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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    ! r% p0 L$ K3 _  q- ~5 e! e$ X8 @( P5 `% n( F5 U* I
    解释的不错) G  n( D7 K% W. G2 ^0 K# j
    ; e1 D7 `3 r% x; w' j. s3 ~6 p$ ^
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    0 A  s9 M% @: v5 m  ]- Y  P5 `( k
    6 U7 U" f  _) ^% w$ B3 P0 K 关键要素
    + b' k: p# X8 p1 K1. **基线条件(Base Case)**& o0 m! z. x8 ?
       - 递归终止的条件,防止无限循环* j/ }7 N- G* u; l9 @
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    0 W! E6 P0 p$ }- ^/ ~6 Z( n3 E. c# L/ `5 w
    2. **递归条件(Recursive Case)**
    5 K5 g" a1 X( D4 z& ~. P   - 将原问题分解为更小的子问题1 u) \) g* K% _! z9 D5 P
       - 例如:n! = n × (n-1)!
    % J2 @" x, ~) s" V" k& p
    + f) d! ?/ J9 R. p" e& u/ O 经典示例:计算阶乘
    / W3 a4 ^) G& u7 L# j2 Vpython) {1 |* L6 |9 ^0 H
    def factorial(n):) U8 ^: n8 d0 u1 f
        if n == 0:        # 基线条件
    2 D" A3 Q$ s" q- p6 \        return 15 O1 f/ C2 S9 T9 b; z8 d- D
        else:             # 递归条件5 G6 w4 T# d% a
            return n * factorial(n-1)5 r( a; Y0 J4 p, R4 M- j2 D  O; X
    执行过程(以计算 3! 为例):; L- D, Z6 Y7 n5 @0 O# X' `
    factorial(3)
    6 K& u# G2 E: a: e0 S3 * factorial(2); g) H+ A4 J+ f; s% @" ?3 Z
    3 * (2 * factorial(1))
    5 |5 l" L4 Z: f  c# z. l) H3 * (2 * (1 * factorial(0)))9 y6 t; M5 j) `( I, ^0 n9 A2 i
    3 * (2 * (1 * 1)) = 6) f  r3 ?; S! m. J4 F1 S
    - f" N* v# A6 z" n
    递归思维要点
    ) d* O' H& p: z1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    5 c  Z3 X3 L, Y) c2 R2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    8 k4 F* Q4 w" \# R4 L4 P* |5 K3. **递推过程**:不断向下分解问题(递)& ]' V' e) U1 r- [
    4. **回溯过程**:组合子问题结果返回(归)9 x, b# |+ D& h6 \! a7 c
    6 Z# r7 B3 s; ?# v4 H/ `
    注意事项/ H, L( c" g5 q, V; q9 M
    必须要有终止条件
    / ~9 O  |  l; j% V, v3 C# \' W递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    7 u4 {1 \. E* k. s9 X% s- T8 ?某些问题用递归更直观(如树遍历),但效率可能不如迭代
    6 K+ e* \, l/ J, m; t+ y3 n尾递归优化可以提升效率(但Python不支持)7 a. |+ Z8 A3 _* v" w
    & u/ m: v& |! G3 g% Q+ w; {
    递归 vs 迭代
    $ r, \9 x$ v" i; k" x|          | 递归                          | 迭代               |. ^" {5 S( g6 o9 j3 }6 p* k) J
    |----------|-----------------------------|------------------|  ^/ j# T6 }3 x8 U% H* R; f
    | 实现方式    | 函数自调用                        | 循环结构            |
    9 G; e& U& g. v% U| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    4 Y0 ?* X1 V+ d: W| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    , O9 [: O- z. I9 x$ x7 Q| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    5 P: A5 ]) ]$ s9 T
    ( Q+ Y# a  H" \: F  d) W" X$ j* ] 经典递归应用场景  A) h- F8 j$ |! D9 T8 j, {9 U
    1. 文件系统遍历(目录树结构)2 k) @7 K  a" q- X. ]4 H) ~* `
    2. 快速排序/归并排序算法
    0 l) A/ O+ s/ b4 w8 o- G3. 汉诺塔问题$ ]! a( k3 B; X
    4. 二叉树遍历(前序/中序/后序). ?; o; ~7 ?' Q
    5. 生成所有可能的组合(回溯算法)0 r' T# U/ S( A& m; F( j( {
    $ k5 G8 v# ]5 Z% \' _. S
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 06:02
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    ; |" Q3 l" f8 _- y我推理机的核心算法应该是二叉树遍历的变种。
    ; [8 }  b$ U9 E' l# G另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    . }8 _3 R2 B- B; e/ P( C5 wKey Idea of Recursion) e  K' c5 s& K6 W7 H

    ( x6 S9 t5 ~; ^9 N+ P4 ?A recursive function solves a problem by:4 G6 }9 w. m3 [9 v$ k3 G& s. I6 Q
    * d; q+ l7 D; i  ?  o) E) b
        Breaking the problem into smaller instances of the same problem.
    : P1 p7 \* O0 J& K; H! B0 p+ B8 V: b- Y3 `% L
        Solving the smallest instance directly (base case).% l% `& X2 L" i3 }, n, h: S

    7 ~+ e9 o7 g1 V+ n2 ]+ C# D    Combining the results of smaller instances to solve the larger problem.
    3 J3 V0 m  e* d1 I" }  s$ N  ?! H: e3 C# u+ [
    Components of a Recursive Function
    & d. V; _" _: Y6 Q
    1 F7 ]* s! ~" r* I% i5 ^7 N    Base Case:4 L: K. c8 a) r
    * m& L! {1 b1 \8 Q8 z# L
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.- b# F7 @& s+ H* x* D, F6 G

    : G& |. d8 H2 e5 `# p6 v        It acts as the stopping condition to prevent infinite recursion., g4 h2 y; q/ Y8 x+ @) j/ c
    % `. M9 {% M: O2 E
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    3 y$ D! {( W7 |5 N* z" g6 W; b% b6 e4 e6 y' U0 P
        Recursive Case:
    * @! p* k. q2 o; C' V/ [
    : |3 c; g; l# t9 c' M4 O' D  d+ P        This is where the function calls itself with a smaller or simpler version of the problem.$ w: v6 X( e+ }! n" ]$ a

    & K4 X: F. ^+ v  W  W        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
      j: W. \* J$ U$ C6 h- R
    9 K- A2 a1 N* F! l/ pExample: Factorial Calculation9 x' G- C& M5 i/ ^

    - R4 I$ `* D5 Q# _3 HThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:) i) B" e  k" u+ s6 K) D4 S* u8 _" N

      I5 ]. b/ D6 V4 i, _  c- S6 q; C    Base case: 0! = 1
    * T: Q8 e% M# j& l% x
    / }* m; U- e: N, F4 }$ E    Recursive case: n! = n * (n-1)!
    ) p: U0 G# a  W
    5 i, q( d9 k7 }3 B  K+ qHere’s how it looks in code (Python):# ]; c! ]% |/ @4 `: d
    python
    : }) O$ Z! U. v& m) E! u% m2 d4 s0 n3 e4 {8 h  T4 w  p

    + j' u7 ~' T9 Q7 v- Adef factorial(n):3 x7 h/ D3 E2 S; l2 ^
        # Base case
    : Z8 t/ G0 N1 L, \  {    if n == 0:
    1 a$ T* h; M- u* e& J: ?        return 1
    ; r( B) b# F8 E0 d4 J! x; P; Y& G    # Recursive case: S$ w1 k2 N3 D( z2 ^
        else:
    + [3 H3 d& `6 X, r2 u. v: u        return n * factorial(n - 1)2 O) Q9 e7 v- E! y+ A

    6 b7 m0 y5 w* i# Example usage
    $ h2 ?" N' k" {print(factorial(5))  # Output: 1208 }$ ^& k1 }, ~% P8 t2 p3 F% i. u5 S
    9 T. w( K7 o: }! m6 |" s# H6 s
    How Recursion Works
    ' `" ]# ]8 |! Z! a
      |0 X  w' ?$ n) l5 o+ q    The function keeps calling itself with smaller inputs until it reaches the base case.9 y1 _0 l9 H" n) r) _* B6 d4 G

    $ {3 V6 f( w" \% i    Once the base case is reached, the function starts returning values back up the call stack.
    . P, a& l: ~2 }* A/ C2 Y) m9 v4 l# p- Y6 D& B  Y5 o1 a4 l! {  F
        These returned values are combined to produce the final result.9 z; q' d# i: K

    5 |  d. Y- q7 j2 C6 `For factorial(5):
    3 h% T) |3 k) s% N/ d+ U
    ' x1 F, W% u% O, c6 X, L/ {+ o9 d' `& r& k) U% B6 U+ b: c4 V. J
    factorial(5) = 5 * factorial(4)% H0 t8 W/ s: }( f* d
    factorial(4) = 4 * factorial(3)9 a+ ?* b0 w' Z: V) y' c/ J0 a
    factorial(3) = 3 * factorial(2)
    # [% p0 d3 u: `1 P2 afactorial(2) = 2 * factorial(1)/ N) y6 B- L: U1 Y- Y
    factorial(1) = 1 * factorial(0)
    & W0 G+ D4 x7 Bfactorial(0) = 1  # Base case
    8 c2 O5 d# B* @* a% R
    3 U1 x0 y/ F" H! y/ u3 M3 oThen, the results are combined:, u+ v: n# K) f# s+ A; c1 F

    # B1 l/ r) \  {& a9 @0 Z7 f. r# G# _6 Y, t: b* {( I
    factorial(1) = 1 * 1 = 13 K9 f% z, M$ U* i) K
    factorial(2) = 2 * 1 = 2
    . R+ v9 T1 V$ f6 p3 Hfactorial(3) = 3 * 2 = 6
    9 V4 |8 g$ B0 ~' c9 b3 Tfactorial(4) = 4 * 6 = 24
    - Z& t8 {. D' F  ?, V/ afactorial(5) = 5 * 24 = 120
    2 x9 D9 S2 [7 Y" R2 n
    8 V  ~; Z* ~  X  i% n# aAdvantages of Recursion9 W- S6 p, h- \  p

    % _* h5 K$ \/ c9 n    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    " n$ z2 X; q4 X3 Y% ~0 @
    , k2 h, r. h7 c! _' o    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    % Z# P0 ~# \* [' C8 Z/ J
    / w7 \8 s$ F  Q& GDisadvantages of Recursion
    8 k. N! e: C2 v3 ]3 A- W' D7 b0 Y5 K; J; h! @1 \, k, ?: {  l
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    7 x! h8 |: M0 a3 h6 P2 }: q+ O$ l8 D+ @/ i9 e; L
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    2 H" e1 K1 j) t. _( X4 [* G
    : D8 j+ L/ L  b" hWhen to Use Recursion
    * s; z. m& e! X0 r+ L7 p1 s; c9 s/ o8 D% j
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ( {0 T" Q& L" c4 T
    + |. b3 Q5 o+ C. N    Problems with a clear base case and recursive case.
    9 n7 x/ U# d2 G$ Y9 y! _% K6 _  @- ]0 H0 J/ a) I8 l
    Example: Fibonacci Sequence9 b. _6 r1 W- Y7 H: U1 ~1 {0 u8 B
    ' s% W  M( X3 J: P- d/ @6 d
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:) f$ K* T) i( u& G7 @! H

    1 Y. f0 k5 j4 n* @. n" ^2 O    Base case: fib(0) = 0, fib(1) = 1# u* S7 R/ y* l2 O4 a( a* F" l) ~

    1 |! f  x: [) k5 z    Recursive case: fib(n) = fib(n-1) + fib(n-2)# E/ J, d. U9 d" a
    " f  h8 l: i' U- I
    python2 H9 T4 j; D; T, D

    ) H$ j: R7 a& E% I
      H1 L/ [9 _3 c$ ]def fibonacci(n):4 d% D% `# p$ [; d
        # Base cases
    . G* c* [. O4 [1 m+ W$ A    if n == 0:
    ) P! @; W5 Q" H: ?9 R& `        return 03 v1 {1 x* S( D+ z
        elif n == 1:
    / Q, s' j# S0 Z        return 1* q' A1 T/ D# ^
        # Recursive case  B1 V# X6 y- r9 ]) L6 n7 Z9 c
        else:
    ) O3 R9 _1 Y2 l+ `& p. r        return fibonacci(n - 1) + fibonacci(n - 2)
    9 d# ?# P. g+ O5 p- w
    , J+ E! f$ T3 }; t+ g5 C# Example usage
    " r1 q- f( q/ }, k6 s2 kprint(fibonacci(6))  # Output: 8
    : v. g7 H0 b' C( L! M
    3 {. r, ^' `9 Z: HTail Recursion
    7 B1 ]- E, h: P( q7 a& f. H5 l8 M; N# h  M2 i( G3 H
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ! X/ E' r; v; [( ]
    2 @. ~0 B& e+ CIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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