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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    1 }6 x9 T% q/ ~, J9 l4 ~/ l7 J* I5 o3 s% E! A
    解释的不错; Q7 R' L+ s% A
    5 A  |! b6 P( |* O4 ~* a+ L4 x
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。2 z, M1 ~5 O' K" F

    : `) j  Z" N* L8 w 关键要素
    ( v( r. ]6 I, B2 J5 @( q! j1. **基线条件(Base Case)**
    * q( Q; i' ]7 F   - 递归终止的条件,防止无限循环
    $ @, Z! J8 Z3 I: J- H% ~9 G   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    0 c/ W1 s, w3 T5 L" e& P% V8 Z+ W" r  ^( C3 y, e, M% f  s% V
    2. **递归条件(Recursive Case)**2 {5 k5 ?; p" i/ f2 k' K' a
       - 将原问题分解为更小的子问题
    ; G# p/ y& T5 K   - 例如:n! = n × (n-1)!
    + F: S2 e: i$ V4 \! }8 r
    " k1 l# Y3 o/ s/ y+ L6 z2 C 经典示例:计算阶乘
    2 O) D% q1 k2 ~4 k4 v* i- [3 ~; M9 bpython
    3 F4 i/ Y9 T$ Y3 C6 Udef factorial(n):
    3 X. U; t. U2 w8 R$ m  J& |* i    if n == 0:        # 基线条件6 p3 G, p& s4 G3 M0 L& @$ v0 B
            return 19 x& S3 z8 R- V& a: S: `& \
        else:             # 递归条件1 i3 f8 j% |! p
            return n * factorial(n-1)1 o$ b* f! w' _
    执行过程(以计算 3! 为例):
    ) [. ?6 j  }+ r+ wfactorial(3)
    0 s+ u9 Y/ B& R( ~2 {% Y3 * factorial(2)9 m2 z( l  F- O
    3 * (2 * factorial(1))5 h# T$ C( ?# Y# R' s7 x( s$ \
    3 * (2 * (1 * factorial(0)))/ ]1 _5 F1 G' @6 C9 ]: k2 Q# q
    3 * (2 * (1 * 1)) = 6% d8 Q2 ]. x; z9 T0 u
    : C4 ?$ V2 P2 {; o
    递归思维要点
    * e% H+ Z' W& j0 v% A( |1. **信任递归**:假设子问题已经解决,专注当前层逻辑+ x$ D! e' `# R8 w- [4 P3 X) \
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ! c4 R$ c) k% W/ I8 I5 j3. **递推过程**:不断向下分解问题(递)
    & O$ I' Y3 |+ o8 R* i5 B+ ^4. **回溯过程**:组合子问题结果返回(归)
    : w2 [" D- W+ Q- Z. G: @# a- M
    注意事项2 G6 ^5 o( C0 q' a' L2 T0 U% m
    必须要有终止条件
    8 F) s, ?4 q7 ]5 d% |递归深度过大可能导致栈溢出(Python默认递归深度约1000层)5 ^+ I7 f8 F% @8 _4 a
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    : e: U' Y; |5 G4 Y0 L尾递归优化可以提升效率(但Python不支持)' ~) u5 S( B. P( C" P% b& U0 d9 i
    6 x/ F7 s, i3 }  E
    递归 vs 迭代! t* X9 x: E' U
    |          | 递归                          | 迭代               |0 Q4 C4 Y# |! G, k; |
    |----------|-----------------------------|------------------|
    3 {* H7 t$ K, r" q, c* o! @- n| 实现方式    | 函数自调用                        | 循环结构            |
    ; C3 x" U  K$ c& w: o| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |$ P7 K1 h" y9 B' a2 x( \' D
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
      d7 ]. G2 ~8 m: d8 U) X| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |1 c6 Y8 ^# |" O; H+ G, o

    : ~8 Y4 y' F& x2 j9 {" s( c# ] 经典递归应用场景( }- d- E5 u# h) W2 @
    1. 文件系统遍历(目录树结构)
    8 U# Q) a( N9 W5 q* }2. 快速排序/归并排序算法
    : W; e, N( g  Q/ X  _: l: [/ H3. 汉诺塔问题6 C, N! V1 X4 v7 s. D1 c9 C
    4. 二叉树遍历(前序/中序/后序)
    # M# o, _, _6 ^5 ^; P5. 生成所有可能的组合(回溯算法). Y2 Q4 b# Y% ?/ @$ d4 Q& z  B0 ^) K
    5 U$ A! M7 a% I2 b5 z  B
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 09:53
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    . }8 Z) n+ }8 S' _8 q我推理机的核心算法应该是二叉树遍历的变种。# U0 K% e8 a  y6 V  u
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:/ L9 S. E2 C+ W3 e8 E
    Key Idea of Recursion
    3 f( F% _" C, R! _( e( O& K( k5 u, I& _* `5 |( A" q
    A recursive function solves a problem by:( s2 @0 W0 H# ?5 q! O8 `

    3 O  j" @: R! k" g! g1 {    Breaking the problem into smaller instances of the same problem.
    ) r9 _8 e+ P0 t: Z3 C6 [% j/ j% z! G  u! h7 Y! D: \
        Solving the smallest instance directly (base case).) Y, i& }' |) A. ^" u

    , V3 U( W, `8 j% R, @( z1 F' h    Combining the results of smaller instances to solve the larger problem.  Q1 K+ \: v9 f3 z

    : X5 W: h9 q# p; b- YComponents of a Recursive Function
    $ p5 {6 \1 x- c1 r  d9 B
    , P0 r. P4 {- i9 I2 }$ c    Base Case:- @! `! R- J$ |: @0 D1 Z
      n, D, ^5 ?: y0 _" p
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    9 d/ _; {) u$ J' C2 Y6 M
    / z+ N0 j3 A1 z8 B4 C# K0 d$ f        It acts as the stopping condition to prevent infinite recursion.7 M8 q  d1 ?6 ^
    * z" g) U3 w+ t$ {
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    ! Z; }0 P* e" k3 m
    3 l9 Q4 `' A4 C# F    Recursive Case:6 W+ C. `  |9 o  h7 w: a

    4 |4 g! r3 s9 v( U        This is where the function calls itself with a smaller or simpler version of the problem.
    1 P. u4 H+ P+ A, u, o$ D% O2 Y; F& g$ ]
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).: C4 c4 O2 |7 E( f6 A7 t2 @

    3 k0 d2 Y  M4 X. ^+ G1 e+ v, m( EExample: Factorial Calculation" J; ~1 H5 }' W
    5 D5 F' s1 S7 D! g8 Y) g6 B
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    $ ~' K+ c' H/ _4 i" V. b" W$ d; r( n% R7 x) y  M* H: [
        Base case: 0! = 1
    & @! L7 C% U" V. m, ]( D8 Q8 @
    ; \- B0 Y6 |. b' B1 \& i& M" u4 t    Recursive case: n! = n * (n-1)!
    % H+ U9 X! r4 G1 A$ a  J. N3 F2 C) M6 T- S1 |5 `
    Here’s how it looks in code (Python):
    / g: ~7 |6 J4 `. cpython; @% ?, }! v) {) N1 N5 ?
    # E5 Y6 p( P+ ^4 M$ _8 L! {  [

    & L" O% q2 V: Adef factorial(n):
    3 ~+ Y9 ?0 S* e8 b4 A9 g, ]    # Base case0 D( N! m4 D9 F/ J- [& b
        if n == 0:
    7 x+ H7 ?5 s3 ^        return 1, I$ K2 ^. R/ M+ h& O, T
        # Recursive case3 Q' \% E* n2 l) w* j
        else:- w/ Z; L6 W. q
            return n * factorial(n - 1)
    ' v" l9 c( Q2 {5 A
    $ Z0 I, M5 X! @( ^) ?: f+ Y# Example usage# s8 ^( M$ [) ^* N
    print(factorial(5))  # Output: 120
    " J# e5 V9 t8 q5 a5 T( C9 I' w6 \9 D. w* h% W5 u7 Y7 d
    How Recursion Works
      d/ @" B7 P8 v* h' J# x/ T6 k6 E# N' U+ g9 a
        The function keeps calling itself with smaller inputs until it reaches the base case., p+ j- h/ c! l2 d) p# ?1 U' c6 i$ b
    ) ]8 E$ `$ }& A* F9 u' R. ^
        Once the base case is reached, the function starts returning values back up the call stack.
    % @) f8 u& E9 d. G8 b9 S, ^- t" Q' |
        These returned values are combined to produce the final result.
    ' E! t! Z( R* U( ]: U. u) |7 j6 k! B4 h7 W4 F7 L5 V& m
    For factorial(5):
    ( B- g/ r2 |2 A% _
    9 j$ H0 y# y! _1 S* j: s5 A9 C; R) e+ H  P/ }. U
    factorial(5) = 5 * factorial(4)
    % g$ ?( h7 j/ C" g0 Vfactorial(4) = 4 * factorial(3)( h" H- M# J* Z$ f* h! Z* M1 X2 v5 N
    factorial(3) = 3 * factorial(2)
    ' p5 @: K3 i- E& H* Q" K) E' X3 Gfactorial(2) = 2 * factorial(1)
    : G. Q' q6 e: c0 Zfactorial(1) = 1 * factorial(0)) `. N; {$ [8 P. K0 l4 ]$ k  I0 r; m
    factorial(0) = 1  # Base case) d9 [  t5 T* `9 R& t! h

    2 q) X# {, y5 I+ s9 ]( K: SThen, the results are combined:
    0 B( a6 H  h$ l6 T3 r1 F6 c, M* |! B0 J9 e

    4 g3 u' {: C4 f* p3 g, yfactorial(1) = 1 * 1 = 1- `! e, k! [, j
    factorial(2) = 2 * 1 = 2: Q, N  z1 z# l6 p+ j
    factorial(3) = 3 * 2 = 6
    " }7 d% l* \5 b, E4 nfactorial(4) = 4 * 6 = 241 X3 L- p' o2 f  W- x, l
    factorial(5) = 5 * 24 = 120
    ) n+ `9 ^+ }. }# J3 W- U
    / @$ ^) p$ F2 H  x1 O. }- YAdvantages of Recursion
      S- ^+ l$ d: h' N5 W# ]
    7 u3 ]+ P* P0 l    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).7 ?- M8 t; l% B, M  l
    1 ?+ Z. _5 ?4 _3 R/ _, V
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    / O+ h9 x2 @+ @# X/ v1 I
    # B, R0 x7 J1 }* \+ \' F) V0 |9 t5 NDisadvantages of Recursion& K8 y, |  }. A* e# t

    4 \; E+ h/ w/ n& q9 M, d1 P    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.: K% m& |8 @  @1 @) t2 o
    0 s- @) j( u% @8 h8 r; S
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    0 f! M  y: R* B: v% [  H
    ; g5 m$ J& o4 l# \When to Use Recursion
    1 C3 M8 k6 O3 m* a# d2 u# u, z! G$ I+ ^3 h6 z* g" }" `* H$ ]
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).5 A1 D: ~2 M/ W0 ~2 D+ z
    ; v# ^0 N4 h! q
        Problems with a clear base case and recursive case.
    # K( c& I6 b9 y- h3 T  ~' A
    6 \5 C8 z1 |* g% h' c; }Example: Fibonacci Sequence+ U' X. r* A( Z+ z( H4 q
    3 e/ g) T7 o  {, h  D: }# }+ `
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:6 K7 R% D' f6 S2 B% B6 Z
    1 I% B( L; y  w  [1 {7 \0 t5 [: ~
        Base case: fib(0) = 0, fib(1) = 1, I# a8 F9 ]+ i+ G1 g
    ( W& ~6 `- G4 h- J
        Recursive case: fib(n) = fib(n-1) + fib(n-2)  m+ z* [0 T6 v9 c. a0 ~
    3 h) i- O/ j( L6 v( G
    python+ E  U0 v! ~1 O$ C% ]* n2 [+ `
    , g3 f) N& k# l
    5 g" _" @" r8 T9 w8 m2 I+ m$ _
    def fibonacci(n):# K; }! s8 a# t0 s) Y. p2 ^; O
        # Base cases
    1 ~- I' L5 K$ Z& E( l( q; K    if n == 0:
    9 `. R* E" J8 @/ E3 l9 {* P7 J4 P        return 05 f$ W* v" I8 Q9 g
        elif n == 1:6 }, \7 ?0 m( E* Y' t
            return 1
    * p) A1 p/ k& v. [: W+ f1 W4 l    # Recursive case
    1 g- K0 Z* b3 U5 A4 ]$ c    else:
    * }3 e6 n+ P! M0 P        return fibonacci(n - 1) + fibonacci(n - 2)" H* D1 G+ Z# u
    5 y. _0 s4 J( {
    # Example usage0 m+ ^; O7 E( V- g* F, R
    print(fibonacci(6))  # Output: 83 w* U5 H1 p9 ]' Q) N+ z
    + r/ V! L/ J7 c0 H: V2 Y& b
    Tail Recursion
    ' R2 p* }) i4 w0 b3 G' f* t0 h+ z" H+ D' S( Y% G* f* {# _
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    7 h- n. F  S" F1 m8 s. T3 q9 M/ ^' U. }% ^2 |. I6 \* x% Z) A) N
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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