设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2760|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 0 P. x- h( K2 P  N8 \% T. b
    8 k4 R7 `( k& v
    解释的不错
    8 H$ S0 E# d! J% }
    0 I# r) b# T! }4 P( A* R递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。. E& r; J8 x% n5 D% Q) P2 }

    5 [% F, d' U* t5 O5 d9 |( V 关键要素$ O! C  y5 I4 q9 A: g
    1. **基线条件(Base Case)**
    - t- p; b' o4 x; M' A6 W   - 递归终止的条件,防止无限循环
    9 Q" P# ~# P: _5 X& V6 M/ D( t" o   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    6 }: u; G4 c! ~, y
    ; r: H8 v* k# C8 [. i2. **递归条件(Recursive Case)**- c1 ]. f* u+ T* @3 I4 G
       - 将原问题分解为更小的子问题
      t! {$ J, V9 \, S" c   - 例如:n! = n × (n-1)!2 Y4 R0 t) }" C$ k

    + M5 E5 n; Q% b6 N6 l9 Z 经典示例:计算阶乘
    1 W$ L) \5 }" V2 g6 l! k5 Upython4 A8 y- Q/ K8 q! E
    def factorial(n):/ F! g( ?* Z$ l, u+ M' x
        if n == 0:        # 基线条件* x. ~6 d# E2 c+ `
            return 15 ^! e# }+ H& t, |/ Z
        else:             # 递归条件9 O/ n4 a5 g1 \9 `& h
            return n * factorial(n-1)
    ) \8 V% H' s9 C2 b0 h执行过程(以计算 3! 为例):5 |6 {8 P. C4 w* v; R. _
    factorial(3)
    ( }0 Z& F9 _! I! L0 J3 * factorial(2)
    " b% H( H! U8 }3 * (2 * factorial(1)). e3 G' O: o$ I) e! U7 }
    3 * (2 * (1 * factorial(0)))& \7 I; Z( V. z! d/ i
    3 * (2 * (1 * 1)) = 6
    & |% |9 T0 m; \1 i+ @* k3 C% {
    : g2 R7 m* i: r8 u9 N6 P/ D 递归思维要点
    # L; ^7 E: Y3 n' K7 c1. **信任递归**:假设子问题已经解决,专注当前层逻辑, g3 N# n8 l; a
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ) V$ x  v- s  E, Z0 x! U9 x" r$ R3. **递推过程**:不断向下分解问题(递)/ a2 Y9 N2 w1 e/ q7 T7 L9 D4 y% @
    4. **回溯过程**:组合子问题结果返回(归)
    ' W( h6 G3 m( d7 }3 m  }! e8 a, ^4 S. c1 D" Z# J- n3 h
    注意事项
    % S3 L/ q8 N  J) i必须要有终止条件
    4 ~5 k5 Z( {- X7 x" x递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    9 G$ j/ m5 D9 p, e0 m; h* E某些问题用递归更直观(如树遍历),但效率可能不如迭代
    $ A- Z# }" R% u- ~2 m尾递归优化可以提升效率(但Python不支持)
    3 g& j7 n! m7 m3 K( s
    3 z, J! _8 s6 W1 z3 p( G1 I  u- K5 W$ q 递归 vs 迭代9 b. o  `' v4 x' o
    |          | 递归                          | 迭代               |* C. g7 h. R7 k0 f
    |----------|-----------------------------|------------------|, R8 Q1 V8 p) j) T* D/ c" e
    | 实现方式    | 函数自调用                        | 循环结构            |" h* Q, P  F" |3 d% z  Q: r, s
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    / o4 }4 B9 L1 N  V9 x6 N| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |) @! X$ _2 [; ?6 s
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |5 T: q' u; Z( f4 `

    : w, l) z6 Y) }2 S; S4 q$ w 经典递归应用场景
    ' N' C0 ]- _3 d& \- k! V' W( w; b1. 文件系统遍历(目录树结构)
    $ ~1 k" V: D3 T- f2. 快速排序/归并排序算法- Q2 f/ f* [: p( S) j( m
    3. 汉诺塔问题
    4 o, P0 K8 @1 d' T4. 二叉树遍历(前序/中序/后序)
    7 t% Q* S6 c6 Z( y9 Z! g5. 生成所有可能的组合(回溯算法): `9 M9 h: D8 X% h& U4 \3 Q
    3 {# u0 ?0 R8 \/ l
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    郁闷
    7 小时前
  • 签到天数: 3247 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    $ o- @3 Z7 p' B' Y我推理机的核心算法应该是二叉树遍历的变种。1 j% m) G  B7 y4 ?
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:& D& q# o/ a/ d( ]1 B1 R+ @9 o
    Key Idea of Recursion7 i$ e0 M. q; \
    + b/ W* ~% F. ?6 L' z
    A recursive function solves a problem by:: t; ^7 w# v1 O& O- U- A0 m* w3 _

    , k* T8 X; Z3 Y- _    Breaking the problem into smaller instances of the same problem.
    ; @( b# T$ T8 l; L; C* i& H, k/ B: i2 Z! p# E' _
        Solving the smallest instance directly (base case).
    / J( p! D6 _9 r* C4 j- e3 }8 e* u
        Combining the results of smaller instances to solve the larger problem.5 m8 ~* M( w6 e7 n8 i+ A

    , e! n- {7 b5 {! OComponents of a Recursive Function) P: i* N! u5 c* Y. c# l

    % {" z: Q+ G( }' ]- x( W    Base Case:6 g3 V! g6 |0 d3 q( q9 V* }
    7 v# l& ]' B$ {5 O
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.% Z% x1 J- T7 v# Z4 ?2 `. _" \0 t

    # t+ h2 c, [( I4 L        It acts as the stopping condition to prevent infinite recursion.
    4 f+ U8 Q# |6 s& v: L6 |, y) d( S% _2 q/ v
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    : x, k  x# ~/ U  m2 A# M, w) C) ~5 L- L2 I: i) @6 x
        Recursive Case:
    2 U% k) a* T# h0 D' J% P% f1 i  ]0 {4 V& k0 I; }% e: F4 R0 u2 f
            This is where the function calls itself with a smaller or simpler version of the problem.9 G; I% ^- y1 ^+ l+ Q
    ! ]9 A2 r% Z$ [6 k8 n
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).' e7 U( Y0 N  f. W- s

    / Y  z5 l  i1 u) y6 Q3 `Example: Factorial Calculation
    5 M! M# y8 n! U2 q; J* S" Q; s: F* g& z0 B% N' p+ Y
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:1 q8 `1 \" T& g4 b7 n* i4 B
    $ {( L& O8 o, k) M# @0 x% c
        Base case: 0! = 1
    / z  ]% n+ J, m) f0 v5 X5 V. ]. d0 e+ L( j9 ^" D& n. m$ i
        Recursive case: n! = n * (n-1)!3 z* o7 G$ Q# j3 ~' E; e. ?

    7 n6 S. J8 v. f2 M8 [Here’s how it looks in code (Python):
    : d3 l) W" @) P/ [python  c/ E. T' ]2 O5 u% a
    5 q" J1 y; W0 u% M; c' P0 A/ f
    : U; w1 ]5 _% w) I1 N: |6 O# F9 P
    def factorial(n):
    . o3 a* S* c% M3 j2 k    # Base case
    9 c1 l0 g$ F6 L    if n == 0:  o! v5 H" C" u8 M! V
            return 1! c1 w( q# q$ C0 k
        # Recursive case
    . ?9 m4 n: |6 U8 {1 r    else:
    $ M6 m* `9 G; P        return n * factorial(n - 1)
    9 X; U  o: [% D8 N0 x& ^: A# M9 l2 ]+ g. v
    # Example usage. r8 Q% U4 y: V$ P) e
    print(factorial(5))  # Output: 120
    % R2 o% D  Z0 U
    " b6 [4 g0 G% i$ O  [/ A7 sHow Recursion Works- ^& H" Y) s+ V' x: \+ k
    6 i. c. B' E* z
        The function keeps calling itself with smaller inputs until it reaches the base case.
    # H' P( H2 h6 H1 ~8 k
    + M, R6 R7 j, ]$ b* t    Once the base case is reached, the function starts returning values back up the call stack.( r  [3 B- V% W7 D. p7 I0 ?3 T
    / l. H0 G: G( N9 W" {7 v
        These returned values are combined to produce the final result.
    9 D5 v( R9 ~3 ]7 @, ?1 o- N, N5 Y/ A! M
    For factorial(5):  w1 e  y, V0 ]8 g

    0 J9 e9 w0 c. p( I- O- u  E: n9 n' Q9 @5 r( v( o  j
    factorial(5) = 5 * factorial(4)
    . u9 _' S' e# h1 _' W- B( Z% x) {4 _factorial(4) = 4 * factorial(3)
    # }! Z) c& i0 w4 E+ `factorial(3) = 3 * factorial(2)! f8 y2 b' h& g6 a7 M) _* k% e
    factorial(2) = 2 * factorial(1)
    7 h# C0 s/ Q! W. ?factorial(1) = 1 * factorial(0)! P, R; j8 B5 K3 h
    factorial(0) = 1  # Base case: Y- Z4 ]; g( z' H
    * R: `+ }  g6 e
    Then, the results are combined:! A8 {2 N3 ^0 O4 w5 P# T

    % ]0 q$ W0 Y7 m5 N2 F8 p" ~3 ?, y
    % B$ g/ Z% U/ e! ?& dfactorial(1) = 1 * 1 = 19 x9 W- c( c$ V6 F1 a0 t# |
    factorial(2) = 2 * 1 = 2
    / \- h" p. Z0 R9 n3 cfactorial(3) = 3 * 2 = 6- I* E: B! L( g3 o
    factorial(4) = 4 * 6 = 24
    4 \- g4 |3 b! r! Ffactorial(5) = 5 * 24 = 120, V& a. a$ X6 [8 u4 z: [
    ' E8 T3 d5 g$ @" p/ d+ Z
    Advantages of Recursion
    $ L; N" H" a% B" E- ^
    . R& R. ]8 R) q    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    - k8 L: M% U, {3 g; }; x8 E9 K1 l+ J$ U3 x8 c0 }) C
        Readability: Recursive code can be more readable and concise compared to iterative solutions.5 }; Q6 J# }$ R4 {  a* y4 @
    : ^  G- }) r4 T# I5 ^% ~" K0 V
    Disadvantages of Recursion
    5 Y4 D. i) j/ \1 Y+ Y% m) ^4 c0 d, r. \- ^4 V+ t& n$ h6 V
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.+ _  L: n3 ?. S% G/ p7 x; _' i" j
    * U- }! M9 O- b0 {
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    & T) }0 D  X; y. k5 b, `2 Z! W
    . v3 B( \' p2 OWhen to Use Recursion& T$ s# |5 b- u% j3 R

    : U* ]; g" U' a' P% I9 F    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    8 |  ?( M* j. y, G, k& U0 b7 U+ o% i% Q) b1 M2 \. A
        Problems with a clear base case and recursive case.( ~; w% X: R( i1 i. W& C, B

    ; C0 q9 Z, @& ]$ U6 W. F* ^# lExample: Fibonacci Sequence: t& I* |. ^3 j4 F
    1 F: G3 M0 v2 I! d  Z! c, g
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:5 l' ~5 k* k9 d' e2 P1 L
    ! n- A9 U6 C7 u. u( g3 i
        Base case: fib(0) = 0, fib(1) = 1: P0 j$ d' a. I- G! h( i
      c, n& e- p2 r' x) W9 o2 O6 V
        Recursive case: fib(n) = fib(n-1) + fib(n-2)3 C6 v1 X( z. ^7 L+ B/ C2 \& W. [
    , S# a* |4 I- [- ~% v
    python- r0 y$ I! B% M7 k! H2 ?

    + x' \* d" K+ \8 q7 h: H2 [6 S( J: m8 |
    def fibonacci(n):
    9 X/ s2 q5 Y" C    # Base cases
    & N1 [" H, e# P    if n == 0:
    5 @, q$ j# d7 Z% t$ G8 m0 \        return 02 ]5 J* o+ l3 m
        elif n == 1:/ ]5 t6 T, |1 E' V; z* @7 @0 n
            return 1
    0 w1 F( U0 V/ I* @; l8 A- {3 H    # Recursive case
    6 l0 c0 j( V1 I! X    else:
    3 O: ]; p5 ^% y+ j; ~1 I! B( U        return fibonacci(n - 1) + fibonacci(n - 2)
      R7 Y# I+ P& Z. z+ @* G& a2 K1 Z
    # Example usage
    . ?3 ?# ~2 k: Y: I, F0 _print(fibonacci(6))  # Output: 8  K) R, h$ T0 n7 v' N

    ; e+ x3 b; n: xTail Recursion
    2 ~/ M# p  `' Y( E6 D) y0 T  Y, I
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ) ]9 E; S( Z) k9 d' A
    9 R8 B/ a$ Z  z1 [3 |$ m* B' ^: lIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-5-23 14:34 , Processed in 0.060050 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表