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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 $ t0 `; N* a3 K& U) L& V

    " L* N4 e& ?1 z, c- s! _解释的不错
    ( X9 ]% z9 Y- P1 ?. ^/ h, N0 r1 v0 h! z, `  ^  z% ?; V
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。( p7 r0 V3 C. O$ O
    ; D/ t8 H8 y4 O& f' \% X
    关键要素$ Y) h1 n  F6 W: L& X0 P& X. n: e
    1. **基线条件(Base Case)**' ]  P' w3 }' n% f1 ^# N: _
       - 递归终止的条件,防止无限循环) H( {: {- B3 c4 E
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1- P" U, ?& M, L* o" W
    ! ^6 l4 U, m% B/ u8 ]# _
    2. **递归条件(Recursive Case)**5 T3 N: B2 g' ?4 k
       - 将原问题分解为更小的子问题6 I, V; }& w$ C3 V3 f
       - 例如:n! = n × (n-1)!* ?! K4 W0 x+ B

    1 z5 Z- E! x0 g  @# Q1 J 经典示例:计算阶乘
    5 b( c! {4 ^2 ?python- a# H- r4 p$ @3 B5 W
    def factorial(n):# E; d3 b$ m2 j6 M" l* \$ @0 O
        if n == 0:        # 基线条件
    , S9 h$ t( c; W/ B% @        return 16 Q) I; J. w1 d5 c* O2 ?6 i
        else:             # 递归条件
    : B7 i% s& {" h* ~2 G        return n * factorial(n-1)
    2 N' w6 O) T. B1 [执行过程(以计算 3! 为例):
    % Y& c% n* }- l: Rfactorial(3)& r3 \) a1 r2 y" a" M# V. Y
    3 * factorial(2)& i' \) P1 W4 N( f( i6 s
    3 * (2 * factorial(1))
    , T6 |1 r) @( v7 s2 J1 k, K; {3 * (2 * (1 * factorial(0)))2 Z' g/ C& S4 x
    3 * (2 * (1 * 1)) = 60 s' [# k) L5 g2 D& P9 |. j
    ' A1 |+ h- t8 m0 q
    递归思维要点( Z  ]" H* r; R! e
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑- l% J7 i( l" G6 I0 C0 f
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)7 W2 K6 L; o( [1 O
    3. **递推过程**:不断向下分解问题(递)5 |4 N0 f' X% H: I5 F1 e
    4. **回溯过程**:组合子问题结果返回(归)
    , p2 P5 v. D( l! M  Z/ m* W0 e1 ?4 q6 e% P2 X9 z4 s
    注意事项
    % X" ^3 ^$ ?/ ^必须要有终止条件; e. ]' s5 K( K5 E( B* H. U
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    3 T& S! d. X0 K. k# P' s/ x1 p4 D/ k! O某些问题用递归更直观(如树遍历),但效率可能不如迭代
    & _4 S+ v; t! H( E9 @) Q3 _( r. s尾递归优化可以提升效率(但Python不支持)3 N7 Q' h% u+ v+ Z: j0 z) J

    ) n' A% |8 t1 a8 P& f 递归 vs 迭代
    & J  l  p  s8 f6 ~5 |; b|          | 递归                          | 迭代               |* s; q  O! c9 v7 z: {- x+ d# _
    |----------|-----------------------------|------------------|; E. {& ~# F4 I5 I# R  n& d& S
    | 实现方式    | 函数自调用                        | 循环结构            |8 J# V: ~% ?1 L
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |! b+ Y$ n" Y, C; B. h( h- G: e# Y
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |7 H. i# f- B& i+ @2 w  J
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    $ _* D1 d" T( w& Q3 o0 h$ V
    ( x: s5 @: V8 n  R/ v! \ 经典递归应用场景. r7 S1 O. H5 z
    1. 文件系统遍历(目录树结构)2 e: N: @0 S6 F( l/ m+ z- y0 q
    2. 快速排序/归并排序算法7 @9 u2 `7 E/ Z+ e! o# ~4 ?! F
    3. 汉诺塔问题
    4 h) f) ?0 a6 t# S3 d# t4. 二叉树遍历(前序/中序/后序)$ j' w/ D" L' R
    5. 生成所有可能的组合(回溯算法)7 y9 ~% q' V) l, D
    * E+ U, ^+ H# F
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
    郁闷
    前天 07:20
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,7 D/ Y) _) f& D) P6 j
    我推理机的核心算法应该是二叉树遍历的变种。: E3 Q. w6 N$ y# p6 B% S- i
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:& H: u$ s/ B, J( v! P; a0 j+ A& ?( [
    Key Idea of Recursion, d6 B, K: _, p- R* H* I
    : _- T* T- J- N- P
    A recursive function solves a problem by:% F  j3 l  g* F! ^0 D& Q6 d7 m
    . q" g) v* P& j9 `
        Breaking the problem into smaller instances of the same problem.
      ?+ t3 _# V6 X$ q0 T/ \. O( t7 R4 j% h8 {7 M7 W0 o3 A' ]8 x
        Solving the smallest instance directly (base case).0 R# z5 a$ M2 j3 l' M; [
    * G. O( a. C3 n
        Combining the results of smaller instances to solve the larger problem.
    2 W& @$ t' a$ ?! ]1 ?7 J4 o! h6 _0 _5 B8 s
    Components of a Recursive Function
    7 t9 B; s! q: r5 i+ k- {" T- g" W2 w- H7 m3 R5 u  B- i
        Base Case:* q7 K( J9 d+ @

    ' w8 x3 J, i0 G; d        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    . D3 R' X' r9 `- P9 o9 K* s1 n- \: t: g  s$ i2 D
            It acts as the stopping condition to prevent infinite recursion.
    ) {! |/ u' Q, _0 f: g
    : X% C0 M2 W  b- o  J        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.% k8 A- f( Q) q$ Q5 ?  \3 S" {) [
    * \* C9 \8 u5 Y2 F
        Recursive Case:
    , r; ]! y: H# D( I2 y
    3 h. d& w1 z+ t        This is where the function calls itself with a smaller or simpler version of the problem.' d# \  w; n- \( W/ h
    / r- ^8 ~" p+ }! J
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    $ y$ n6 ^& i/ p( \7 H  K6 Q% u3 }/ P4 D0 ?
    Example: Factorial Calculation
    , F/ x& A+ D" L+ m; k  x5 o- N2 ~& h+ b1 C/ F  D
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:. C$ K5 {4 z+ j! e7 ^4 [

    % S  ]( h* ]7 r4 K; o- d& K! ^    Base case: 0! = 1; t" A* a, g0 }0 s/ x8 F

    , g. R) Q, F8 b1 H0 l1 G% d    Recursive case: n! = n * (n-1)!, O. a' d, _4 h3 C* y4 _0 u
    + O" x& R4 G( O2 b" R" G/ k0 Y
    Here’s how it looks in code (Python):# ~! t$ o& v. n/ ]' [/ @8 I) M# d
    python
    ( a# Q7 @; Z8 E4 x* `: z) Z, d3 v0 l, M

    % C5 I1 H! l4 F3 C3 C1 G: zdef factorial(n):
    9 A* y1 F8 X& ^& @% ^" d( \" q8 w2 q! _( m    # Base case& P5 I/ m; J4 @* Z/ k9 ^8 z! g
        if n == 0:( W5 r$ E& H) ^2 S
            return 1
    5 t& b/ i/ v* N  }( ^    # Recursive case
    . R+ q) f* |' ^5 ~3 n" o5 m1 L    else:
    $ i* {1 V: X/ A3 p        return n * factorial(n - 1)
    3 Z" O) ?% Q6 b/ h
    ( U% l, y% M" X. E; ^4 w  u9 {, p' w# Example usage2 u( v7 |3 c& l8 G* B
    print(factorial(5))  # Output: 120' Y+ D/ Z$ Q2 V) u1 _" A$ ^
    8 h" ~) R8 F4 r' B& T8 {" F( T
    How Recursion Works
    ( D, F8 u- _+ P) }; c; i. f; W! ^; A" z8 U: f! m7 i3 A8 A0 Q
        The function keeps calling itself with smaller inputs until it reaches the base case.
    ! h+ A2 w' s. p, {; y9 h7 W7 _6 E& h# w0 ?
        Once the base case is reached, the function starts returning values back up the call stack.
    $ K/ P' @$ K, t1 {$ ~6 q9 ^, I2 a% T  O+ \2 s0 ^$ V" b) x- t
        These returned values are combined to produce the final result.+ j% I& E3 V9 Q  G3 W! [4 `' M
    9 T4 f1 H' b. B
    For factorial(5):
    / Z9 y+ ?- ?5 u$ i# ], r' O4 B- e2 [4 C/ |# l
    & O9 f4 V) }' k: B! C
    factorial(5) = 5 * factorial(4)
      L/ ?/ a( f" ?factorial(4) = 4 * factorial(3)
    9 Y# A( R" Y4 J0 t! P. d. G& Lfactorial(3) = 3 * factorial(2)
    % `7 m% s" \' l8 j5 ]. x( Lfactorial(2) = 2 * factorial(1)1 G! G/ z) _" k8 k) `. j/ h; S% O0 z
    factorial(1) = 1 * factorial(0)
    8 l' n' E' M: i  Q$ Bfactorial(0) = 1  # Base case
    " B9 e" W- U: \8 O0 |% w& r8 i+ D. `- Z$ @
    Then, the results are combined:
    # z. t, u5 x2 M; @$ b1 B6 R. M
    9 I/ U. G" |- S! y
    % ~8 ^* X; A0 ^factorial(1) = 1 * 1 = 1
    / a+ F8 c/ a# Tfactorial(2) = 2 * 1 = 2  j7 \4 v1 S% E8 Z$ ~1 n
    factorial(3) = 3 * 2 = 6( Y  Q5 A% n/ {) I
    factorial(4) = 4 * 6 = 24( P; A: X4 c2 }% Q% J8 j
    factorial(5) = 5 * 24 = 120# }1 r9 g. R, l! L0 e

    2 z8 |/ h; u9 m  \+ m- IAdvantages of Recursion, o0 p1 Q4 p! X" r) T' m
    3 p3 O, g' q$ ~5 r6 G8 B
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    % L& \0 {. i- |* Q! I, a+ W! ^4 k* t9 |0 l8 [$ G# y  N4 T
        Readability: Recursive code can be more readable and concise compared to iterative solutions.; P* z$ ~4 u- I6 L# A; P! b# p, s
    9 K2 _; b2 k: c" ~0 {+ b( h
    Disadvantages of Recursion9 }7 Z% a/ j0 o. w1 k

    ) [  S# O8 }- ?9 |0 X3 W" t    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    " Q+ ?. c! r6 x' J: D! F9 J0 [. S* u. k4 i& H/ \
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    1 h1 H9 A. c# a- c* F7 |
    ( X/ r* r7 i' ~2 A$ |, ?. D6 gWhen to Use Recursion
    - `. B: r; q6 R* L( {4 S3 M
    - m+ @) |+ p; a! Y5 n; R' s    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).# Y. d! I1 y, f9 v/ M- B
    ) P* C; h5 K9 Y
        Problems with a clear base case and recursive case./ C( B! S1 K4 H$ \# [! L5 A8 A

    ' [* b& i% w' `, w/ I- S4 e8 a0 q# uExample: Fibonacci Sequence" u+ [6 J+ H  A& Y
    * ~: c& g! u0 a+ x0 x
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:" e  U2 P5 B+ I' K/ {& d

    & c$ O. c! e: {( E    Base case: fib(0) = 0, fib(1) = 1( \, @, d/ o3 X* r2 E

      C2 p+ R% H+ W: k* \    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    & d5 u0 x$ e, G0 e. C
    ( Z: @* {8 J+ f/ y- ^8 p0 D9 fpython
    ! q, E" v) r# F! `! v, h
    : c2 a' z' `) L! l/ h, n
    3 ]$ J& B3 {2 s/ M; {1 Z, @4 s) }def fibonacci(n):
    ; Y; M4 S& V7 X4 |% F    # Base cases
    8 W) s0 j; B* c/ k  p: E, [! b  Z0 k    if n == 0:, W: z- t, w4 k
            return 0
    ) u9 l+ I% A* e% Z9 F    elif n == 1:- J+ v) {; {- N7 i
            return 1
    ' ?% B- @& j" M    # Recursive case
    4 `8 V$ C6 J/ G! |+ s" u    else:
    ) h/ r- U8 ]# U: o; e& e( p5 o        return fibonacci(n - 1) + fibonacci(n - 2)
    # W. X& ]$ ?: S9 b+ D
      S" f5 N6 n) w, g# p" F1 v0 P# Example usage
    ! x8 F: n, |* f. O* Dprint(fibonacci(6))  # Output: 8
    5 z4 D' K) L. z! |2 s: A- \8 z6 h" i" }+ j6 Q
    Tail Recursion
    1 u5 ~8 V2 g3 Z  w+ N8 W
    ( m  U! e5 S* w/ o; w5 N) a& ^. J( QTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ; f* p0 ]3 Z& n* ^* o, l4 x. c* i2 A4 n5 ]6 U
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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