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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 9 }# t! S3 r+ M6 \+ o" J: b$ l1 E0 Q2 f

    , {+ Q' W% J% V3 g  E解释的不错
    4 M& G: j, C; I7 {% P! s( {5 g: @: q
    / k7 E* P1 h2 Y) T, v递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    % e6 C9 R4 Y# i1 J! n/ i4 d0 H  f/ @, j: k8 U. p
    关键要素
    % O& O9 \! \$ e- N( y% x0 r1. **基线条件(Base Case)**
    3 z* M  C1 [# @, R" Z  h   - 递归终止的条件,防止无限循环
    % y! w' D5 p: \( J3 H   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    ' E: C# ^; }8 D% `( s4 ^: E0 B
    5 s( X/ G1 M3 Z& |! [: ]7 o" X7 s2. **递归条件(Recursive Case)**! v8 c/ D  N$ B. B" w% h
       - 将原问题分解为更小的子问题4 L, J9 l9 f: u
       - 例如:n! = n × (n-1)!
    $ Z: `5 J, |$ V/ o
    : A4 M1 E, r' z  I, Y8 J! q 经典示例:计算阶乘
    1 L, U% A$ R! x/ Jpython- Y  o) R. n: v. p
    def factorial(n):8 x9 ~2 @: u( \9 h% ^3 d5 {
        if n == 0:        # 基线条件0 I, M+ L% {$ k
            return 1
    7 Y9 ?5 d6 w# H) w. ~: G    else:             # 递归条件
    * |8 b! i5 r% Y& z* N1 Z        return n * factorial(n-1). ~: ?& p. n. ^/ W% m  U8 b
    执行过程(以计算 3! 为例):
    4 J8 }. G, f, e4 o' m6 p/ n2 I" xfactorial(3)) @2 I4 B& R$ V1 r
    3 * factorial(2)' }$ K5 X- Q$ _8 N7 V- W
    3 * (2 * factorial(1))5 n8 X6 S8 H+ f1 f+ y9 l8 o2 T( }5 m
    3 * (2 * (1 * factorial(0)))3 Z7 U, X: ]1 n
    3 * (2 * (1 * 1)) = 60 D1 a: u% |2 d2 c! j& M1 F7 q! L
    5 Q' l# G4 I  X& s2 L
    递归思维要点3 |0 I. r: z2 a1 q4 y. H+ e7 }
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑) d7 @% X! ]- w* B
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ' Q5 u& G/ w" Z; _! |3. **递推过程**:不断向下分解问题(递)
    4 |% V5 |* R" n2 [8 o( c5 I4. **回溯过程**:组合子问题结果返回(归)
    # B" Y; L& X! r$ B' ]  J
    : m) t/ i9 i, ^+ m& U 注意事项
    2 _8 R  c1 _2 E2 I1 J2 r/ f6 ?必须要有终止条件
      M  Z$ g* {/ I; w递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    & j# ^) J& R! p0 Y8 X+ A$ z某些问题用递归更直观(如树遍历),但效率可能不如迭代
    2 q# M/ Y4 E  L, p' u' l# ?* K尾递归优化可以提升效率(但Python不支持)) Z: [- y- T) B8 q6 D$ E
    ! i8 u4 X* N' z( }+ }3 d
    递归 vs 迭代
    ! E6 n! H: ~3 W. \7 D  K|          | 递归                          | 迭代               |
    / ?) k/ T+ w. Z  _+ m|----------|-----------------------------|------------------|$ Q! \  b; S8 r: W7 D8 K
    | 实现方式    | 函数自调用                        | 循环结构            |5 c9 ^% m5 P7 i7 z! W4 [  F
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    9 v# `$ T& b& z, n' x4 U+ N| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |4 f) y: C0 [" u$ l$ K% |
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |0 z! [- I# t0 s8 s( _9 K
    2 N0 K- P* v4 J- f+ x- w
    经典递归应用场景
    ) l+ q* ]2 q/ x  g3 z1. 文件系统遍历(目录树结构)6 e( L( `% ]- ^
    2. 快速排序/归并排序算法
    ; t+ j# W( F; u, C# f5 W3. 汉诺塔问题* k4 o2 d/ ~6 c7 _
    4. 二叉树遍历(前序/中序/后序)
    9 p+ h& d) f3 h, F2 ~4 \8 ^+ A+ ~5. 生成所有可能的组合(回溯算法)9 t  g$ \7 \1 B4 F. O8 J+ X; v2 b! C
      K7 F, s2 d: k9 N/ P
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情

    昨天 07:45
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    ! T1 X& }$ s$ M我推理机的核心算法应该是二叉树遍历的变种。
    4 G8 G" z$ r: D: K( Q) h另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:* q! \- y% z9 d" j8 g8 M1 q
    Key Idea of Recursion
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    + g; U, v* W$ Q+ ~5 j6 TA recursive function solves a problem by:
    ; n4 N( U% t& a2 B5 N! e' r8 n, |9 t- n
        Breaking the problem into smaller instances of the same problem.
    & c9 Y* d' G% [! S: ^
    + H4 i: q+ _. W, d4 C+ _& h    Solving the smallest instance directly (base case).. d0 l3 x/ L# n2 I% Z' ^

    8 N) R; i+ a! X3 o    Combining the results of smaller instances to solve the larger problem.
    " `0 ]+ j5 N/ _' p" p& M; H. K: F: C# H6 [
    Components of a Recursive Function: T- L' g2 c& V4 @; s
    4 E  u3 ?6 R8 i4 ~1 z, ]
        Base Case:
    * z' V0 s7 d9 X/ [  \4 Y: |. Y! R. C
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.1 z$ H5 W) M/ _3 ?" z! b

    1 u9 j( k3 X$ X- u# Q0 C( T+ P* Y        It acts as the stopping condition to prevent infinite recursion.  `* H& B- k* y" s# Q' [
    ; {5 F* E5 M, U+ ]. D1 ^$ {
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    ) k3 v0 [: y  T% S3 ^. a
    : c: e8 @& Z, w/ G% e) h& V    Recursive Case:% ]/ p0 H. @; l5 |

    8 u# i8 r2 J- f8 v8 b% s6 z8 y        This is where the function calls itself with a smaller or simpler version of the problem.( T5 j( G% y+ l8 I: F2 E& [1 `

    $ x3 p4 e- m- a! w+ X9 z) ]* `8 h        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    / ^+ [1 W% Q. I9 ^* W' Z2 Y
    5 W6 P: w" l- m) |Example: Factorial Calculation
    8 r5 V+ P3 I1 i: T# D; q8 m& s! w' G  ^+ n
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    2 o3 ~' W% K0 {7 j
    4 G4 \0 J9 @: x4 w% H    Base case: 0! = 1
    " t( h% n1 U6 _( ]/ H" E4 U( Q5 i7 `& u& H6 Q; C
        Recursive case: n! = n * (n-1)!
    & z, b( O4 p" k: v
    / R% A- L1 w7 f. M3 FHere’s how it looks in code (Python):& y4 ~9 J1 P: i# O- Y
    python
    ) C8 Z* C; c& h. K" f9 Y5 G
    0 G* _4 F5 I3 D, i& {
    . ^# I$ g$ Z8 o. ?: w  L0 Hdef factorial(n):
    * O' h0 K& t% V( n    # Base case
    + ^6 h" b; i. d! ~/ Z; ~    if n == 0:" b8 M8 F7 j! T/ n( g: h/ u0 X
            return 1
    ' E" }8 D* m3 f3 e) k& {    # Recursive case7 L& @* T& e+ a& M0 J( F
        else:# i6 N: n& M& G
            return n * factorial(n - 1)
    1 ]/ D2 ?: z: F! ]. C% Q  r) l# F! J6 c4 Q
    # Example usage
    # Q* l$ p+ P- f' @print(factorial(5))  # Output: 120
    2 m( S, j: `; g7 g" P3 L  O+ h7 e  Z& P- b, v4 y; F
    How Recursion Works
    # r( F& x! ]: q
    * ]" G/ `6 R$ v5 ~$ _4 b+ b9 x    The function keeps calling itself with smaller inputs until it reaches the base case.2 h1 c  j4 W2 b3 j* S/ Y4 ^* g
    ! y1 \# {% }" I; w1 J/ I; N
        Once the base case is reached, the function starts returning values back up the call stack.2 A& k- m* h+ l* t& }; X  L2 _

    6 y, Q% I. V9 t: Z    These returned values are combined to produce the final result.7 [, }; d! W0 t

    . V9 K% @" P+ _, X) \' f6 @For factorial(5):2 n5 P& l) Y2 u- o) G  n/ Z1 C
    2 r7 }. y2 j: @& u
    ! M8 v6 Z) t( k1 Y* J
    factorial(5) = 5 * factorial(4)
    . h# T! S+ }' A4 wfactorial(4) = 4 * factorial(3)8 [% `, h) @2 A- d# j6 t% I
    factorial(3) = 3 * factorial(2)
    & T4 _+ \! G+ s7 C1 v4 P. [factorial(2) = 2 * factorial(1)
    1 T2 t+ `& A. T! i: b. |factorial(1) = 1 * factorial(0)
    & Y5 ^) `$ R+ c" i/ y6 }factorial(0) = 1  # Base case
    ) s; P. I. ]! _3 k( ?2 H5 g$ j/ T$ H8 a; V% D& J6 N
    Then, the results are combined:- K9 A$ \. b' h3 e4 E# S4 B5 ?) }

    8 W5 {  l' E+ w3 i6 |% U2 \  x* b, r; y, D3 o3 m0 N
    factorial(1) = 1 * 1 = 1
    7 X0 d; ~! z' x2 X% U9 Dfactorial(2) = 2 * 1 = 2
    8 d" i( r5 |" Y  B7 s" Rfactorial(3) = 3 * 2 = 6
    0 H/ R- D' Q6 F4 r; x6 Q/ _# }$ Efactorial(4) = 4 * 6 = 24
    2 Y+ `: O2 g( cfactorial(5) = 5 * 24 = 120
    & j) n6 i; @% U, C3 p. R1 t7 @8 \0 w* M( B/ l
    Advantages of Recursion
    8 _+ N5 E; Z+ r4 w  W6 L. u. D! [) K; C5 J
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).5 }# Q$ A7 K8 s/ ]( z3 z2 _; e$ u6 E
    : B- h- q0 s% J* i6 v0 V
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    7 h1 _, m9 F( O, L% B3 y( R* N# A0 ?$ L" B7 o) q0 }
    Disadvantages of Recursion
    % o: i; l5 u) g4 Z3 C. W  D: Z- W0 U3 S9 S$ ?( x! Q
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.! F" |! I5 L/ W: h' ~6 a6 K
    9 i' z8 A8 j) w
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    6 C* @. p9 k8 R  t3 u- ]
      v$ N. {" f& z* h$ DWhen to Use Recursion+ u$ E* b: Z) ?# N* }! Q
    4 `, [! I" j+ {7 Q$ {7 ~
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    7 }. R8 j  g% B2 L3 f8 l  \6 {! Z$ l) C: a
        Problems with a clear base case and recursive case.
    + y: ^% L- u5 [, z
    # ]" V& Q) ^! P2 \) ?Example: Fibonacci Sequence0 `, ?% `. a: r* q5 Z
    7 O, U: A3 V, A, L! i
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:. m# V8 u  H) j# e
    9 _! n9 L: `0 P% O( O/ b6 e+ ^, C
        Base case: fib(0) = 0, fib(1) = 19 k7 S$ Y% V7 I& x0 j

    & O' Z# R$ C, e# @9 M    Recursive case: fib(n) = fib(n-1) + fib(n-2)6 x! O1 J7 L$ y* Y7 o, x
    ' S. _8 @: E# p3 ^  ]( L4 h5 V
    python& {8 s( }8 A! W/ U0 T5 C6 E
    " V+ e: J5 G% Z: ^

    + {' E! Y9 ]8 D: Ddef fibonacci(n):3 A! a3 W1 ^! K) K
        # Base cases& ^1 s3 s/ J2 Y# T" d
        if n == 0:& g- |+ k7 \* c; W' A6 ]
            return 0' _' C9 n7 N0 ]9 d* |' ~  O
        elif n == 1:
    3 W' N* N% J4 J% F) A        return 1
    , ~3 T# _4 T4 i0 Q  G  K& y    # Recursive case
    % L2 P8 B- l5 Q& g' M* r7 y    else:* t. L6 A9 k  ~% T4 M% U
            return fibonacci(n - 1) + fibonacci(n - 2)
      P: U: }; Y# M4 D7 ]: L" _
    ' n8 u( v6 B: p# R5 {1 g# Example usage
    , F1 l# W. N6 Y3 Z3 e) k# ?print(fibonacci(6))  # Output: 8
    ; ~  x( e5 P9 |. U+ J2 @4 F* U2 f1 `4 X- A( k' g2 ?+ |
    Tail Recursion
    # A# W3 P: R* C0 t
    . p6 I6 r+ Z' F( {" nTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    3 g; y4 ^: w+ `$ Y. c- b. R; I/ [
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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