设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2411|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 , @5 A& ^3 i) U7 d
    ; h9 x. W- ]& ?8 I  H  `8 f
    解释的不错- b, n& z, j( x- u+ w, [

    & W, D. K# u0 ~; Z8 @递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。2 q+ |$ L1 m& f# N3 @  t, d

    - O0 F9 q5 i, p% j/ `% b1 i# X 关键要素& o4 K4 S- d! `, g: A9 [
    1. **基线条件(Base Case)**
    ! j. X/ [: S& E! k. p   - 递归终止的条件,防止无限循环! C5 f9 H- `) J
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 15 @8 u# W3 u+ K0 L

    & w; c# E" Z7 O2. **递归条件(Recursive Case)**
    ) ?) d# V2 |$ U7 s- V' n   - 将原问题分解为更小的子问题+ J- u2 r& |# m+ }  D
       - 例如:n! = n × (n-1)!; Y! X6 t9 u* W( X& f7 T" p

    ) C7 F  _7 W$ {2 V' ^7 j* S) {/ O; U5 q 经典示例:计算阶乘/ I' V2 e: S: ~6 t8 Y
    python
    / a$ ~; ?& H6 H* Ndef factorial(n):! v4 s7 l$ n2 M  L5 h3 l
        if n == 0:        # 基线条件* n4 ?3 q  J* r* D2 b; p$ t5 C' q
            return 1
    ! T; D& z. ~$ R# H1 Y    else:             # 递归条件
    5 e$ o7 d5 v  ^0 C3 E        return n * factorial(n-1)
      H/ D+ @+ [9 i5 l7 c执行过程(以计算 3! 为例):
    # \7 n2 p6 ^/ I9 ^4 M: dfactorial(3)% u) f  X# C& H/ A. c8 U5 }( E; E
    3 * factorial(2)
    1 [* W& h$ C( S7 u% b* T( ?1 O3 * (2 * factorial(1))
    . v' ~9 x2 F- p2 M0 b1 }3 * (2 * (1 * factorial(0)))
    & D3 z3 F4 L% {2 J/ ^3 * (2 * (1 * 1)) = 62 T" P; ]5 d' r5 S& l4 ~2 v
    ( u0 F" L$ T. e8 R  w1 J
    递归思维要点: d. v' [. W) _2 r+ l
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    9 y3 ]0 a% x/ a; T& ]( U, ?2. **栈结构**:每次调用都会创建新的栈帧(内存空间)$ t# f( [- R' u" z
    3. **递推过程**:不断向下分解问题(递)
    6 J- Y( B7 t9 L$ v1 Y( z4. **回溯过程**:组合子问题结果返回(归)7 W* K# U0 h! Y  k6 @$ |/ X; `

    9 ~6 V1 L5 j% \, K 注意事项
      F$ H7 \4 b. G# q. j6 L& @# w8 Y必须要有终止条件
    ; U+ V2 g5 C2 m; T0 C' p4 ~3 m8 w递归深度过大可能导致栈溢出(Python默认递归深度约1000层)! T* n1 l1 ^9 D
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    + o1 y' q: ~  ~6 T6 K# ^6 H尾递归优化可以提升效率(但Python不支持)
    , A9 K5 B5 C- r9 S, S9 D  d$ B# N" k
    递归 vs 迭代, W: v+ z/ ~# p) `
    |          | 递归                          | 迭代               |- i* R7 r) w' Z
    |----------|-----------------------------|------------------|
    - {: U0 ?  g, b- a# m# T% Z! j/ Q| 实现方式    | 函数自调用                        | 循环结构            |" \3 g; P1 _' q- [+ B. c! k
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ) l, G# q- T9 k| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ( s% W) W8 v4 U0 n: k/ j0 @0 z| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    $ h6 E/ C) r  G( d! X
    $ _- o* y% x: v- Y% L' Q* R( T) f$ N 经典递归应用场景
    ' ?% e9 C/ J' {, A3 z1. 文件系统遍历(目录树结构)1 e( y& l1 I4 H  _0 s8 s; G
    2. 快速排序/归并排序算法
    2 h7 |( Q3 y& Y2 [( ?( V3. 汉诺塔问题$ z% V; h" e+ ^0 i, i! o
    4. 二叉树遍历(前序/中序/后序)( Q- b2 Z/ p# `/ T- s& s& U
    5. 生成所有可能的组合(回溯算法), }$ _( a, L5 v& H7 A

    2 k, e. }7 q! q试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    无聊
    9 小时前
  • 签到天数: 3212 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,0 O6 a2 Z) Q; S' l& ~# f
    我推理机的核心算法应该是二叉树遍历的变种。
    5 \1 S  ~& a& v: Z另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    . e6 h$ N& h; _8 {. f! a! W9 xKey Idea of Recursion
    ; z4 M. C" Z- m& W
    / V0 _1 z; S- i6 Y& u7 h5 F! H$ VA recursive function solves a problem by:: ~& L% N" \+ L% l! E% x

    ( a( U! v; M& V& I/ J    Breaking the problem into smaller instances of the same problem.3 U7 t- Z+ w7 z# R* a+ Q

    + m* T& E7 G& E6 C8 G    Solving the smallest instance directly (base case).
    ) Y) X3 F, R& S; z
    4 U- y6 B% T  Q$ l( ~5 I6 f    Combining the results of smaller instances to solve the larger problem.
    ( E& n' Q- U, r# C
    + H+ l0 r3 |' @! n+ P4 BComponents of a Recursive Function1 B/ n+ R3 o- O0 _" a2 P0 l& }

      q# G* }: F/ T8 M    Base Case:
    0 K; Q1 C" \, A3 w5 }# f8 [
    - Q% a4 F: T4 s        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    % X& a) F" |5 a1 u3 W. x
    * r! O+ U2 m4 X( d: C+ o  n$ H; J4 g        It acts as the stopping condition to prevent infinite recursion.
    7 |* \: T9 V7 N# x8 C& b2 i. S  S
    2 q) U6 A: C5 A: e. c3 ~        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    0 M8 t" @9 n& e4 T
    0 ?2 q& N# {: b4 i' _5 y5 X    Recursive Case:4 c3 r4 K4 w/ @0 m
    / t( ^5 U5 ]5 {
            This is where the function calls itself with a smaller or simpler version of the problem.
    0 }( T* _. C4 D# E  N7 X7 Y# b9 V! x
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).7 L# F2 I  r3 J
    - U) X& M( h2 r6 O5 B/ M7 k
    Example: Factorial Calculation# ]- u; t0 o9 A! W! K& Q* S
    $ N+ u: K- `8 ^5 @" {! ?
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:5 E& M" V9 v' M0 r' C; l, [: t
    2 `( j7 V/ w8 C, H6 n( N/ `
        Base case: 0! = 1
    . P# {5 d- N: [2 A8 X* J/ H8 I6 Q& G  Y3 j  W+ g1 f9 c' {% ^
        Recursive case: n! = n * (n-1)!
    : N1 [- a/ G. o7 [  E, C. d, j6 Y' @! u% a$ e8 I
    Here’s how it looks in code (Python):
    2 Z$ g7 U+ c( M; |6 a$ T9 Ppython# f& g" g; @+ D* v. a# q: h

    8 }7 d' _% t* k: M  T; U
    ' R; V: x) D6 v, _. pdef factorial(n):- U5 I& A* M! K1 {
        # Base case2 E$ C& p* I- t' h7 h9 n/ S
        if n == 0:
    * G- ^" r6 A4 Q5 Z3 ?) y# e        return 1
    3 A9 g* p% x( m    # Recursive case
    8 T& A8 H$ D4 Q9 u( S% Z& E1 g) C    else:' x$ y' G1 c7 t4 H4 S8 Q
            return n * factorial(n - 1)
    1 ~& H0 D# T4 x8 K% o& [% R$ a6 W/ ^/ ~
    # Example usage
    + K! D/ i5 F& W' Z( h" F4 Dprint(factorial(5))  # Output: 1205 K2 p% `1 T, U

    8 X5 s% J# ~. ~5 S8 i" WHow Recursion Works
    - u" ~* a" a: F% R: I. _
    6 N- L1 W$ [$ Q: Q/ I    The function keeps calling itself with smaller inputs until it reaches the base case.
    / S, c# _7 p: V. R. E6 @  s5 m
    $ |, c' e7 r' T8 d1 A    Once the base case is reached, the function starts returning values back up the call stack.( c2 j6 O+ b: w% }1 k3 f0 x
    ; j, _4 I- |  o% H& U* G" g
        These returned values are combined to produce the final result.' V8 E7 O- p& g$ A7 j! R, `8 }
    & V" Y/ C5 f+ I4 m; A) b9 D. F
    For factorial(5):
    4 H, D, q' f! E# m- {- `& M5 M# _* B5 c( }" a8 f6 z
    . ?+ @% t* T! \0 F
    factorial(5) = 5 * factorial(4)8 H% m7 ~1 A! B9 F1 j/ M" L1 T- u
    factorial(4) = 4 * factorial(3)5 R. ^9 h1 S' z0 P$ y7 x
    factorial(3) = 3 * factorial(2)% p# U7 S, V# l0 G
    factorial(2) = 2 * factorial(1)0 G. [* f) [1 ~
    factorial(1) = 1 * factorial(0)& U# k$ c1 d( S$ o- H
    factorial(0) = 1  # Base case* S2 {+ t8 `" h% L% ]
    9 T& u7 E1 l8 }! X
    Then, the results are combined:3 V7 M4 C3 Y9 J6 |, P

    : K# ?* N/ |- s; g$ j5 |4 r1 X' G) p
    factorial(1) = 1 * 1 = 13 w/ e. v6 o% ~  X( D& L
    factorial(2) = 2 * 1 = 2
    ( L1 t' d2 w! s1 @3 x1 {% ifactorial(3) = 3 * 2 = 6
    # k+ z. w/ ?8 Z5 dfactorial(4) = 4 * 6 = 24
    ) i0 y( o( o! s( ]; i7 L- Efactorial(5) = 5 * 24 = 120
    + C% O4 i/ T' w0 I
    ( g! U7 Q2 L5 [; l& M1 iAdvantages of Recursion. x6 _3 h8 Y+ `3 F* r) x4 |$ N
    , }. p3 ?* {2 ]8 M$ J
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    * Q5 J. ~- h& d- }) ~7 g% b) r- k& c$ E* @: U, V
        Readability: Recursive code can be more readable and concise compared to iterative solutions.6 U: s! K. V% m2 R: U2 Q2 u- l9 |. R* n3 t

    ; K9 O  S3 W4 h3 R  ^( yDisadvantages of Recursion/ r/ t, S1 ^. h5 ?: Q3 h4 r  d
    ; f" D, o1 f4 H" t# [
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.- D( F1 K, M! F  I" a  P
    1 b" l, r' C" ~
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    " M7 e* K. y- k' C9 G6 [- R3 b: }# V" Z; D9 X# \9 T! k
    When to Use Recursion
    0 M8 r* t* v) j- l1 D1 X5 s" }( p; X( ^+ j, x, c% q7 a0 U
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    1 L: O9 ?) L) e4 s
    5 ?3 |+ P6 `# A( x4 b/ E5 Y+ E. S. u+ L    Problems with a clear base case and recursive case.3 ~2 O- Q5 E5 n, L; h9 t
    7 D! V+ k# u" ^: m
    Example: Fibonacci Sequence
    8 g! j# R& t4 ?1 s6 [7 a
    & W* P" ~  V$ L5 Y) @* qThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:# ^& G# b2 {$ Q$ F* Y

    0 x. \2 k6 t/ x* I( F0 k1 u    Base case: fib(0) = 0, fib(1) = 1. e. u. B, k" P' J5 k; H9 a$ ?
    / Q& Z' @1 _9 n, N$ A& r
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    ! k& B) D, W$ C4 \, L, O6 B8 V% a' p/ v. _$ U* D( v! p
    python
    0 N& y" G" R+ b' B8 U0 h6 ~: L9 A% U% M. c& ^
    7 E  I2 v$ Y& r
    def fibonacci(n):) u; ~0 y8 H  ^! q9 A3 F  {
        # Base cases
    9 F! Z8 c- c. B$ x) d    if n == 0:* D/ E' _4 i& C4 ^! q, x  a2 [! k
            return 07 k; z& W) Q( A: X0 u9 j
        elif n == 1:. W! g+ `* R" I$ n% J; {
            return 12 D1 T. H8 u" c9 N2 w0 \
        # Recursive case/ t# o3 r( f# ]  P: e+ W
        else:. M' c, H3 b! Q2 A' B
            return fibonacci(n - 1) + fibonacci(n - 2)" ~3 P  Q9 z2 J6 n

    1 W, h; U. h5 I0 o$ B# Example usage7 m3 G# p4 {: A
    print(fibonacci(6))  # Output: 8
    % k+ F( ~9 s, W/ V. X
    1 n6 l9 L8 s: V6 J4 c0 @Tail Recursion
    # w7 y' h1 s$ b1 M0 |, {8 c
    ' u1 l, }/ N& `+ MTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    2 }( V' P9 C1 \7 {/ ]
    3 o) ], B+ t  \* O' K4 dIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-4-4 17:00 , Processed in 0.063997 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表