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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    % Q! [: m! k" Z9 E1 A: g5 T: Z
    + ~, M4 }8 I0 K/ ]/ g解释的不错& c0 e% I" j/ ~* N
    $ d+ F" A( K# w! ?! q( |: \) ^
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    / r6 V2 F2 w! K8 Q$ c' u5 V8 Z/ \1 z9 W3 C5 w
    关键要素9 |$ w, p$ o# N8 M/ w
    1. **基线条件(Base Case)**! ]8 B: {, A1 L, y9 ]$ l: l( P& p
       - 递归终止的条件,防止无限循环5 b( e& E0 {2 x5 H7 G+ I
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    ) ~3 D3 q+ q7 t: Y) a# @9 x5 I) ]
    9 b3 K$ t4 G# z" y2. **递归条件(Recursive Case)**" [' h/ I" x$ T4 D, g
       - 将原问题分解为更小的子问题9 Y7 k$ o# Z; e% j% w, |! H; c5 r
       - 例如:n! = n × (n-1)!; Y8 v% g* ^) M9 P4 M3 @3 Y

    9 D; Q- U& O# n& |$ U& S/ Q 经典示例:计算阶乘
    ) s6 r' e# o6 v' rpython3 e/ Q! \! b5 }3 Y
    def factorial(n):
    2 q  r/ Q9 K0 ~, y9 ^    if n == 0:        # 基线条件
    ) L' Y8 q8 j; Y$ k8 h        return 1  ~, l3 r% ?) i; y2 a( K
        else:             # 递归条件- U$ w' \3 t  ?0 z* @) d4 ?
            return n * factorial(n-1). P: J3 }: E7 l: o0 i, r
    执行过程(以计算 3! 为例):
    5 u8 _7 i/ u  _factorial(3). A( p: k- H, Z' D
    3 * factorial(2)! o  x3 H- [! {" m! m* u
    3 * (2 * factorial(1))
    + a  V2 v  v: @/ E( N: _3 q3 * (2 * (1 * factorial(0)))2 E) @3 A5 }' @* l
    3 * (2 * (1 * 1)) = 6" ^7 s0 w$ Q3 g! q1 u3 \

    0 ]' v1 _/ D) M! x' o* ~ 递归思维要点1 ]7 {% N6 S  M3 I7 M9 i3 d& C8 B
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑/ E) I, N" s0 N
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ( h1 M' S: v- O. \6 J: S3. **递推过程**:不断向下分解问题(递)
    / L2 c- L7 d& O* J5 Z  h- o4. **回溯过程**:组合子问题结果返回(归)
    ) T) _  ]" x9 Z) s3 [8 {$ q- @' ~6 L6 |& f- M' q- w! |
    注意事项4 D* T/ V- G! F- |! _. f: i! Y
    必须要有终止条件  W- d! Z' J* ~& K1 i
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)" f+ L9 f* k( G+ R+ F
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ) N: d6 H0 f5 p; W6 p( C) N尾递归优化可以提升效率(但Python不支持)9 }: _% I5 {1 E" @
    2 z( d( g9 `1 v5 P; H, h- ]
    递归 vs 迭代0 N# a( R, X- ?; M; t; h6 r
    |          | 递归                          | 迭代               |
    $ l) R, @" M0 v9 m! B+ f|----------|-----------------------------|------------------|" O3 U3 ^' c, N) m" B  S; d
    | 实现方式    | 函数自调用                        | 循环结构            |
    8 j1 d" i3 M0 J| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    + R% G3 v1 x% `/ \; X| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |  K8 U, ?* r) t1 I$ P
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    2 c3 u$ r( G4 N+ h' F
    9 a" E7 s2 o! c, ]1 ~ 经典递归应用场景
    ' A% `6 Z# O$ S  o8 M% }# C1. 文件系统遍历(目录树结构)4 i+ S+ |/ }$ W: M. {
    2. 快速排序/归并排序算法
    6 ~9 X, b- t: k% Z3. 汉诺塔问题
    0 c3 ^' x$ l# n6 W, Y! k8 a4. 二叉树遍历(前序/中序/后序)
    6 M) [+ V3 G# [# H, j; ]5. 生成所有可能的组合(回溯算法); ^' L7 e  K+ c! e. D+ O2 P

    2 {  V4 J* G3 Y0 z: a$ C( f试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 17:32
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    5 Q. i- G8 C( ~我推理机的核心算法应该是二叉树遍历的变种。
    # \8 }) n' O% C; R  T6 ~% j2 b另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    + k) J; Y) Q  F9 P5 RKey Idea of Recursion, @$ g# X; |! `# f$ S
    4 c' k/ ?1 h4 g' o+ V/ t4 S8 j6 C
    A recursive function solves a problem by:- {0 t0 D6 c- K1 s/ r

    ' ^/ d1 A" v* b0 c) w# ^    Breaking the problem into smaller instances of the same problem.
    5 y) w' ~1 Z( t5 U8 Y7 l/ N" _( ?# F3 z
        Solving the smallest instance directly (base case).
    " O% k+ A! n# K! H; e! G
    + S" i- I7 F, R, R- z3 @    Combining the results of smaller instances to solve the larger problem.
    - p# H; h9 o# B( q
    ( G% O2 }* i( g3 TComponents of a Recursive Function
    $ v6 Y3 g0 r( H7 t! K" k- S# e' S0 k- N! [2 ^
        Base Case:
    # x0 J2 E% m0 t3 t" q
    : B2 W6 `( H3 E: v% q/ u# X) k        This is the simplest, smallest instance of the problem that can be solved directly without further recursion./ i" c/ q) G$ h+ t0 a" d
    * t8 H; ]+ r9 h$ }+ ?( |
            It acts as the stopping condition to prevent infinite recursion.
    $ m! \( t- C; y. ]4 @4 D0 I; F9 T- Q/ |
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.1 ?* R8 i! K7 C4 K$ O1 Z
    ! m& Q4 z5 n: v2 y$ t  T
        Recursive Case:
    / u( {: C2 _( t- |$ p* C8 h! o  T! k/ j) z4 U! ]
            This is where the function calls itself with a smaller or simpler version of the problem.
    7 H; o- h# u& p# Y: C8 `1 A  p- x& W0 \% {
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).5 C* s& ^2 w' P
    ; q; N4 [" N% I- g7 R
    Example: Factorial Calculation# j4 K- j' N8 j0 |. J- L- u

    # w0 ?- v1 }  n3 [1 ?The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    / ]( h$ C; }  h) S, g" H$ j# d* [! ]) {+ Z; H. l8 h
        Base case: 0! = 1' J' h+ Q  T9 c9 r7 v  c

    : h: f5 m4 V) v+ e    Recursive case: n! = n * (n-1)!6 k( t& @$ ~% ]3 j: S' R( R; O

    0 J; k3 ]/ W- _9 N! J! h( }; SHere’s how it looks in code (Python):
    ' z* q; o+ M" ipython3 J7 j$ r5 a7 s: R. j6 f) N- }2 q
    2 Z6 g' y, b  W1 f! w" Y
    , O* O+ z) b8 _; \% m
    def factorial(n):: E1 x. x; o; S4 ^8 t- @
        # Base case" G5 ]3 J$ u- T( p* m
        if n == 0:1 h2 A: Q5 t! n1 K& n' i& f
            return 1, f* Y" [. w4 `  O4 }
        # Recursive case
    & \5 f# c) F2 t9 A$ v3 s( I' J    else:6 S8 `  J( g% T
            return n * factorial(n - 1)8 M/ {7 p  N/ R. T) q: d4 S

    + [! ^# `/ s* @2 n# Example usage
    ! {' I* L9 q9 ^print(factorial(5))  # Output: 120/ @. m. w7 V3 v0 F* B4 e  Q8 g. v/ e
    7 q* _( G$ u) V* E2 W5 b
    How Recursion Works6 E! c% x: L* ~6 m. s

    # m5 n2 l$ L1 j, p8 i    The function keeps calling itself with smaller inputs until it reaches the base case.
      W& p* b9 v! K: p; j8 v" d
    ! ~! d8 T5 t* n5 ?# ?    Once the base case is reached, the function starts returning values back up the call stack.
    * C/ I' E! j( p% D" S- p2 {( {5 ^: [! h% t8 B
        These returned values are combined to produce the final result.4 c$ T; E: `# D" F% Q
    # s. I( @" |& r* ?8 b
    For factorial(5):+ V; L2 ?1 A  j, H. v/ ?# M3 s4 A
    / L! B, @1 d5 Q% X: C9 @

    % k% @8 e8 c& V0 G9 B7 ifactorial(5) = 5 * factorial(4)
    6 |+ A. a) I% ~8 t. B+ @2 h4 Ffactorial(4) = 4 * factorial(3)
    + ~) h5 H8 g, q/ X, V5 k3 ofactorial(3) = 3 * factorial(2)% t8 C& L. j( k8 A+ F
    factorial(2) = 2 * factorial(1)) m# E% k" g& J3 n5 m3 g& z
    factorial(1) = 1 * factorial(0)
    8 p5 p0 y2 W1 y+ B( c3 Z, pfactorial(0) = 1  # Base case
    7 S; B  k$ y; h" d0 k5 G, C# s; l! B- N2 `! f" s
    Then, the results are combined:
    + }' d# p1 ~) `: {. ^! w9 d
    1 A  N( @1 }% d2 M! z9 ]. ?- |0 i8 \5 D* u% T3 U) b# v5 _5 q' |# K
    factorial(1) = 1 * 1 = 1
    . B. o( b8 U* d* Gfactorial(2) = 2 * 1 = 2, s. C" F5 [$ v& c4 a+ f5 B
    factorial(3) = 3 * 2 = 68 v2 t  A+ r2 j7 [* Z# P
    factorial(4) = 4 * 6 = 24
    * U9 k$ P) |( j& m. ofactorial(5) = 5 * 24 = 120  ~1 Y6 B: ~( Q; W8 ]0 u1 \
      C& C0 `; K3 n) X5 e- y
    Advantages of Recursion/ q1 _8 A0 N2 v. _% ^
    ) s7 Y) h! B5 A
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    * P9 |$ a* g8 \1 f: C: X  H5 n7 o$ n0 g1 s0 ~+ R. q7 O
        Readability: Recursive code can be more readable and concise compared to iterative solutions.6 l4 s& g' E" ]  d1 F

    * Q8 j8 S* U1 w8 h9 |% p4 ?1 TDisadvantages of Recursion
    ' x5 M# M$ S, o4 q$ r; y- o! `0 X" t4 l, m
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion., Z4 A" G; X; X- b* h8 m7 w
    & ~1 v( u+ `; C/ m5 ?8 H6 x
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    * e1 E% y7 W2 j( l- U1 h9 u9 n" c
    3 N) Y0 J1 }% t& RWhen to Use Recursion, X! H6 b5 j$ P" R2 K+ g( o

    ; f6 o2 T9 s2 X) z: N' w, X    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    1 p4 `3 n# ?3 h. [7 ?  J+ H
    & E- G. x; B9 G    Problems with a clear base case and recursive case.9 L5 t# Q" e2 z% m  c

    # K+ Y  Z4 j% S- J6 A/ V( K9 HExample: Fibonacci Sequence
    0 o, v' c! V9 _' E% X" ^0 n! i! I! Y# `' q' O. U9 _, [, M
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:' a1 g( O+ l$ \

    5 H" E& ^/ C6 @8 i1 ~    Base case: fib(0) = 0, fib(1) = 1
    4 o4 C. I  {. q. V) o% E! b8 x
    & m7 n6 g  H# m0 s& U! M9 y8 A' y    Recursive case: fib(n) = fib(n-1) + fib(n-2)* X- A7 m5 `! ?7 w  B4 j
    ! m2 H3 s- }. X4 \; a* Z
    python* }' J$ s! n7 V! L, n0 P) m

    ! ]" K& l, l$ P) R, c- D& P) X3 k
    def fibonacci(n):
    2 ^2 T& S6 X) D2 ^# N1 G9 q# m    # Base cases
    ; c% L9 T1 H4 d2 u( Z    if n == 0:7 M8 @' h+ ~# C- A6 U
            return 06 y) K3 v) k, w& ]& N+ `. X$ a
        elif n == 1:
    # w" d9 l4 S7 ]9 T6 B! h; ^        return 1" O1 V0 k( A% U5 T4 x, _
        # Recursive case! b( Q' M  m# T3 R
        else:
    , Q5 Z4 J" S) \: d. p/ y7 A( }        return fibonacci(n - 1) + fibonacci(n - 2)' B. t' N3 @+ ~# c2 U# N

    ! t! R5 X+ L* K2 |& |# Example usage; U* ^: H$ U/ @7 m& K
    print(fibonacci(6))  # Output: 8- `+ V; m: Y" i6 `/ I& Q

    ( v& H+ v3 s4 H- `* m: jTail Recursion
    * u& k: [, \5 S$ a: x' [0 K) J" S' }" _  |9 v/ W7 n8 F
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).7 `4 B/ S0 u5 j3 r& A
    / O$ t4 S  v/ l" T; B3 o* L3 O* O3 `- S
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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