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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 , ^( I* P) k: c/ V0 n
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    解释的不错
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    5 ~0 ], J8 Q2 L: }5 A8 |递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。' A0 q4 h; o6 S& W4 m5 W' o

    / W6 G$ [' ~" a1 C: I* v; d8 X 关键要素
    + s1 e/ B  b; _1. **基线条件(Base Case)**3 V0 {% W! W5 u) U8 y+ z
       - 递归终止的条件,防止无限循环) M2 M' L4 x( `. s. H
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 13 h: }% ^- W0 q" F, p& E6 K
    ' j3 e% Y% s& t# \* e" H
    2. **递归条件(Recursive Case)**4 b% I- p8 ^' w4 a: z/ G2 w
       - 将原问题分解为更小的子问题2 O& H: H1 P. }3 r
       - 例如:n! = n × (n-1)!
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    6 D6 Q6 |* |0 ^# N 经典示例:计算阶乘# j1 }4 A, `9 c2 o3 Z& Y; b
    python
    % n$ `3 ^6 ^9 w0 d& A7 Edef factorial(n):
    1 c8 A6 x, _( _, t    if n == 0:        # 基线条件
    6 b8 i" ~# b4 O        return 16 H9 G9 _2 y3 t
        else:             # 递归条件6 Q, x& P9 [' K6 }( W
            return n * factorial(n-1)
    5 z) \+ }5 f& C) {4 t! g: f执行过程(以计算 3! 为例):0 H9 o8 i6 I" a% g; L- k) A
    factorial(3)& b" b; c% {: J7 y) A
    3 * factorial(2)2 Z7 s8 a, B3 p
    3 * (2 * factorial(1))
    ; e, G6 U6 u6 ]3 * (2 * (1 * factorial(0)))
    * s0 N2 A1 u! w; s( Z- u4 R! W  I3 * (2 * (1 * 1)) = 62 |# g7 x9 e! a  b

    % Y0 ~* n3 i! O 递归思维要点) p- Q' r% l6 t* S4 P6 e8 j
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑! O) U! n2 u+ |
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)( H: Z- G- a! P+ q( r8 m  X2 T
    3. **递推过程**:不断向下分解问题(递); p" Y, Z  ~/ x; C
    4. **回溯过程**:组合子问题结果返回(归)
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    ; w# d. e0 J: _2 T 注意事项3 r9 [0 W/ B+ g0 Y- H
    必须要有终止条件% z% h5 R4 L' k( R. C
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)! |" O7 v7 [( k" h$ }! U
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    6 J, [) m, M, N  @尾递归优化可以提升效率(但Python不支持)
    7 Y" i, B2 S5 O: W" U# e& p- O7 K& h% F2 Z9 W2 Q" Y* R
    递归 vs 迭代+ ^2 H! H5 {3 d. r' c, u/ G
    |          | 递归                          | 迭代               |' N6 U! |. E$ G5 M7 m
    |----------|-----------------------------|------------------|
    9 y  Q6 H( e8 u, U| 实现方式    | 函数自调用                        | 循环结构            |. G- Z+ |1 E8 Q  U. }
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |. T3 a  o  R# m  q' A
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    % s4 m" K( E+ ?8 @5 F0 F| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    8 O1 V0 z, P9 U9 O9 a, y9 c  |! x; ^' n
    经典递归应用场景2 x1 V1 I6 ?  M! |( f
    1. 文件系统遍历(目录树结构)
    & C* Y5 F' p: {2. 快速排序/归并排序算法/ O8 f3 x& E* w3 C
    3. 汉诺塔问题* O8 U! K! U+ Q' b
    4. 二叉树遍历(前序/中序/后序)/ Z. @8 ^; u' l. y! K* |% D& o/ D
    5. 生成所有可能的组合(回溯算法)* g% ^5 x  Z7 `( Y

    3 T1 @: u+ b; G- m7 e: Z" _试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    11 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,. T/ s: ?+ M) p7 D
    我推理机的核心算法应该是二叉树遍历的变种。$ W: ?" h1 u) A, D7 X, N
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    . D" B; \4 w  P# s" S1 JKey Idea of Recursion! U3 S3 y: w6 j% t, q% C; G

    7 k, [: p# M+ u, g7 }0 Z) _' ]6 G+ \' u5 \A recursive function solves a problem by:! I/ @, r1 a7 e* v8 y

    % f/ d- K# i" K    Breaking the problem into smaller instances of the same problem.6 s$ V. t- B: N& c% O
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        Solving the smallest instance directly (base case).
    + _) d/ Z: @- P  j
    * p3 V$ r2 c: @/ D; P; `9 {    Combining the results of smaller instances to solve the larger problem.! T; o4 ^% g( R1 \& J

    / U' _" N8 Y3 e2 CComponents of a Recursive Function
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        Base Case:! U9 T$ U: E3 `+ L

    1 d+ X- ]: H* p5 F+ d! t/ y        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.. \: l& Q2 j5 |- i9 o
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            It acts as the stopping condition to prevent infinite recursion.9 B7 E7 m/ W8 f7 w

    , h4 B! E. t6 X2 ^5 n3 R        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.; a7 l& U3 ?1 g: Y; m7 G$ ~0 E
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        Recursive Case:4 i9 K7 n' _% Q6 k* H) [0 I
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            This is where the function calls itself with a smaller or simpler version of the problem.
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    # G+ h$ e* K9 {        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    : T( }" u$ \0 M2 W& n: p2 u4 n! d: S$ |! [% _2 U3 u7 O
    Example: Factorial Calculation
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    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    9 o- o. A4 [4 j: g( b1 g# S1 H6 F  j
        Base case: 0! = 1
    2 w; O5 d6 @: Q) ]7 t, ?8 V5 Q6 G' i, x
        Recursive case: n! = n * (n-1)!
    6 I. ?2 c/ ?5 i8 a; @, V2 X, `8 L6 I  H2 w7 ^
    Here’s how it looks in code (Python):  V1 \! Q! _$ r1 R- T
    python
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    ) W: M% r& z3 U( U
      K2 s; O8 C4 \- e( v* D) {7 jdef factorial(n):
    * d4 a: I1 l7 D: W. k    # Base case
    ( u( H. X1 u3 T    if n == 0:3 R. L/ w& Y: O
            return 1( M# c' y& l' j# I% w
        # Recursive case  T  t  i$ W' _1 ^5 i
        else:: n: Q" W) ~  n' j) ~0 o4 }3 o( L
            return n * factorial(n - 1)5 Q5 l& t5 ]8 K! R
    ' Q( x4 C; s6 q
    # Example usage8 x" \/ c" b/ ^
    print(factorial(5))  # Output: 120# D' n8 N  n- Y
    4 Y: v& d4 I2 O* ?) V
    How Recursion Works
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    , O' r5 R3 d5 Z* {3 c. M6 `    The function keeps calling itself with smaller inputs until it reaches the base case.
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        Once the base case is reached, the function starts returning values back up the call stack.- V* P/ T8 U0 ^- m( s4 e+ |6 A. @, B, }

    . @3 k/ w! ?7 T    These returned values are combined to produce the final result.
    . t% u8 R2 B8 g4 N7 T! I/ D; y; r# L
    2 O' I. z! k7 u. F! O: \8 KFor factorial(5):5 `' h3 z. l: Y6 W
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    0 x8 D) _: U0 K& w. ~; y0 u
    factorial(5) = 5 * factorial(4)
    " v/ ?' t8 J, N. Z2 g' Nfactorial(4) = 4 * factorial(3)& U, N$ M4 r) V- L$ I; _' q7 b6 F; M/ B! M
    factorial(3) = 3 * factorial(2)
    3 f- q& G% L8 `8 h* |factorial(2) = 2 * factorial(1)
    $ s" F! ?7 Z" M0 t" V: xfactorial(1) = 1 * factorial(0), t. b- @3 u# D5 N+ y
    factorial(0) = 1  # Base case
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    Then, the results are combined:9 O" O3 _& O* h) P+ T/ |% C$ G
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    factorial(1) = 1 * 1 = 16 c5 A. P$ l/ ^4 f8 B2 [% q
    factorial(2) = 2 * 1 = 2
    / F0 S! ?7 b4 ^9 r" b! ifactorial(3) = 3 * 2 = 6* B7 P( D' g4 ~3 V5 c
    factorial(4) = 4 * 6 = 24
    7 p, q. o$ Q+ g% I- |factorial(5) = 5 * 24 = 120
    8 H( ]7 e# l. T6 ?9 F3 t3 q' I, J3 D  B- c) w' _/ e8 w
    Advantages of Recursion: H" d8 |+ f) F1 v: H

    ' {3 m3 U4 _" Q- a    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    6 ~3 m- {: X% B. X) v& B9 }2 c/ V) ?/ A
        Readability: Recursive code can be more readable and concise compared to iterative solutions.# r; e6 I: ]& I
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    Disadvantages of Recursion0 ~* w( i% _$ A( \$ g9 j3 @- _
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        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.' ]: |9 z: }* {3 b

    * D0 w. }0 O; {# l6 i  }    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).* W7 g9 U# M3 i
    - _) I: e# j" f% l" L* h  |! a" A
    When to Use Recursion9 `) [& N2 ?) q4 o) x* J

    1 E- G. r, G3 p5 K8 w* |    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).! F+ }  s1 N2 g! r- n4 Y

    3 k' e" G8 I. \# `    Problems with a clear base case and recursive case.' v* u* Y. M3 M7 j" y

    ' z- L+ V; |3 f! ?- LExample: Fibonacci Sequence
    ( ^  s( R5 |- F, Q$ i: t! U: K- y+ |0 x
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    ; X0 M" {5 N) F: K4 D
    # N) d& G2 c9 C/ G# w1 B    Base case: fib(0) = 0, fib(1) = 14 G! r3 Q3 C% m
    ( A) j& e; o- l' [2 G
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
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    python: E7 t$ R2 [; {. E" P
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    : P3 A5 ^5 m- i) H" m! R# B3 U
    def fibonacci(n):
    ) q. \) _' C( [# U5 \3 d0 `3 U    # Base cases
    " [- Y6 z7 o# u: P    if n == 0:
    * ]2 |) p9 N) X2 v( ^5 Q/ M( O) Z        return 0
      U+ }" z7 S, u: P$ S% n    elif n == 1:5 p( S2 r% ~: R+ F) d* \
            return 1
    & F; n3 ]8 g# G& p; z    # Recursive case
    8 P9 T6 {0 f# M* n# M    else:
    * Q$ U; k$ S' j3 f+ q        return fibonacci(n - 1) + fibonacci(n - 2)
    ' g' ^* m9 P% T0 Z( R
    7 Q6 A. r1 H: n! U# Example usage
    * E5 {/ E0 u8 I# _) ?2 uprint(fibonacci(6))  # Output: 8
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    Tail Recursion
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    " G1 Z, h+ {: u! G( a1 s& w9 NTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
      b( j3 I3 T# }, h: k8 }/ `: o) D  U) x3 @" P1 p' A: W
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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