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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
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    # s% W$ b$ T3 e& M/ E( H' w0 R4 Z解释的不错
    6 {4 t; m6 B. C1 c- l1 ]1 ]3 u( O0 ^7 Q! A
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    - `- G0 f: x: d# p# n0 W 关键要素
    " @* ]1 \! |3 O# v5 h1. **基线条件(Base Case)**
    # ^7 D7 ]2 ]1 H4 K2 {% P" I$ m   - 递归终止的条件,防止无限循环& Q( v( s# f+ w5 `8 }* X" k
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1: N: ^! R2 Z# M% u# C

    " ]. l9 |" `0 B2. **递归条件(Recursive Case)**
    , Z; n3 k% k+ \- U0 @: L* y  ^: G   - 将原问题分解为更小的子问题
    3 E5 p0 g+ @8 E* }  n   - 例如:n! = n × (n-1)!
    1 n/ X3 p: Q* |" K5 d- @$ \8 h: u- @
    经典示例:计算阶乘6 V8 t( l7 T5 M. y) b4 C' Y# L
    python1 b( e5 P. [. c5 Q2 F, m; `; w
    def factorial(n):# Y2 P2 L* v7 `' K
        if n == 0:        # 基线条件
    $ D& L+ f% d, r! _+ p        return 1/ @! |! n$ _; {0 Y
        else:             # 递归条件
    & v# J8 e( e+ O0 h% U9 S' t) c' i        return n * factorial(n-1)5 {9 l0 W8 w( A* S: o; N3 d3 j
    执行过程(以计算 3! 为例):
    7 i0 |! y/ d- [" u* Bfactorial(3)3 T; q1 ?5 ?+ E5 L; Z
    3 * factorial(2)
    # H3 H3 @" m1 u# X. C, C6 @+ W3 * (2 * factorial(1))
    # `7 C' W( t# r: s) `: e2 r3 * (2 * (1 * factorial(0)))% M  S: T0 i/ c0 B
    3 * (2 * (1 * 1)) = 6
    ; x8 p  l7 g, b; z; I( s
    ! @  N+ ]8 J) T$ ^9 _+ S 递归思维要点
    9 W) K  V9 I9 P! e1 E1. **信任递归**:假设子问题已经解决,专注当前层逻辑" g& v0 ~# I6 G  b4 @
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)4 n8 v0 G0 E/ @' B3 t$ j* u
    3. **递推过程**:不断向下分解问题(递)
    * k$ U" J- ^' O1 T( m7 G6 D- S4. **回溯过程**:组合子问题结果返回(归)5 i) s' n2 E7 L$ b" i4 M& B

    $ o, d8 b# |  }" L 注意事项
    - f9 Z: l: i" Q必须要有终止条件3 L& V; J3 Y; o6 w5 a; D% Z+ }% e7 a+ @
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)% m1 `4 \$ O% D
    某些问题用递归更直观(如树遍历),但效率可能不如迭代/ C' D( ?/ L! L
    尾递归优化可以提升效率(但Python不支持): ~2 i* Y3 q7 |0 D( X9 v
    % M% N9 G% G$ q$ K
    递归 vs 迭代- v' L/ a+ H+ b- ?. R8 b6 P. E7 X
    |          | 递归                          | 迭代               |6 g$ O9 a. ~0 p  d& P
    |----------|-----------------------------|------------------|  E! P& \1 N+ p' S/ v
    | 实现方式    | 函数自调用                        | 循环结构            |0 v& u, p6 p) p& H3 Z9 o
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    # |, p+ y+ }3 R) v" r| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |$ g+ o; z+ @- Y& m
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |( W9 B; Y5 u4 W' e0 _4 R+ k
    2 I  l7 `9 a, ^9 r) ?0 H
    经典递归应用场景% h, q+ e+ [! ~8 W; @; V4 a" k
    1. 文件系统遍历(目录树结构)
    6 D' j/ D1 |1 z% f, d, `2. 快速排序/归并排序算法
    + L; ]) k: g" ^, f3 k3. 汉诺塔问题
    + J. L% p. A9 V0 K  `3 w4. 二叉树遍历(前序/中序/后序)1 {/ |& w' e1 ~' Z; T6 y
    5. 生成所有可能的组合(回溯算法)
    3 N& T: m9 D4 M* S0 f
    / C4 _! _3 Z) D( v8 H% O: N& W) a试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    4 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    : n* V* ?# Y4 Y9 }: Y3 W% Q4 \我推理机的核心算法应该是二叉树遍历的变种。
    ; ?" |9 T1 u! p- e: H2 _另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    7 n9 O! S3 a) |4 _! u# I1 u0 U3 bKey Idea of Recursion  X9 K$ H( Z% Y  t$ S/ ]) B

    2 T0 |8 V4 ~0 g0 x" X7 [# VA recursive function solves a problem by:) c, l5 S: R& t# D" l

    6 \' j( G7 s5 |9 T! R3 W) t3 E    Breaking the problem into smaller instances of the same problem.6 L9 F; e; @# _, L
    6 K; g7 K/ X- q' u1 m
        Solving the smallest instance directly (base case).7 s) q( W0 n* Y0 S, W) }

    . o6 y4 ~" p8 n    Combining the results of smaller instances to solve the larger problem.! L& K. l. R( I* P4 D; H3 M

    0 u- o& ^  e' S2 J' EComponents of a Recursive Function6 ~4 {& f! A1 m( u
    & @1 x- K2 {! v
        Base Case:
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.( Q7 N, T0 l; J" g" U

    5 m& ^# G$ l6 \        It acts as the stopping condition to prevent infinite recursion.9 N3 z7 _" {# v1 N- C# N2 C

    ) {$ I6 u: |. P        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    ; `7 ]( ], H- j8 L, n
    ! i8 M6 L' F6 K* B; f' Q    Recursive Case:. i$ s, X8 J0 I9 K

    + w$ ]3 R: A; a/ a% {! i. R        This is where the function calls itself with a smaller or simpler version of the problem.' S" P3 D# `2 f. t1 X; _
    1 d6 h. b/ ^. m2 l' \; b
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    6 w# q& ]$ M  g. C1 uExample: Factorial Calculation
    $ }1 X6 ]+ _5 R4 u' g8 }
    ( @0 e* N+ ?, c& Z( LThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    3 \; k' r! J# |& U; Q! b
    4 U0 B% |5 ^/ [  f    Base case: 0! = 1: D' W9 H; O% @7 J4 J" {
    5 p7 C# k! m4 a, {3 k
        Recursive case: n! = n * (n-1)!: J$ J# ]) E- i1 u
    ! }% Q$ t5 ?) b8 U  a" J2 B* J
    Here’s how it looks in code (Python):6 ~/ W1 K2 D9 G1 T# A0 [
    python' s9 Q$ D" q" q, j, U

    2 s( ?; u2 Q5 ^: b; @2 l- p/ a9 G: ^8 I+ L3 o1 t8 \
    def factorial(n):
    ! r2 [6 a- {8 A# D% {; |    # Base case
    5 `7 S. z" r$ e5 {    if n == 0:& a  O: Y! O  x. L
            return 1
    % F; ~3 m/ K4 Y- I    # Recursive case
    + d8 G, j4 _9 F! c+ I# l    else:
    # j6 d  z, G, }( l( K, i8 ~* v; u        return n * factorial(n - 1)
    1 o" B" h! T; `1 F% [! f2 G9 P2 K: s/ ]" N! t* N
    # Example usage* B' Y0 o; f( ^( G' k5 x
    print(factorial(5))  # Output: 120
    & o( F' [# n7 C2 r) @$ C
    + P9 c, H4 e- g: t7 L) KHow Recursion Works
    % \( I, T, K; z& j
    7 ?7 q* v, |2 S) [4 t5 E- i    The function keeps calling itself with smaller inputs until it reaches the base case.) `: M+ U7 t/ a' O
    : \. B: n4 }: m$ A
        Once the base case is reached, the function starts returning values back up the call stack.
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    - T+ U" f" {& c/ Y    These returned values are combined to produce the final result.
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    . k$ r0 t8 ~+ [: U# k; x; wFor factorial(5):" P3 O* c/ M( l. q# F+ Z/ E
    - @5 c% {" D" ?) a9 P

    2 H* c4 u8 n4 G% w  n7 v4 Vfactorial(5) = 5 * factorial(4)- Y$ [6 I% W' D. x2 I1 M
    factorial(4) = 4 * factorial(3)6 y/ c% ~/ s- T) q
    factorial(3) = 3 * factorial(2)  [2 X/ T7 v5 h3 N9 ~/ K, n0 ]
    factorial(2) = 2 * factorial(1)
    ; Q/ A- i& b3 mfactorial(1) = 1 * factorial(0)" s" O) |# M5 E" D
    factorial(0) = 1  # Base case3 `: [) J7 o% Z# k
    - \; f% a! ?: I0 d! q% u! ~1 O# J, T
    Then, the results are combined:
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    % R  D. c8 p: X# ^% S- E  ?: A$ ]7 [. U% @" q
    factorial(1) = 1 * 1 = 1
    / A: R& f3 V0 Ufactorial(2) = 2 * 1 = 2* p( O6 O: r/ w* i' Q
    factorial(3) = 3 * 2 = 6
    - b- x& d, Y7 d, b' \# \factorial(4) = 4 * 6 = 24
    0 [- y0 W4 N7 |) Q) tfactorial(5) = 5 * 24 = 1208 ^2 O, i1 q/ J
    / W' ^# T3 I/ ?6 g3 [
    Advantages of Recursion- P7 \3 ]7 S- C: l( |& x9 x
    0 R; u9 j* _5 |1 E; h$ c  A# H
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    & Q% R% x1 |0 ~+ E0 {% Q/ J( Y/ i. Z6 N0 c3 y8 l% ^
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    * J( w( Z0 G( e' I1 H- S3 l
    ( h& m# K1 \, \Disadvantages of Recursion
    3 ?: ~' E; ^% o4 ^6 R/ ~; Y
    , D/ }  r% M; c% b, H. ^0 a( k' w: g    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    2 q1 K- A1 K' E8 Z1 j. {; e# d, t
    # k: s- Q% X8 Y) X3 n    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    6 L- }; R/ m8 I% k3 B* M/ s6 Y9 J3 V4 V  I3 I5 p% i
    When to Use Recursion
    % E' F* B) e2 @5 p& w/ X- n: {/ P  E" M" w, O2 @( h6 b6 I; q1 G0 o
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).* Z  U6 F$ v% z6 K  b+ A. Q
    ( E( n$ A( ^/ [* ^' V1 h7 E4 P
        Problems with a clear base case and recursive case.0 p# ?- ]  H# M2 z/ e
    # H, h. u! M5 n' Q2 ~! ^+ f7 r
    Example: Fibonacci Sequence
    : y4 y7 Y: q; ^& }
    6 g; ^* m9 o7 v/ ]The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:( H5 \" l. H6 {2 k* {3 `
    % R& d- w- p" `1 u1 i
        Base case: fib(0) = 0, fib(1) = 1
    6 U9 v% O- S7 a+ K# {, R: L2 X. Z& J& _, [; R; P
        Recursive case: fib(n) = fib(n-1) + fib(n-2)5 j8 P& ?) d- X8 m1 ]' M

    % o' O4 `$ X/ _, f. ?0 J! @python. i- l, L. |3 ?! D

    $ d# q' x1 y1 \3 P
    4 G7 i: Y/ @! z. I" ndef fibonacci(n):
    2 d! x  r  P6 E9 R$ O+ ~    # Base cases) ~. B7 s4 l! R( Q& _* C8 {6 M& m
        if n == 0:
    6 k. R9 D- u- j3 E% f+ ~% {        return 09 a* T" n* L. U
        elif n == 1:' b, [& `; A1 C
            return 1
    . R/ t8 l2 V" K- y" X8 n3 l& c    # Recursive case- m5 x) ~" \# ^2 R0 \% ?
        else:+ F0 I% x4 I5 m* E
            return fibonacci(n - 1) + fibonacci(n - 2)
    4 ]# n4 b! B; i& r
    % w$ @# H' L) t- s* K# Example usage
    4 c, V% X- Z2 o# U( qprint(fibonacci(6))  # Output: 8
    5 N0 L# T9 s0 }
    0 r/ f* \) V$ o& B0 nTail Recursion# L* R6 `) @2 g5 v+ X0 a
    ( u% q( u8 {- {: t8 Z1 t1 t2 ]2 J
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    6 ?; O9 M3 {/ a& Z; t& Q1 j4 M) c6 O: p
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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