设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2431|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    + r% a! U) M. V; O8 x+ v/ s8 P6 P3 H) W6 B% m9 o
    解释的不错, a# l; X4 B, q+ T

    % \2 H! Q% u5 H- l+ P递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。" |. i' E, f: F7 K" u5 \$ S1 Q

    / y* d$ r% a3 X) H 关键要素) q) H; B( j: N- c5 b
    1. **基线条件(Base Case)**
    0 ^1 U5 n& R8 x. k   - 递归终止的条件,防止无限循环, n* Z: @- N( d, \8 i1 F" m' k
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1/ ?9 W% {3 L0 P  B$ v  u
    / t2 f6 s. k2 d7 o2 q" O
    2. **递归条件(Recursive Case)**1 K' ~1 X3 k8 T, _+ y$ H: I: U
       - 将原问题分解为更小的子问题
    7 @, N* ]9 S' w( b   - 例如:n! = n × (n-1)!
      |# j& \" w6 `5 c, q4 I
    % j/ Q4 s# ?5 r, @, @ 经典示例:计算阶乘; v" R4 j" f$ ?! ]; x# v
    python7 |; U) {- p8 @/ n8 O2 N
    def factorial(n):
    9 @1 j" o2 d* S1 ~0 ?9 X) Z& M    if n == 0:        # 基线条件
      u% d4 `" F/ l2 E& K1 p" j9 v# O        return 15 ?$ X5 O7 W1 X
        else:             # 递归条件# G9 P# Z" B! r  K! Y7 |( j
            return n * factorial(n-1)" g9 X6 Q) w& `& D1 r7 ^3 d7 o
    执行过程(以计算 3! 为例):
    ) k; ~8 T3 S7 y: w$ ]5 `& ]- o. w$ F( ^' Ofactorial(3)
    # A# L9 q/ P* m8 I2 E. _( Q3 * factorial(2)" k* `( y( e0 e! }" ^
    3 * (2 * factorial(1))
    ! T# P- ~: ?8 `* O: b0 r. X3 * (2 * (1 * factorial(0)))- I& w- s1 w% {4 d2 X
    3 * (2 * (1 * 1)) = 6
    3 h8 R0 x8 G6 [* B' V
    ; J7 m8 P0 s/ Y, M 递归思维要点' G) l: _7 h8 |( e
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑: C% j, R. k3 _
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)8 h8 r; x! x7 c; X4 ^  \* V% [
    3. **递推过程**:不断向下分解问题(递)6 g4 l. l* b8 {
    4. **回溯过程**:组合子问题结果返回(归)
    * a8 ?6 J" v  g4 C- i* Y0 `) ]. T5 r0 L9 E: }
    注意事项
    ' A; g- l* ^& B7 l- a- C8 }必须要有终止条件
    $ n% k; S4 _: t6 v递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    # {0 _9 s1 ^- O: C% m& n某些问题用递归更直观(如树遍历),但效率可能不如迭代4 ?: V" A% K" ?+ d6 E: w* |
    尾递归优化可以提升效率(但Python不支持)0 j  K* W; g! D
    ) h& {* n, s& \5 c
    递归 vs 迭代" r  t. u4 t4 D/ J/ f
    |          | 递归                          | 迭代               |% c3 x8 y: ]/ O! y
    |----------|-----------------------------|------------------|
    0 M# i/ O* b! u6 k| 实现方式    | 函数自调用                        | 循环结构            |+ G4 ^$ E" r1 v! k8 E+ n
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
      K& z( t, }& X  o: _/ j1 l' I| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |4 H" i9 ]4 b$ m6 s  O; y2 [
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |, l/ B/ ~( D8 V: Y' I8 ~- x; W( M
    * ]3 Y3 L4 R# N! E2 d
    经典递归应用场景2 e) I5 m7 M- `5 t2 x
    1. 文件系统遍历(目录树结构)
    - i/ L5 d( j" d/ Y' N9 r) T. V3 l- }2. 快速排序/归并排序算法
    % L; Z$ D. B4 }0 p- _* m3. 汉诺塔问题. ^- B1 {) _. H; P$ P6 B7 M( z
    4. 二叉树遍历(前序/中序/后序)
    * S6 J4 t1 E9 v  j9 |) i3 N5. 生成所有可能的组合(回溯算法)2 q, O; m$ |' E
    " e8 o" ?0 \  A. m4 t' R) b
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    擦汗
    昨天 06:52
  • 签到天数: 3214 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    9 L7 x6 ?  S5 o: a我推理机的核心算法应该是二叉树遍历的变种。. ]8 _8 u  x$ X2 F4 ?; r8 }
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:' U1 f# Q: Y) n5 r5 S" u6 k
    Key Idea of Recursion1 A4 i" q6 L& K* N, _% I

    4 N$ @6 w0 }. K- HA recursive function solves a problem by:' i) s! F; n" A8 b* E' x+ Y
    ) x& `0 w6 O& Q# g. c
        Breaking the problem into smaller instances of the same problem.
    7 V( p3 H6 K% C% S. ?! C4 o
    - I. w& n+ c) w    Solving the smallest instance directly (base case).
    2 W* ~" k, V$ D  Z3 ?; F: j( w: m6 t9 Z/ e9 A$ D( p& ]
        Combining the results of smaller instances to solve the larger problem.
    6 w  C7 u& m( J- t; X* s
    , X1 h$ C3 _6 R2 m4 j/ fComponents of a Recursive Function
    . j7 a2 J" G0 |6 @7 c
    7 W5 g' L7 D9 l    Base Case:/ W# A2 k" [  s+ c- H9 T1 j/ x

    6 [7 s# P6 g! v% R        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    0 t2 \9 s, Q% s, S0 ?5 e( K: U
            It acts as the stopping condition to prevent infinite recursion.
    + t7 ~' e. U0 m& M6 K; w
    , f' \/ C6 x# l& k        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.1 ~# f" [3 N$ P5 W2 N

    9 v2 g! V2 a( J, P: U    Recursive Case:
    - q! J- Q4 U7 {$ a2 s* ~3 _( f% W
    ! ~- J$ P: q# c9 @; U        This is where the function calls itself with a smaller or simpler version of the problem.
    % y, W8 `+ y6 R& A  F
    3 ~/ ]* }; j# h8 t! K4 q        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    $ o' y( B/ K. P! r9 p$ y0 X. e4 w4 |2 z" `
    Example: Factorial Calculation
    , b) }% |8 D3 n- G/ l
    0 b+ }, y! V* vThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    & m0 t6 D: h6 m) l7 V4 I2 [( Z3 N/ c4 z0 ~5 a  |' b: v' L3 a
        Base case: 0! = 1
      t6 ^9 _8 L8 Q, l, J) h: |" c% _" F; w
        Recursive case: n! = n * (n-1)!
    0 N8 q6 @( m7 G- S+ D; Q9 t' z3 g0 E
    Here’s how it looks in code (Python):
    ) b2 U. e9 s/ s- t- Lpython; S/ h3 s' s2 W$ f9 a
    / M2 Q$ v  Q: |6 y, e- s9 d
    + c$ X1 n  G) B
    def factorial(n):6 V9 d1 s; k2 U
        # Base case% u( G* n( z$ m  O: {0 W. e
        if n == 0:
    / }$ @/ E: T) P' m        return 1
    : m" _( A# t8 Q. @+ f- H    # Recursive case
    , Y4 d$ g+ K0 P5 x& q* O- V; P    else:% a7 K; q8 \6 i; I
            return n * factorial(n - 1)4 P% [$ K( N! d3 u. B
    / f0 Q- b# M6 ^' S
    # Example usage
    . d2 @! c+ V2 gprint(factorial(5))  # Output: 120. v( }4 E, j! _7 y
    / w  t) z. M& O# x$ `% [# l
    How Recursion Works
    % L/ E! G* R: `9 n. D; M+ \
    ( @" ?$ a, ?5 _    The function keeps calling itself with smaller inputs until it reaches the base case.
    # ]. _5 W0 o, B. ^+ b( \/ E
    + Y0 y  h6 I# }4 e    Once the base case is reached, the function starts returning values back up the call stack.
    - E; J* I' Y+ O$ m' f/ ^; l0 z" q! k/ ~% v
        These returned values are combined to produce the final result.
      u# P, u7 v" m8 o! O, {, N( R
    * P- z8 |1 {1 N- d1 ^2 V) U, aFor factorial(5):
    9 c$ v# B- x, B. F+ j8 `
    3 c& W! `& h# }+ P) e- e( d+ v
    , N$ y$ l; D5 m0 U& ?factorial(5) = 5 * factorial(4)* n/ d5 q! g/ l! B
    factorial(4) = 4 * factorial(3)& u8 N  T) r4 Y
    factorial(3) = 3 * factorial(2)
    $ H3 E' L! f% Z. T4 S# Afactorial(2) = 2 * factorial(1)
    4 ]6 B& R- S& o7 G& i- ]7 E, Nfactorial(1) = 1 * factorial(0)$ T6 [9 D& l3 Y: \5 \, J% x% Q
    factorial(0) = 1  # Base case
    4 z2 H: q9 c! [3 O& J. F- d
    - Z, j% w9 O  p2 FThen, the results are combined:. V& R7 n3 D- R: U) n4 Q6 L
    " g8 n1 |8 V9 @4 \" m/ J

    : b$ y7 ?( O6 T- ^0 O" M2 U) Z8 tfactorial(1) = 1 * 1 = 12 {" |+ D, ?2 ^/ j% B- m- F
    factorial(2) = 2 * 1 = 2
    & S' g+ k& y. |2 {$ G5 y. t6 `! |* Yfactorial(3) = 3 * 2 = 6
    1 c$ g7 k) M$ i& @! `1 u/ [( O+ \/ qfactorial(4) = 4 * 6 = 247 M" ^) j% t6 I* Y
    factorial(5) = 5 * 24 = 120
    8 s9 b, J$ t9 S. T+ S7 F7 S9 C, _% w5 r4 H" P8 S# D8 t- `  g# I$ y
    Advantages of Recursion+ C: m5 F( A7 x  ^. T% e: k8 [0 t' e
    8 Z# y: ~% H' o; d0 N% m
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    * B/ B* ]& r; \7 @) p- \. f3 J2 `$ W) v* e
        Readability: Recursive code can be more readable and concise compared to iterative solutions.9 }) v2 J( h' Y( h" r. Q& @
    : A) q1 Z- M7 p& n) U
    Disadvantages of Recursion
    ; i% {0 _, K% C+ c4 ]9 ^: ]
    0 R" m) }5 o/ p    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion., x" m* D! f; i8 R
    0 m2 x$ z. ?2 A2 w& z  T
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).. o7 k! Q7 G, v# ]

    9 S) L- L* ]. l0 v8 N, `When to Use Recursion$ d* M; X6 u4 J; [- B
      a% P4 S6 u6 P& L
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).8 r0 U. n; H! C5 |+ G  \
    9 G  _- }' f* R( S$ b
        Problems with a clear base case and recursive case.
    9 g8 s" C6 w7 f3 r% N5 Q
    : M1 b$ V# X7 c7 _+ {  l5 T/ BExample: Fibonacci Sequence
    / K: O, f1 ~3 q9 a1 A4 I' q( W& ?3 f, Q0 Q$ [, a
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    $ e4 V( r9 L$ q( ?; r  f* f
    ; y. j5 K% \! u. L; v- U# G! A    Base case: fib(0) = 0, fib(1) = 1
    , P3 B$ d7 Z4 S0 I( M, {5 v5 D* }" z' @' ]/ O& ~1 R+ n/ `
        Recursive case: fib(n) = fib(n-1) + fib(n-2)1 r. d6 H' M9 Y7 K: s

    5 g  R% T) q7 x8 _, `9 @1 c0 Npython
    ; X- s, Y! r) Z5 M+ S/ O  O  Z  E. B- i$ n% `

    , K. P. l& k1 G% vdef fibonacci(n):
    4 k0 E. U. s: L( [! A* H) J/ d) j    # Base cases. p, s/ B! {7 S/ N2 K
        if n == 0:+ d" }6 A2 A* w8 s/ w6 P
            return 0
    0 m- ~4 C- s9 K  f; u    elif n == 1:
    " g4 |! B' `! E) y1 a        return 16 Q6 ^1 \, h; E
        # Recursive case
    " Z8 ]) X7 U& T& i    else:
    . P; I- D0 D. E- x) L! Z: e        return fibonacci(n - 1) + fibonacci(n - 2)* [  e7 m8 C* p5 ?8 X% ^- ?
    " J4 F# s6 e1 l9 O
    # Example usage
    # Y* s  o- |: Mprint(fibonacci(6))  # Output: 87 I# K) n# C0 W4 E, n
    $ q8 n. L  x- S8 h. U! y
    Tail Recursion; S7 U% Z) _/ j3 L

    ( L" O' m' S- R- F* S# t' t9 P% zTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    / r6 ?$ ^# O- J
    . P2 `- A* q1 x, X+ x) X, pIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-4-7 04:08 , Processed in 0.054785 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表