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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
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    5 `) W4 {- f" `! N3 p解释的不错
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    ' e& c( ~1 g* B. ~递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    - ^& B9 b, V+ P6 X, P2 v% u 关键要素! U) o$ f! r3 K' j. ^
    1. **基线条件(Base Case)**
    ! m* ?( j) U9 ~1 B' k/ p   - 递归终止的条件,防止无限循环
    * T2 N  P4 q. V# h& q2 ?# y9 Q) a   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1+ j$ d* O, p+ R4 w
    : h5 ?% V) g; ?" f; Y6 k
    2. **递归条件(Recursive Case)**# J* Z. l* i- b1 k* a% y/ u  z
       - 将原问题分解为更小的子问题! t4 x  _0 k- q
       - 例如:n! = n × (n-1)!
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    经典示例:计算阶乘
    ( |+ V# g5 X) ~& s" Tpython1 A  W+ C- R- {( L/ V
    def factorial(n):3 Z8 y$ Q( Z! d* C# J; F
        if n == 0:        # 基线条件$ H% c( A' b9 ?( f$ p- c2 p
            return 1
    ( v  R$ t) z5 [% U    else:             # 递归条件
    " t- n8 ^( P5 q) ]        return n * factorial(n-1)
    4 e: I# M4 m# u) i$ b执行过程(以计算 3! 为例):
    ) A& v5 Y' K, I: E- {- Yfactorial(3)
    & H% v- q# K6 A* v9 i8 Q3 * factorial(2)) f6 ]% z. M/ W: v& u7 P9 q: w
    3 * (2 * factorial(1))! s7 J7 R& [5 s4 l
    3 * (2 * (1 * factorial(0)))( S0 n/ n. i, K  o
    3 * (2 * (1 * 1)) = 6# i. n2 s+ t$ F" W0 f' ~2 ?

    2 Z7 u- Y$ Q! w. @6 `. F 递归思维要点6 d4 C! }* k& u' E6 ~
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑; ^5 p6 Z2 `! d4 P" D9 g" e
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)7 P0 u: \7 j, F5 H0 K! }
    3. **递推过程**:不断向下分解问题(递)/ H: R. |0 A/ W- N. K# j% N# C# f
    4. **回溯过程**:组合子问题结果返回(归); @) \0 \$ r7 r  V1 U" V  ~7 \: x

    + `& C, d8 l( Y( i4 T# W* W( T6 R0 W. ` 注意事项" a; |/ j1 T: ?. W
    必须要有终止条件* ]8 X: `3 g1 K& M
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层): @5 H; \8 ~% u0 p9 f, c+ A5 ]* ^1 D
    某些问题用递归更直观(如树遍历),但效率可能不如迭代: A: R! V; F1 L) |5 Z$ b% L0 ~& ]  w
    尾递归优化可以提升效率(但Python不支持)6 @. n, C. W' ]" Q2 D
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    递归 vs 迭代3 @$ |* @) L7 ~8 Y( [+ o+ [. d
    |          | 递归                          | 迭代               |6 G  ~& [6 ]% \3 N! D1 E
    |----------|-----------------------------|------------------|
    / b# O  m, _# s# x. C3 J0 f| 实现方式    | 函数自调用                        | 循环结构            |
    ' i% {! p" e. k2 b5 P| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    7 q) ^8 `& G' Y7 {| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |7 r3 O- ~5 o6 }9 U/ j
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    . a3 o3 V7 Q( b7 E: O
    ; J' j$ j  @/ `& ^- x 经典递归应用场景
    2 h  j  D& [2 a1. 文件系统遍历(目录树结构)
    ' s9 @* s" |' F0 u) d. N8 z2. 快速排序/归并排序算法: @4 {! J: Z; y! N. e- K
    3. 汉诺塔问题
    % L0 y  n/ F9 |7 M5 U4. 二叉树遍历(前序/中序/后序)  M# u: [8 z! a! ~) ^
    5. 生成所有可能的组合(回溯算法). \' t8 `5 }) N5 ^6 _

    ( Q& }, N7 U* i) V7 P试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 07:34
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    3 a  Y' r) B# `我推理机的核心算法应该是二叉树遍历的变种。
    3 g9 k$ r) {# z' z另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    % {. f" b3 M- N. k8 gKey Idea of Recursion, n3 X) z9 t& K  f+ `0 B

    & ]8 V2 {3 ~" n6 i. }3 wA recursive function solves a problem by:2 }% U  K( n: a# y. [& ]5 ?2 r% R

    5 G. I+ }) @( q    Breaking the problem into smaller instances of the same problem.5 T) r7 ~6 E( Y

    + @. V( G9 Q+ c. f6 h/ x5 r    Solving the smallest instance directly (base case)., @- i7 V7 E: Q0 ]

    5 K# M& B% F& G    Combining the results of smaller instances to solve the larger problem.2 s4 {# I' K5 z9 A
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    Components of a Recursive Function) x/ C( t2 b- e  m5 B9 V% ]
    # j: _7 ]  \8 P+ k' b& v% v7 r
        Base Case:/ ?* g9 |2 d+ t5 Q& C5 l9 Y
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.: b: r) }3 U5 a, }4 S
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            It acts as the stopping condition to prevent infinite recursion.
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    # [% z: K6 F& u8 ~+ P        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.6 I* k" Q4 |1 C. K: J) J

    ! ]" b6 p1 f- d' l1 ~! M& U/ x* R    Recursive Case:8 P: C7 l+ ]! |$ P3 A, H! Y- G
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            This is where the function calls itself with a smaller or simpler version of the problem.; b' k2 ~# {' @$ d  k

    4 c* ?& m( v7 N8 t+ l6 E  r        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    3 q7 @  f4 L* p, f9 n: v) A0 SExample: Factorial Calculation
    ' f! b4 i5 \( v& ^* m  ^7 X* ~, D& D3 A5 {% c' M, V9 D: |. |
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    " H9 }  S5 `1 P, r# q0 ~8 p+ @- {; v7 v0 y
        Base case: 0! = 1
    " R  B* B' n/ u. @6 R  h% v# V- B; d
        Recursive case: n! = n * (n-1)!1 D, p. j. y& ^  [# U

    & @5 N* u- g: W$ Z5 s7 q; HHere’s how it looks in code (Python):& Q9 w4 k. G/ J* N
    python9 A& E% {& _6 n0 v5 {3 A& z0 c4 E: D

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    ) ~% e* ?, o6 \% v, E% x( S/ t( idef factorial(n):/ D% Z, ?' v% u; |8 e
        # Base case
    0 J* `( E6 |& A' n* v- r    if n == 0:
    5 C. {6 u! Z) `        return 1
    ; t/ P' T+ q. x: o0 z    # Recursive case# r  k+ y! C; C: S, t  u
        else:
    ; z+ q# K' N1 `) E        return n * factorial(n - 1)1 j% o5 P, Q- b! t0 P
    ' Z$ L; }/ e1 {, e7 I! p
    # Example usage4 s% v2 z, b) H0 f3 Y! M4 [3 S
    print(factorial(5))  # Output: 120
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    8 y2 N  e. c8 y% t( a! |1 X$ H# P8 hHow Recursion Works! \. l; d" y9 J- i+ D
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        The function keeps calling itself with smaller inputs until it reaches the base case.. `0 C3 G3 i- [( l" L) b. w7 k

    2 `9 s2 K3 i, f, V' C, l- h2 ~- _+ h    Once the base case is reached, the function starts returning values back up the call stack.
    + K0 G% p/ o" w. P3 a6 z! D& e. R' v: c' T' c. O" T
        These returned values are combined to produce the final result.
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    For factorial(5):) M" j4 k# z( N4 k

    + Y! J6 W5 v- s- f/ t2 Z; H/ l* h, p5 L+ `
    factorial(5) = 5 * factorial(4)
    / V) o5 i1 Y! B9 y8 t0 pfactorial(4) = 4 * factorial(3)1 ?- C. g( w& Z* D7 P; I/ a% a( ~
    factorial(3) = 3 * factorial(2)
    3 j& L2 i/ f4 _, U. d: X% nfactorial(2) = 2 * factorial(1)) k" c5 @- E# H- O0 H
    factorial(1) = 1 * factorial(0)
    ( O: j. j2 u2 i) Cfactorial(0) = 1  # Base case. o6 P8 {8 K7 _, m
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    Then, the results are combined:! E. C, d- p. B6 F5 T

    " @$ b+ s5 z( V) `0 \9 X4 [& O7 ?- ~1 m1 h+ Y
    factorial(1) = 1 * 1 = 1- d$ H. j1 D$ w
    factorial(2) = 2 * 1 = 2; `0 t' ?, f/ C* @0 j0 G0 F
    factorial(3) = 3 * 2 = 6
    2 E  i7 V5 \' O, t" Gfactorial(4) = 4 * 6 = 24
    0 B" U5 y, d8 ?% ?# ^factorial(5) = 5 * 24 = 1208 ]; S! v! `! L# B4 x5 c

    8 e" K5 r; B' f" Z0 XAdvantages of Recursion8 A! Q7 G4 \. T! F1 n
      y9 J( J, q, D! Z1 U
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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        Readability: Recursive code can be more readable and concise compared to iterative solutions.3 s6 i( j+ p- a  R( m* _! `' I% r+ L) Y
    * ~2 s: Z4 i1 O/ i3 W* V
    Disadvantages of Recursion
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        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.- J/ W8 F- m& U8 A5 t
    ! H! `% D3 ~% S9 s2 ]
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).! ?3 {+ T; d) l! U0 a
    % z$ E9 \' s) S1 c& Z5 @
    When to Use Recursion* t& S2 E; X. `/ V! x+ L1 j
    ! _  J* A- H/ D% r# @
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    2 N* E4 [- b& p. }2 H8 @6 A0 j. p
    : K8 l5 J( T; W/ t& Z    Problems with a clear base case and recursive case.5 K8 I* P( b3 b8 n- C: }' _( t

    2 j7 h! w% ^8 H; F$ H4 BExample: Fibonacci Sequence$ U, E: z: F4 w: V% Z7 H8 c1 W

    + A5 f% N1 {4 TThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    - V( A( O0 Q$ e& @$ k+ r% A- P* [* d0 s
        Base case: fib(0) = 0, fib(1) = 1
    2 L% G+ A8 t$ p" o; T& {  V) p2 Y* C- d
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    5 J( C( F  [! }+ v8 e9 t4 ?, l) W- C) `- }6 f9 ]0 `4 ^
    python
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    - ]/ x0 L/ S+ A% `5 T; m+ _. i( ]8 U5 K, }# u# u) c7 ?
    def fibonacci(n):$ F: a1 r3 X, e- `" X9 p( r
        # Base cases
    % r9 n. [4 k& A8 L    if n == 0:
    ) M7 F2 n! a6 m! @( R" R" u/ O: U        return 0- K) ~- x$ H/ ]3 J6 a+ S7 R! ^
        elif n == 1:
    0 x- v1 o% V$ J6 \6 {3 U        return 1
    8 D. w  {) p! k& x4 }+ i    # Recursive case; |/ C) v1 i" O7 r
        else:
    5 i+ w4 ]* C  q6 |9 p        return fibonacci(n - 1) + fibonacci(n - 2)
    * o- m4 n: N+ \; P" p/ d% k
    & [1 Z% |& V- n/ G. \# Example usage$ n6 Y  M7 G# j/ i
    print(fibonacci(6))  # Output: 8. k& t& A, |2 t3 M/ _
    3 e3 f4 G, d8 u
    Tail Recursion
    3 K) O. ~0 X) e5 P* ]1 ^$ l& w2 I4 k
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ! b7 u' m: Y  L2 C6 G1 A; w( r
    - ^4 e8 V5 R8 s& y2 Z' RIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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