设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 3411|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 6 h7 {+ b3 y4 ^$ F; T  T8 [

    0 w7 \( _9 o' l, a7 C解释的不错% Z1 |9 b/ w2 k( ]0 c/ [1 |
    # @- R6 h0 F" k7 G9 U- [  o" U1 w8 I
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。, x) {2 E2 |9 }3 x- S& C6 U5 o

    2 C7 S' f8 ?& U# P& o- f9 k; S 关键要素
      c( e  p7 G2 m& n6 n: B' W1. **基线条件(Base Case)**' t7 y! m3 T) L! k
       - 递归终止的条件,防止无限循环
    ! q% y( _( ^+ z7 F4 v4 B  z# w# G   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 16 ]- ?; W5 [8 x& v
    . C: S  j9 Z1 W( J0 O' X; M; n: ^
    2. **递归条件(Recursive Case)**
    1 i8 Z% ^  E2 a6 c, e0 b   - 将原问题分解为更小的子问题% u: E: O9 [' ?# q( ]. W3 A
       - 例如:n! = n × (n-1)!
    7 }! M, [$ g+ Y+ f' U$ w
    " J4 U* b+ H) s4 Y& i3 V8 ` 经典示例:计算阶乘
    ( _9 T0 ?" m& b# `) Z8 G) upython0 h. H+ C1 A2 V6 ?; u: e
    def factorial(n):
    # M% y* N; l- ^    if n == 0:        # 基线条件
    5 m8 K9 A  n/ K6 u. y        return 18 N! ~, S8 G1 Y0 V; T5 _  f
        else:             # 递归条件
    + |# ]4 h9 N) r0 s- K        return n * factorial(n-1)
    8 h( ^, s- F% `) E! m# @/ f( n) l执行过程(以计算 3! 为例):
    4 R$ ]% j  ?7 s3 l4 o! bfactorial(3). z5 D! t5 _- k. m
    3 * factorial(2)
    ! F7 t" d! k) a3 * (2 * factorial(1))
    : C, D8 y- E  d# H- u( l3 * (2 * (1 * factorial(0)))# {  g/ Z/ J% l( q! [* L
    3 * (2 * (1 * 1)) = 6( `1 G4 N& R1 p
    ; \6 K& r# V! \% H! u" [
    递归思维要点2 _/ J/ ~8 y( r% m: r7 G3 q/ Q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    5 q) Z# e/ e; W" X! _$ ]6 G2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    , h0 N" S) r6 N6 V8 w& a3. **递推过程**:不断向下分解问题(递)
    $ d" w0 l4 B4 G6 t4 e6 k, N4. **回溯过程**:组合子问题结果返回(归)
    7 H0 C" o6 u7 ~3 j; b& l0 {9 N( q& u. _# E8 V1 s
    注意事项
    ; n4 O! e, Q5 ~/ a$ u% P必须要有终止条件
    ; ]% W  w) ~0 j1 r6 V& J6 H6 W递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    / u9 S3 ^4 f5 P  P3 x5 w9 m( _2 G某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ! f) |) @1 r- C4 ]8 x尾递归优化可以提升效率(但Python不支持)
    ; z- `5 ]" ~! a) s) U& f( ?+ ?. h9 B( b- X: i* F; V( L
    递归 vs 迭代
    8 E* v$ K1 V5 b8 Z|          | 递归                          | 迭代               |
    $ I) v6 S+ M/ `8 F|----------|-----------------------------|------------------|6 f2 }; Z* S1 g& |) ?2 I/ K
    | 实现方式    | 函数自调用                        | 循环结构            |, ?3 S! g, }) P
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |+ J3 Z0 {4 w4 {+ I# a* d9 k
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    8 l- A3 m/ B- k3 f' ?| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |9 ]; D: m3 x$ C- M( e/ _  ^9 V0 H

    ; c" A7 B& w' e: a2 O7 Y' | 经典递归应用场景6 f8 D4 B; m) m1 r$ ~
    1. 文件系统遍历(目录树结构)& O) A2 E5 |2 ~8 y5 ]
    2. 快速排序/归并排序算法7 e( j. ?  u, z/ c3 q0 d+ r
    3. 汉诺塔问题0 p* e  ^) T4 B& S/ X
    4. 二叉树遍历(前序/中序/后序)
    3 k7 U% P% j' v/ e5. 生成所有可能的组合(回溯算法)
    * r2 C9 T; T! i( r$ B9 y4 p$ v( ?- |/ B4 }# p$ N: R4 D  y4 J/ D1 M
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    擦汗
    7 小时前
  • 签到天数: 3371 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,. H4 L% r4 R& X6 P2 x7 ~
    我推理机的核心算法应该是二叉树遍历的变种。
    9 A$ T0 A2 t$ }, s8 Y+ @0 `/ v' T另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    9 o1 j, U/ Z1 M. y  c8 c; RKey Idea of Recursion' W! ?/ Q% q' \" W# [
    : t0 w+ n9 |) I1 r( C
    A recursive function solves a problem by:
    + j( {( U, |3 q: G* g' M: q( J( ?% y
        Breaking the problem into smaller instances of the same problem.- [1 ?7 y, x6 D& X  P6 T

    # Z! s, i- v% i; j/ q6 u+ k! e    Solving the smallest instance directly (base case)./ G& C; N6 F9 E5 |

    4 K5 X' ?  i1 F- z& P    Combining the results of smaller instances to solve the larger problem.3 o) A% t- o  c  ~, W  G1 |* B

    , ]/ u1 |5 z- o9 W. v  `7 s6 ^, I% MComponents of a Recursive Function
    ( G3 U! {# y. x2 s% I4 M! k7 M& E# O8 X, J- d% }
        Base Case:' x1 W1 S/ C! s" e& W* |% S! l

    " b2 E- r7 S1 }# C9 y        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.# s7 Y/ l" C) x( \
    & H; [) t6 N3 }# l6 `
            It acts as the stopping condition to prevent infinite recursion./ |! D+ q8 f! y7 H1 t. Q' M, M

    ( j. E+ J- h% T" \1 j( F        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.9 E6 i  ?4 R" L9 w' l' H
    ' ?, X1 d! ^# E6 \7 I4 \
        Recursive Case:
    5 W. E3 w* B/ {5 Z+ S& o0 S- M
    7 l2 t5 q5 _( \        This is where the function calls itself with a smaller or simpler version of the problem.& k4 [4 l: p$ @. [5 g) N
    0 D6 ], `1 e. J' l/ h; Z# [) E
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    * Z  X* k: Q4 h1 J
    9 P/ R7 k8 F" ]6 S6 R2 i) LExample: Factorial Calculation8 Z/ z# M2 k( {/ q
    / t" q/ g4 ]' U' T+ v
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:# b+ y0 J  P( C/ u( ^

    - U" x) H0 k7 s5 ?& e    Base case: 0! = 1
    3 o4 B$ v6 B6 C; O* W- x2 x7 r' l  B6 W/ I8 e8 y% t5 K/ X6 [
        Recursive case: n! = n * (n-1)!2 p3 x8 ~% H5 ?3 _+ B

    4 R2 n: D0 d6 L- m! G3 i- EHere’s how it looks in code (Python):, z/ R! u+ D6 t) `" w
    python2 c9 B0 J" J" H/ `# L: a. d+ V

    + a4 y7 V* s5 K% x" z  j7 e# m4 T: r% {$ y% l" ~4 \9 D4 u
    def factorial(n):
    . Q* v' }" u' Y6 @    # Base case) J5 ^: A  v2 C
        if n == 0:
    # a% I& w/ e4 l        return 11 e, b) _' B2 Z7 J
        # Recursive case) P2 G8 \- y% G
        else:
    , {7 R: z! M# A$ x  Z$ t        return n * factorial(n - 1)3 G* t' T: M* N
    # x' i& q' i- K
    # Example usage+ H5 z1 t+ z( ~& {( m/ q
    print(factorial(5))  # Output: 120
    ' I4 a: f5 Y5 G) Z0 L  }- ]
    5 ]1 E& L6 ~6 _7 o. h9 z5 |How Recursion Works% B- ^1 k$ Z" @! m

    9 f8 y8 A6 t8 g+ [. O& T4 K    The function keeps calling itself with smaller inputs until it reaches the base case.) L0 D6 J8 q8 H3 _

    9 F# L* e- B3 t3 M* O9 ^) S2 H4 ~5 B1 K    Once the base case is reached, the function starts returning values back up the call stack.
    , T+ s, `4 G" P7 |/ s( u9 d& x. ?0 \* `3 W' E8 j' D6 \. R) n8 t
        These returned values are combined to produce the final result.$ N: y2 W3 u" x8 H* I3 e! `1 k
    . P: L# t4 r. e3 a- Y" Y
    For factorial(5):
    % i! K4 O) X; X
    ( A# x% p/ @" N' z  p3 e
    - }; x5 |, r8 ?. Q# U' w, M( V$ Hfactorial(5) = 5 * factorial(4)
    * K7 L. f7 `: n# w$ F$ Pfactorial(4) = 4 * factorial(3)$ A0 `( O; k2 o0 k- F$ o' A: _
    factorial(3) = 3 * factorial(2)3 _9 s* J1 V" f& E4 U' ~2 P3 E
    factorial(2) = 2 * factorial(1)
    ' |0 J. y  u- R+ c3 U( ]" hfactorial(1) = 1 * factorial(0): G% \  P( Y5 Y# ?- H6 V) {) G
    factorial(0) = 1  # Base case
    - `  k/ r# u0 F+ G% e2 H3 X' ~! d, q) p6 s
    Then, the results are combined:
    , j& K$ J% J- Q8 c6 ]& p2 T0 e- x/ F' A7 y
      |9 G# T) g3 Q% U$ _
    factorial(1) = 1 * 1 = 1
    ) M7 R& t5 ], }: c* p  Qfactorial(2) = 2 * 1 = 2
    - |% H( ~, a1 j( E9 ~3 C6 K& I& zfactorial(3) = 3 * 2 = 6
    5 R* _* g) f: g, ?! v* O) ffactorial(4) = 4 * 6 = 24
    5 B, O- ^- _2 W: Bfactorial(5) = 5 * 24 = 120, H3 B  X0 U' i; E3 o! ~
    9 x! }; r6 N( l
    Advantages of Recursion3 x+ z4 z- r* V& k; K& P

    & x- j( d4 M5 v  h$ ^* i9 Z    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).+ u1 c& c4 K/ B, J3 S

    0 A5 ?" q$ N6 Z( ~! \    Readability: Recursive code can be more readable and concise compared to iterative solutions.0 |4 ~* S. f/ y% g/ s, M* j1 i$ s; d

    2 r9 ^3 @* a2 X( P" T6 ODisadvantages of Recursion
    6 p9 Q5 i# ?0 V6 k* \2 |4 D* Z# e' _% ^% {* A: b; m& B5 L
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.# D3 s  A1 n$ ]$ F1 A

    6 C/ S8 X# B4 ~5 U* e    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    3 \. A6 k5 a7 D- Y
    / [' \3 h# L# c! y. ^When to Use Recursion
    5 [/ t6 H5 l" U7 X4 ^& a8 x  h) |7 @2 g% |) T+ k6 f% a# U: T6 t7 t
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort)." r# c* ]. ^' _7 R5 \3 j- x

      a% }( v. A7 {2 A    Problems with a clear base case and recursive case.
    % {! Z" `, z# E8 g6 s
    1 H$ O7 ]8 v8 x2 L; u+ xExample: Fibonacci Sequence& \5 U3 b* v- T6 `1 i! M

    ) j* ^5 b1 U+ Q$ K, y2 zThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
      ^2 s9 }5 m* M; ?1 Y0 H
    ! l% \$ m  I  \8 b/ S% }    Base case: fib(0) = 0, fib(1) = 1
    + S) I& o; L/ x7 N3 `3 {  X) m5 d: e7 m9 a* ]/ h: P
        Recursive case: fib(n) = fib(n-1) + fib(n-2)0 K! v- Y1 U) X& D! \2 ]9 ?
    + P: B7 n- ]6 N
    python2 `5 b! s7 r% l9 j+ Y) S6 r% C

    : v! B1 y- @' R
    " B/ p* c+ A2 y! ~% z4 V' ]- J1 tdef fibonacci(n):1 n# f" i2 h! @/ i
        # Base cases4 z6 \8 j# j8 h- K! J% Y
        if n == 0:' _; ?: Q: H; h6 Q
            return 0
    % ]+ L/ B0 `- Z5 l& B+ v8 P    elif n == 1:
    6 Y& J; M  u5 i: S        return 1; M5 @% m2 {* a1 f! X! N
        # Recursive case9 ^% y( I9 q5 P) g
        else:8 D$ q" y2 L+ W9 A. m. h
            return fibonacci(n - 1) + fibonacci(n - 2)% M8 z+ E: Y+ T% u* k! g) a

    4 ?% R- }, w4 R" z" c0 q# Example usage( ~4 |* V# l/ \
    print(fibonacci(6))  # Output: 86 r" Z5 l% t' N3 M* U; ~- v# A. Q# W! a
    9 C6 G* _5 @' T5 {, K" r; ^
    Tail Recursion0 p3 _7 ]8 ]1 g

    / E$ v5 z& E* O- s& N# |Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).4 v4 S4 Q4 Q9 L/ ~

    $ P. c6 o/ m" O& E% {" YIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-10-6 14:27 , Processed in 0.064387 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表