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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    " o1 ^% F0 C' h0 X+ E1 L6 S0 P* ^/ Y% Y/ u9 ]( g& O
    解释的不错) v& F8 n1 Z7 A) h& w
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。. ]. R# Z) j6 j  g- B* K! O( }( [$ k' ?
    9 l) `+ p6 ^0 s9 q6 b
    关键要素
    / i  S1 S% ~6 N6 i1. **基线条件(Base Case)**. d: _5 T$ s5 J# y
       - 递归终止的条件,防止无限循环
    / P; @! C( p5 J   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 12 z  s( ~4 Z& T4 l) a

    5 j$ c, N7 P$ E# m/ {  z1 Q2. **递归条件(Recursive Case)**
    9 W5 h' ]  ?  c   - 将原问题分解为更小的子问题. j: Z6 u8 t( i0 G& t1 f& E
       - 例如:n! = n × (n-1)!
    $ d% A- P2 S" O  m  a7 D5 T! l% g# O! b: k3 e
    经典示例:计算阶乘
    * L5 x$ [* e/ ^, Jpython
    2 q" o: I  }5 b' Ddef factorial(n):! b, Y/ h, p8 c
        if n == 0:        # 基线条件
    ; b3 p2 ]" m1 ]2 t0 f" ?        return 1
    . i% H  s, ?4 @    else:             # 递归条件
    , x6 Q8 B9 ?( Z6 T  ^5 r. |        return n * factorial(n-1)
    $ R0 g7 v+ m" _执行过程(以计算 3! 为例):
    % V( P) q- q* u# f! u* m$ Cfactorial(3)
    ; w% F+ ]* S* |# U2 Z3 * factorial(2)" r) W/ L- I) a7 ]. G
    3 * (2 * factorial(1))
      B- c  ]# f/ i3 * (2 * (1 * factorial(0)))* B3 j7 d! X; c! P
    3 * (2 * (1 * 1)) = 6' r$ h; L5 y# \
    4 K5 i2 L9 K; p9 |# M) m
    递归思维要点, P2 N  k0 o/ r
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    * C8 L( A: }' ]% }7 k: k! f. A2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ; j4 n: P  L. Q  s- N1 q$ u$ R& ~3. **递推过程**:不断向下分解问题(递)
    1 E- ?% c# N% X3 ~7 G9 C; ~4. **回溯过程**:组合子问题结果返回(归)
    " y: a! c- D) a* h: w  p) P$ w2 g! @" A2 g( C, Z
    注意事项
    3 Z. @/ U3 M/ A1 W必须要有终止条件/ ]$ q$ V& C) `+ b7 m3 H
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)2 D3 s4 \. B) n* P
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    2 F; ^9 ^1 L# y  f! ?; u尾递归优化可以提升效率(但Python不支持)5 I  y3 e" Y: o
    ; j0 l+ j6 [) A' Z/ J% N
    递归 vs 迭代
    3 g" m) w% z2 ^7 x|          | 递归                          | 迭代               |7 r) Y% @% I$ K. o- M
    |----------|-----------------------------|------------------|
    4 \6 C! R3 ~# [5 L5 U| 实现方式    | 函数自调用                        | 循环结构            |
      Z. T7 Z7 f. d9 A2 [9 m| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ) h2 \) m3 @$ Y, o| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |) d. d$ x; P% N6 H5 k
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |$ w; l2 M) x  E2 ?  w2 N6 N$ [9 A8 q

    & p  s1 S: u: F) _( I: y 经典递归应用场景0 d1 l) ]* ~0 p* l- B
    1. 文件系统遍历(目录树结构)0 m, d: g  }4 C0 T. v, v( }, {
    2. 快速排序/归并排序算法
    7 L; V/ \7 y; j1 H0 E6 Z3. 汉诺塔问题
    1 M% b% E3 h+ {4. 二叉树遍历(前序/中序/后序)
    5 ^4 B: B1 c7 R, ~9 I6 q. g0 g5. 生成所有可能的组合(回溯算法)* Q; X% e2 O4 g/ Y
    ' N. d$ j( K# x) `& i0 S
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    11 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,; P: ]" F; ?, |6 i" S/ [" q
    我推理机的核心算法应该是二叉树遍历的变种。
    $ n- J: W- w2 ], o另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    1 s( i: e3 b* M) M3 b! ^6 v, qKey Idea of Recursion" u# f! z. N1 C) R7 V  C

    9 g% m8 E0 V; ?) f) x: `+ j6 uA recursive function solves a problem by:
    ' k3 a0 w' H" E1 Z+ @
    7 Y* _' |, {7 N2 V    Breaking the problem into smaller instances of the same problem.! J! I$ Q4 W: B; e- i3 f0 k/ ~7 ^
    + [+ M7 \' P$ m6 l0 y4 h
        Solving the smallest instance directly (base case).
    8 j4 I4 W  J# i/ c4 C4 f2 g$ A. Q4 p8 @* M+ B+ b& M6 T
        Combining the results of smaller instances to solve the larger problem.9 u3 O! C7 N& R. @* N% V, _9 i
    - C) {, I5 O4 M; v
    Components of a Recursive Function
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    $ w% L2 B+ }* ^+ V    Base Case:
    4 e$ J5 Y' m. g7 y% l( Y/ q/ v: _$ E+ `# H5 ^7 r4 `8 R9 {! H
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.  N: ?% y! f1 X4 j1 w8 ^/ N
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            It acts as the stopping condition to prevent infinite recursion.' W# O6 _' y$ {
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            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.( ~. o! p/ e9 ^7 f# p

    5 m7 Y. I  a; P/ t2 L    Recursive Case:9 C* V! G. ~3 K
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            This is where the function calls itself with a smaller or simpler version of the problem.
    ! t, ^4 \( N& t  W' l/ u3 ]) a) N
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    2 S- j; r+ E7 b2 O8 Y7 i/ ?% n$ t- ]0 v' R9 o8 j* V
    Example: Factorial Calculation, ^! M' X& p) c( t8 [

    2 Q! W% p* ^# \: J; K( f' JThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:2 x. ?3 ]) T4 o/ _
    : u- k" x/ N9 n
        Base case: 0! = 1% G, P7 o0 b7 n1 _2 s- L8 L8 D

    * v: T$ C% E1 y% }8 h    Recursive case: n! = n * (n-1)!4 @: o) Z# I1 B& X& B

    * H+ `) P; r3 @* O3 I3 H: m, gHere’s how it looks in code (Python):/ _2 l% W4 @2 b- Z2 L1 \3 k1 ?
    python$ J1 l8 e9 _! y: R! O
    + T* ^5 z4 D% ?7 f/ I

    9 J& h9 U, f% n  _" `6 @$ udef factorial(n):
    ( V! K" u6 u6 i$ @( n6 j; [6 U    # Base case
    & K: D2 z1 ^! l: F+ w6 C    if n == 0:
    , |; H: Q- h; |1 i3 o        return 1
    + D5 t) E% y' l/ s. [4 r    # Recursive case
    . G5 N6 H3 W7 u$ y( n2 f" c. I    else:1 _, D" S$ }2 Y1 {3 j  Q7 @& Y2 S
            return n * factorial(n - 1)
    8 h$ q- V( Z7 B2 c) Z8 x8 x) `4 t" o
    # Example usage
    " ]" K, W' R, h  h1 ]* Qprint(factorial(5))  # Output: 1201 J* C% f& r7 s# }* L
    ' B7 G7 H9 y' c3 L' s4 I
    How Recursion Works
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        The function keeps calling itself with smaller inputs until it reaches the base case.3 z; ~( Z/ y  p2 N7 E5 ?7 e

    4 Z' ]4 d3 v* _; {( Z    Once the base case is reached, the function starts returning values back up the call stack.2 J( h8 x- U6 Q1 B7 }! L- j4 R

    3 \$ U# R' g1 o; G+ v5 s    These returned values are combined to produce the final result.: a! z  d. e" ~) h" X4 M
    4 O0 R1 u/ ^8 q& Q) P5 Z2 H$ |
    For factorial(5):& L. p+ c( ?' b' y% m. A( M& _7 z3 P

    ; B! d* H& Z2 d, H; b( X$ e0 N# Y5 K3 U. i3 }$ j# }" J
    factorial(5) = 5 * factorial(4)
    % ^* d7 V: A; a: G( x# gfactorial(4) = 4 * factorial(3)6 J; u, k- T* z
    factorial(3) = 3 * factorial(2)/ Y5 c( x% u1 ~8 j$ R( o/ P5 x
    factorial(2) = 2 * factorial(1)
    ' I" ?7 ~- }- h( jfactorial(1) = 1 * factorial(0)
    $ j  ~( l' P+ H: Kfactorial(0) = 1  # Base case5 p9 U( \+ y. o0 t  q

    1 `, e- u- B) sThen, the results are combined:; i, q: R9 a1 a! [0 O" `$ y6 ^
    , E; @; v; R+ R2 H* d) V4 M
    / Y  d; D$ P5 u; z+ D
    factorial(1) = 1 * 1 = 1
    / ?# s( z2 J4 J* M! Tfactorial(2) = 2 * 1 = 28 h) s! G  A+ B& J  R
    factorial(3) = 3 * 2 = 6+ Q  D5 s; M% j) [' k
    factorial(4) = 4 * 6 = 24
    ' a8 ], U: M5 ^( ~* `factorial(5) = 5 * 24 = 120
    & c/ Y1 o# Z% |9 P0 E. i7 T9 b; }+ @9 z! I
    Advantages of Recursion/ S& n0 x9 ]% q2 `! y; h& y8 {

    5 ]0 T- X7 [1 }" S2 T    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    " T# U; x: G: U$ g& l7 b' a4 D
    7 C4 X$ V  V9 b6 r* z3 t& [    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    ! H* C+ {8 C- l, H& k5 r0 G$ `5 [" W7 J8 Z  ^4 o6 M
    Disadvantages of Recursion! y' x3 N  x) S3 T$ T6 d/ N- t$ o
    6 n2 G3 c7 }2 ^0 r% I- y
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    1 U4 @* ]3 u* X% t4 x5 w0 h) f8 C! d( f
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).: w) c5 n  a: ]+ O
    , z9 U* i5 v; K0 b4 Q6 O+ m2 |6 H, [
    When to Use Recursion
    . W1 \5 c; j6 W
    0 U* ]' A8 N' s' c    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    % j$ |; T7 D9 p: m  ?
    2 b8 K2 Z8 X0 u& J. S    Problems with a clear base case and recursive case.' K- [  h4 C  N/ j

    , p( \3 P: s+ o9 q( U' |Example: Fibonacci Sequence
    ! t. ?+ S( m/ B+ U5 K* v' ?8 h# A4 R5 D+ @. i+ x. b6 g" P
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:: @2 Q3 f5 W& x/ e" w
    ( e" U3 I- C) |- B0 a0 f
        Base case: fib(0) = 0, fib(1) = 16 @1 i5 B4 `" u/ H' E" o/ c5 b
    5 Y: N" a4 ^' Y4 U1 J  {% ~
        Recursive case: fib(n) = fib(n-1) + fib(n-2)( b' B' [7 o! d; U
    / j# P( r+ _8 H2 N7 s  `) N. t( N' [
    python& Z  ]5 f8 Y0 d5 p
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    / f5 ^) c# s+ t* b1 e
    def fibonacci(n):* y! M8 V: K! E$ C2 _  R3 r
        # Base cases
    1 m+ b' G  c) S8 w; L4 V: s# c! k    if n == 0:) M/ I  A" O1 o$ X& M- D, ?
            return 01 l2 p0 G- p* M2 j4 P' g9 F, P
        elif n == 1:
    . W% o5 j. N5 {        return 1; g5 Q6 ~% A- ^7 u$ H# I( {0 A' i
        # Recursive case
    & P& N- @8 S$ a1 b  ?' G. w; r  ]    else:
    1 s7 l/ c' Y9 ^, w( M        return fibonacci(n - 1) + fibonacci(n - 2)1 y  w2 p8 P) ^2 i
    3 @. H* `$ `6 B4 d: a
    # Example usage
    % Q' Z% p; w4 x0 K4 R" I" Qprint(fibonacci(6))  # Output: 8
    2 @) y4 f, Q# |5 B9 `' Z) ~" N: z% ~" d# S
    Tail Recursion
    ( @' M) g8 W( b! t' ?! B8 {1 K& z- v2 Z$ @. H3 d
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).+ P; X9 [/ H  D6 Z$ \- q

    ; d8 }- l, j% C7 G* D. R+ b  IIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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