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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ' U- y' o- m8 t9 n2 B: z
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    解释的不错- |" _& |- V- @7 o& u: x
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。3 _: F) X/ X" d  v. f  A, e

    6 q3 M+ B1 F& X5 E% _  Y; a- @! A 关键要素
    7 o7 t' h- ?" K) Q1. **基线条件(Base Case)**8 O0 k- K& ]. @/ w" m
       - 递归终止的条件,防止无限循环
    + K0 L4 N7 k- O/ j9 V: l   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 17 J, K+ A$ H; `& b3 q, D; {

      [4 [- h- p: D% ?9 d; p2 g4 _4 j: K2. **递归条件(Recursive Case)**( w1 F( L4 C6 {' _+ Z# D. _/ l" s
       - 将原问题分解为更小的子问题4 P6 l* {2 F& N6 U' J2 x, X
       - 例如:n! = n × (n-1)!
    ' Y/ j, `) t0 l# z! F( g; f4 G1 ^: w4 r& Q3 w& d
    经典示例:计算阶乘7 L, m4 ]3 y4 e3 r7 q
    python2 t$ z7 B. t: W0 [
    def factorial(n):
    & Q9 A. V) r9 H    if n == 0:        # 基线条件7 w' _0 _' @: X  b. Q
            return 1
    5 q& H- ?5 z3 j, g  o( P( F( ?6 a    else:             # 递归条件
    * q/ P& V( R# B* P- M! L        return n * factorial(n-1)% c1 _6 d3 z2 O
    执行过程(以计算 3! 为例):
    3 L! g, c% Z1 s! [/ T2 jfactorial(3)
    0 q) J/ a% k7 `3 v" F4 [: X  ]3 * factorial(2)
    7 I. o( v1 N( c: L3 * (2 * factorial(1))
      I  g$ H% K, F& q  f% N# s3 * (2 * (1 * factorial(0)))* e5 f& c5 h: K* O( R4 u9 P$ [
    3 * (2 * (1 * 1)) = 6
    3 x  [4 s7 m+ Y2 i0 s0 V, \; Q; {+ C# r% V, t2 Y# b: G* O
    递归思维要点: F! g- h* x1 r, i' M' Y
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑4 @" a6 I& q+ V0 d
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    2 G8 @0 W9 ~' I! V4 z3. **递推过程**:不断向下分解问题(递)
    1 R/ d! T/ M; f7 p3 A4. **回溯过程**:组合子问题结果返回(归)+ k0 A+ X5 I# i$ G$ T& o# }

    + v$ _; y* \6 v6 {3 X2 Y 注意事项5 _% \5 ?1 Z: Y% P4 l
    必须要有终止条件) v5 ?0 n  ~- s$ ]" Q& ?  E! |5 l/ u
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    4 V  A: u& i4 W/ s% E某些问题用递归更直观(如树遍历),但效率可能不如迭代) P3 p+ a6 h5 C, r( r
    尾递归优化可以提升效率(但Python不支持), A/ A4 E( p; R1 {) t
    $ e8 m7 |# A3 {0 c0 B# h8 n5 Z7 e
    递归 vs 迭代# ]. |4 b, n) I+ a& G
    |          | 递归                          | 迭代               |6 [' i2 M4 g8 ?0 W
    |----------|-----------------------------|------------------|
    0 F7 [# @9 n8 |: P' r+ a| 实现方式    | 函数自调用                        | 循环结构            |. M& ]: H; _) ]# W! }% [
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ; f- ~" {+ C7 `1 K$ w5 Y/ K' H| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |7 h$ R2 m' ?0 e6 Z  c
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |' \3 B& z  R6 Z" ^# K/ z* w
    % j! i/ @$ H4 v) F
    经典递归应用场景
    7 x' Q+ {2 X5 n: }8 X; p- F1 q1 W1. 文件系统遍历(目录树结构)% B( O4 ^3 x( S# @
    2. 快速排序/归并排序算法" f: J" _- y3 a) C  k( H7 O3 Q5 n3 t
    3. 汉诺塔问题
    4 v8 r4 I, U1 p4 r7 E( ]4. 二叉树遍历(前序/中序/后序)/ X' g, m' O  J$ T5 _2 }  V2 g0 g4 S
    5. 生成所有可能的组合(回溯算法)% R) G3 |3 {2 [: q/ e8 Y  E+ Y
    $ r: u) A; l' ^# P- c( u. m* i
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,0 a. R& Q* p3 k* q; y6 p5 I! H; U
    我推理机的核心算法应该是二叉树遍历的变种。
    $ x* T+ v" W9 R4 \# ?* D3 g& t  j另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:- R9 u. _( C8 C9 x) _* _
    Key Idea of Recursion/ O6 @3 a3 C' h$ Y0 g0 ~/ z
    5 s. d9 i5 b! V2 ^% e) V/ ]
    A recursive function solves a problem by:+ K$ f4 a' g& \6 b/ r) J  ]

    5 `, l8 f3 P7 W. i    Breaking the problem into smaller instances of the same problem.
    4 V4 s) v8 C- o- L0 ^( f# E6 o2 b+ r0 z1 Z
        Solving the smallest instance directly (base case).# L; t3 ^4 g$ z, @- b* U

    7 z) q4 C3 \+ _  K7 a6 J) M    Combining the results of smaller instances to solve the larger problem.
    & |8 `2 b9 n! o, Q  u" ^& H
    / z5 Y0 A8 [; Q' @8 u& w1 lComponents of a Recursive Function& Y7 e, ]: Q* t' }" E& c. G

    ; J  m+ ~  V! U" F. L    Base Case:' y- f4 }# Q6 D( G6 S/ l3 [
    ( H" s* S' q3 L8 T, g9 B- d, E- J
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.5 W* U# [1 b, x& L* f
      o3 q9 l6 D& O& t1 J
            It acts as the stopping condition to prevent infinite recursion.( ~2 M  i# ~! H

    5 c: H: }  E/ l9 z& |% h        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.- p; q. u0 f( o' D0 i
    8 C1 o  Q4 T8 l
        Recursive Case:3 G+ B9 L7 i1 V7 M$ M( J
    ; B: R, v5 x- t2 o% l" r
            This is where the function calls itself with a smaller or simpler version of the problem.' m0 `" C. ?% h  Z
    ! R; r6 Z9 W9 `7 F$ H3 i7 {
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    9 `2 P1 L) i0 q/ B, I( n# c; l8 e2 Z
    Example: Factorial Calculation# A& p9 X8 O5 e$ m+ |! ?& _# [! o
    / i/ x! H! h  X
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    1 h0 F/ _3 j7 c( U- z. J% C" P8 T9 {7 V- l
        Base case: 0! = 1. u3 ~- W) j; o0 |4 U* |
    3 @0 q2 P  {, N# L5 S
        Recursive case: n! = n * (n-1)!
    2 }$ [9 d& \; C( Y8 ]1 s. N# ]- {5 f& `  P3 O
    Here’s how it looks in code (Python):  J* q8 z0 a* R5 F
    python! v! [0 w/ i0 Y$ |; u" d7 h- T& Q/ p

    $ l7 S3 L- D6 L+ O" a3 S  c0 q/ c$ A* s8 I) h
    def factorial(n):0 p- O5 r' m! J2 m, ~5 T
        # Base case
    # ^& r2 |8 w! U% a# K' ^    if n == 0:
    ! F# D7 q6 T2 J- M+ e+ W7 x        return 1
    5 {. O% |0 e: i  K7 v3 P: y( s2 w8 J1 x    # Recursive case
    7 f( P' E; d/ U2 z* }8 A0 t    else:( n0 G& P4 `! m+ p
            return n * factorial(n - 1)# S3 R9 \5 X* A$ Y( t# u' B
    & v$ p5 Z# H. A  [
    # Example usage
    : e/ C% O# F  E7 C2 P1 Fprint(factorial(5))  # Output: 120+ K# q" L9 L+ v/ A8 P+ A! {
    , c# b; |0 h8 S7 _
    How Recursion Works* N  `: I$ U, Z% Y6 E
    8 |8 r- x$ w, M7 M
        The function keeps calling itself with smaller inputs until it reaches the base case.
    7 u2 d; i0 S8 R4 B
    / N  y  e2 R. `: S    Once the base case is reached, the function starts returning values back up the call stack.- u3 H& d3 p0 Y9 x+ l; Q1 e
    / B: ]1 Z, P$ Z0 r& o
        These returned values are combined to produce the final result.4 z+ e, R9 y. Z! ~4 h! K% ]
    7 c/ D; g5 E. d( p; v* o2 w5 C
    For factorial(5):( v) m; p; o# X9 \3 a  I

    ; x9 u! k; Q+ I- \- a
    ; g2 c, a, d+ O  w" ]% _( kfactorial(5) = 5 * factorial(4)! F3 T. s; G# m; Q, s' E
    factorial(4) = 4 * factorial(3)
    ( z) [/ I- F. tfactorial(3) = 3 * factorial(2)
    6 r. U& p% h- ?. D. ^factorial(2) = 2 * factorial(1)
    5 h, P# o! H% V" Q$ Sfactorial(1) = 1 * factorial(0)
    0 V7 ?) p' k+ m2 _factorial(0) = 1  # Base case- E1 A2 ^; }3 ^( G1 H* p9 x7 W

    4 r! |5 Z- _% n# j) n: ?2 Z; \Then, the results are combined:  W% ^5 ]% h; h  L3 L

    ' p8 b6 O4 L9 c* R; R' W, a$ _' d* }. \0 K7 w6 T7 ~8 ^( C
    factorial(1) = 1 * 1 = 13 e. J* u" M3 X7 v
    factorial(2) = 2 * 1 = 2# @* u* F+ k. g: [) [
    factorial(3) = 3 * 2 = 6
    . ^0 l1 X# W- p2 Afactorial(4) = 4 * 6 = 24
    3 Z( N  y) \. d8 [5 w1 hfactorial(5) = 5 * 24 = 120& h  T# t5 _2 o% j! d

    - T, R" w: k! K' F' cAdvantages of Recursion& x$ Q, ?% X( B. E
    ) Z: t# a! G$ I3 c2 \" r
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).- ^4 C# g. x8 f
    : C+ C( q: P+ F- u$ J0 ^7 I
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    - P& _: e  O5 O9 F7 q/ u' f6 M" z% L* x- S  i" C, O; H' K+ s
    Disadvantages of Recursion
    ; }% P' T8 r4 Q/ ?7 s8 T0 g; r- E& `5 ^1 k2 H1 z1 j
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.( \9 S7 }  Q  R4 ~' w& Z) ^
    1 K2 u/ [1 y; R0 T1 }3 M
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).& |# K- E: v5 ]; _

    9 M4 @' X9 |- c+ [. L+ C3 fWhen to Use Recursion3 k) k; ?+ z. y
    & {; F" Z: A! A. o
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    4 o6 x! n8 c. D8 \
    8 k  c: e) a. ]% l# N# |  K2 e    Problems with a clear base case and recursive case.+ ^4 o2 x0 s9 G

    8 k* E; R! c: F7 {/ k9 K! O+ B1 MExample: Fibonacci Sequence
    # F* I$ s* o4 q4 X3 j2 |0 b" ]8 w. u9 s4 N) C4 e2 A
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    $ @6 V/ R% n$ w* l5 g8 L6 R" q) ]2 b! q7 ^$ _/ ~
        Base case: fib(0) = 0, fib(1) = 1
    8 M0 Y( d* |3 k  d% l' {7 m
    / j. y, _( {, z- B$ V    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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    1 v. R6 r+ M. w3 o1 D. L& ^python; F% g0 u& c! `9 X1 k" f- i

    * a8 k5 S4 l1 y7 a! F0 X4 c$ v# V. r5 g& f- q: F0 M( e& g
    def fibonacci(n):& m# s$ P0 K2 A5 S# }) ]: P" n# C
        # Base cases
    0 L# B2 A" ~5 W8 c* H8 u    if n == 0:
    : {* L' d6 f# r4 m        return 0
    : A5 G& w* I# s- C# t* b    elif n == 1:/ Y, W" s0 g# N1 K/ x. {) ~7 I
            return 1
    ) N: T6 d* g8 k( Y. r& M, l0 C    # Recursive case) Z0 [/ ]$ w, M
        else:6 F* I' Y6 j5 x
            return fibonacci(n - 1) + fibonacci(n - 2)! ]3 A$ F6 w# K( E- j3 K9 d
    3 I9 \# K6 ?; g0 k8 w
    # Example usage1 j! t7 x+ I! f+ a
    print(fibonacci(6))  # Output: 8
    ) ^* D1 \: @' h7 ]% G) T, q* J; L) d3 [% c3 u
    Tail Recursion
    8 `2 m, \# A6 C0 O: e6 E  e& o+ `2 _
    6 t: i: y" n7 k$ BTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    . \. B+ ^/ h( ^  X( J  T% J" A  s5 u7 z; B2 p  D
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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