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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ; y6 `: G2 F- V4 P2 W9 M
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    解释的不错. I6 r; E1 f9 l  x( }9 b4 c

    : D  h1 }+ k% y0 P4 Z递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    * D6 _7 D5 m$ ]. K' F5 ^9 t 关键要素
    ! M, E1 D9 m( e: O: A1. **基线条件(Base Case)**
    ! f5 c4 ~1 L1 y1 Z   - 递归终止的条件,防止无限循环* S4 \' [9 ^# N* Z& Z; P. w: a
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1' ]  Z3 r/ ^+ S" x4 z+ d$ A

    & O  s- y1 f4 J2. **递归条件(Recursive Case)**
      B4 p9 [( p: F+ h6 f   - 将原问题分解为更小的子问题" ^0 p7 Y4 p. v% D4 \7 d8 H
       - 例如:n! = n × (n-1)!& M& r4 |# Y8 c1 I. {

    ! Y  j, g! {, {8 G, A8 r- n 经典示例:计算阶乘
    $ d% w7 J8 I# h! a8 u- Y& D$ dpython$ X/ r; I& s3 a2 a3 F9 ^' d. E
    def factorial(n):
    2 ?3 G3 P" R  i2 @1 {: Z3 U/ G    if n == 0:        # 基线条件
    , _1 O  _1 O  E$ c$ q4 |        return 1
    # q& J* M, ]) x) _* P    else:             # 递归条件
    ' _5 Z5 j5 E3 n$ K( e; T" k3 W        return n * factorial(n-1)% r9 l5 ~9 C0 r% b
    执行过程(以计算 3! 为例):
    7 Z, W- g- l# t1 Wfactorial(3)% c, Z6 h8 [4 ]8 z6 b
    3 * factorial(2)8 I* ~- h) p' A) `
    3 * (2 * factorial(1))
    1 \0 a& S( L4 \3 * (2 * (1 * factorial(0)))5 S7 J1 Q" u3 D/ m8 L
    3 * (2 * (1 * 1)) = 69 }, ^) I! B; r8 k, L. v+ D1 Q$ [
    & O  v# w' j$ J5 f9 \9 Z  x
    递归思维要点) ?5 s( q  W, P2 V: z
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑' g$ W8 E: \* K% [
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间); S4 Z/ w; b/ q5 d
    3. **递推过程**:不断向下分解问题(递), e" {% r& u. p- o$ ~
    4. **回溯过程**:组合子问题结果返回(归)- P6 U) [, a* x

    8 A4 |$ H- @) d  }0 A2 |' z% H 注意事项
    2 F5 ]2 ]3 z- K* i; U7 p必须要有终止条件
    9 u+ y9 O3 ]+ N; V3 Q4 O. J递归深度过大可能导致栈溢出(Python默认递归深度约1000层)& r% M1 p5 ^' B& u
    某些问题用递归更直观(如树遍历),但效率可能不如迭代* u( E$ N* R: L1 j6 @
    尾递归优化可以提升效率(但Python不支持)
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    , A7 N7 b1 t# R" @. M5 @' l 递归 vs 迭代' r2 k5 h( P  ^" q4 N5 b( v1 j
    |          | 递归                          | 迭代               |
    0 z% m: T1 D. U5 }|----------|-----------------------------|------------------|
    3 t* ]- ^" O0 h( B| 实现方式    | 函数自调用                        | 循环结构            |5 v! h' V9 ]; E( p
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    - S% v6 n$ f" V: E8 F) k7 h! f" Q| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
      h- j. H2 [2 I$ i8 m+ g1 ]| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |3 [& d1 n9 i( n0 g; V

    - j" z$ Z' c/ |: I% b& v$ X$ c7 X 经典递归应用场景
    : y9 u, j5 R9 u1. 文件系统遍历(目录树结构)& O+ M+ H  Z* v0 r0 f+ C6 z
    2. 快速排序/归并排序算法
    3 n% b5 p: Y) i  ?3. 汉诺塔问题
    ! B1 |- S% S# ~% W0 D; f' e4. 二叉树遍历(前序/中序/后序)! c4 r' A$ c- l4 b7 e
    5. 生成所有可能的组合(回溯算法)0 S) W, J: E7 M

    3 }8 x0 H; r$ t( i' ]) j2 y试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    * @0 T4 i% N4 N9 r2 @7 [$ y/ r1 G- k我推理机的核心算法应该是二叉树遍历的变种。
    + y, ?& c, p; I另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    0 K" w% y/ n& Z3 `: Y" ^+ R. pKey Idea of Recursion
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    + u6 y# P# d& V; |6 n- BA recursive function solves a problem by:' x& }; U1 y: |7 B$ a$ s! n6 y
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        Breaking the problem into smaller instances of the same problem.. h1 s6 _# J, `* K1 N$ B
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        Solving the smallest instance directly (base case).
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        Combining the results of smaller instances to solve the larger problem.
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    Components of a Recursive Function: M, `- B) s  Z2 g# K$ [; u

    - ~: i( {, W; t$ ~% u$ p9 H    Base Case:1 r# l. b$ F7 ?( R+ s9 p
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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    7 ^, l7 N5 y, J* \/ k2 s  _& I        It acts as the stopping condition to prevent infinite recursion.
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            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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        Recursive Case:% M: O, i! d9 t* J3 _2 ?1 u4 ~

    4 Y& Z: a. ]8 Y* f        This is where the function calls itself with a smaller or simpler version of the problem.( o( M* F/ S# E4 r9 x" @" ]

    * h+ \2 @+ z. \# W! C: H        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).+ R0 m* Y/ K# X3 K

    . |! B+ w. I- L7 x2 ^. Q. t' G: YExample: Factorial Calculation
    0 N- O3 Z- A3 q8 _) X3 v! G; ]4 G" n7 m) A- F1 y5 l
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    5 z' T. |$ }8 {. ]' n; Z- c5 Q& W7 }9 l. e$ B; G
        Base case: 0! = 12 x# F* N/ w: g" O' s1 {; P7 c
    ) D: i; ~; @1 Q) p, d
        Recursive case: n! = n * (n-1)!; R, {* v9 O  h* R2 i5 W
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    Here’s how it looks in code (Python):7 |& o* W0 N% L5 u. C8 i( Z  e
    python' Y: O6 k' a  b' `% s3 r2 V
    # f, N9 r$ u4 Q+ k
    * I8 K/ q7 Y. ]; [
    def factorial(n):
    : u1 i4 H/ b! i& O( Q; X2 {2 V    # Base case9 I3 Z! r  Z3 u) ^8 M( u* ]
        if n == 0:% x1 p) X' ]# I, G2 f/ R$ ^
            return 1
    , I( [0 r* L+ s5 W9 b  p! n    # Recursive case! ~  c# o1 S0 c- k$ ?
        else:
    3 s0 v4 c1 M" L$ U        return n * factorial(n - 1)" k, z; ^8 {( F. k5 P5 u- ^8 H: K
      b! d4 {: Y/ }0 X7 ]$ D" A8 H
    # Example usage
    8 I. J7 ~4 y: mprint(factorial(5))  # Output: 120
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    2 ^- m4 v0 c+ _" Y- Z0 U4 t% ]How Recursion Works$ }2 ?$ B1 p0 \7 L" N' e$ Q& R
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        The function keeps calling itself with smaller inputs until it reaches the base case.
    % W5 o6 w* ?( H2 t: r! J6 U, O( D1 r- r( u; {* t
        Once the base case is reached, the function starts returning values back up the call stack.7 Z# N+ l, V- Z& k# Z3 @
    % n2 z" @3 Z9 c3 z! S  M) \
        These returned values are combined to produce the final result.
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    0 f! I; u  Q7 A9 U0 O* ]For factorial(5):
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    5 K. n5 a. W# G
    factorial(5) = 5 * factorial(4)3 }$ F  q1 J1 @6 q/ `1 @
    factorial(4) = 4 * factorial(3)
    9 d4 Z; j8 J% Q" o$ ?factorial(3) = 3 * factorial(2)
    : {2 q" Y( s, |* W8 Ufactorial(2) = 2 * factorial(1)( J/ I. y0 p" g% y( g% T8 g( Z
    factorial(1) = 1 * factorial(0)
      J$ n( _1 r! sfactorial(0) = 1  # Base case2 ]1 Y" N7 ^2 q

    + H3 T5 k6 V( N5 e6 i0 P  D* DThen, the results are combined:
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    0 k& l' B. D# W( K5 C0 Q& O+ _
    ' m  e9 B5 l& X! G- Gfactorial(1) = 1 * 1 = 1" ?5 p3 I! x2 ?  ~5 D
    factorial(2) = 2 * 1 = 21 n! \, L9 k, U! s% x- I' D' l9 \
    factorial(3) = 3 * 2 = 6
    . L1 N. A+ n/ n) f  Pfactorial(4) = 4 * 6 = 24' ^4 ^5 H+ q, H1 g/ x$ i4 q! j* A6 Z1 D
    factorial(5) = 5 * 24 = 120
    0 L3 M4 u4 o! E) i: a9 y, x9 k, ^. O: C1 q; t+ w, ?2 A. ?1 K
    Advantages of Recursion% M8 S4 G2 C( T  B

    0 E) z- Z' Y* g( b" E    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    6 F9 \3 y6 ^& E( j1 p) N+ o& S3 \# c, h; `. r" }
        Readability: Recursive code can be more readable and concise compared to iterative solutions.+ W! W4 _% ]0 C, C; m

    2 e  p7 }/ {$ i  w# M. l; D) NDisadvantages of Recursion+ n4 c, Q# @# v; f2 w3 e8 g3 f1 ]
    2 t* s- [5 W: l
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).0 r* q( [& L1 Q+ p
    , c* ^& L  @7 X! a
    When to Use Recursion0 C9 G: m6 h" d$ S& |

    6 V7 ?4 k4 m" n# H9 J, p7 q    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).1 \( ~/ C, J9 U) J# q1 I

    # ^  n$ R/ A4 a0 D6 ^    Problems with a clear base case and recursive case., K! i7 M' `! n! `5 a# x6 s

    . k' [7 R' J" q8 a/ z7 iExample: Fibonacci Sequence
    8 ]) G" _9 ?! C* c5 m7 f
    ! a, w. g  d. e3 S. F3 [The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    * A3 Z4 k, C! I" H
    ) m4 p- _2 b& e6 X    Base case: fib(0) = 0, fib(1) = 1
    6 P3 Z+ ]. e, r5 u7 w% _
    . t  g. b$ D$ z2 I. _  _    Recursive case: fib(n) = fib(n-1) + fib(n-2)4 i: P/ Y- M4 N, e% e5 }8 a

    9 M/ ~: B; v. s0 u/ Ppython
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    5 \1 e( Y, ?) }1 o* T2 l" g1 n! V) Q/ D+ N- E
    def fibonacci(n):- `" Z2 k, ~. ?9 F* k
        # Base cases
    - C, O, d1 s0 m3 R    if n == 0:
    $ s/ z9 R& g& x2 E, j. X* v        return 0; w" y+ @9 b0 i/ I3 k
        elif n == 1:
    & w3 b9 s. ^4 V        return 13 ~- c2 m% V9 E2 i
        # Recursive case
    # W2 D& |3 Q4 ]4 R6 J    else:
    $ h5 ?3 A; W' T6 `( A5 l3 g        return fibonacci(n - 1) + fibonacci(n - 2)
    / t3 s. }6 e( v2 Q" ^" r3 O8 Q2 ?; u! ?4 n4 R- y
    # Example usage
    " l; ~4 P% E6 ]' o3 ?print(fibonacci(6))  # Output: 8; R5 Q# E5 r9 {/ v$ V$ q
    ! s& G% W8 v1 b, X/ L
    Tail Recursion2 E6 b1 ?0 L+ A4 ~4 K

    & Y( _- ^1 e7 z/ STail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    # |# `$ A. s+ }, @) m  Z6 s, E$ ?7 Y1 Q4 O0 N
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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