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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 * b6 K9 q, o! P9 [% o" E
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    解释的不错! P& w& F1 Q* Z4 z7 \* u

    ) g. k, h7 V5 I7 M& i+ R* X- n递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。: U( {9 E; R' J3 o8 Q
      E8 i' b/ _$ _- }: p
    关键要素$ c# S( T* t7 ]8 N3 O$ ]. m: O
    1. **基线条件(Base Case)**6 b& r7 m2 U0 r* o- {
       - 递归终止的条件,防止无限循环
    6 ], z! U0 W4 O8 z. m   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 16 z8 D# V! `3 F( |& P. Q

    & d' v- V2 t9 f- N2 t4 c2. **递归条件(Recursive Case)**7 @; b2 Z+ {7 d0 ?
       - 将原问题分解为更小的子问题( L* P8 w6 w" m1 T& f
       - 例如:n! = n × (n-1)!  W+ U" i( m# ~+ {8 f/ P
    , `6 x* R: t# q& ?
    经典示例:计算阶乘' h, X% h/ D9 G
    python
    " j! o  r8 y5 gdef factorial(n):1 {* F* _0 D* r; z) @
        if n == 0:        # 基线条件
    4 Z  X& V( Y1 e" V        return 17 D; K2 U+ t" C" B
        else:             # 递归条件7 u# v9 X7 L, |
            return n * factorial(n-1)
    7 @8 L# c% Z6 O2 I/ V执行过程(以计算 3! 为例):
    0 A0 e  g2 S/ M* `0 _factorial(3)
    & U) O/ a1 s% W* A: V6 o4 Y, f) |3 * factorial(2)
    / b  [$ x* I: X+ w  A3 * (2 * factorial(1))
    - h: D) `3 O# ~/ U: A3 * (2 * (1 * factorial(0)))
    7 A7 O$ T5 h, P1 G7 l- l3 * (2 * (1 * 1)) = 6, Z* P" u$ Q6 n% n6 u/ G# Y0 g

    1 P0 H  b* ^. Y 递归思维要点
    7 k" [; W+ a3 o/ o& s1. **信任递归**:假设子问题已经解决,专注当前层逻辑% N! a1 D& C" o6 z) R4 F
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    0 ~! X9 F; ^+ K3. **递推过程**:不断向下分解问题(递)
    & w# D. q$ Q& u9 Q" e7 d4. **回溯过程**:组合子问题结果返回(归)
    ( `, `& w8 D8 K' N
    ! g$ y) h1 i# o 注意事项
    5 w5 n$ z0 s. q9 F% q必须要有终止条件1 ^* m: \# W* }
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    % K8 _6 e5 ?; w+ |8 |6 l& D* S9 Z某些问题用递归更直观(如树遍历),但效率可能不如迭代  \% v6 A1 f. A' t
    尾递归优化可以提升效率(但Python不支持)
    * Y1 `. M8 s! [& h6 C
    3 I$ b- v* ~0 L' }  b 递归 vs 迭代) ]8 D( O+ |6 q% F  k; c3 o
    |          | 递归                          | 迭代               |! v3 j, n: H. \& o$ E
    |----------|-----------------------------|------------------|( f- S; R8 Z  N: L! x% `) W* q5 e
    | 实现方式    | 函数自调用                        | 循环结构            |
    0 o' |) J7 K; e9 F| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    & S9 H, R+ B7 m& y9 J" n| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |# w# g4 h3 @+ {4 U# I1 Z) A
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    - _5 M2 ]4 N5 {/ _
    ' W9 G' j( Q# l+ H: H- i$ ] 经典递归应用场景
    - `+ v; d; \# W( C- ~1. 文件系统遍历(目录树结构)
    9 e! v6 l6 K  v# M' j7 W, L' @2. 快速排序/归并排序算法
    9 t& J) Y& {* p: b# C) l7 }3. 汉诺塔问题
    3 F% n/ j9 j! d6 M2 P7 m3 ~& U  I1 d4. 二叉树遍历(前序/中序/后序)
    # E, r, j9 F" q/ ~7 {% i0 k2 d* O5. 生成所有可能的组合(回溯算法)7 \* F9 K' Y/ r5 i# i  P- U
    * P: p; R, B  s: q
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 09:26
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    : z% S* P" [9 t" F) o我推理机的核心算法应该是二叉树遍历的变种。
    6 q; V3 a6 X9 @8 S3 L, Q  a另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    $ ^* x5 _8 J( t9 w! }Key Idea of Recursion
      F* ~0 a( V$ ?& i3 x3 t3 ]8 D1 f0 c* V8 }- }
    A recursive function solves a problem by:
    5 ^. M+ E) E/ ^7 Y
    / Y1 c! ]+ T2 g( q1 R7 H/ v    Breaking the problem into smaller instances of the same problem.1 \) E5 Y: u0 M3 n

    0 T4 H' H2 h) O, t9 z    Solving the smallest instance directly (base case).6 v- P6 M- _  J% p$ q

    1 @/ U7 w% D1 G/ c" u% E5 o    Combining the results of smaller instances to solve the larger problem.
    $ _! E/ K2 _/ Y" Z, k4 w+ \7 R0 |! F4 i4 @; T: x+ u' `# t( t0 T* U$ J
    Components of a Recursive Function% A8 j3 L$ w1 N. ?
    3 @7 Q9 U) W- N( G5 b
        Base Case:
    7 u& u- [; g4 r) R, X
    , I* g6 h! V7 e$ `2 x4 v! J        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.8 C& F' M$ W5 H) w/ V# @

    , o* ]6 C; S4 m  U/ N% j! a        It acts as the stopping condition to prevent infinite recursion.
    # b" ^% e! @' j2 ~% |. b) {: l  ?; h
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    4 a  e; }7 D; p3 f! I8 q. \
    * z6 F! F* H; [4 Z' g1 [4 a1 `1 P4 j3 \    Recursive Case:
    8 r8 ~, L! e7 ~1 x  m# @4 {3 P8 d/ r. p7 \3 f
            This is where the function calls itself with a smaller or simpler version of the problem.
    & h& l# H& D9 P/ N% X- q3 W9 P# b7 l  G7 [
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).3 m& F& q( G& v* {# `

    0 }" s# M! s! Z+ F0 T0 Q( ^Example: Factorial Calculation2 x! y. l& [$ X- Z: w. ]9 G

    5 F+ x/ x! d: i0 nThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:5 D: h$ G, h. s' f( Y
    & y! H& A- |+ \+ d9 U
        Base case: 0! = 1
      ^! W! l$ f4 T( F( [7 o0 W8 |$ M. g, @9 r) h6 h) D1 J/ ?
        Recursive case: n! = n * (n-1)!+ i; z$ p  v9 I: o# @4 `% ?9 o
    # V4 n$ J2 N  b% I  L1 C
    Here’s how it looks in code (Python):9 r7 ~2 V* n" q0 E
    python0 N4 _( u+ _5 U! s

    1 Z* F1 r+ U! Y$ w9 Q2 X% q" a5 [9 o. l7 f
    def factorial(n):
    5 j+ I5 q7 e% @6 _* C    # Base case
    5 l3 ]* k. q; ~0 ?4 z% y( g( ]5 X$ T    if n == 0:
    & o, J, Z( A" D7 d  y) q; U( G        return 1
    $ H9 {# Q& I, ~  F& J) p    # Recursive case
      f$ V( L8 d# F$ f5 Q    else:; \6 D" v7 Y" m( D
            return n * factorial(n - 1)
    + x7 @, g* g, x: x/ v/ U" a; ]' g
    $ `, K( _( o3 Z6 {) ^# \2 Q9 p# Example usage
    & M9 Z5 m* A" T# j8 F9 T7 P' S' Kprint(factorial(5))  # Output: 120  u: v" e3 B  m5 `. Q9 W
    . u0 r4 f6 Y) t9 s
    How Recursion Works
    ' m# ]4 ]. J+ L9 ~4 l" A7 Z
    0 U8 Q/ n# Z5 [" L2 x; I, s    The function keeps calling itself with smaller inputs until it reaches the base case.4 m( x% s/ C1 F& a, H5 [# }" P" `

    $ I4 R  M2 P+ m( {% {! U    Once the base case is reached, the function starts returning values back up the call stack.* V* z* a; g! g; V5 m4 ^
    / x  q- y: {: T4 h4 D6 G
        These returned values are combined to produce the final result.5 |/ s2 K; z# Q: l  C% j

    % j7 z" `5 F* o- w& [For factorial(5):
    ! L1 t1 c& L! f5 T: j: _& A9 a3 i! @/ i5 w
    ( E, ~! x) v8 P/ f- b. E
    factorial(5) = 5 * factorial(4)! _  s. B% K7 b  w
    factorial(4) = 4 * factorial(3)
    1 n3 G! l! L% J6 P+ ^factorial(3) = 3 * factorial(2)6 E3 A+ e4 u( Y& Q$ H
    factorial(2) = 2 * factorial(1)
    % I9 P$ p. O. c+ i! tfactorial(1) = 1 * factorial(0)
    5 b' `# K8 |% `. d- C; B; Yfactorial(0) = 1  # Base case
    ! [6 d# K0 ]" u2 `: e. ]9 D* L- [5 S: v1 a, ?/ h# ]+ ^
    Then, the results are combined:
    1 ^, N) {  N4 [& p% h, K: ~2 h: _; ~3 U+ G

    + o- X' B, d) w( e7 T4 y& E3 a* xfactorial(1) = 1 * 1 = 1! m7 v& M; t+ c$ {9 A, K$ o
    factorial(2) = 2 * 1 = 2% Z" R: f* V2 i# {2 n
    factorial(3) = 3 * 2 = 6" L8 L# q; h" M+ R' u' w) B
    factorial(4) = 4 * 6 = 248 D- t, o& i* d/ u
    factorial(5) = 5 * 24 = 120
    . c2 x7 S( ]7 l8 B: X  N! o! Z* I2 L; Y. {7 o2 `. S5 u
    Advantages of Recursion/ G8 I8 L, m$ `3 d
    * m' S6 g8 c) j7 G% }
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    8 ~* r8 u3 S- D8 p' u. j$ V  f! c4 E$ J/ @8 r0 _
        Readability: Recursive code can be more readable and concise compared to iterative solutions.; g* `1 D# D+ G4 p2 {
    7 b/ `9 d8 r3 M* K3 H7 k. X# a
    Disadvantages of Recursion, [* @  C' L9 [3 C

    , \9 z6 j# w$ h    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.. t! I0 o) a  c3 k) ^+ r

    ! i+ h! \5 H9 E. z! W    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    # c( y, `! [7 Y7 ^0 \# H7 ~# W4 g) ^
    When to Use Recursion
    7 m8 \4 c7 j/ q0 W8 e0 d9 a/ [. }0 Q1 [) @( v, `
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).5 V$ f7 B+ i- w1 C. I) C! g% N9 ^: {

    , l* _7 l$ T! Y    Problems with a clear base case and recursive case.% ]! l- W( _8 n: B4 U% I2 o

    ! D0 ?* C9 L8 q/ o( n/ p4 \Example: Fibonacci Sequence
    $ h  c+ e$ E# i+ x+ @# T6 Z/ j0 ]2 C7 Q3 ~" z! L
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:/ ]5 C+ w$ a' X1 t" {- M

    3 z8 N" K& U! O) h    Base case: fib(0) = 0, fib(1) = 1/ o+ J9 H# ?& }

    - B, H6 n: |- l3 m    Recursive case: fib(n) = fib(n-1) + fib(n-2)  d0 E7 s' m$ S) p& z( j2 G

    ! o; t9 l& C! k) w: `# T, y. rpython
    & @: a5 z9 l, _+ j
    + k7 X0 W7 K8 w* u( i0 G! t1 m2 U, t1 ]/ j6 Y
    def fibonacci(n):/ G9 M8 V4 Z6 U8 }5 @
        # Base cases
    % s8 S1 K+ X- t0 m( k$ f8 O: s    if n == 0:1 ~/ S. _) y+ o1 T) J7 K
            return 0
    & {% U; W0 V7 P    elif n == 1:
    % J6 g& }0 T/ G# D, B9 U        return 1
    . s6 r, D. g7 f    # Recursive case
    / ~+ e6 ?  ~7 t! {; R( S! k+ ~5 Q    else:
    " j8 M% X% V/ [1 _        return fibonacci(n - 1) + fibonacci(n - 2)
    7 T8 Q5 T0 E9 D* D) t: |- {. E, F6 n+ ^2 _5 C
    # Example usage
    ' Q- R4 U$ f6 q) F! i; A& rprint(fibonacci(6))  # Output: 8
    . S& z: ]  L( A. n; X$ r8 V+ t% x3 v; T8 x% I7 y- u
    Tail Recursion; _! ~/ I# ]. c1 s$ C8 P% h

    . a2 L6 D- L, m0 FTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    1 k3 Q: H6 C! r0 X" h: I# C* j8 f+ \* a3 F5 s* k
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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