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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 3 S1 N# P% y, i8 K

    % S$ _1 W6 o+ ^% {; {解释的不错6 `7 J: I+ h- i/ t: q

    7 \, b7 x. m, Q. F- U* @; Y, h递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    0 N/ C$ [# k" S  T5 i' O& G 关键要素2 A. e+ Q  r/ h, \
    1. **基线条件(Base Case)**) _# Q; F1 [$ W5 d
       - 递归终止的条件,防止无限循环7 K% J9 j( i) b' r& e+ B
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    : U% m& l' M7 g0 M1 r2 w. r9 p5 h1 V
    2. **递归条件(Recursive Case)**
    8 b& l- f" c; w0 ^$ R5 ~( v8 ]   - 将原问题分解为更小的子问题9 O7 W: ^# E- I
       - 例如:n! = n × (n-1)!
    ) m/ t" Y8 b' b- S
    % u) P  A4 ^  F 经典示例:计算阶乘
    3 R5 Y8 }) F- t; K# F) N& ~: ]6 Epython0 {+ |+ N* K) L  |0 D
    def factorial(n):
    % @6 |# {" Z% u! K0 u% }4 _8 \, o- ?    if n == 0:        # 基线条件
    & f* h: m( }2 Q/ k7 ?        return 1
    4 W/ n/ y+ i3 R) O    else:             # 递归条件
    % e7 O6 ^8 K% s- n# b) h% D( F        return n * factorial(n-1): l6 R2 u/ K  ]) u" _1 R. Z+ Q! V
    执行过程(以计算 3! 为例):6 }! I1 R# U1 }7 v0 [8 r
    factorial(3)* n& J# g* W+ y
    3 * factorial(2)% `" j: \9 l0 y' Y/ i
    3 * (2 * factorial(1))
    4 f% q) b- s. b! m( _7 }3 * (2 * (1 * factorial(0)))( b1 q+ r0 J: c; l
    3 * (2 * (1 * 1)) = 6
    8 y$ T# a! s1 \5 q7 I' {. |! z1 W9 x) d; L
    递归思维要点0 k" R- b% W8 `/ A0 {. k
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    2 }/ H2 ], w8 D2. **栈结构**:每次调用都会创建新的栈帧(内存空间)9 p/ j) W( L7 X$ y3 w" Z% y
    3. **递推过程**:不断向下分解问题(递)
    5 h6 c6 C/ P: ?& X" U) b0 i( q1 P  E0 G4. **回溯过程**:组合子问题结果返回(归)3 [, F! Y, s' L6 }
    0 B4 H) K6 _3 T; l  d8 K% X
    注意事项
    & O4 m' E) L( }0 Q* G必须要有终止条件
    # k0 P% O% @' ^3 M' y) @递归深度过大可能导致栈溢出(Python默认递归深度约1000层), N2 F; A& q0 D
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    7 x+ S' ?$ Q: E% N8 h/ a. x4 ~尾递归优化可以提升效率(但Python不支持)& k4 \# D; b( n% F1 K* l
    , }" u: n! T* X* h* [, g
    递归 vs 迭代
    % i! e/ l- P! J" ?# ]$ G  s|          | 递归                          | 迭代               |
    5 f1 w! }2 U( M|----------|-----------------------------|------------------|
    4 W* _, s* X: j4 @! J) n| 实现方式    | 函数自调用                        | 循环结构            |
    9 E  @+ v* s. z" V; L' ]7 o| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |7 G9 H, W$ L0 W0 b
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |8 V! N; X2 ]( N8 r
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |0 M& `8 b- E) z( p9 ~

    1 M1 L1 e8 f( [. W6 Y$ ?( r 经典递归应用场景& a* A$ f/ W8 @7 u  m0 B$ p7 |1 p
    1. 文件系统遍历(目录树结构)0 s: f/ F" z# y5 {# ~" O( z
    2. 快速排序/归并排序算法
      T( o, ~3 c. e' u8 f0 h3. 汉诺塔问题
    % o, Q  b* L# g, T7 ^4. 二叉树遍历(前序/中序/后序)7 {  Z* G0 M/ o0 K! u/ w
    5. 生成所有可能的组合(回溯算法)
    3 M1 U9 l4 Z$ @- @1 Y( Y! T# l3 c' h7 T/ J+ W9 j$ ~4 K0 Y
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    * j; I$ u2 F8 [% `  {我推理机的核心算法应该是二叉树遍历的变种。
    4 w0 A& g% ^7 T" B3 X7 r' U. U7 L. j另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:: \% @. W* Z  b" c( J& d
    Key Idea of Recursion
    - g8 T. j9 a; `9 m7 `, g  ?0 C* Y) s" T( c7 }9 Q8 |
    A recursive function solves a problem by:8 m# {- D) p3 ^  Q$ P
    8 p$ b) }6 Q  h' K
        Breaking the problem into smaller instances of the same problem.9 m9 {3 H! v6 z+ P8 A& F( h
    + a9 ]0 \  w1 w6 E% v1 q9 a% K
        Solving the smallest instance directly (base case).4 i/ A5 r' P# z( Y5 E

    + _+ @; o! N, t! \; a    Combining the results of smaller instances to solve the larger problem.; [; {, W* _) |( b
    ' j" D. u+ o4 x. j! v. q% W( j
    Components of a Recursive Function
    0 u) h3 ?5 u2 r2 h- H
    / g3 w& F8 |6 z9 {( W, }    Base Case:) {8 Y. `$ j, M+ S/ J0 _
    ' @0 S- I' O; @! P/ W0 d  I
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.* y' C+ s4 @0 o9 V
    - m* a% v7 a# y' H
            It acts as the stopping condition to prevent infinite recursion.: t. c4 d& V7 C" I# X1 ]* k
    2 I- T$ O/ K$ c. E1 {7 V1 A
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    ( _5 u1 G6 j, R% d. v# G$ P% ?. O5 }& f3 G
        Recursive Case:
    1 P1 k6 }0 v6 O% {! W$ o8 y: V. [/ A. D& L
    : D1 x9 A1 I5 S        This is where the function calls itself with a smaller or simpler version of the problem.
    0 c3 H1 b# V* G3 w2 F7 o) w3 v6 R6 p8 n
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).+ p5 F( M* e' I2 ~
    / B+ k: X; K. E. ^% ?
    Example: Factorial Calculation4 N- p; R8 ^4 A2 e

    # o  r& ~6 ~' ~3 p5 O, fThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:" ~$ G0 n5 s* K, C

    " |  x9 A. U7 Q/ p6 T' P    Base case: 0! = 1; S) w/ U6 R. P* o2 |

    9 c6 ?) ?* R5 F* ]$ V8 o% H& ?    Recursive case: n! = n * (n-1)!
    ) \/ T. N; j. K7 ~: L6 D, T
    ( s( }. i# u# nHere’s how it looks in code (Python):" ~! o9 q& x) t2 [
    python
    ' C* u: L+ B: Q( ]9 F5 P7 m; c2 k! [: ~; o! F' I* q8 v/ F

    . `& ?- i8 P+ w$ a+ Cdef factorial(n):
    / J" r& h3 P+ k4 Z( X5 w    # Base case) w/ B7 U# z% C: t
        if n == 0:  L5 H& F: y* C% B4 p) y
            return 12 A$ o; x% R9 f4 [6 r/ [8 u8 H: r) C0 h
        # Recursive case
    : T+ E6 G% L4 c& ]9 o; ~! x    else:
    ) q: ^1 d* G, b4 k        return n * factorial(n - 1)- h( C2 Y* t  g, v# R$ P+ Q
    * B8 I2 c8 N! B2 E) K* G3 x
    # Example usage
      v0 g+ T' Z% B5 K6 x/ ?print(factorial(5))  # Output: 1206 W: a1 _, L' ]8 I" j

    1 \0 v+ y+ c4 i9 Z8 E- I0 f# m( ^% N# E3 KHow Recursion Works
    / _) R, u: ]6 \& p5 z5 p  w. {, D3 |' Q+ X1 A
        The function keeps calling itself with smaller inputs until it reaches the base case.4 b+ I0 i1 H- @  B& z7 _" s' I3 [$ q- Z
    $ _: _2 u7 w2 ]# @8 a
        Once the base case is reached, the function starts returning values back up the call stack.
    7 g  S' A8 g, i& R3 T0 b. h4 ~8 k9 c4 \
        These returned values are combined to produce the final result.
    4 {2 J& L5 `1 {+ p( @: U# v, R" n- a# f2 `8 T
    For factorial(5):, x2 b2 N; P) q% ^
    # p- R8 ]3 \1 `, W3 a9 {9 B
    2 ?+ v4 Z) s2 C4 @# S* \
    factorial(5) = 5 * factorial(4)# Z9 b$ A( q3 m! \9 o. l7 T
    factorial(4) = 4 * factorial(3)! I* ~* n" }. q4 V) a* n
    factorial(3) = 3 * factorial(2)2 m& r( W$ Y+ k$ i" K5 M1 y
    factorial(2) = 2 * factorial(1)
    / p* y1 y5 \3 ?+ t3 W, S+ }. L$ Gfactorial(1) = 1 * factorial(0), r' D! O( {, l, D4 [
    factorial(0) = 1  # Base case
    " a7 C7 f/ k3 T5 \. `# ~( ^9 b; d# q* G  Q7 ]9 ?
    Then, the results are combined:: P) M+ h9 y' D( d+ D

    - T% [! {8 z. t4 D6 o- p
    6 q& K  N7 R1 I4 _. @factorial(1) = 1 * 1 = 1
    ) |7 o) o* f, [6 T; W! O! z* x7 efactorial(2) = 2 * 1 = 2$ M+ I3 ], j0 Q- {& q, C+ P& c/ n+ x$ n
    factorial(3) = 3 * 2 = 6
    % Z! g9 k) l4 E( }factorial(4) = 4 * 6 = 24, r+ z+ x7 O% h  I* x7 D
    factorial(5) = 5 * 24 = 120
    * x+ x9 }6 \# P+ n8 X# c+ s& S% m% b  B, c
    Advantages of Recursion2 Y0 v: Q3 _! h3 m/ s

    ( L8 D# V3 k' n" w% u) U& h7 v    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    # T* U1 E* b6 ?! R+ n0 M0 v! J/ X) D- F6 p% |* A4 d9 K. x
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    ' t% d7 H: o) n6 P
    % N# c# t1 H4 t& {/ E5 E0 SDisadvantages of Recursion% }0 o) n7 U0 [3 p; _, F% K0 M

    * Q+ u) m# U! J, ]2 l    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    7 o1 p. T' Q8 l. @. F& x5 N# ~4 J2 u) J4 \; M5 t; F/ P
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ) I4 d! G0 E0 U9 \4 ~7 J9 C' _5 \% _# _
    When to Use Recursion
    ' r; |& _- t; M& j
    " `3 I/ x' s- o( c- G7 |# Y; m    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort)., A9 W2 e( W, o

    # g9 n9 V$ k3 {- t7 f4 s0 H    Problems with a clear base case and recursive case." E; s3 t* ^, e" V7 H
    4 _. S- y. E$ ]& Z. g- D
    Example: Fibonacci Sequence
    ' J) A! b0 c& Y0 }/ H6 {% l$ H, N6 U: D3 ~7 m# C/ Z
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:& n$ ]: E1 S8 f5 d" d
    ( ]5 ^, |# _% \9 g5 {0 T
        Base case: fib(0) = 0, fib(1) = 1; ^+ D$ i! c1 m6 E
    - t9 l% {2 J. w8 t4 U  x  l
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    ( k. i  g+ D+ D; J0 p  T
    , ^  T8 Q% }6 g% m  d' |python' U* Q) S0 k" s' e4 e4 d

      U5 {" [8 f# o0 r( g
    : U- Z8 V  F# [/ S5 W0 [) V9 I" Bdef fibonacci(n):
    ; X2 v+ h- X+ b4 Y  a' P5 b) r    # Base cases3 o) \2 f: t7 t! A8 e, \1 j
        if n == 0:- ~) C) w) `) X7 {- S: L8 a2 d1 ?
            return 0
    0 }: ]2 D' f7 b3 f4 z) I% a    elif n == 1:/ R2 H3 K; T' |6 C7 z- |4 q* \
            return 1
    & A+ ~7 @# n1 G/ U0 z5 r1 j2 C    # Recursive case
    % c* X8 m+ \; W0 Y1 S& Z    else:" y$ D9 K. o* M/ K
            return fibonacci(n - 1) + fibonacci(n - 2)
    0 k5 A3 h8 K8 z+ u# K. s2 v" t/ D  k7 p
    # Example usage
    " z" k: s) x9 w- k% |print(fibonacci(6))  # Output: 81 S9 g6 R. Q: j9 M9 ~- M
    % k* F0 W& _. G, s* e: M2 w. z; N- W
    Tail Recursion
    ) z; F. U/ @, y1 d6 }, |( Q3 m9 N
    . J6 O& Y) h% [$ R: DTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    " U6 m: P8 n( h  E- K
    ) z& q/ Q5 Y* o* }( KIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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