设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2738|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 1 U8 Q" S7 Z1 f5 F  p' l
      ?. r) z0 t, v0 X4 O& P! s* w+ p
    解释的不错" a$ a, q- ?9 K7 n+ Q

    ; ^5 N: B4 n" z+ l0 K! @递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    ! g& n1 i8 ]  c- g' `
    ; k$ Z9 L7 s% L2 @ 关键要素5 ?9 M3 u; i3 J  {5 G
    1. **基线条件(Base Case)*** e+ i; p. C* q# g1 p3 _$ E0 F$ Y
       - 递归终止的条件,防止无限循环
    , l! P, O! c. W   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    ( Z/ b4 O1 w& p; V* ?
    0 I4 R+ k  }3 a/ e2. **递归条件(Recursive Case)**/ j& r! z$ b$ K3 I5 w! u
       - 将原问题分解为更小的子问题, Q8 A$ I2 a4 r# G
       - 例如:n! = n × (n-1)!! H5 i- \# p+ V1 N# [
    % `0 c; b6 i7 C; W4 {$ Z+ G( G
    经典示例:计算阶乘, i1 ~' D1 o) a% i
    python
    8 h. p5 f8 ^1 K3 a: ?! zdef factorial(n):+ l5 M) s; N+ y6 X) m2 N
        if n == 0:        # 基线条件
    0 a: i+ [7 C8 s6 k3 G        return 11 k, [4 X0 i  A( U
        else:             # 递归条件
    3 V  R8 x) p) W  c  n  m$ o$ E        return n * factorial(n-1), n+ @- d$ T7 {, R# t5 Q
    执行过程(以计算 3! 为例):2 t0 h7 F, H7 ?2 L: p6 D. B& s/ |
    factorial(3)7 ^9 P: k; t( C7 j, [
    3 * factorial(2)
    ' x! c' N" Y: W8 W3 * (2 * factorial(1))5 N* d/ k$ r; D, @
    3 * (2 * (1 * factorial(0)))
    . r0 E' R0 s) `- b+ C$ r/ F3 * (2 * (1 * 1)) = 6/ R2 S! f& ^/ {  f1 e
      H% N+ ?6 K9 f, ?2 v- A
    递归思维要点6 q1 q1 `% K6 K0 p/ T4 R$ x3 c
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑( n/ }; I4 y( T6 F, U7 `1 j! `
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    1 i: B+ P0 a5 t' d3. **递推过程**:不断向下分解问题(递)4 N5 ?7 {% x3 f" z" S1 K* t
    4. **回溯过程**:组合子问题结果返回(归)2 q9 z0 p; h2 d2 X  |7 G4 u" @4 G
    $ e. K2 A; c) I7 Q: W- M& u# O6 b$ Q
    注意事项
    ( m  S. g9 q* O% ~必须要有终止条件
    , l7 W+ X% L& k7 H+ I递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    + \) H2 N5 J" i! U5 _& F某些问题用递归更直观(如树遍历),但效率可能不如迭代
    4 g6 N8 Q' h9 \  {( B" Y7 c尾递归优化可以提升效率(但Python不支持)) G# D8 [1 Q9 ^* f* [1 H7 [

    6 q& l5 H# i+ o" P, O5 L 递归 vs 迭代
    ( W7 @, u3 b/ `|          | 递归                          | 迭代               |, F; O5 f# v8 w1 V5 C# I
    |----------|-----------------------------|------------------|
    2 a( P% q' O& {, e+ Q: M. O( b6 E3 }| 实现方式    | 函数自调用                        | 循环结构            |& a, Q* {- C) }9 B" y; S
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |' E/ t% m8 K5 T; r! w
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ) C* p0 N, K6 ~* {( Y+ Y5 }4 D0 R| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |' n2 u! R7 m2 D* {

    * _5 ~2 u: G8 N0 f4 P 经典递归应用场景
    / j9 g' Q! o. x2 u2 D1. 文件系统遍历(目录树结构)
    , L$ e  v4 u; I4 N% V% v0 x7 _( _2. 快速排序/归并排序算法+ N3 X% x. q% V  @$ s6 c
    3. 汉诺塔问题7 I; p/ `: U# f, m. S: H- d0 g* o
    4. 二叉树遍历(前序/中序/后序)) P2 ^3 D2 @8 z- v" W' ?
    5. 生成所有可能的组合(回溯算法)- B. @2 b4 L, C' R3 c3 q
    % Y/ s. S5 t+ M
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    奋斗
    2 小时前
  • 签到天数: 3244 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,9 R. Q% G( I6 |& @
    我推理机的核心算法应该是二叉树遍历的变种。% F& E4 y, M( h' b
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    % e7 F% V, L+ K. g( `Key Idea of Recursion% `0 X7 j8 W1 V) j. T
    * K6 T1 G- b% X
    A recursive function solves a problem by:: z( i! h% P" C! ?( ~) `

    ! ?/ \; j6 Q4 O+ u/ z" p3 w: ~* ]) K4 ~    Breaking the problem into smaller instances of the same problem.3 x' C- r6 w# b3 H" V( y
    : H8 s( N6 k$ |+ ^- Q; W6 I' M
        Solving the smallest instance directly (base case).
    # L" T0 H/ j" ?, E0 J8 \4 _0 `2 J
        Combining the results of smaller instances to solve the larger problem.
    0 |% \8 w  q+ J( J
    ( ^  \+ d3 R7 m/ k' _" h* F& S- cComponents of a Recursive Function
    8 n$ `: Y5 u8 `0 W% q; }
    % w" L/ D, H7 K9 L4 N' v. Y    Base Case:1 T* P0 f6 d: u/ L3 d

    % a9 o0 T! p/ g' M5 s6 a        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    " p% L1 }7 V6 T
    4 F7 ]  y% s' D, A* J% ^7 L        It acts as the stopping condition to prevent infinite recursion.% L4 d" b, B( Q' |% ^8 T

    ! Z5 L! b: }% `8 {0 ~        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    - w- o/ h" A5 }' z+ @: h  I: R
    / t$ @% K* i( ?9 x1 C) }9 @    Recursive Case:
    + W; D/ P/ M6 q: |% ]  @7 h1 a( G$ r; z
            This is where the function calls itself with a smaller or simpler version of the problem.; F* N- ]: e- [* Q
      j7 P$ n/ `7 r  |  r
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    & f! o) W/ g( u3 Q& ?* T5 ?8 X* a$ \% Z! u- ^' m) y) c8 x
    Example: Factorial Calculation
    1 F* s) S: _& ~5 p9 D0 R2 C  t
    8 [9 U7 W$ A6 p) E- ^- hThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    ' p1 e4 K3 R+ Z! x1 c' A0 s/ ?3 V' n% [0 G
        Base case: 0! = 1+ {/ ?6 F  _  A+ A( Z
    / F# ?$ m$ n) L6 R, Z- }; @
        Recursive case: n! = n * (n-1)!
    8 v; L% v1 v2 Z) |+ x" H( Y3 g6 L+ G0 v8 `& g  ~+ i) t
    Here’s how it looks in code (Python):; _3 A8 f/ Q/ y. }6 M9 o/ u7 ^
    python$ k8 x) i7 g; J( u8 s; `

    9 R4 N" e( g  b' n  F6 h9 N$ j3 {0 A: \! s: M% O" l/ h
    def factorial(n):2 j3 i. _% G6 {) k/ W  _0 R
        # Base case: C) |, y6 N8 Z; L
        if n == 0:( Y! p: w8 Y/ G: D9 V# |5 O- |- |: _
            return 14 O* V1 V8 n9 G
        # Recursive case
    ! P; F' E: L9 M+ Z0 P1 B    else:  Q0 o5 \) R, K$ L: I2 ]6 b4 ?3 E
            return n * factorial(n - 1)( i0 b) ~  }, {/ x& z$ x+ Q6 K
    ! g3 D; E$ L3 c1 s
    # Example usage# n: j5 W: `6 s* H# g
    print(factorial(5))  # Output: 120$ K. f% E$ X# [7 o' @
    ) U0 p5 }& u# p$ c; D" T3 }
    How Recursion Works7 M; g2 Q! w* v9 l" W

    * A/ l& i; \* H" _0 X    The function keeps calling itself with smaller inputs until it reaches the base case.
    ( l4 b+ Y/ a' H1 Y9 Z$ @: a+ s) @- s; P( ]
        Once the base case is reached, the function starts returning values back up the call stack.
    ' ^. |! V7 v. j# t
    0 x: s/ Z( \& y1 `: X$ J    These returned values are combined to produce the final result.
    : n' f& `7 I% Q  m. c* I0 ~2 P  O& X, f# N7 p0 ]2 [% _2 a
    For factorial(5):
    % [* V/ w6 n  a2 s$ f, n
    5 [  z0 q0 ^; _/ [$ Y+ d
    1 }/ C4 f- G) {6 y5 Efactorial(5) = 5 * factorial(4)
    9 x% Z/ g9 B% L. |factorial(4) = 4 * factorial(3)
    ) H& x. Q5 u+ ~' E4 q" S+ F4 k3 R; Hfactorial(3) = 3 * factorial(2)
    ( {! |0 d2 V  c4 E% h/ Yfactorial(2) = 2 * factorial(1); Q6 r9 S, l: L9 t1 m0 S- o% F
    factorial(1) = 1 * factorial(0)( \0 _/ x- G9 [/ o, E
    factorial(0) = 1  # Base case
    6 M% g* a9 D, ?. |) G" }: _6 n
    4 f* x' }/ E# z) R! L# S2 {8 NThen, the results are combined:1 c  L4 ^% t0 F: k

    ) k/ M$ J' z+ `# p# a; j& W- l+ g
    factorial(1) = 1 * 1 = 1
    ( U7 I2 Q' X2 |, |/ jfactorial(2) = 2 * 1 = 2
    ! m% B$ U) r- I4 j- h1 ~factorial(3) = 3 * 2 = 6
    * Y8 e1 o, z; Hfactorial(4) = 4 * 6 = 24
    5 T& v( P: i7 C, i! Afactorial(5) = 5 * 24 = 120
    , b& n+ Y$ ]2 c4 h9 }' P9 L6 Y/ I, t3 ?% R* k8 o- p
    Advantages of Recursion, [  q* ]. _: S! ]

    ' O( B) R% c+ N& V5 J    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).* y% @' M/ {/ j8 t" q4 D
    ' }# v, e5 N; S. a9 ~
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    " C' y4 u1 F0 a- k# Z
    ( A- W& X, }* b5 d/ FDisadvantages of Recursion
    ) b8 m) q9 V) d$ Y. }" a, ~+ _# `& o4 e: D7 {0 s
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    : M6 Z9 O$ o' @4 X* ^  X
    ! e* l% q) R4 n0 e    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    % I. X" |, A; e( {/ v. k1 |% d4 z
    ( V7 ^) {/ Y; ~7 n& I4 H# q5 KWhen to Use Recursion
    ) Y: K5 k' g1 P# e! G5 w& O' u* z& V6 K$ H
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).; M) V* f; F  t* X) L! ]: H3 s3 {

    * ]& I# \" [' x3 B- B! d    Problems with a clear base case and recursive case.
    ! b$ D4 G& d& k  W% A1 ~. y* N* I! u' H; q; O/ ~) h
    Example: Fibonacci Sequence+ @+ P- _3 A9 X) q2 a& T8 I# W/ L

    5 Z: v( X5 \4 O' m, I4 r  XThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    ) i% a0 Y; K$ m0 m5 ~& y$ n: L
    8 s1 j6 N) |8 i# ^/ ?& ]6 C    Base case: fib(0) = 0, fib(1) = 1
    % d2 N- j. W9 t. M/ `/ E  ?8 B0 H( {5 Y3 G) s1 p
        Recursive case: fib(n) = fib(n-1) + fib(n-2)% [" V3 A- }  A' p* B2 j( ^
    1 t1 ?# |' h; _
    python
    6 W& z+ C. j8 j2 d
    ! U4 h' R8 }- m( |4 _& g4 N% i! q2 `5 c- W4 W) n# S
    def fibonacci(n):! ~: `, s1 ~* e+ T" Z: ?
        # Base cases+ e1 `$ Z7 d4 e, p0 R3 f) y
        if n == 0:
    + ], Z7 a3 v9 R9 ]  w$ z- z        return 0
    1 w' g2 C# E: l" a    elif n == 1:( f5 k+ d7 d8 S" ?8 @% {
            return 18 n8 C8 h* P( A9 x- A
        # Recursive case3 o7 j3 q" S& E1 f8 z. l
        else:. Y1 Z! F) X) J
            return fibonacci(n - 1) + fibonacci(n - 2)3 ~1 d! |' S9 s5 ~

    $ f, I0 ]8 ~; G# Example usage. v5 T, I0 Z0 h; L* q2 y5 B
    print(fibonacci(6))  # Output: 8* U& e0 [9 ?$ y% A" |1 m& I
    5 R, _) l9 D! G. }9 Q1 G3 w
    Tail Recursion
      `3 N/ L1 ~0 R1 c
    / [/ F6 }$ q& A  x* gTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    3 n( `  e" b& X  x
    : K! F" q3 Z2 _In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-5-20 09:23 , Processed in 0.056249 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表