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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    , B$ {6 k4 C! o# d, q4 n9 h5 R! z
    3 n9 }# N, j! A9 ^解释的不错& b' Z$ W0 E2 x6 H) a/ h6 H- O
    9 i6 }8 O* ?4 r( i* w
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。. {# F+ [- u1 Y

    & r* B5 ~2 ^" _' L/ J# [4 `) c0 K 关键要素9 j: h/ S2 z' c" T# x9 \( j
    1. **基线条件(Base Case)**
    / d4 g4 f6 V7 e9 N7 {& x& d2 m   - 递归终止的条件,防止无限循环3 x, ]# O7 C$ G$ y( R4 v
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1& i0 \/ G9 u( w

    & g- x( Z; w. y) A5 _5 p2. **递归条件(Recursive Case)**
    # j  Y6 C1 h" J1 ~   - 将原问题分解为更小的子问题$ x8 e- Q* C3 X
       - 例如:n! = n × (n-1)!
    - I6 Z( \- a! A+ x% R# S( N# I
    " a' b: y3 }! ~  A; ?7 @$ B1 g 经典示例:计算阶乘
    8 J1 I/ {* l& F6 }; u* Fpython
    * L9 S& s, U2 H, n$ bdef factorial(n):
      {7 B" k* T! z7 I$ ^    if n == 0:        # 基线条件% t3 @9 e3 B& J7 m
            return 1
    # n+ u% B$ c6 c- |    else:             # 递归条件
    ; }4 n2 S2 L/ W/ h  z! Y1 Q        return n * factorial(n-1): t- K# s9 q, k$ N8 _' i
    执行过程(以计算 3! 为例):
    & O8 Z( L6 v' ]9 Yfactorial(3)% @5 v* v2 g2 M' X
    3 * factorial(2)
    " I$ E) E) @1 ]3 H5 m+ E+ k5 w3 * (2 * factorial(1))" |9 r6 r# Z7 D: q2 |9 m* b: H' y+ h
    3 * (2 * (1 * factorial(0)))+ s  M  D7 H8 r$ R' b7 D7 \
    3 * (2 * (1 * 1)) = 69 a  x0 {- ^, q

    ) x7 T- f( e* T& z: f2 V 递归思维要点
    : j" ^+ O7 }! f: n- D  k1. **信任递归**:假设子问题已经解决,专注当前层逻辑5 `6 b. z1 q  @) f
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    $ |; u+ z9 `; I9 D0 m. b3. **递推过程**:不断向下分解问题(递)
    % T6 [) s) p* j, D/ B! X) ~4. **回溯过程**:组合子问题结果返回(归)  W6 X3 {+ E) j% b3 H

    5 l0 u" D5 K+ e2 P; x( [" @' y 注意事项- p: K  z9 P- W' L
    必须要有终止条件
    # L% g" r- o+ ^- J) Q+ I递归深度过大可能导致栈溢出(Python默认递归深度约1000层)  R! M4 Z+ s2 I' S7 ?2 \
    某些问题用递归更直观(如树遍历),但效率可能不如迭代' O6 y: B( n- _( ]: @8 @
    尾递归优化可以提升效率(但Python不支持)( F# g! v3 b+ A1 I* D/ ^
    % T; ~& c5 g3 f  U; m5 @
    递归 vs 迭代
    ' b+ ]3 b" H4 A' k/ S|          | 递归                          | 迭代               |2 F3 P+ w/ X3 |. W6 J
    |----------|-----------------------------|------------------|
    " L( F$ C5 i# S, j8 R/ M| 实现方式    | 函数自调用                        | 循环结构            |
    - M" u% s0 t1 e| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ' T9 s5 `1 ]  F6 G) S+ M| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |8 p5 F0 S# h( ^- Y' M% _
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |+ I3 B; r# r* v, B

    2 q) C$ A6 _9 ]* t 经典递归应用场景
    ( l  N5 I" U% `  @4 K0 [$ C( E1. 文件系统遍历(目录树结构)
    4 S5 `/ k9 \0 n: I3 D: d6 g0 j2. 快速排序/归并排序算法
    ! f. }0 c# g( n4 u% w. @3. 汉诺塔问题! B1 d# o' O9 u& ^9 X2 Q$ A7 F
    4. 二叉树遍历(前序/中序/后序)
    ! M5 s# n  \' p# W- F# V5. 生成所有可能的组合(回溯算法)5 q4 G" x7 B, c) `; P
    ' G/ o: M1 K! k9 y: x/ r
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    7 ?* \6 I+ d0 {1 X* G$ y我推理机的核心算法应该是二叉树遍历的变种。
    3 _6 J* O; [; S( \; o+ y另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    $ y6 s3 k  w1 x3 a( A9 F4 M9 m4 iKey Idea of Recursion
    & G' I' m3 l6 t. k/ ?/ K( a
    : j9 r5 O+ K; v- c* j6 {A recursive function solves a problem by:
    / F( j& f3 n& Z+ ~' h6 S9 @5 q
    3 k( k* x- X6 M( I- a    Breaking the problem into smaller instances of the same problem.
    : w5 k6 L) `3 v, f7 [
    / c7 C+ x& e7 s1 W0 j+ y+ H. z    Solving the smallest instance directly (base case).
    , ^( A+ Z" z+ q
    " O& D; \1 ~( n/ `1 ^    Combining the results of smaller instances to solve the larger problem.; i9 V! N; L. ~2 E  u
    * s$ b- q4 e! n  O# s0 @
    Components of a Recursive Function
    ' \. G" O- T% b, N  n8 {
    1 j4 h$ i: i* a9 c1 u& s; ]    Base Case:" {1 H  f3 {9 ~% B: a

    6 Y1 y0 U+ Q& s" _5 f& u5 E        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    2 s  O5 g& v$ T8 U# x- @  k" I8 s& a
      o7 W7 n, @' _# E; `* U        It acts as the stopping condition to prevent infinite recursion.
    ! s# b( b. t8 H6 ]5 q1 d
    $ {: i7 ?7 E; i% W7 m0 }2 a        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.2 ]9 [- u5 k/ B. i" ~  ~
    + M1 B7 Z, Y: f( t
        Recursive Case:
    5 F9 q+ }- L6 w% u9 E% B! _; U
    : }- ^) _5 c3 V+ \        This is where the function calls itself with a smaller or simpler version of the problem.# K* c7 V: J+ ?0 \( t, d
    1 o% J# Y. w1 A1 s- g" `
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).9 t' L# i: c" x
    : k3 Y2 L& e! ]$ @' J0 Y: _  B
    Example: Factorial Calculation- S/ h! T& a3 G4 n  J
    5 t0 E% E2 P) y/ X+ S9 {
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    " e% ]" b2 n% |% x' p0 s2 d& W5 W5 T/ i
        Base case: 0! = 1& j8 ]# }+ H. q& L/ t
    + b- Q( S- t8 }8 _' E6 _
        Recursive case: n! = n * (n-1)!
    - ]% c' ~7 P' C4 ], N
    5 T9 K* ~! @6 T- P8 h- FHere’s how it looks in code (Python):: @: y- \, f2 f3 a7 H+ _1 s  D
    python  J) Y* Z6 y/ b2 Q% ?0 _, r
    9 [: O% w! a  b/ n4 G

    7 t+ e. A1 s5 j7 j7 ydef factorial(n):4 O) G* [: b% M1 J3 K* G, G- @1 ?7 C
        # Base case$ r# c# \* K. r( X
        if n == 0:! n( K! W  B& M- M; @) |, Q" B2 |
            return 1
    6 J- \( q2 C- I& `, k    # Recursive case
    - M/ o; A, ^. z    else:( R0 s' g9 c; K0 {' E5 p. m5 |4 C& T
            return n * factorial(n - 1)
    6 U; v5 u' T# @! T4 v9 B7 `$ \
    3 a) P3 f& U7 x8 P# Example usage( D( d1 Q9 {$ a3 y) Z- c- j, p
    print(factorial(5))  # Output: 120. d$ A; @* h) Z5 @2 ^& L

      X! c& S6 B9 \) G0 fHow Recursion Works
    ! l+ _# y7 Y7 \6 A2 j+ ~- ^' q6 k. O' ?$ p3 }' S8 c# [6 [
        The function keeps calling itself with smaller inputs until it reaches the base case.- J. M' S$ a" V3 K/ S

    4 D% V! U9 [; \+ F2 r  e9 M0 S    Once the base case is reached, the function starts returning values back up the call stack.* r6 v$ ?. S0 r& k+ H' J7 Q3 k

    $ V. S" J" _6 Y: T6 P    These returned values are combined to produce the final result.8 v2 a+ `. M7 F, l* y
    ! b9 z9 c, {8 Y3 U
    For factorial(5):$ O1 k5 a: `8 d- Y; x; v0 P! `

    6 K- Y- ]4 G& A: k* m$ g$ _" C
    $ F) \( k; q- @. d8 r  C6 [factorial(5) = 5 * factorial(4)/ h( k. y. k( u* e6 e2 i8 z# ?  R- m
    factorial(4) = 4 * factorial(3)
    4 h% i0 I: T8 ~/ T% E7 D6 Bfactorial(3) = 3 * factorial(2)) M- ~- J0 @9 b6 N! u8 i: U& W
    factorial(2) = 2 * factorial(1)
    8 s- J5 _' ~. o' y0 ifactorial(1) = 1 * factorial(0)
    8 w! n/ m  m& j/ Ofactorial(0) = 1  # Base case
    . j# S9 k; Q1 ]. T9 Y: a: P, J5 a  k: o  j; \4 w) f% x/ U* u) M8 j
    Then, the results are combined:/ h% \3 k7 B1 r
    ) R0 K. |/ S: J" r* I* U# W+ [) W6 O
    . _; Z$ T7 Q3 F- B: p
    factorial(1) = 1 * 1 = 1+ q$ _  `8 z1 P% Z* n$ C
    factorial(2) = 2 * 1 = 27 f# g; R: g( }5 I4 V/ H# E, ?- K9 k) d
    factorial(3) = 3 * 2 = 6
    , V. q, H* O3 p2 pfactorial(4) = 4 * 6 = 24
    . I) k* J. a, Z6 Ofactorial(5) = 5 * 24 = 120
    6 c$ G- N' p! t" z( [$ r" {# T6 O9 f/ N, d! p. ]
    Advantages of Recursion3 V0 ^5 S$ ~. \' F
    1 f  w# z! J, p1 F+ X
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    . K- Q! g, f. n% f' [
    $ G  n2 q3 V) T8 _. p    Readability: Recursive code can be more readable and concise compared to iterative solutions.) p, C  t0 B. E2 I$ ~. T3 D2 f0 s
    & A, H; k, _% j- L3 E9 k5 D
    Disadvantages of Recursion1 z. y5 u# ~  c% K

    " E* B& H! E8 K$ G5 ^4 u* f    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.8 g2 R+ I0 @% Y0 L1 u

      ]" k2 M; f( e3 {/ X0 F    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).. h" ]" o) @% ]

    . y' S3 \2 x: l+ y! K' gWhen to Use Recursion
    1 ~# F: g* @& l* z$ ~$ x. z5 |, h0 T. B
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).4 v/ |$ g3 R' K- Q

    ! }% `0 W; Z- w; o8 _( w    Problems with a clear base case and recursive case.
      d' _3 c* \# \+ c, Q0 S; b, n3 F* z* Y& t- E
    Example: Fibonacci Sequence8 d0 ?# j2 J0 C8 W8 n
    % O! _. m; e; |$ a( z
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:; q8 v& M+ |! ~" X$ T, W" w
    , g# [% A6 u/ ?+ n
        Base case: fib(0) = 0, fib(1) = 1$ `1 ^5 T: d$ Z/ `- o2 c5 P

    $ Z: A+ t7 ?. {( J; ^2 y    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    3 b1 P- X, D& W6 z
    4 g: w0 X" o- X+ {4 ^  H2 ypython+ |/ v0 |) X2 t  a, E: A/ t
    ' t; q& v, F" D5 O
    : l6 q+ q% N% b' K8 i1 r- ?
    def fibonacci(n):
    + n5 b7 d: y1 G5 R, z& t  E    # Base cases
    ; {5 z" R) l1 W    if n == 0:3 k( I) q# ~) M! ~
            return 0
    ; @% e0 X. q! G* ?0 f5 Q, S' U    elif n == 1:5 C0 q4 g& S' g( I/ g# {* ?3 n
            return 1
    , a9 m+ H5 ^7 D+ |8 z    # Recursive case8 m) @/ B' p% {; c
        else:" S" j9 _" l( s0 O; j0 `2 |/ V
            return fibonacci(n - 1) + fibonacci(n - 2)
    $ m: S: A/ u( }; h( Z) W/ S, b7 h) R8 E+ e
    # Example usage
    . W. w3 ?+ ^* u' ]8 W# {print(fibonacci(6))  # Output: 8
    1 F* Z  R# U! J5 _+ U# X& r# h2 I1 m& M1 R, d3 {0 [' ^
    Tail Recursion( M) Z% K$ }3 @" K8 S: d
    , `/ s) F. Z+ ]" T3 Y
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    7 D! u( v/ v& s- k6 E& L- R3 e4 h1 u  s
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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