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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
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    ' A' {0 s* y+ Z解释的不错
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    # U/ @: }' Y. U递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。4 A' F: N: s* s) |
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    关键要素' L8 d2 _) Z! k- w* n* R1 ~; Z
    1. **基线条件(Base Case)**
    ' H  T- ^0 r! H8 P. N: b# _5 A' e   - 递归终止的条件,防止无限循环1 Y, v4 _" s  `3 C
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 14 D: l( y0 Q) M9 y
    ) }6 r: p/ @5 z9 w: X( K' R2 `
    2. **递归条件(Recursive Case)**- ]! ^0 j3 _/ Z4 z7 q
       - 将原问题分解为更小的子问题
    1 D( p+ b2 r$ ~* X$ `   - 例如:n! = n × (n-1)!
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    经典示例:计算阶乘
    " P9 V0 U! D3 h- ^" @: @" }python
      z$ v7 A$ D. s! r0 Fdef factorial(n):
    $ l0 ?2 K8 h7 m4 \    if n == 0:        # 基线条件
    8 i9 k' H% x- F- @        return 1% [% a  s; e' d" i* [
        else:             # 递归条件
    ' ^! @0 i) P! g0 A3 T% a& W        return n * factorial(n-1)
    7 L. P8 V8 r. E: C; i" s2 N, o9 r执行过程(以计算 3! 为例):, \9 Q2 K$ u8 Y: G& U+ g4 z* r3 X; f
    factorial(3)
    ( |/ f8 D& m( e3 @) N3 * factorial(2). M# o5 A3 r0 i* C3 H8 t
    3 * (2 * factorial(1))
    1 K! r5 A5 e" X5 F! I' R0 w6 N% e( w3 * (2 * (1 * factorial(0)))
    ) g) Q7 p9 T8 ]8 m1 ^3 * (2 * (1 * 1)) = 6) \. B) Y+ N- @! @1 Z5 E; ~

    # y( I" s( P+ b' H3 H& s4 C: \, V6 M 递归思维要点
    $ }, T. `* K+ G; f1. **信任递归**:假设子问题已经解决,专注当前层逻辑
      L3 }" ^. q7 w9 v) ?, S: D1 L2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
      x/ L; `/ X2 f2 D3. **递推过程**:不断向下分解问题(递)7 o- O  W, H' s
    4. **回溯过程**:组合子问题结果返回(归)
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    注意事项. ~% K* O/ Y: h3 T# b" G; m+ e$ j7 j
    必须要有终止条件5 X, h: P' G; ~% D7 `
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)1 n& F) M, @' N$ U, i- ?2 V
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    5 ~) j) P& a. p5 I# I尾递归优化可以提升效率(但Python不支持)
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    递归 vs 迭代
    9 i5 O. N# d  W5 ]2 m|          | 递归                          | 迭代               |
    , I% ~) M; G' f|----------|-----------------------------|------------------|2 U. D$ D9 Z8 A9 s' ^( t5 _
    | 实现方式    | 函数自调用                        | 循环结构            |
    . x- ?9 K9 ~+ m0 |# e| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |/ k3 c) _/ L9 h& @- y: O2 O% n
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    4 i* z  E: m' G( W: P* o8 u3 y& h| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |5 }4 S5 Q6 H+ Y

    7 i7 C% j% E" h4 w 经典递归应用场景
    / Y1 V, N7 P- }1 H% ^/ z1. 文件系统遍历(目录树结构)5 n5 `  F) U/ m
    2. 快速排序/归并排序算法' ]* g$ A6 M7 v- E/ r0 e  a
    3. 汉诺塔问题: y, @* p: E% I  d
    4. 二叉树遍历(前序/中序/后序)' o+ B# h* |: L+ N- A$ W2 d
    5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    ( |4 w; P* j7 f5 `# K我推理机的核心算法应该是二叉树遍历的变种。
    ! ^! T0 t0 G4 A另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:/ W; [& l- J3 m1 c
    Key Idea of Recursion' k4 V# O' w# g' N, c. W* I
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    A recursive function solves a problem by:% x, q  `1 T  _" p- _9 U
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        Breaking the problem into smaller instances of the same problem.$ n2 _! i; V; B; e2 |* p

    3 g& R. T6 I% A8 U. R& t! n  n* |    Solving the smallest instance directly (base case).
    ) V3 j" ?( T! S% R0 r, ~
    & T6 E1 ^1 s) v9 X: l8 U    Combining the results of smaller instances to solve the larger problem.
    1 N" ~: m4 v% l* x5 j0 ^: I7 q8 |& ^; q- y3 Q/ S: \4 s
    Components of a Recursive Function
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        Base Case:
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    $ @( s/ b5 e' e        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    6 L4 ~9 j& C7 X2 M. a; m; n# D
    4 k' p* |% j, h6 U6 a6 \+ h        It acts as the stopping condition to prevent infinite recursion.1 U, H# \+ y8 s3 X/ Y

    9 _0 E: `1 X; j' X& ?: ?- }2 j) a        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.( g5 o) R3 _% E* y% C2 a

    6 H2 ^- h# u3 T3 `    Recursive Case:' P. P. E  y! b  P) ?
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            This is where the function calls itself with a smaller or simpler version of the problem.
    + H$ n- M; B% y4 [& ]7 ]
    2 ]+ C1 h( B$ w        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).9 i9 t7 B, p( R* G
    + {  A& @& J8 u" ^3 w7 R
    Example: Factorial Calculation
    + r4 t4 o& j" M4 J& V' R: P0 Y6 ?0 X9 e% u
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:8 f- q5 {- P, y8 c, x5 c4 Q+ c
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        Base case: 0! = 1) y+ J/ i  p+ y  s8 E+ U  K

    6 n1 J! p6 m* k    Recursive case: n! = n * (n-1)!, _$ |9 ]. T3 p  J  u

    % u2 g, k. o/ fHere’s how it looks in code (Python):6 w4 F/ a6 b/ C2 j6 D/ {
    python
    # W* v  h1 m8 l8 E; g$ r# c# _9 O$ w" H& B. C* |

    . E) {* p  n* Y2 m2 v, A& q9 b0 e6 bdef factorial(n):) M# I7 e- h/ I. a! O! p& R
        # Base case& L8 k5 ]3 S9 J6 {$ {) @3 I% c- |
        if n == 0:
    6 d! v" `2 A# L, I5 Z: A- v+ E        return 1( ?/ q4 C" t3 z# y9 i- s) w
        # Recursive case$ I0 z; H2 H+ W7 G
        else:7 r  c3 E/ X, C7 r( o8 }
            return n * factorial(n - 1)
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    ) L" f& ^' `, e  V# k( _' L# Example usage
    2 T7 d' k. }0 y3 `print(factorial(5))  # Output: 1201 q6 I/ R4 [+ T/ J
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    How Recursion Works+ S3 [$ D" B2 [' @% C9 U
    6 B+ G4 r; u4 U, J" i
        The function keeps calling itself with smaller inputs until it reaches the base case.
    ! P0 l  x  Z, P3 r3 L) z; c1 E+ q3 Z
        Once the base case is reached, the function starts returning values back up the call stack.
    # c4 e* m: {7 j% }* r  k/ q. }1 m+ P* `
        These returned values are combined to produce the final result.
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    7 A5 [% h; Y  w5 PFor factorial(5):) a4 J" t) ^- c3 O/ Z" m! G* b
    5 h: V: h8 `" R. F  n) N2 g5 D

    ' i* I; E) u0 W1 I( P2 M2 gfactorial(5) = 5 * factorial(4)% \$ H; f! j5 K5 L: N6 N; j1 G
    factorial(4) = 4 * factorial(3)
    & I. h) Y9 b6 X6 z% b/ x$ Lfactorial(3) = 3 * factorial(2)
    5 Y* D. I* H( q' F  ?factorial(2) = 2 * factorial(1)# e6 N0 c+ S4 ~2 H
    factorial(1) = 1 * factorial(0)
    ' s5 w: R2 l" F# y1 B& a& q1 d! dfactorial(0) = 1  # Base case- [3 L8 z; Q! S. B
    8 |) K& b; D2 _
    Then, the results are combined:
    ) _0 u, x) p7 M# [5 w4 t) M
    ; g, C# ?6 z1 |9 Y* p* D
    - t* C6 I% Z& b7 J4 Y1 g) U- Tfactorial(1) = 1 * 1 = 1
      g! g% p' _1 m  o2 u  vfactorial(2) = 2 * 1 = 2
    6 h: }6 p8 }8 H0 W  U8 Rfactorial(3) = 3 * 2 = 6
    ) ?0 J7 g3 K8 p5 o5 R& {factorial(4) = 4 * 6 = 244 ?9 O; q  b' @; D2 g* }
    factorial(5) = 5 * 24 = 1203 U. C3 D5 Z( j& X+ G- A, n5 L
    / P. t/ N' F+ D( x% m# T
    Advantages of Recursion& L, C* |! Y& q+ u* _
    2 D3 h( b" O- E3 n! s+ A7 b, _# U
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).3 |5 g0 g! Y: {3 w1 t) Z: D# k& M

    : U4 Q/ r  |7 C5 }( H* `    Readability: Recursive code can be more readable and concise compared to iterative solutions.- Z! i+ _& D* L% v

      c9 m) ?9 O. J! J/ d. n+ L4 P8 tDisadvantages of Recursion7 R/ S! y  r3 i6 C: ]0 M' q
    0 z: ~& _; D% M! J+ p9 ?) |# M
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    . n! ?! h  `8 o" z
    : H- u8 H* @2 ^- K- }  N    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).2 p1 _  f  I: e

      P6 v& J- }7 o: z" ~& [+ u# r, \When to Use Recursion
    ! v, |, A' I* _1 L& C+ P- [
    % M4 X! W! @: B" k2 |1 ]    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    : Y( N( |; v  R! |) s
    " \8 p8 p: _5 Y6 \, k. K1 B: r* G    Problems with a clear base case and recursive case.3 g6 B8 p+ k  {$ `: F& }
    ! r$ g  [: f4 K/ f! l
    Example: Fibonacci Sequence
    $ ?. O+ g: p4 [8 j- j) k3 @" p1 f, d# M: n
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    4 X& v) }% c  T! i- R. c1 O/ [( O0 W: ^
        Base case: fib(0) = 0, fib(1) = 1$ B9 m! N  d; ]
    5 V" n# ?0 ?- ?# G) z  M, F% S
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
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    python
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    4 A2 O$ w+ Q4 V+ m; v# T; b* w
    def fibonacci(n):/ P0 C8 c" J' Q1 b$ E
        # Base cases
    ' i  P8 m# \3 R; f; G    if n == 0:
    0 y- t) \$ B! y8 M9 ?# A        return 02 v3 j) s) H  |' p; j7 s
        elif n == 1:
    . ]" F7 {) O5 u  z" H        return 14 |) K4 _  P) a0 ]5 f" M
        # Recursive case
    ! I! v3 M  N/ i# B    else:
    ! O- \) ]. K  N% {* f' u. u        return fibonacci(n - 1) + fibonacci(n - 2)
    . M) @8 D5 |/ W: H+ n' H: O+ `0 v3 N9 j- l/ O
    # Example usage/ E6 K# y" K* p
    print(fibonacci(6))  # Output: 8
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    + x7 B% R/ N) E/ p- d: n2 [Tail Recursion
    1 B. \% y) v- X- ?# M8 i- J/ K0 X# d) b* t/ U
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).  B3 ^6 j3 o- a
    ) Y* T- e, D  {$ i- ?7 B" o! f
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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