设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2388|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 $ Z3 r, H# `$ v5 ?+ h2 E1 n' r: L2 N
    1 \' x# A- q( b) ]: n- N
    解释的不错
    9 \5 `& V$ c! g, F$ f2 i. J! n4 X: m: Z8 [( d
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。% Q7 w3 L! m3 N2 q; l6 Q$ ^2 a2 G5 t

    ! U; c9 J: Z9 Y4 G  g2 C$ z* z6 g 关键要素, |6 i! L. y! ~% I5 h
    1. **基线条件(Base Case)**
    : [  Y5 I3 B$ X* z/ K8 \& \; A   - 递归终止的条件,防止无限循环  w# V+ G4 f5 @! H
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 17 Y+ h# C9 P# b7 C  t! ]
    . r2 n- @0 k/ V) _& @1 ~" m
    2. **递归条件(Recursive Case)**
    & K1 N1 f$ W! j. H   - 将原问题分解为更小的子问题+ I) |2 Z' d  V
       - 例如:n! = n × (n-1)!
    % v6 `( ]6 g! f9 }. a0 m+ E( k6 E' b% R9 c
    经典示例:计算阶乘8 ~( q$ w+ V; u4 n$ g1 |
    python
    ( ]4 y) t  W2 t; ?. f( odef factorial(n):
    * I7 W3 P, c# E    if n == 0:        # 基线条件) e  N* p; I0 X9 W- K: ]% L
            return 1; z7 j1 o# c5 r* W
        else:             # 递归条件
    0 `4 l/ R- q! M, C* Q9 R        return n * factorial(n-1)
    3 U1 k% g  {; @, e# W执行过程(以计算 3! 为例):' ]' v! L/ I  q
    factorial(3)' i/ i5 Z( m/ S
    3 * factorial(2)
    ; ?. R# s3 e( n" s; L3 * (2 * factorial(1))
    : ?- j  y% X/ C* f1 `3 * (2 * (1 * factorial(0))): B4 c: N# I$ M$ x" O% ?3 C# v1 W
    3 * (2 * (1 * 1)) = 6
    - {* w: G! u8 ?) y: I
    & F4 ]8 q' n$ f: R6 ` 递归思维要点
    $ I1 P+ K! [6 {' K) S" T1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    2 F7 n4 n1 B; L8 d4 j, y3 @2. **栈结构**:每次调用都会创建新的栈帧(内存空间)+ R" d. J, \% g; O9 d
    3. **递推过程**:不断向下分解问题(递)8 ^/ c- G" A/ y# [
    4. **回溯过程**:组合子问题结果返回(归)2 Q; Q9 ]1 V/ s0 A

    * x4 w: M# t% f/ s) G+ n 注意事项
    . G* H9 k: M  R* r, }必须要有终止条件6 n( q- ^1 o6 z' \( Y
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    ) [* i" z1 H, v5 V- C8 x" E某些问题用递归更直观(如树遍历),但效率可能不如迭代- H9 F0 X- \. i/ f6 o
    尾递归优化可以提升效率(但Python不支持)& u* w( z% u/ v  ]$ L

    7 g3 J/ e' E, ?" T% a" n- E; d 递归 vs 迭代* n8 u3 s; L! p/ a, x. r
    |          | 递归                          | 迭代               |
    " Y- n6 A" e$ `7 t. b! c; p|----------|-----------------------------|------------------|
    , T# r2 A% L8 ?2 u0 n| 实现方式    | 函数自调用                        | 循环结构            |/ l  s6 b) l5 |/ t1 z
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |$ T" ?' n* d- c& T: e
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |7 t2 m% w" q0 i0 U& U
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    8 m: Q4 w/ L& o# B0 t0 j+ e2 V, F" h0 `( b5 O% P: p3 |4 @. B
    经典递归应用场景8 b! S6 C6 {- R! `- A, o3 t
    1. 文件系统遍历(目录树结构)
    ' F; i1 z8 E4 C/ R2. 快速排序/归并排序算法9 y. W/ ?% I  c6 K
    3. 汉诺塔问题5 p. M; B+ J! V
    4. 二叉树遍历(前序/中序/后序)$ H" a3 B! B5 `& G
    5. 生成所有可能的组合(回溯算法)5 b; g7 Z; S- I3 m" q
    / i/ J& R% t! F$ r; C5 R
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    开心
    昨天 06:54
  • 签到天数: 3210 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    6 Y. B; S6 K( x0 A) a& K我推理机的核心算法应该是二叉树遍历的变种。
    6 U0 c5 V6 r1 J) N另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:! F  \* v7 L( b* |" ^( i
    Key Idea of Recursion, p& ^9 N! W: T$ {% U2 ]

    9 g4 l. G% j: l$ ]9 L* }9 JA recursive function solves a problem by:
    ) }4 H! t6 u1 o! y2 i, R
    $ l4 J1 P5 C+ Y! X    Breaking the problem into smaller instances of the same problem.
    , n: ], T# X9 Q: f4 ~. ~2 O! n& n1 J2 y! g' ^% ^
        Solving the smallest instance directly (base case).
    & v; N4 w1 x! x2 k
    5 u" L' [/ ]6 r8 b6 ~    Combining the results of smaller instances to solve the larger problem., ~# @7 B( y) ?$ k7 z

    ! m, j. [0 ], F3 ZComponents of a Recursive Function! H0 u9 q3 j8 `! Y4 R& q

    1 l1 X. M' b% Z2 P0 i    Base Case:' n# q9 l. y5 ]( M8 W1 E. F2 |4 {3 V

    ) o% X0 f! y: L/ l! \- j        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.8 h; v4 ~" U% M6 [( ^. ]: Q: R
    5 P6 S8 J  {, E4 J# ~
            It acts as the stopping condition to prevent infinite recursion.3 M2 |1 y3 Q3 g

    ! k+ a" {4 W1 V' D1 T/ i4 D+ Z        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.) x/ E; T# c( y

    , g# z5 o; Y, m) M6 O  b8 X* R    Recursive Case:5 }/ }/ l4 J; V8 x5 q9 ]( B% f

    - o" `. a0 h4 c        This is where the function calls itself with a smaller or simpler version of the problem.
    & y$ h$ c3 ?0 N1 s
    + O* @, V( H  ^9 U( Y" F; p        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    ) p3 p" E' m6 l. P  E$ V- |' z3 y4 D7 b- y0 h( b$ |& ~, q
    Example: Factorial Calculation( j; |& y: L$ l( v& ~# `( p

    , |/ m; ^3 O: _: vThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    5 @. W, {: ~8 V4 ~3 H/ n1 n$ w! |  ^  M. I
        Base case: 0! = 1
    ; y5 r1 ~0 ?) U, J, r' C' u
    % a5 G2 T' L7 J" a7 Q. J. M; V" L    Recursive case: n! = n * (n-1)!
    & u$ y  r3 d  a' G
    8 \4 A2 u5 m. D8 A3 KHere’s how it looks in code (Python):
    % Z: ?* I. x0 L3 B. Ypython; N+ k% H/ {3 K: N7 M- k

    ) @8 }6 Y5 }3 w6 L9 ^
    # [7 m, Z7 L% ndef factorial(n):+ h) G  Y2 M4 \2 m
        # Base case) A5 N- v/ {3 Q3 y# h2 h
        if n == 0:
    + c. P8 W4 V  x( V        return 1& E1 T' ?) J, w" I5 S' P* T
        # Recursive case
    0 m( x" g$ @3 ]4 K1 U; s    else:# }/ p. g; {. ]0 e
            return n * factorial(n - 1)
    & `) e7 R# Z7 t4 T' l: ^) M
    $ ^8 Z& U: F& U# Example usage
    6 u- A' z: H4 L6 f$ Nprint(factorial(5))  # Output: 120
    ; Q7 L, v  a# K- P5 ?
    3 E1 V: Y  P! G6 c( p7 gHow Recursion Works6 N9 z( k4 N) Y

    2 k/ K. ^7 z* ^( T* e    The function keeps calling itself with smaller inputs until it reaches the base case.6 O& D* ^2 x( S# [& u

    9 {) I) p1 q9 {* r4 I) L* |    Once the base case is reached, the function starts returning values back up the call stack.3 G; o' w: a& ]
    # \7 ^- x" v: A/ U" J( L. m* j
        These returned values are combined to produce the final result.
    3 c  x  S% l. H4 U3 u5 r! w5 v7 M  K6 s6 }  f* b; l
    For factorial(5):5 ]* }/ C4 L2 o0 X: k: Z6 _; w

    $ i3 z- O  W# ?% @, p$ k- i" q1 |3 Q$ O- E4 p
    factorial(5) = 5 * factorial(4)
    ) J" n; _$ _! x8 r( rfactorial(4) = 4 * factorial(3)
    . a& [; l1 @( Afactorial(3) = 3 * factorial(2)
    ) ]6 l2 l$ @1 N3 X1 V) S% ifactorial(2) = 2 * factorial(1)
    7 J  k  \  R; Z# ~factorial(1) = 1 * factorial(0); f6 ?3 }& M# K0 o9 [6 Z! h9 `# h
    factorial(0) = 1  # Base case2 y# L9 R9 O2 N/ X# B$ V  @7 |

    5 T$ Q4 X; u" H) q/ vThen, the results are combined:9 D# V2 P0 O1 V9 ~! j

    ! |7 n  I0 ~8 ~' N1 z( p- b) i  b+ ^% W. t2 _2 N" E6 X
    factorial(1) = 1 * 1 = 19 t) h- v/ a4 M" Y! e. z
    factorial(2) = 2 * 1 = 2
    8 T6 U7 B0 L* ofactorial(3) = 3 * 2 = 64 b" I- v' q* T( C
    factorial(4) = 4 * 6 = 24
    , X% b7 b: V: _) W3 |factorial(5) = 5 * 24 = 120
    8 Z" K% b# S) p8 Z; ?7 N+ C8 z( \6 v# Y8 q/ v4 v& [- T5 \" ~( {
    Advantages of Recursion  ^3 h- F# G2 M! s; e

    4 A2 J: s  L, \    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).0 r- D% e' p# p& d. K8 @
    , }7 l2 K8 o* O( X: D# I; f
        Readability: Recursive code can be more readable and concise compared to iterative solutions.7 X- J( O3 V$ ]. I1 h8 A; l) J
    2 p- z7 n% M0 Z+ R1 u' \
    Disadvantages of Recursion' Q6 e% |, L0 @  C

    - t, w* \7 O0 k+ ]! V" @. a% H    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    3 k1 U' V, O* k/ h4 }& e  r( W) a8 F5 N. O3 K& h1 p6 O
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    : y/ s5 y6 i( n* D" R. l7 H# U
    $ P1 X6 V' ~! }) m+ @" {& _0 B# i# rWhen to Use Recursion* ?. z2 ?9 M! O0 k

    ) L" h# M( ^! m; F, K' ~    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).) W. t4 I6 r6 z! ]* V" j1 i9 Y

    ) Y& v. G% }9 C& k3 e    Problems with a clear base case and recursive case.
      Y7 z3 s5 h" r1 e: s5 }6 P! ?$ w6 i6 }5 N
    Example: Fibonacci Sequence
    ) J, k/ s4 p. J. B0 j7 {; u4 \! y* f& Y
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    3 \8 F% c+ B& m
    8 Z  g: x% a; z3 Q    Base case: fib(0) = 0, fib(1) = 1
    ! u! A5 Y# t6 {3 K! M8 O
    ) r" C9 d4 X1 C! b/ ]    Recursive case: fib(n) = fib(n-1) + fib(n-2)( r! P+ z. d' V3 X* P
    1 t+ y! w+ G& B) E
    python  _& g/ n' }4 d  |* C

    7 G  }3 c9 Z9 `2 {# v* H5 n* b5 ?, E. ?6 S/ |! p
    def fibonacci(n):
    $ g9 J4 o, C" s5 V. `5 I    # Base cases6 T, f0 ]' X' Z
        if n == 0:. I; r! l7 ]; O. S
            return 0
    0 p/ G( Q, Z5 U3 F5 r* Z! ]; b    elif n == 1:
    . k3 `* \# k# z" E8 u5 T' ~4 W        return 1- _$ a# p/ F1 q* }) N; U% a8 a+ ]
        # Recursive case1 h0 i; e# X* t4 K
        else:# Y* L$ W3 B. ^. l
            return fibonacci(n - 1) + fibonacci(n - 2)2 B" [4 x7 u/ M0 i4 {0 `* h+ N

    ( @# T  }* g/ C. ?$ b# Example usage7 \; u+ F! E8 o
    print(fibonacci(6))  # Output: 8- o( i* L  y5 d# e* n& R
    ( Q' E  d' v: c7 i; m8 b* @
    Tail Recursion" B# @( W- U5 q; ^
    $ K8 j0 D( ^9 ~' ^; U/ Z0 Y8 N
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    $ j7 L; K2 M8 G/ s
    1 W7 W; t( \# g4 y! _In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-4-1 03:50 , Processed in 0.069509 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表