设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2723|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ) p; y( Y2 x& Z$ l
    / e1 W9 @# D: e1 D" c/ l" F% E
    解释的不错6 c- i! x8 U0 ~- a
    ) p; n' M) ~8 U  g9 ~) ]  d5 ]
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    , ]5 h( t' g+ B
    9 l, t0 V$ g' [. j% N 关键要素
    / f, K* V/ r6 ^7 P$ s; N1. **基线条件(Base Case)**
    & X* F$ P! J4 Q' q3 y* [; }   - 递归终止的条件,防止无限循环
    3 B' a9 o2 j  O" X+ @   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 17 b! a- d) M6 u0 G& H
    5 s+ _4 @  A" P* ?' G/ l
    2. **递归条件(Recursive Case)**
    7 B& T/ I7 _' p' O% e" m   - 将原问题分解为更小的子问题
    ( b+ H( M$ I6 E0 a7 Y% ]5 ~% Q   - 例如:n! = n × (n-1)!" F1 t. H* c( h0 }" `6 R2 _

    # B' S: k+ g7 P 经典示例:计算阶乘
    " r* t" r" ^% [9 D* g0 f/ ^python
    ; j6 c- [7 |8 e' R  |def factorial(n):8 @6 O  a3 y/ c/ U1 y
        if n == 0:        # 基线条件9 p2 O& N* Z: R5 _
            return 1
    / F& o0 V8 H5 m, I3 a$ T    else:             # 递归条件5 c% L8 A+ h. S
            return n * factorial(n-1)
      s3 Y9 h* {' E* r: h0 B执行过程(以计算 3! 为例):( I/ o6 j+ o1 u9 c5 ^3 L, p
    factorial(3)
    4 C8 G* c2 x( b& u0 W$ Z3 * factorial(2): M) ]' R: y$ H6 R. M1 w9 u* Y
    3 * (2 * factorial(1))8 M3 m4 U/ y! X  d  C! W
    3 * (2 * (1 * factorial(0)))
    1 Y! ~1 O0 n" D0 Q9 U" d3 * (2 * (1 * 1)) = 6
    9 ~* f4 ?, Y. t+ |- \% ^4 h4 N( D+ D( i* d3 N/ H% |: ?& A
    递归思维要点) i4 I. `" u0 x) V' q) [  s
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    2 T$ X1 O! o2 b( s5 y3 {* ~2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    2 r+ U0 @# z& }4 {3. **递推过程**:不断向下分解问题(递)# m! B$ V- o% S. c
    4. **回溯过程**:组合子问题结果返回(归)1 X. F6 h# B* v+ v
    1 x+ x# q0 Z# J; G( L8 R7 {5 U* M
    注意事项/ Q  I( |3 q' H: A; ^: ?/ A
    必须要有终止条件/ g1 ^6 {* f% c# V8 W; V) |1 d
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    + k' {/ o" D5 B1 [( g8 `某些问题用递归更直观(如树遍历),但效率可能不如迭代. q  j! f/ v! l, {
    尾递归优化可以提升效率(但Python不支持)
    . o4 t6 |- y3 @/ I# ^' L, Z5 f2 i# V3 O/ L1 `- h: I
    递归 vs 迭代
      x9 J+ z! N& R|          | 递归                          | 迭代               |& @8 b5 B" ?3 }# A$ p5 ]9 s  T
    |----------|-----------------------------|------------------|
      A) d3 \% [* q5 Y| 实现方式    | 函数自调用                        | 循环结构            |6 p( s$ N3 m! F+ b1 Q' z5 P5 h6 \" E
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |0 ]0 N8 F) ?8 w4 x' ~+ Z
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    - T) I. q2 B4 l0 w# L& I4 q| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |; @" z# N2 M7 v% e9 ?. }

    - R3 Q; T7 k0 A! {' x 经典递归应用场景
    ! j; J  L7 d1 v1. 文件系统遍历(目录树结构)
    ! O1 _' u/ `1 C* n* w# A0 V" m2. 快速排序/归并排序算法
    1 Q  }! R. o# t* H2 [3. 汉诺塔问题
    - u) G3 i; k# x1 {4. 二叉树遍历(前序/中序/后序)
    + s; Z. D$ ]1 \5 l5. 生成所有可能的组合(回溯算法), V1 X& ]4 N% f# y4 `! Q0 _
    9 z' j( }7 N- U/ U
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    慵懒
    6 小时前
  • 签到天数: 3242 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,% q; S2 S) A! N5 U0 W' J8 z5 J* C) }
    我推理机的核心算法应该是二叉树遍历的变种。/ l+ i1 h* \! T( s2 i/ J
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:6 f7 S  \0 U% P# K8 @" u
    Key Idea of Recursion% Q7 v" k3 N4 j' x3 Z
    ) [. n5 X2 H4 ~7 \" Q; S
    A recursive function solves a problem by:1 ?3 j1 B/ B8 g6 t8 E

    - j% a3 k0 O, \    Breaking the problem into smaller instances of the same problem.! I7 W4 c* a, C& i
    8 r" T6 J9 z' n0 j* I
        Solving the smallest instance directly (base case).
    ' p1 S2 j/ u6 Y' F1 q( B+ b* U: d7 l1 e0 u' y  T; X
        Combining the results of smaller instances to solve the larger problem.
    9 }) V4 @- f) v" m( `$ {5 E! v  r* T  J
    Components of a Recursive Function
    4 F% u8 |, @. m& ^) t% l1 O/ f, V1 }! i$ m3 x% @
        Base Case:
    5 a9 Q! ^" `2 L+ v  Y
    ; }  n# x1 |4 ~. X% \. ]. l        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    * [4 Z- Y% m2 b
    * L7 \6 {0 y/ b1 Y6 Q: b        It acts as the stopping condition to prevent infinite recursion.
    $ c' {1 H0 w4 j/ V4 j# p, d  u  u3 |9 Q  y, J
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    : W) F+ N/ N" h& c# I2 g
    ' H$ i1 M6 @! m0 ~! v8 _9 D/ S- e* d    Recursive Case:# w7 v+ t8 Z' o( U4 }, F
    : ~, o9 e# b0 ]/ d
            This is where the function calls itself with a smaller or simpler version of the problem.
    # B- M/ ~1 y/ ]: v8 l, ~: V3 f0 k$ Z2 a/ m3 Z
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    6 ^6 l' a+ k  X/ f  C5 p' L2 ?' `0 P* b0 l; K" `
    Example: Factorial Calculation
    ; n4 j1 F2 _& q7 L5 t2 G: c& B1 K2 a0 T! M2 e6 }7 w
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    * b$ g0 h  e. E( v1 d$ k+ K
    6 S9 |" i  h* I' I2 I( C    Base case: 0! = 1) ?8 [( X* j- m5 t
    7 j' x# C, `# S+ h
        Recursive case: n! = n * (n-1)!* b! v  I( ~/ ?- S6 _! D9 \6 n. M0 h
    3 _. I- H8 R  b% ^, b  P4 ?. i5 b/ X& K
    Here’s how it looks in code (Python):
    1 z% b" L. i: Vpython
    . y/ a# z8 z* Z9 V! H
    3 n. I! z9 A! o1 ]; w- s7 P- G
    " \  `, ~! [( Z' G2 Mdef factorial(n):, V$ U3 k" Y* V% ^
        # Base case) k) U9 C: S( E, F9 h( C
        if n == 0:
    4 t+ e: [( ~6 L0 J, \        return 1
    % o( Y! X5 a5 D" O+ A* r3 I    # Recursive case' c0 S  T" S/ m+ o( C# c* V/ Y) ~
        else:
    , i& T) b" V. H/ {# Q        return n * factorial(n - 1)
    + e0 ~9 h  E9 ^3 t& S! @% s% e+ ]$ _( n! {' `3 Q
    # Example usage
    - X+ t* g4 k0 X- U) [print(factorial(5))  # Output: 120, A6 v  G6 o+ E* H8 C, |

    1 J1 ^" q! C6 H* yHow Recursion Works" `) H# V. H& z: ]: j
    2 O8 c: ]/ I& Y! ]
        The function keeps calling itself with smaller inputs until it reaches the base case.
    ' \  k+ ?0 h+ l2 d- x
    9 B5 _' ?/ D/ |$ ~    Once the base case is reached, the function starts returning values back up the call stack.
    # D! x: T' A: u! O9 k! A
    & k: e7 T" w! {/ p( L5 O    These returned values are combined to produce the final result./ ]0 g9 a4 M, N; m$ H

    5 `* ^; O+ e. D/ PFor factorial(5):
    0 m. g; e  S" w4 ?
      i- c' u) T" ?0 X+ R) v' D- `; U3 E: u/ b+ {. L5 c1 H5 D
    factorial(5) = 5 * factorial(4)
    5 C& ]2 _/ r- x8 M: H5 u. H3 ufactorial(4) = 4 * factorial(3)  q: m; |6 x  T* b- O3 I
    factorial(3) = 3 * factorial(2)3 Q' Q  t& v1 N
    factorial(2) = 2 * factorial(1)
    # ?5 G7 J" U, J0 M, }factorial(1) = 1 * factorial(0)
    : M* h! m% y4 @/ e5 ?1 a% ifactorial(0) = 1  # Base case
    / E$ I5 S6 H, c# r7 r/ m1 _6 B' ?: O
    Then, the results are combined:
    ' |* ~' M2 w, K6 @
    % D( d* N! G7 o7 }% v4 G) P( ?1 H; W
    factorial(1) = 1 * 1 = 1) S6 ?3 F+ Y; P8 ]
    factorial(2) = 2 * 1 = 2
    - S5 E3 ^6 Q: I8 Nfactorial(3) = 3 * 2 = 6
    ' I  i0 y& j" Qfactorial(4) = 4 * 6 = 24
    % z# P6 K1 t6 L7 |& S0 Gfactorial(5) = 5 * 24 = 120
    ) h) C( B, Z; E$ b
    8 r+ z1 N/ w; ^Advantages of Recursion
    3 n8 n$ c2 l& H- U7 a( H+ V) `* O. w# l1 Q  m
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).# \5 _% ~! \- B4 N

    ; u' J+ f) H  c/ L7 b; [8 e: f    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    1 G; _/ x" |- R- C6 v: z; ^
    6 R6 ^  D. H9 o  K. JDisadvantages of Recursion* H; ^$ a5 e: B, p

    # X, G8 {8 t9 P    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    ! j: Q* c& ]- e: Y" F( I/ e) x/ S, Z0 n& L7 Y  ?
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    & E6 K0 \$ o' L+ q+ l" M0 B
    : T% T3 [2 ?4 b! ^% pWhen to Use Recursion
    6 i, Y& f8 Y! P- \; u1 Y+ @: y
    ! I7 E+ K+ i% P9 v    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort)., K4 s) I9 Q! U/ G# N
    ( P6 j( |. S, C% ~
        Problems with a clear base case and recursive case.& Q1 W/ _, p8 w# o
    $ e  a4 Q3 D9 I, X% u# p+ K
    Example: Fibonacci Sequence, m2 X  b8 v+ |* z% Q

    , @8 L: S$ J& fThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:0 D0 y+ b) ?! Q  k4 m, [
    # F/ L3 `3 I/ ~* c8 T
        Base case: fib(0) = 0, fib(1) = 18 [' O/ o' Q4 Y5 w7 }" w0 A& T
    * p7 t" k6 t/ v# E% |+ [% i4 `3 O. a
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    9 `# E1 o$ l0 P4 M' k
    0 |$ ~( h; Q/ `/ v* R! m/ Rpython* _; }3 G. l, ^

    / b+ m6 Q& [8 C$ u0 e, y, q( ?! a  y; z+ y0 m
    def fibonacci(n):5 b; `8 p, v$ i% T0 h0 k1 [3 ~, y( v  k
        # Base cases
    # j' \: t1 N7 p& B    if n == 0:7 N; y- G' @/ D
            return 0
    3 D' Z! F  x; _    elif n == 1:# J, T  a1 t1 N* ?
            return 11 b7 t/ v, N- k9 l- X  X
        # Recursive case
    0 Z6 p9 _- F$ m    else:$ X) }/ C, k8 d5 _$ p4 a( W
            return fibonacci(n - 1) + fibonacci(n - 2)- A  Q& i1 j4 Z' U/ A

    9 J" p$ v, R  C, t5 R# Example usage
    " c% U# Z& w4 l+ w2 M/ yprint(fibonacci(6))  # Output: 8
    ) P& Z, k( l1 R7 O6 @
    & r9 K8 ]& n" v& p2 B) U  l+ bTail Recursion
    & U. j+ w+ T* y( u( M/ x; F4 x7 W  \) _. d
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion)., z# i' d( V! a+ ^4 _0 [. z" G0 T

    + `  v5 _9 S7 m( u* P+ WIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-5-18 13:31 , Processed in 0.065556 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表