0 H9 z9 y5 g# n" {- i4 L: {4 E; e7 a0 z* |  v& m
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).5 P' x4 ~7 U1 |# n$ ?# P5 D
    $ G# A8 H! }3 r3 Q3 o+ L& h
    Example: Factorial Calculation& M9 r2 j0 H9 d1 h; F8 ]# Q/ w% W  u

    9 \4 _, r- Y' o$ @: jThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:( ~6 _* d7 X/ _! D

      J! p% T4 w! u+ Y. c, o, V) e+ q    Base case: 0! = 13 z  m  A; T. b6 s+ t3 |
    2 O$ h" ]: Q# Z3 R
        Recursive case: n! = n * (n-1)!
    % s% A: V" k& z3 r$ ^
    * w  B/ p( G, w7 J6 B- h$ YHere’s how it looks in code (Python):
    $ g8 Z4 h9 `  F3 ~( f2 }/ xpython
    0 ]" j3 p9 y/ A5 U7 U( z2 ~9 z, H! J4 [) n# |' ]6 S
    & ]# n3 `: ?; |+ z$ }: v" @, V
    def factorial(n):3 x' M4 m4 `. M2 Y
        # Base case6 Y$ c. J# @! {) F% \: G8 u
        if n == 0:0 f  P. s$ ]7 O2 R& b+ l
            return 19 h% e5 V3 d1 e# s; h  ~) v0 F, U
        # Recursive case/ |0 b7 w- J$ N$ @+ D6 }0 R
        else:
    ( |8 Q, Z5 r8 W# b        return n * factorial(n - 1)$ q4 n0 ?+ m; Q3 U! L6 t& a

    7 D/ ~/ W9 l5 L. i/ m# Example usage
    " l  J) G% s) yprint(factorial(5))  # Output: 120" {" g1 d# V% z) _3 v0 f% X5 h

    5 @7 b8 {' F+ L- JHow Recursion Works) D: M. ~$ w5 }( Z: X5 H& M- W
    + P/ E' s9 L! T1 ?$ z) U! @
        The function keeps calling itself with smaller inputs until it reaches the base case.
    1 B) n8 r' m1 P8 S# p
    + a) D' ?8 X1 x- s" N, e    Once the base case is reached, the function starts returning values back up the call stack.8 [& y- q; q7 _6 P9 n

      v* q) R6 i7 ]0 l4 c' L6 D2 O    These returned values are combined to produce the final result.
    * ^% D% d+ ]4 q0 `8 {& |
    ! c8 Q* y% M2 G' h; L7 T) y$ j* YFor factorial(5):: f8 E7 d1 E! |/ ?% K8 |$ J
    . ?6 w8 ^" `# x4 I( \7 C

    & L, X( x9 X1 U6 Cfactorial(5) = 5 * factorial(4)7 N; ~% d9 u! e7 h; v! x9 e
    factorial(4) = 4 * factorial(3)
    & ], t' \3 }2 v  Zfactorial(3) = 3 * factorial(2)# t" T) }$ J2 l
    factorial(2) = 2 * factorial(1)
    7 G3 F$ q+ L+ Q0 q# Mfactorial(1) = 1 * factorial(0)
    ' i- S0 V+ q# Qfactorial(0) = 1  # Base case' u$ D' G1 w2 V$ q2 \' X* ?6 o
    3 e0 _& h) a% |4 J) `+ G( ~
    Then, the results are combined:
    1 u* h$ N+ \- g+ j* B, _* @2 w$ Y; H" d! ]7 y; G

    / y" w9 k$ n, K" E% Ufactorial(1) = 1 * 1 = 1) ^6 Q; m5 v5 m% \$ Y
    factorial(2) = 2 * 1 = 2
    1 Z& D3 c; v, ~% P# ffactorial(3) = 3 * 2 = 6
      \7 C! O5 o0 u1 Pfactorial(4) = 4 * 6 = 248 t% `% H$ S: j  g3 a4 x
    factorial(5) = 5 * 24 = 120- l" l& W/ Y5 l7 `  c3 r
    " \9 L  p  t" m( t+ K) x
    Advantages of Recursion
    4 X* x; ^& `" n+ Z2 T$ U: B
    $ ~9 P0 j# S9 b& d7 l1 Y4 w    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    + n( i; }% U* y0 f  {$ O5 K0 `$ ^, m! [! v5 H2 Y
        Readability: Recursive code can be more readable and concise compared to iterative solutions.: B* x# n5 @! ^

    2 {  ~+ f; z# T0 u, H7 Z/ aDisadvantages of Recursion
    ; X4 M4 ^& a. _7 ~( N' E  [2 u6 h: \3 J- L) i6 l- E
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    ( g( k0 I; _: j! G) |7 O3 U& b, Y9 G
    * r' p$ F/ e7 B& c- F' W# c3 I    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    9 i- x. S0 l: S! e6 A/ _
    % E2 d8 _* G3 T  \$ z8 {When to Use Recursion
    7 O) y+ I8 m; u
    0 a7 _. o# @9 u* j. `    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    * F( u1 h+ `  Y- i6 c. l# T& L8 H  N: B
        Problems with a clear base case and recursive case.5 d/ H  a9 k8 h! L& N2 C
    / ]$ |& l% n1 B* ^$ C. i
    Example: Fibonacci Sequence# L- V3 }% P: E0 B7 U- L
      }0 h& d# ?. p5 O$ k- e5 O
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:6 A" h3 D! m& i0 X, j( c, M) T

    $ y5 W* L/ x9 ~; ]3 v5 j. B# r& z% i    Base case: fib(0) = 0, fib(1) = 1
    $ t: g$ V8 p3 N5 a5 `! O& l- Q# X; V7 G; B
        Recursive case: fib(n) = fib(n-1) + fib(n-2)$ q8 u% L) u" |* u: v$ X. C

    . u  s/ ^/ P2 spython
    8 _6 h$ J1 @1 T0 {# G8 `5 h; [3 k8 @6 Y6 m; w" R

    : E) [6 Y- X9 y/ L  p: F. O5 Gdef fibonacci(n):1 Q2 ^/ i+ N- v2 w! N' i
        # Base cases
    9 I; O( a8 C3 M6 m6 d6 m    if n == 0:
    ' S( U$ Z* ]$ z        return 0
    4 F9 v$ K$ a+ o' w/ D4 r    elif n == 1:
    ! i2 y( ?; d/ h: h, Z7 w        return 12 a" Q3 U) Y  v' t& _6 G- Y0 w
        # Recursive case
    : F- p7 Y+ O7 j" _    else:
    / p) p5 _( U( J9 f6 E7 k        return fibonacci(n - 1) + fibonacci(n - 2)
    2 o( e  O) D$ b2 g2 ^% J- ]+ \+ r  S6 B/ ^
    # Example usage
    & ?% H$ E' m& ~( Cprint(fibonacci(6))  # Output: 8
    ! @1 ^" w; p& s+ O4 W4 r
    " x- I$ J( I5 k! vTail Recursion8 H) G: d" }# H0 ~9 q4 o
    2 G: T% }: V8 \! I: j! z) H2 S+ T
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).# ?4 U! q( e6 n3 f+ y

    5 }' _. ~: B9 O& ^2 }In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-4-14 00:25 , Processed in 0.062579 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表