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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 % `7 v+ y$ {7 \8 f: k: C( P9 t& f1 t
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    解释的不错. e: a% D2 \8 K( I7 \5 E  ?

    + J+ O4 c3 B8 b0 x- F6 |递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    # p/ u; ?  [1 D7 W: n 关键要素/ z. z+ C5 c5 s; x- F' x& O
    1. **基线条件(Base Case)**
    / }. e5 g. ^+ c% [   - 递归终止的条件,防止无限循环
    8 f" a1 `+ l& @   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    & F6 F* r3 Z+ Y) O/ M6 V9 q, G) w8 y8 t1 _2 d! C+ Y+ f, Q5 p8 t
    2. **递归条件(Recursive Case)**! o1 I, t* Z1 y* s: I" w5 j+ W
       - 将原问题分解为更小的子问题
    : h+ y* z. w' E/ |8 ~0 r   - 例如:n! = n × (n-1)!! n5 p! U( _! _1 X* t% |! y

    8 W6 L: `9 L* @0 I# V- ^, Y8 g 经典示例:计算阶乘
    $ M- `; R5 I( O0 r: r  Lpython: H3 M, r: @  i2 X5 B  m8 L
    def factorial(n):
    1 [" o2 E* k2 |8 G# n    if n == 0:        # 基线条件$ k' Y7 D' J8 O
            return 1
    ( S4 O* i6 A4 A& r: U" D' H    else:             # 递归条件- l2 k& l+ c7 e1 H0 ?8 ~4 J
            return n * factorial(n-1): D; t) q. ^5 T0 a! d: `( N  z
    执行过程(以计算 3! 为例):1 L% B3 |) K! G4 Y" X9 [
    factorial(3)
    . i8 }# [2 L; b3 a3 * factorial(2)
    8 G" p0 c% t2 d/ @2 x& J9 @. h3 * (2 * factorial(1))
    , L# h; i, e+ o9 o) \3 * (2 * (1 * factorial(0)))
    ' x7 G/ C& ?+ p, X3 * (2 * (1 * 1)) = 6
    7 n; S6 V$ Z! `  D1 ^6 Q6 y) H# U7 ?, ?8 U, ~, P
    递归思维要点! t' L: M" A- K/ F1 q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑6 @* M3 T, V3 |
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)- M. o: U0 ^& E1 e. Z7 }4 z
    3. **递推过程**:不断向下分解问题(递)
    ' l1 t# G) f! v: [! Q# Z) q4. **回溯过程**:组合子问题结果返回(归), A" Z( ]( t* b1 y& A$ M& [& i

    9 \! H$ t$ |, B/ V: j! V) k 注意事项
    ' I. u# L3 h/ w2 r( S$ O必须要有终止条件
    % w/ E( s4 |' _+ w: T$ \递归深度过大可能导致栈溢出(Python默认递归深度约1000层)/ Z: S7 n9 H; o3 v
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    - F( b+ J4 z+ I# R5 f9 G尾递归优化可以提升效率(但Python不支持)+ I" p9 O3 I. a4 @/ D; E( w

    : ]* K7 H5 |! p) c0 c0 D9 d 递归 vs 迭代
    " t5 d: t6 g# r( v- T8 f0 Q) ^|          | 递归                          | 迭代               |. f# B4 p0 M" b1 b. ~# e
    |----------|-----------------------------|------------------|) u8 }5 w; n, Q# J( N3 v: Q
    | 实现方式    | 函数自调用                        | 循环结构            |  l) h& n; |* R6 \7 g0 C
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |9 N* u. I- P0 W& d! G
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |# b- M0 C0 u( g
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    + m: }% F) K! ]/ H& G3 B+ \6 v' E) Y# m5 [; b+ w2 t: q7 [* S
    经典递归应用场景* G; J, V8 X  e& t9 W
    1. 文件系统遍历(目录树结构)
    * t7 d6 X, V1 O4 R2. 快速排序/归并排序算法5 W( _8 p3 E$ V4 B! u
    3. 汉诺塔问题
    ( F; g6 X* J* R2 T9 B4. 二叉树遍历(前序/中序/后序)
    : M3 n- S2 o. v: o( G2 C  T4 L5. 生成所有可能的组合(回溯算法)( a# \* g0 {* l6 M8 ]0 o
    # ?8 l* g5 k6 u' q
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 06:03
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,) D$ w) r2 f4 ^9 q! U3 O1 D, Y' K
    我推理机的核心算法应该是二叉树遍历的变种。
    - j! R: K( e) l& X7 T! N) Y另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    9 ?, W2 a% u" [& I6 oKey Idea of Recursion
    & u' B8 q. ]' ^+ o$ w. j2 h* }
    A recursive function solves a problem by:0 r! I( f8 v9 E
    ) Y  F5 T9 P" m4 c1 M! ?
        Breaking the problem into smaller instances of the same problem.
    + B9 r9 r, m) U: `- f- b4 \% J+ s( d& n/ k  G$ |
        Solving the smallest instance directly (base case).2 s* Y/ d& ?% d) d% _
    " [' ?$ b9 w% R) N" u# u4 j
        Combining the results of smaller instances to solve the larger problem.3 n# u  g' v4 N; |& p
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    Components of a Recursive Function# o! ]4 ?, S$ `! g" G3 j% }# d, {
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        Base Case:  \0 R- X  N% ~9 Z( d
    - K: Y5 y9 K- H6 p2 C8 \0 x
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    - I; O3 `7 E* f0 ]/ @. v- i. u9 `1 C+ }) W6 p; Y
            It acts as the stopping condition to prevent infinite recursion.) Z" g) w" _" }- [0 Y- ~# e
    2 R( [% _. X. r6 n% B
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.2 y1 F! d. |# k8 Q  C' }

    % K1 G* Z9 x% w0 _9 \    Recursive Case:
    6 T2 c, s7 n7 R& H2 w- [) j: E
            This is where the function calls itself with a smaller or simpler version of the problem.
    . j# J1 z2 d9 h$ x" t) k
    2 A1 k9 X/ v9 a" b        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    % G! L# L( U' {4 g: e+ x/ R7 ]/ J7 v. e* W0 _# M  l+ K
    Example: Factorial Calculation" L/ x2 U3 j, Y
    / _, f( U% l1 r. {- l' t
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    + R$ Q. x0 c+ B1 @9 O. e& b- ]  }1 {$ @# y" k" c: {
        Base case: 0! = 1
    3 U) u/ Y8 m; {( x$ N/ {7 f1 g4 j
    - k4 ]- h3 w% S1 w  k/ }) V4 Z    Recursive case: n! = n * (n-1)!
    " ?! P+ P, p4 Y8 l% O& i( ]3 K3 g+ v$ a& {+ ]' i4 w" ]9 \
    Here’s how it looks in code (Python):
    2 T2 R2 d4 `) O( V2 }python( R. n( O7 i' U, e

    % ~# n! w6 r2 x
    8 N* p+ @' O9 Y$ H! w" Vdef factorial(n):
    ; n$ t& ^; s; e! U, _    # Base case
    3 Y4 ^* m/ h" b    if n == 0:+ S0 ^7 L7 ~5 c) E9 M
            return 12 P% r9 Y; E- l. c# ~; v
        # Recursive case$ x1 X' R. N5 N
        else:- e4 [1 a' t3 B% \
            return n * factorial(n - 1)6 @7 w- ^0 F- }; n$ ]  X& M

    " ]5 ~3 h* R) H# Example usage
    9 P/ Z; o1 |! `" vprint(factorial(5))  # Output: 120
    2 k$ B/ i) @4 A, d3 ?! Z: r
    6 `. w! P" e) x8 M( F% AHow Recursion Works
    * Z/ r- k) s1 }6 p0 C9 I
    8 g4 J0 S  L* l( Z( F- q    The function keeps calling itself with smaller inputs until it reaches the base case.9 P) ^% R) I$ Y7 d& L( D2 ]7 t) O
    1 H* D  |8 i. x1 \+ J
        Once the base case is reached, the function starts returning values back up the call stack.# s7 X  D0 F0 @5 n7 t- D" \3 ]
    ' R. _8 g4 |+ Y0 s' Q
        These returned values are combined to produce the final result.
    3 W4 ~' }: o+ a9 ]; o& B
    0 ~6 F" e+ V+ N- ~For factorial(5):/ M$ A4 i3 d  Z; b. Z9 @5 L3 p2 i
    * h: d7 [3 K: I

    . S( P# f& m* y, c+ \" ?factorial(5) = 5 * factorial(4)
    0 V, S; r- _/ Z  }3 a8 `/ g/ ^; `factorial(4) = 4 * factorial(3)
    - _8 c' {8 d: zfactorial(3) = 3 * factorial(2)
    ) e8 G  s* k4 M" h- qfactorial(2) = 2 * factorial(1)
    * ]! S2 ?6 n) [- @! u9 I+ `factorial(1) = 1 * factorial(0)* v/ M" F! J2 r* H
    factorial(0) = 1  # Base case
    6 q6 E% R! P# F, c+ f3 q
    3 `( M! _- A6 ^0 }+ H+ j) u* _Then, the results are combined:
      p& S: [: W: I4 r- P" t, F! U; p8 B& z- |

    4 D- s+ m( u2 Kfactorial(1) = 1 * 1 = 1
    & c# g: ]4 Z: M, Jfactorial(2) = 2 * 1 = 28 I5 T8 W5 z6 ~3 c1 E1 B
    factorial(3) = 3 * 2 = 69 y% a* e: ~# r. P! w0 P7 R. ?- W
    factorial(4) = 4 * 6 = 24
    / |4 [* N. o! E% Pfactorial(5) = 5 * 24 = 120/ ]# c; e; c3 O2 `3 C6 x% [  i

    ' Z( i' P3 s9 s1 y+ ~Advantages of Recursion
    3 @8 D- e- _: u3 c& v& M" P. h$ R% `) [% }
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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    8 R& {; z! _# Y$ |; v    Readability: Recursive code can be more readable and concise compared to iterative solutions.- u; o. ?+ Z  W7 }/ m/ i5 @4 |! F* i

    4 ]5 O8 w0 O" Z, C9 b, P& w2 o  }Disadvantages of Recursion
    . }5 I4 ^3 E: q/ G( {/ T5 S% k7 Y
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion./ F0 V( t- ~$ F* u/ Q( R- a- l

    5 l' z8 l; T& \* |' P    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    2 b2 r) C9 |! ~  i# r  z7 F" N2 J. z; o7 a% P! w9 a, t: K6 m  F
    When to Use Recursion
    3 M2 r1 x5 h3 I3 E* x: o/ u. u) M+ I: \
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    # v7 p7 l0 ^: R* X) U" P2 _1 s6 t- R) J) b
        Problems with a clear base case and recursive case.& d9 v* ]6 E- Q, q3 G

    $ n. q0 H" Q1 y3 ZExample: Fibonacci Sequence
    ' r& u4 g( {1 ^+ k& Z+ g2 a& L% O3 M5 o3 ~
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:* Y7 ?. ?  y5 l# [# Y

    % V/ I: a& G5 Y9 i    Base case: fib(0) = 0, fib(1) = 1) I; n7 t: s' i! u

    / ?3 C. d- b9 R    Recursive case: fib(n) = fib(n-1) + fib(n-2)  t2 @  u1 v% d1 Q, \  v+ G; e

    / N5 v- z* H5 o6 ]( epython8 M* t/ x& U( X$ V* }  G

    ) g3 C0 q6 q% P4 k
    # ^3 Q. @, a: Zdef fibonacci(n):
    & M/ D* q+ S: S& ~    # Base cases! \# ~. H" Q; J% h4 {4 [
        if n == 0:3 o- y% a" L5 b- T! {( e
            return 0  I& q: N3 j5 b2 f
        elif n == 1:
    & m. D8 D+ c! F$ y7 m. s        return 1
    5 g% x6 B5 `* e( Y8 w# S1 Y8 x    # Recursive case
    4 ^+ \8 c4 w- s3 @7 q1 Z    else:
    " V9 d, i# Q" J5 T        return fibonacci(n - 1) + fibonacci(n - 2)6 W8 c- m* ?: D: u

    4 k; ^& H+ h' n# R4 |# Example usage1 x' H2 t# T1 ^- g
    print(fibonacci(6))  # Output: 8' p& y6 _  s, h' G7 `

    ) f  E  ~( Q9 }& }# GTail Recursion
    3 |+ M  i& N+ S- |+ ~( f6 L3 G3 O- c' W7 R
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ) _5 I* \: d1 h( ~) B; O* B  \! p, @6 \7 Y; e2 o) r
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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