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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    ) w$ ^5 z+ ~6 _5 C' D
    7 k& M5 z, O' F6 s( h" o解释的不错9 q5 X$ Z" j4 A

    : ~% f, R# X7 S6 V0 n/ A2 i. c' {递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    9 i( u: b& J& J9 D3 n) q% o) \* w2 j
    关键要素
    ' h% N+ p# K2 D) I1 `1. **基线条件(Base Case)**
    1 D1 A: F: E" `0 ^   - 递归终止的条件,防止无限循环
    & `+ l( u! |" ]   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1( h* }9 N. g; T; J
    4 v; `# f! e# F
    2. **递归条件(Recursive Case)**
    0 o2 H+ `+ }; Q. n8 X   - 将原问题分解为更小的子问题3 G( v. j, @( a7 d, ?
       - 例如:n! = n × (n-1)!: T6 N; [, E$ ^2 E; \
    / \; ^4 h  M2 O/ B% Z9 w
    经典示例:计算阶乘
    % ?' i* j( p4 f) _python
    4 a1 C1 B# U# N. gdef factorial(n):
    5 H( d- `# Y  R; V/ U    if n == 0:        # 基线条件$ C' E0 X! s3 a% k3 |
            return 1
    2 L6 s3 T0 o1 r  k7 y& h    else:             # 递归条件7 D! P6 y9 [+ F. \% [+ F
            return n * factorial(n-1)7 e! N0 t' K- B4 k% ~
    执行过程(以计算 3! 为例):
    - `4 A# `; i5 V8 g$ h* C9 N% B1 Efactorial(3)
    2 K$ a9 E9 K$ o3 * factorial(2)* t( B3 z, [" M# w+ a) {
    3 * (2 * factorial(1))
    ! \4 H+ I' g! Y3 @4 K. Y- @3 * (2 * (1 * factorial(0)))! P+ W6 X- m0 q. |6 F2 ^0 q' u
    3 * (2 * (1 * 1)) = 6
    . h) m2 l$ }6 Z! T' t! t# p9 F2 W% `3 A( S
    递归思维要点. d- d0 j4 t2 \% b, `
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    ! [% u9 e% S& N4 A& y: @2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    3 _" |% Q' Q7 z/ t' `3. **递推过程**:不断向下分解问题(递)
    ! O0 I1 g4 C! X7 {4. **回溯过程**:组合子问题结果返回(归)5 K- p$ ~$ K1 i1 |

    ! l: G! t+ O0 ?) C' ] 注意事项
    ' J6 D8 U8 S# ~必须要有终止条件- M* ^( o, x! V9 a, I! T% k/ N  r
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)! J: R: h1 N, `* g4 Z! p6 t
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
      c" ?: I+ E# _1 D尾递归优化可以提升效率(但Python不支持)% U8 _- @$ F6 A0 g

    6 P4 {' q3 _$ t" E6 @4 i$ j, u 递归 vs 迭代- D: L' b9 a( e  ~
    |          | 递归                          | 迭代               |/ L* c% w! [9 j9 I
    |----------|-----------------------------|------------------|3 S/ E+ {/ \$ w5 X# y  U
    | 实现方式    | 函数自调用                        | 循环结构            |/ [& C& ^  g" f: t0 a7 d& c' o
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |3 c$ ~: h/ t+ I0 y
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |) {' w4 T9 C# E& V% s$ T
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    4 q$ `, ~7 z- l# K0 F' p* C4 _) y9 t# K! i! v$ G8 X
    经典递归应用场景
    " }0 A: n0 j; ]$ n8 I8 ~$ F; c1. 文件系统遍历(目录树结构)3 A, D/ m' Y. J
    2. 快速排序/归并排序算法
    0 a0 W# I' O+ f. ~- ~$ v3. 汉诺塔问题2 h2 ?- n8 _: f/ L$ F, r3 O3 v
    4. 二叉树遍历(前序/中序/后序)
    ( M) A4 h, N; M4 T0 V5. 生成所有可能的组合(回溯算法)) F& d& R; A7 C+ H
    4 f* Y8 R$ U9 @, d9 d5 s' u5 B  l: R
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    3 天前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    % q4 t& p; I% R7 |' o, W我推理机的核心算法应该是二叉树遍历的变种。
    % \# P; V  s7 A1 Q另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:& ^) H* G' T$ C1 K: Y
    Key Idea of Recursion
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    1 \5 Q6 w: |  ]) vA recursive function solves a problem by:: l$ ?- |* y& l( w+ e! I& N

    / B! ]8 j- g: g- d4 ?% s+ G    Breaking the problem into smaller instances of the same problem.
    4 j, X; b6 f0 R$ s
    9 Z. _' A+ M+ Q    Solving the smallest instance directly (base case).
    2 c2 y% t+ d  C( H  n9 n
    . v2 M' P( E7 {4 N! R    Combining the results of smaller instances to solve the larger problem.# B: m( Y8 \" R: F
    3 A3 W; b  I. t/ t  ?, j
    Components of a Recursive Function
    6 _! N' D: e! A- y; D2 x& k: S( @& O! A5 [- `2 a2 Y  @
        Base Case:( m  ^% Q/ ?8 L1 x0 j" X
    : z  O+ w2 O8 v5 J4 d
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    ' h( j5 v& c, V3 \. W+ D7 T
    ; t" z9 u0 v5 p* |- D! v        It acts as the stopping condition to prevent infinite recursion.  n! e0 I/ n. `& a

    / L- l9 y/ B" s; n9 {: A- j        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.4 G+ r+ Y( k& o. K$ R1 d& l
    # s) d7 ]; f% }+ B# b
        Recursive Case:
    ! r/ X/ x' [3 \3 C2 W
    1 Q, e' S, p) T0 r        This is where the function calls itself with a smaller or simpler version of the problem.
    & @4 `5 Z( J. I: g* t" z/ t6 z& m" V/ _; j7 B- g; ]1 A  K. t$ @$ M6 Q
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    " A1 ^; k5 m5 p8 s% N
    ; ?  o' h0 n$ Q" {8 T) XExample: Factorial Calculation
    " l+ P& t5 b+ T" G; N( W) K2 p4 i# K1 A, b2 K, s8 W4 b! C
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:8 Y3 N- Z- \* E# s
    - D* l" j) d: I$ L$ B/ M
        Base case: 0! = 1
    1 W0 E' J* x$ a2 Q! Q# a- E: V9 B% H2 J9 C% |) Q
        Recursive case: n! = n * (n-1)!+ O& T- y; E+ n% l+ ~7 {4 n
    7 T' B* D  A2 @, v5 N* k3 A
    Here’s how it looks in code (Python):
    & A% U4 P7 `$ W1 [python) q  b7 C% @0 H, _* r
    7 c, N+ C8 H% O( I/ a

    ! Y# j' x5 h/ g- Qdef factorial(n):
    0 ~8 x" B. {! v, O    # Base case! U% K6 J( S+ _% \
        if n == 0:/ v% C: t- Y+ U+ J  U0 b
            return 10 o8 J% K9 K- Q  Q) X
        # Recursive case
    ' g: U( E$ f' _    else:
    + r% k  K; }6 ?1 ^$ O; O9 {        return n * factorial(n - 1)% ~+ H: ^% }: a  s& T7 A* N- S
    8 |. u- w6 S; r
    # Example usage& N+ ?) F% I4 c. c' i
    print(factorial(5))  # Output: 120
    1 t* _! W: F1 _! _! W4 W3 \: A( R, D4 t/ r, o
    How Recursion Works
    7 t3 J# Y" T- S( A% G2 t- S" b, t, u4 [' s+ p) n8 G. E
        The function keeps calling itself with smaller inputs until it reaches the base case.8 b9 \- Q. H' N8 a
    % c0 F4 c+ p" g$ z+ W
        Once the base case is reached, the function starts returning values back up the call stack.
    8 V8 g/ E- m  w! H# c
    2 `- X5 n( J! j" M    These returned values are combined to produce the final result.
    " f+ Z4 r- ?8 {  l" Z5 k4 A  m$ J' Z; O2 N
    For factorial(5):
    2 D1 W$ N- f) d6 u0 [5 Q" l1 ~( a0 Z) x; K
    8 N  h# [( U! y$ y
    factorial(5) = 5 * factorial(4)3 A! @' z  F% d1 W- P6 `
    factorial(4) = 4 * factorial(3)* N+ B. p7 V8 \: H
    factorial(3) = 3 * factorial(2)
    ' f5 d- ?0 m. n, W; xfactorial(2) = 2 * factorial(1)
      ^9 d  R- F; ?. a/ M: h$ nfactorial(1) = 1 * factorial(0)% @9 g- E7 ]3 D! ~
    factorial(0) = 1  # Base case: _2 K0 ~+ i) D+ M! R) Z
    ' h2 D3 ~  m+ \+ u
    Then, the results are combined:) E2 U* Q; k+ @' C# {

    : c6 A6 ^6 U0 a' F/ ~8 @: a  E# \% l4 M& K9 t/ y" p
    factorial(1) = 1 * 1 = 1
    4 B% o4 r% K: d$ nfactorial(2) = 2 * 1 = 28 L' V0 b/ F$ t0 E7 X. M
    factorial(3) = 3 * 2 = 6
    3 d, j( y3 P! _factorial(4) = 4 * 6 = 24
    2 W. V5 i: T0 ?  y+ afactorial(5) = 5 * 24 = 120" u0 n, P! e& {

    " D1 H4 v( F' C. o8 j; XAdvantages of Recursion, D; h) R% j3 Y
    # X; f- A! y% E6 i+ g5 P# ~
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).! s2 l4 Q5 ~" y$ L5 R

    1 E! W4 _/ l; y: W- ?% L7 N: O    Readability: Recursive code can be more readable and concise compared to iterative solutions.: d* S( l% A1 M" I/ Y$ `

    . ~0 F0 v! ~9 S& l- SDisadvantages of Recursion3 x/ M# O/ P& X. E
    & l, O2 s8 V+ \+ z( R( r$ \
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.9 i. ~; u, P: x
    & @0 D, R2 v+ `1 ]  G) i7 Q- s4 `
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).# P7 Q: h, P* \
    2 y% f8 A7 D) ?
    When to Use Recursion9 y6 }. f+ s0 y* h5 W/ L- e- |

    7 Y: s8 o* A3 e5 \    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    & j% H# {0 S. R  B( i; P* Q/ P$ h  ~2 ^7 r
        Problems with a clear base case and recursive case.% `) I6 s4 G0 c4 g

    " E$ ^2 E' o: c% x: U# h# XExample: Fibonacci Sequence
    ) [0 d, f) H: r$ i" a9 d4 X) H5 c6 }- N  G' o; e; m
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:5 N$ h# B2 ?# _: n& D7 f, V7 _+ Q- y9 T

    0 G1 c) g+ L# s" M. w    Base case: fib(0) = 0, fib(1) = 1. ~5 Z  I% w1 M9 R6 P. y4 b

    $ g( @- B( n% d$ M0 u    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    1 d8 r* y  }8 ]$ F8 }; d6 g
    1 z& @& Z- l- T/ d3 fpython
    4 w) x+ e5 h/ _4 o) K
    & r( o" n' a3 g" w& W
    / V; s9 [/ ^, Hdef fibonacci(n):
    7 D3 [  f- s5 A# @  z    # Base cases
    0 _6 |" J, X+ z" S; E; k! g. |    if n == 0:% m3 j* s+ q, ~# [  P% B+ |
            return 0
    5 L7 [, H* Q/ S& F& Q$ C; h/ {6 x    elif n == 1:3 W" B5 ?+ J9 R( Y0 y: ^! U
            return 1  d# i7 H$ V( M' w" B" D
        # Recursive case, L' }" G8 w! y. A* q6 ?
        else:
    + _2 v, D2 }: c3 Y        return fibonacci(n - 1) + fibonacci(n - 2)
    ( H: p6 R) e7 v2 {& J% `6 j1 v( i
    0 c6 _5 S% U2 C# l$ G6 p6 J# Example usage# u2 c6 i. F2 m7 @9 a. L; Y& ^
    print(fibonacci(6))  # Output: 8
    & G0 c2 p9 T2 y5 ~
    7 s0 [/ \# K( F* P6 qTail Recursion
    6 N" }& G  Z1 f+ K' L: |; X6 H# h7 n, f3 J; \
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    3 V, K8 l6 q8 m0 v/ s. ]& Y+ `2 m, n( X1 {7 B
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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