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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 * x  D6 E+ c7 [' ]2 _( k

    - e5 \. J9 O0 o解释的不错
    % }  E- A6 t2 l; D  O* W! w* u4 Z8 T+ d9 u: y, k6 K" `
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。$ n, O' N* Q0 E1 U
    : Q0 D9 d4 h/ ^% r" {1 e
    关键要素8 ?' f: j& U- ?0 u$ m# l# p
    1. **基线条件(Base Case)**+ t; n% W! R: |. S
       - 递归终止的条件,防止无限循环' q4 m+ G" C3 t
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    / ]8 h! R7 s* Z3 \8 \2 a) R
    ! h, D" E0 J! e: ~+ j& f+ d2 K; _, |2. **递归条件(Recursive Case)**" `8 M- V  f; c# T- I; H
       - 将原问题分解为更小的子问题7 v: A2 [, f8 ~
       - 例如:n! = n × (n-1)!
    - l  D# c: M5 o0 y; V; F( q6 }9 @
    2 [  h% M' g. L5 t6 ~ 经典示例:计算阶乘' e/ y8 l* E# k1 s; w1 Y# V9 E* H
    python+ |/ n4 e% ?+ V, {. m
    def factorial(n):: J3 q2 O6 h. V7 j; O" I
        if n == 0:        # 基线条件
    # V, ~3 A, b" E' e2 S  u- L        return 1+ j$ b8 X% h$ D+ ?' P  Q0 w$ ~
        else:             # 递归条件; I. ~3 H( w# q& [. Z5 {% g
            return n * factorial(n-1)
    / ~5 _0 I8 |9 U" @  [5 f: Y7 ~2 C) U  C5 e执行过程(以计算 3! 为例):. H5 z  L5 M. S  J7 G# ^. h
    factorial(3)& f1 K* N/ N$ ~) }7 T6 j6 z+ Z" s
    3 * factorial(2)5 \# ?+ q& W  [5 h' z1 R
    3 * (2 * factorial(1))8 U4 s8 N8 L7 P( N' w
    3 * (2 * (1 * factorial(0)))
    + x, z& }0 ]9 l" ^% p; u$ V3 * (2 * (1 * 1)) = 64 C( S& l5 i+ ?) A0 k! {
    * M' J( W4 h9 b5 f* R0 ~+ X1 f/ D
    递归思维要点0 ~5 S% ~2 f* O. @
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    & x/ X. F' T& Y5 }: l3 B: N" u6 n2. **栈结构**:每次调用都会创建新的栈帧(内存空间)) h' O8 z' E$ {* u
    3. **递推过程**:不断向下分解问题(递)
    . h3 D- l- }0 t9 C4. **回溯过程**:组合子问题结果返回(归)5 _0 f( k# a: V8 C- t2 D- M3 a" f
    2 U; V8 m/ f; p  p8 b$ ~  S' M
    注意事项
    * ^& B: f2 L2 p; ~必须要有终止条件$ v/ |! v+ U1 q
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    9 [- k0 A' P. K# L" }" _某些问题用递归更直观(如树遍历),但效率可能不如迭代7 `0 y4 v+ |3 l
    尾递归优化可以提升效率(但Python不支持)
    & \1 r0 _0 W/ W, P6 `  }$ ?5 K
    # C( j  [! o  s7 N2 j' G- Y2 x1 i; z0 D- u 递归 vs 迭代, N$ s( r0 f; X: b: {: L* M) N
    |          | 递归                          | 迭代               |  o! m; [7 _& i
    |----------|-----------------------------|------------------|
    * a' {4 y2 }6 Y6 z+ ^4 S; h+ _  B6 ^* L| 实现方式    | 函数自调用                        | 循环结构            |& f9 A4 f; s) H# N
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |- [. ]8 U/ r  ]; W$ v# U" J' L
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    5 ]5 r' H0 g  ^) Q| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    " ^4 U6 K# ]; t* w1 U3 L/ J
    % y6 d7 M' l8 _2 `  Z/ w 经典递归应用场景
    ) x' L2 z5 c9 E) [2 ?- L5 f! a1. 文件系统遍历(目录树结构)
    & h. q4 c* X5 I, k$ p! S, \2. 快速排序/归并排序算法$ d7 R) O5 Y* `3 O
    3. 汉诺塔问题
    - R! l7 j6 f- \4 F$ w4. 二叉树遍历(前序/中序/后序)
    " A3 f. @# W( U7 X1 p5. 生成所有可能的组合(回溯算法)
    ( i5 T  t6 }2 Q( }. {+ M
    & n8 _6 L% I* Q/ y3 L7 {试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    8 u7 c: c) q: U2 T* e! c我推理机的核心算法应该是二叉树遍历的变种。
    ! }% H" }, a& T* t另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    - R$ C/ u. }2 S$ W) [. k) s- @) gKey Idea of Recursion
    % q( ~" [: e2 h+ K% h
    4 {6 ^4 L5 O+ A# ~: A  S7 U: |A recursive function solves a problem by:! G9 d, d9 R3 O. V) c& u

    , O: D7 A( f& F( v' B7 v+ z    Breaking the problem into smaller instances of the same problem.% _) V( W% s2 O3 b1 m

    - ]- r0 O' q$ m- p. `( r    Solving the smallest instance directly (base case).! h. P  v7 Z# }6 E7 e
    . r; O$ u6 [1 o: {3 g
        Combining the results of smaller instances to solve the larger problem.+ B8 }6 @: E- X. r- k
    $ p. |4 ]& o8 H4 _0 k7 N
    Components of a Recursive Function
    ; d) R+ C7 K* ?# @; z9 _" {5 U
    $ f6 M0 ~# C- h# {. E2 p    Base Case:- ]+ n+ m: ~# m( b5 P* R9 a
    - k. H' U5 V. w/ C' \1 a- i' ?' ?
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    3 I4 u/ ^) T+ ^! T. c
    9 S- }7 Z3 \2 Z' l7 _# Y$ c* X        It acts as the stopping condition to prevent infinite recursion.$ \! T: V+ ]# X
    / i1 U# G8 N  o  y6 O
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.% @2 ^; y  ?' t+ p
    + t: s9 X, z" x/ p  V, l) o( k
        Recursive Case:1 w! T1 P" t' u

    ' L2 d) @& C1 S" p/ ~/ J        This is where the function calls itself with a smaller or simpler version of the problem.6 B, r' H( u/ V
    - u0 e' _: Q; O) L
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    $ S4 @* U$ U) B/ k  Z' @8 f2 c8 b/ `2 ]3 J+ c
    Example: Factorial Calculation
      \. r; V6 M, L0 O! `9 i+ N8 F1 t7 |! |! h: i9 {
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    5 ?7 B# v( f' N$ {. d) O" f. G3 S! g  o% c
        Base case: 0! = 1( u. q: v6 `3 L
    * A' }1 x" g% ~( l7 R
        Recursive case: n! = n * (n-1)!( l* R$ I3 V: m1 l" r

    % r' g0 s6 M) A( s: t5 R: V4 b5 n5 fHere’s how it looks in code (Python):
    : T6 r: Q8 n7 mpython
    6 L. P# D. Z2 f- }0 |% _8 \1 ]: d# T! X( u/ r5 _+ f

    4 J, ]8 i; z; h# Vdef factorial(n):2 @; f- a3 I" C: T. R8 f' s
        # Base case
    / ]8 k8 u5 J5 l& c# K) y) N: j6 S. ]  n# D    if n == 0:
    , R" ~% c, B0 g6 K. x& u% k        return 1
    , C; G& y4 x& w! P% m) i    # Recursive case
    , }$ F$ v/ L: Z4 N: a8 Q  ?' x    else:/ t* {: o9 ^' X' |# c) ]5 h
            return n * factorial(n - 1)
    7 i! ?- c- p  e
    1 D8 G8 C* s$ `, S/ s# Example usage# v2 t% o" c# S, b2 M  a
    print(factorial(5))  # Output: 120
    6 d7 W! Q2 c) D: s+ @. g
    . Y- f; }, u9 m) AHow Recursion Works
    ) E% l' v5 O8 ]) Q( [: e9 ~
    1 L0 n/ q3 Y. E    The function keeps calling itself with smaller inputs until it reaches the base case.
    - j( o0 g  C5 x! V$ r1 ^; |) P7 d& e( X+ H0 w7 [8 W! L2 _1 L
        Once the base case is reached, the function starts returning values back up the call stack.
    , e; g# r$ S- L8 S
    / m2 y5 @0 `, Z0 `. V* j    These returned values are combined to produce the final result.: D# E- X: h- j# T1 w

    % b! U6 b  Z& g. Q8 }4 A, EFor factorial(5):: O  a; X2 e: u4 w; I
    - o/ q* ^6 h0 {3 e8 A: U" G

    + p% ], E1 z* d( `5 w; y0 J  ]factorial(5) = 5 * factorial(4)
    . I7 A$ }! O5 s( I5 zfactorial(4) = 4 * factorial(3)! e6 g; S/ _8 Y$ V6 N  I
    factorial(3) = 3 * factorial(2)
    6 G. P# M0 K* H$ W5 }" U7 Hfactorial(2) = 2 * factorial(1). e5 z. x5 Q9 }% t) `' B4 _) r
    factorial(1) = 1 * factorial(0); ^1 D4 \1 v4 M9 c: l3 i
    factorial(0) = 1  # Base case
    3 x2 M7 P+ w: W6 V3 s) q% x# m! c- j7 ^
    Then, the results are combined:7 J' e0 g( R+ o/ m* F

    8 I! G) W. ?# v6 A. i; V
    # q3 v) g6 d# Q$ z  Sfactorial(1) = 1 * 1 = 12 o! z* p, L+ |# H* a! z( J
    factorial(2) = 2 * 1 = 2+ o' z1 ?) q2 M, G
    factorial(3) = 3 * 2 = 63 C. I# N: v" I. z% s
    factorial(4) = 4 * 6 = 24
    0 L1 l5 U3 K, z& Ufactorial(5) = 5 * 24 = 1205 m  @5 a8 T" V2 U' a& U4 M

    " U6 ]8 K/ D3 j# ^+ L- x. eAdvantages of Recursion
    " o5 Y3 E" o& ~  Q9 v% V0 I4 @( D3 T7 s- k1 ^3 B& K3 _+ R
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    # S( q( E7 C6 u9 K+ ~
    ; r% L& q, j- D7 n1 Q. _% |    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    7 U" C& r4 B1 F3 e5 [$ z
    ( J9 z# r0 _! d/ U, J1 IDisadvantages of Recursion
    $ W  M4 `9 V6 x1 ]% ?$ w# N4 P3 Q! }$ z' T2 p7 U
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    . b* y3 Q( N" p# Y9 T0 i6 ^2 j0 }! B0 Z. |4 Z
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).$ b# E9 i; I7 x8 j% ?

    9 R7 b% J; g$ f- IWhen to Use Recursion9 Q4 |" F  e5 G% J+ a! R; R6 L
    ! u2 g. Z) Y" \. _3 W: z: @. n
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    " P" u2 [, H; h+ \9 N1 Q" u
    # }+ i' T7 ^& }( J& h    Problems with a clear base case and recursive case.
      ~8 l: n+ R8 X0 M6 g' @1 S( w7 n) M( V5 i, U3 `, c9 w
    Example: Fibonacci Sequence* o; w& r8 ^; Z* y4 ^
    - i$ S. {9 Q6 L9 g3 a% [2 P1 l
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    " P2 h/ k1 V6 F4 {" m0 F+ Q/ ]6 t% t' Q9 l7 C" h5 T9 y* p
        Base case: fib(0) = 0, fib(1) = 1# L. L! h$ R& ^/ E

    ! v( h' \  O8 ^    Recursive case: fib(n) = fib(n-1) + fib(n-2)' o  V& O  Q& q' L. e# v- f
    " g9 T* R: B: V
    python
    4 q' A5 x- ^. @: p8 I$ t+ h; w& `  G9 d! P# q3 z, u

    % E8 r! T5 b4 \def fibonacci(n):& ^3 V% O6 i& W  Q: H% f- q
        # Base cases
    5 U$ z; o: K  f8 r/ a' Z    if n == 0:& S7 \6 J( W/ H6 h4 C
            return 01 V$ M; G: S6 i" `
        elif n == 1:: F; i' w( b/ U
            return 1
    7 ?3 _5 [: E) l6 R$ L$ j' }    # Recursive case: }. B+ _/ V- D# @
        else:
    6 O/ m2 g  M3 b  S! a/ \# ?/ K        return fibonacci(n - 1) + fibonacci(n - 2). ?# u) |! g/ w; V4 }
    3 @  x( z$ @+ s5 E% I$ h4 U7 \
    # Example usage
    * F4 c) K" Q; S- v0 Mprint(fibonacci(6))  # Output: 8
    3 E) o  Q) ^) ]' q' e4 O. C; s! T/ u
    Tail Recursion
      r  k. e5 G9 _% c2 B" M% c9 ?! ?1 J' \) z/ G: v/ Q% d
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
      I- d8 B! f, T: L3 c5 Z1 e! K2 O8 o+ d. d" l# E7 N9 c; [
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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