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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 . L$ I+ j/ q2 z0 s; p
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    解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    ) u' T" Z, S  p7 D5 S$ r- P  Z7 z
    - Y0 I2 e' K/ g  f. E3 K8 Y 关键要素
    ) u8 e/ Z9 |! u: M1. **基线条件(Base Case)**
    5 g. R! Y" k1 w2 ?, |6 b. X   - 递归终止的条件,防止无限循环
    # w" ?* h# K  z1 R) O   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    - W2 b5 K& G$ q( ]; x' X9 l6 X* t! n5 B# J4 y2 _% j
    2. **递归条件(Recursive Case)**
    * n) Y9 W# g1 K" ?' E" W4 l   - 将原问题分解为更小的子问题
    * W5 F3 {6 j2 K9 F- u) f+ C   - 例如:n! = n × (n-1)!
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    ; f3 @" w0 A3 I# D- `/ W/ V% \ 经典示例:计算阶乘
    * h; t3 I% s3 B( V  Gpython
    6 A  _: M1 x. L5 o+ d  E4 Ddef factorial(n):( [+ N# F* a/ H1 o9 z8 M
        if n == 0:        # 基线条件0 q( Q  {' i) e" X; \) t  V6 }
            return 12 \5 ^! R1 S5 V8 M5 h* {, ]  U
        else:             # 递归条件
    + h0 U" S* Y# T# j1 H        return n * factorial(n-1)# ?7 d# J  s& C. Y/ q- G
    执行过程(以计算 3! 为例):
    3 x& N5 n4 u9 k6 T- C: e; q; sfactorial(3)# F$ B; I  Y& ~+ K. O+ `4 _/ q% u+ x& o
    3 * factorial(2)
      Y2 R9 T! d9 l* w+ N3 * (2 * factorial(1))8 t% ^, i3 ?, D1 A
    3 * (2 * (1 * factorial(0)))
    : y: B! _, x# \4 N; x. z. b$ ^3 * (2 * (1 * 1)) = 6
    , S8 w/ l) d9 A1 S! }: E% W6 e" f. t- p  g) d6 }2 d
    递归思维要点; u, i. ~5 c  u$ [
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    2 {: i0 F2 O; e6 m1 `9 ~5 r$ ^- L2. **栈结构**:每次调用都会创建新的栈帧(内存空间)9 E) ~3 o) F6 d: I' V
    3. **递推过程**:不断向下分解问题(递)
    # K+ `+ ^2 f9 Z1 u9 H, t4. **回溯过程**:组合子问题结果返回(归)
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    * U3 \4 `' n3 | 注意事项5 b8 ^. B" z7 |. u7 H# G3 ]  J
    必须要有终止条件
    & a* P6 b! q9 `0 R, c递归深度过大可能导致栈溢出(Python默认递归深度约1000层)+ J/ p$ q7 ?, k: u# ?# D
    某些问题用递归更直观(如树遍历),但效率可能不如迭代# I0 M6 X1 R- n7 @$ D
    尾递归优化可以提升效率(但Python不支持)5 `, |+ m* }+ O, h3 ^( d6 ]7 X( I
    ( M4 B) X0 o% f
    递归 vs 迭代8 r, _8 W4 H* e  ?. q7 B4 o) r
    |          | 递归                          | 迭代               |
    / W' {* F, t4 j" }/ m2 m|----------|-----------------------------|------------------|- E9 {' o0 W! e
    | 实现方式    | 函数自调用                        | 循环结构            |
    0 G: |7 |) Y$ M4 j. O9 w, k6 H| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |, `3 ]9 z" G) i6 ~3 }" s$ o
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ( p  A! U$ {: G% A$ @) E, Q7 F| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |) N8 o. \4 ]/ H- O: P! m
    " f. h: M! m- ?. D* |
    经典递归应用场景
    " @  m/ `0 w3 j$ G4 j- F/ s1. 文件系统遍历(目录树结构)
    " j1 {3 w* L; t  D, W2. 快速排序/归并排序算法
    - v8 x5 y+ u$ f! [+ q  x  y' _3. 汉诺塔问题5 u" E$ N! x; z6 p
    4. 二叉树遍历(前序/中序/后序)
    , s% N+ [' V$ M: L6 F/ `# y5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
    郁闷
    昨天 06:31
  • 签到天数: 3239 天

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    4 s2 X/ D: }  h9 B9 f我推理机的核心算法应该是二叉树遍历的变种。( p2 F  `. ~  y
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    # ~% |4 r2 q6 IKey Idea of Recursion/ {0 I7 ^# g8 ^! j' A

    / j2 Q9 b4 Q  _: h0 _A recursive function solves a problem by:% S' G" X3 ~* B  d+ r

    7 }: [7 q% l; w! |5 c/ t3 Z, r    Breaking the problem into smaller instances of the same problem.& _% p8 [6 T' m' {0 a: Z

    * t9 Z+ a4 ^8 r' _$ w+ U7 ?* _9 [    Solving the smallest instance directly (base case).
    8 X( q' j1 j& X0 P/ E
    ) C  W& [# ?* G/ B    Combining the results of smaller instances to solve the larger problem.
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    Components of a Recursive Function0 b6 g9 ?* }/ o) \( m' l* ^% Z2 U
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        Base Case:" I. A7 e; S* E' h( Z2 i; j
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.$ X+ _  {0 ^" t0 t# J3 O5 r& h

    9 ?5 H' h% v  b" X0 V  l* G% {        It acts as the stopping condition to prevent infinite recursion.2 {" c9 J4 Y1 I

    9 D2 A3 e# A+ s% A  n        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.* o; S( W3 _) |' U% Q9 ]

    $ t/ }/ p: T7 S/ V' Y    Recursive Case:2 Q* i% Q, R  `% X" m
    $ U, W: @5 }: [, n/ I
            This is where the function calls itself with a smaller or simpler version of the problem.9 j; X3 b* k' N9 B$ U6 Q7 y$ n
    & P& ~7 G! H$ v/ ^. `2 Q4 c
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).3 P' h+ \/ U7 b- q5 B: y$ c
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    Example: Factorial Calculation
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    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:4 d# |* I  w) C) h1 H) U8 |
    ' x) C" m6 F+ U* K2 s7 I; X
        Base case: 0! = 1
    $ F3 s/ b. k$ }, h8 T" s- P5 G2 B. h' K- W
        Recursive case: n! = n * (n-1)!
    + g2 A, P) `% m$ X' t
    3 ]' @. F3 c& g  G2 |Here’s how it looks in code (Python):8 ^5 m# y. |  q. A0 `6 h
    python
    + G- V- b4 W, Q+ G/ d, N7 d8 N, u: H

    - V9 `) [( W4 c% R, b" gdef factorial(n):1 X% O" |7 B# j; z1 ^* U
        # Base case
    0 u: s. o* z2 a9 U5 O5 A' u! s( ]    if n == 0:8 X# e/ _5 n& A2 A. S! v/ h* t
            return 1
    . S6 p2 I- f" f1 c$ F& B6 S. Q8 ~9 ?* N    # Recursive case
    $ \& |8 y" ]5 h$ G; P7 V    else:
    ) o- J0 t+ N8 a7 g, i        return n * factorial(n - 1)$ m# M3 o1 N1 t0 _% ?' A! v

    / c/ K2 n3 T+ r, W, w# Example usage
    * v$ B0 d5 P0 C; g" z9 A# [print(factorial(5))  # Output: 120
    $ p, F5 b( D! K) E3 k: m; {- Y4 a
    * }5 \$ l! G" C' DHow Recursion Works' w$ `7 J( k% L
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        The function keeps calling itself with smaller inputs until it reaches the base case./ W" j: v; z/ Y" W6 H
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        Once the base case is reached, the function starts returning values back up the call stack.% e- W& [, U  H9 T: r
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        These returned values are combined to produce the final result.
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    For factorial(5):
    + g; o0 j; A5 ?; ~
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    factorial(5) = 5 * factorial(4)
    3 ?  J0 n8 q3 b  G  K  U8 u# Q) tfactorial(4) = 4 * factorial(3)
    . a* v* x; N" t, h9 s& t8 |factorial(3) = 3 * factorial(2)
    $ a- o& @8 `+ h: @" T4 }factorial(2) = 2 * factorial(1)
    + p. @; q( X3 ?factorial(1) = 1 * factorial(0)
    9 U, q/ u+ J! y) {4 Afactorial(0) = 1  # Base case
    * H! f7 G$ B0 o
    3 `) B$ L! D9 e$ vThen, the results are combined:
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    0 n  ?- }: x& O8 q, b) x' i# F7 T, O/ n# l
    factorial(1) = 1 * 1 = 1
    ! E7 W6 l3 z) E8 [# W' P" Jfactorial(2) = 2 * 1 = 2
    # s5 A1 w9 y# y* O: cfactorial(3) = 3 * 2 = 6
    8 [& M! u6 B5 _! z; ?/ l1 G* F' a0 W) Sfactorial(4) = 4 * 6 = 24
    2 e1 ?8 e0 S+ n( zfactorial(5) = 5 * 24 = 120
    # n0 A+ L$ }. X3 P7 n% c% m  w+ l
    1 x  C3 D& b9 c9 BAdvantages of Recursion1 c  R  M3 y( G# ?$ o: K8 s
    * O" k" A# h" q4 Y/ M
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    * K/ f- B( g1 `9 L% a- w. Q' g6 u$ ]; B" L1 h2 T: ~8 `3 @' B
        Readability: Recursive code can be more readable and concise compared to iterative solutions.2 D: H# Y1 O* Q- s9 D0 t) E0 v5 _

    & W" Y  [$ t, U% Z; LDisadvantages of Recursion
    ' I( L7 n/ A+ {) A1 A7 N6 f1 q: j1 Q1 K6 x6 q3 E
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.& [: o' e6 U7 E- ^6 x7 E- f* y
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        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).+ C1 M8 h4 }% I. E4 c$ X+ U

    ( V! n' W4 F$ b5 ~When to Use Recursion
    3 {+ ~& X/ s- g: Y, w0 I
    0 y/ T( ]# N* {/ ^% Q9 c    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort)./ h8 L: W0 e* L4 @- r, F
    . b; K- m! W. M! r
        Problems with a clear base case and recursive case.
    ; w8 B( t. z4 E3 X# Q- @) Q, n3 i/ @- ^' |* l% d% B
    Example: Fibonacci Sequence3 _! g+ g" f5 H( Z) j7 X8 V
    8 h$ c; F6 S) h5 w; Z0 Q* W/ X
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:  R; K& T: V% E1 h$ X
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        Base case: fib(0) = 0, fib(1) = 1! H/ f$ E( Y3 G
    # A" P' p, U: x8 r9 m6 F
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
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    python! _( O, d5 K) U* h, j; l0 m

    ; j- \1 l7 E3 ~5 q' r4 ]  r
    1 G6 R. [2 I# b8 k7 ?def fibonacci(n):
    / Y! E7 \$ g  K1 I    # Base cases
    $ Q6 J- G1 b+ ?2 d- r" {$ J& B8 C- N    if n == 0:8 V0 S1 y, |, f- f/ Y+ V: I
            return 01 j9 I! @9 O" ~/ m& f4 h
        elif n == 1:
    / B5 n5 a0 k. H, K9 k        return 14 ^& z& O: Y  T6 J% F
        # Recursive case7 g" x8 _. n2 E
        else:* I; x+ b9 S/ i
            return fibonacci(n - 1) + fibonacci(n - 2)
      Z* e% F* M9 A' R4 p* ^3 p/ u1 z+ U+ ~+ R: V' f; M
    # Example usage0 u0 x& X2 `/ n( W# K5 q
    print(fibonacci(6))  # Output: 8
    $ i, ]( |6 |2 E, }8 h+ Y9 {8 a: V8 I+ ~$ `, m
    Tail Recursion
    + K- u  I. C* N' n' F
    . S+ }2 F8 t+ h6 MTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    - Y9 t' ~2 V, V0 u6 c
    ) w; i. l8 X0 c$ e9 i/ UIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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