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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    9 H9 m% w* ~0 Q) d* _: s$ s( t3 W9 {+ x2 C- ]% w/ t
    解释的不错
    ; J* U. F( b1 w! Z* N9 }
    : x) e6 k; w; g# M" S5 s5 s递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    : \9 E3 w0 P$ P1 R, T+ m3 O: K, _, H% t
    关键要素
    : @* {! p2 G! L# Q1. **基线条件(Base Case)**
    8 s5 \" K! y% l7 J+ f   - 递归终止的条件,防止无限循环# E0 a# H$ v& R' V8 I4 M( N# C
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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    ! u, q+ y, K) ~0 O0 f/ s0 ?2. **递归条件(Recursive Case)**
    1 P  s3 `( m1 N1 W' n: ^. b   - 将原问题分解为更小的子问题, [9 e: ?7 \( l9 A) Y  B. H
       - 例如:n! = n × (n-1)!7 o+ O4 Y+ J# w

    ) x' c' [5 {6 Q8 W; j3 S 经典示例:计算阶乘
    0 X# B1 A! P4 Y4 Z4 \python. X) ]  l( {! y+ Q9 Q. d1 N
    def factorial(n):: |- }# o5 \3 e7 a1 |9 ^
        if n == 0:        # 基线条件
    ! ^7 |. L0 n8 ~5 w; M1 p: U$ k$ s        return 1* u; B, h7 p% \# `- W6 e1 F/ H
        else:             # 递归条件
    " x9 g+ b; y5 F! k4 x  C        return n * factorial(n-1)
    8 h+ u# _+ Y$ D1 {# i* F执行过程(以计算 3! 为例):
    ' m) s) o( Q. F( E) j( x' f! g; Sfactorial(3)4 }9 B* x' Y( f
    3 * factorial(2)! x9 ~1 @$ y3 |7 P
    3 * (2 * factorial(1)); ~- e: n6 X5 ~8 k$ K
    3 * (2 * (1 * factorial(0)))
    ) v- k6 E/ }" y' g$ C3 * (2 * (1 * 1)) = 6
      \5 o" j  X( p; y% V' {
    ( o! j$ M" I% ]# l# D# ~  t 递归思维要点
    , s1 o* U" |' y7 K. z4 S1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    9 ~; k# Z" p! V2. **栈结构**:每次调用都会创建新的栈帧(内存空间), W% N& \' T& V& {  t/ o5 u0 _- r
    3. **递推过程**:不断向下分解问题(递)
    % ~7 A! u3 ]' Q9 z4. **回溯过程**:组合子问题结果返回(归)' M5 w3 f7 S% p2 p; a' @
    ; s6 c( J; l: a/ n$ N' M' F9 O
    注意事项3 K% P- X! c& g7 R
    必须要有终止条件) U1 Q1 N' p! I# e: j/ X
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)* W# c8 s! O" ~9 X% D( T
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    $ d1 v* \! J* ]- U2 A尾递归优化可以提升效率(但Python不支持)! F2 M* ~- k! q& b

    9 W3 T0 b7 _3 r! w 递归 vs 迭代! T5 [( F* Q' ^
    |          | 递归                          | 迭代               |
    $ r2 e) ]5 K1 l/ r|----------|-----------------------------|------------------|. y# ^4 N; C% L: G, B
    | 实现方式    | 函数自调用                        | 循环结构            |; S2 b0 n: X' C2 m4 e' e4 V
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |7 J3 ]( w% R0 B' y. }! l  D0 k" B
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |5 @; K/ {% j0 S; b9 X/ ^
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |/ Q9 k* F6 A1 _" D8 |$ [8 u& _+ `+ v1 M
    1 o1 E& M# I$ V/ k$ q: f
    经典递归应用场景
    & O# C- c! H8 z1. 文件系统遍历(目录树结构)
    ) A$ |5 ]# x8 V# X7 o# e( y+ ~2. 快速排序/归并排序算法
    # V& u( V% r% w8 h3. 汉诺塔问题& R, J" g* T- N, f; X1 D# D$ L5 ~! \
    4. 二叉树遍历(前序/中序/后序)
    6 [) D& O& u2 Q" f9 T# K5. 生成所有可能的组合(回溯算法)
    ; i  t. n  h+ N5 A  o! ]) T+ t& v3 F9 x( P; P
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    8 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    5 a; L& S$ |+ R我推理机的核心算法应该是二叉树遍历的变种。6 v& J7 i6 p5 e! D; \3 v/ l7 e
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    ' n  ~& K; n: ]* f1 ]9 }% zKey Idea of Recursion
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    % ^' D( D7 Z" ^$ i8 jA recursive function solves a problem by:
    : B$ m. H! R: x& N* A7 t% Y7 K. P8 t! N# }# l. y# a
        Breaking the problem into smaller instances of the same problem.: f, [$ Z" ~9 x+ y

    ! V. _- ^- b0 t/ B- U( |9 x9 P; z9 c    Solving the smallest instance directly (base case).6 Q! s/ w1 K$ B& {
    ; M5 Y, G3 ~, s3 {7 c
        Combining the results of smaller instances to solve the larger problem.
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    Components of a Recursive Function& Q* S4 L( S' e- ~" ]# B- @1 a4 s

    . _7 k; W% I, _9 S    Base Case:! f7 m& d. h7 x) C
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.. e; a3 n. _) \0 p" T( c+ I
    9 y' \  j( O5 P" k3 Z
            It acts as the stopping condition to prevent infinite recursion.
    1 ]! v8 B4 a1 b, g# r' Q0 \. \9 G" ?4 H
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    4 N$ I- s" h4 q0 @3 v: N    Recursive Case:* C7 f0 _; ^. }8 w& N

    * t  P$ Z( x2 V- n0 [        This is where the function calls itself with a smaller or simpler version of the problem.
    / r& ?) r7 o1 o. \. F, f8 f) Z( ^4 {
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    4 _( j3 t/ h3 C! ~  \7 ^3 t5 f' ]- Y& |
    Example: Factorial Calculation
    - ?5 _0 s' ]  @( ~/ C0 E
    ; I% X+ L& ]9 D* b; E/ p2 d* ]The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    % H, R; a5 I4 C7 ]7 ?5 O' ~1 G8 o) f+ X7 M- C$ C/ m
        Base case: 0! = 1
    3 U0 n! K% f( m" U
    - O1 [7 v" c6 K9 k* F    Recursive case: n! = n * (n-1)!' N% t# t/ K5 l8 }* y

    % p% L2 k4 v! ~2 ?  Z" v5 cHere’s how it looks in code (Python):
    : p% f3 [' Y  H8 b9 B$ ypython. P& W/ o* O7 L
    - M( ]8 l- K7 e! Z
    & V# n' C9 c2 M; f9 H
    def factorial(n):
    & Z8 w! l. Y# j. ~4 {& c    # Base case( |$ ^5 P+ x) O; G* \6 w; ]
        if n == 0:, g2 A7 w$ l. o7 Q
            return 1
    # \0 r) V0 o7 U( A    # Recursive case& ^4 q5 f( K* `) Y
        else:
    0 K+ z% ]- u7 y* S% T9 w        return n * factorial(n - 1)
    # {9 R/ N0 n3 U# t) i9 J( Q7 q
    1 y- N7 I/ q; u8 H# n# Example usage
    # S3 I# ~4 D' R$ vprint(factorial(5))  # Output: 120# }7 p6 ~; w2 T9 S3 j7 f3 ~

    7 P! V9 v2 v. }/ u5 \1 l+ i$ lHow Recursion Works
    7 W& Z. o7 ~" g2 e, x' ]# f: h9 i1 M. ?5 N" M3 u* @
        The function keeps calling itself with smaller inputs until it reaches the base case.# g* g( A& o  {

    " _! J; s% U, x$ D    Once the base case is reached, the function starts returning values back up the call stack.
    . t  a: s3 T, S. W
    6 i* K4 c$ d9 g% T+ Y    These returned values are combined to produce the final result.
    6 v; [# y' ]& W" Y3 Y7 X7 o( w
    ( z5 S7 M/ l2 oFor factorial(5):9 i1 D' D  U9 T0 J7 M# v4 a9 e

    + I0 U' F4 i1 W, ]% p- |; ^
    6 y6 u$ W7 K+ l5 pfactorial(5) = 5 * factorial(4); k6 C$ r6 D6 x! U: J! E
    factorial(4) = 4 * factorial(3)
    8 T9 [3 z1 ^: u+ N  l% M8 Afactorial(3) = 3 * factorial(2)3 q$ @& [  t9 z8 ^
    factorial(2) = 2 * factorial(1)
    ' e9 n: h, V/ Q4 g# ~factorial(1) = 1 * factorial(0)% \0 W% v% P3 H1 \0 Q2 c) ^9 v
    factorial(0) = 1  # Base case
    , e7 k9 ?9 Z4 p- l! e
    * c2 @- t8 m, H6 FThen, the results are combined:: E: x( A, b, Z/ r; S
    : [$ ~. B' ?6 Y# U' H5 [" M
    ! T; u3 Z' `$ _  }% L5 s
    factorial(1) = 1 * 1 = 17 \+ e: m$ d! ]* L
    factorial(2) = 2 * 1 = 2, S" ~3 F& ]' K4 S) S- B/ l
    factorial(3) = 3 * 2 = 6
    " w  f: h  }) \! S& {factorial(4) = 4 * 6 = 24
    - |# C+ c! Y, h# z, a: mfactorial(5) = 5 * 24 = 120
    . c0 j4 y4 @  l( J  H9 k3 m# M' a& o, b) z
    Advantages of Recursion
    1 J9 \8 C  @( h0 ~) T* k9 s' K6 A) \  u
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).  T; t4 r; {9 s0 \

    $ l) P3 D6 w4 m4 }* B    Readability: Recursive code can be more readable and concise compared to iterative solutions./ Z/ ?, S- K! u: Q% O/ L
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    Disadvantages of Recursion/ Z# f3 T  G- K' t3 d3 Z( w  `, o  Z
    ; R/ f: d, i: ]8 b: \1 o
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    ( L* D7 W% [3 T0 K  R# @. N1 R+ y1 G4 s2 a
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization)., z& u; v' s5 w/ [
    . m) t: b. D4 M/ N
    When to Use Recursion
    5 }8 N! {& c) @+ _" x, l6 p/ b4 _* s8 Y1 L) Y  n
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    # E# N& L( m! ?1 V1 ~& E  v% F& c. }0 D
        Problems with a clear base case and recursive case.& i% j9 p" ~- |- ?. i; L  i, v% F
    ; E6 C7 C, r9 ?/ q; }
    Example: Fibonacci Sequence& @% x% A0 U* v: N- G
    & W- E  G! ~3 p: d$ Z
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:- v" x2 q, e/ T- G5 N& r9 ^5 w

    5 M5 T* T8 o* Y7 L7 n    Base case: fib(0) = 0, fib(1) = 1
    + z6 f# ?3 a% j9 C: N3 q5 m" Z- _/ q) O% e8 J/ O- y
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    4 o9 s. N7 {6 y2 t' O1 G) U3 Y4 I7 `% Q' F1 C* n+ k0 ^0 ?
    python
    % P- I2 {$ t  Y
    3 W# d% t! ^" U( a; j  {4 d& v
    5 f1 ~; t4 a7 ddef fibonacci(n):
    : |$ N6 _" S1 Q0 X" F    # Base cases) l3 K+ B/ k: c3 ?" h* G
        if n == 0:
    % r$ j4 t  W) [        return 0
    $ {8 Q2 b" t/ c/ `" G    elif n == 1:
    9 c# t8 G$ C( h: `, t: j* {  S+ ^        return 1, P( m/ e1 H' ^4 b" B: O$ f
        # Recursive case) S* R. I6 C5 a- p- t! o7 r3 {$ `" J
        else:4 Z) s; g' s& w% o
            return fibonacci(n - 1) + fibonacci(n - 2)
    - M( k: M) l7 r1 ^; D7 V
    ) F! K3 G( b6 R' _) M: w7 q" U# Example usage
    5 O/ O. j6 h9 ~- `6 D, m# fprint(fibonacci(6))  # Output: 8; y* W: G5 t# }" n
    8 K* W2 F1 w0 s
    Tail Recursion. ^/ `6 h' O% ~  i0 ^9 T

    ( J& [; |& r+ {: e& w. B9 C* GTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    : T; X; N1 C# x+ O. e6 C/ a) W- U/ Y3 e' B8 c
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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