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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ( H, V! `, V% x. Z6 A; S( b
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    解释的不错
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    , m! i& ~8 I6 k1 V- P1 y- G9 K: b递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    8 d. a  b5 ?) n 关键要素  }6 m# F3 S4 E0 M% X
    1. **基线条件(Base Case)**
    0 _! x0 G/ u+ Z$ Z9 N   - 递归终止的条件,防止无限循环7 o9 q. c; Q  J+ s9 ~4 c; O
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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    # A0 Z. W! u, n& N( x2. **递归条件(Recursive Case)**0 I6 ~# u# z% }7 i% ]4 P$ P
       - 将原问题分解为更小的子问题
    + L" j- N9 i9 g, u9 u   - 例如:n! = n × (n-1)!) E% ~; k6 b; ]! Q

    + h9 d+ W* o- [ 经典示例:计算阶乘" y/ v, l' s; ~
    python* L2 w% X2 L; ]4 k
    def factorial(n):
    & [" K$ P* K; D4 {! |# ^' N3 a    if n == 0:        # 基线条件+ e8 Q. ^# L# G$ p8 y
            return 1
    4 [8 Z4 d9 ]: d9 B/ y9 `7 u2 h! z    else:             # 递归条件6 n4 M8 m" @8 d& b: \
            return n * factorial(n-1)
    / ~* U' ~4 T4 |7 g执行过程(以计算 3! 为例):( W# M) f, }8 s$ P9 O
    factorial(3)
    ' n2 L5 H) I  y$ I3 * factorial(2)6 J8 V# `# I/ q
    3 * (2 * factorial(1))
    : U' [. K& k( ?) x6 w& K+ Y/ a3 * (2 * (1 * factorial(0)))
      w# A0 P2 J# n8 M% R9 S3 ~3 * (2 * (1 * 1)) = 6- o- {4 H1 a* _  w6 I' B6 v

    - s& n3 l; X+ i! T; H# \ 递归思维要点& e% G. E# z! E" M+ n
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑( h/ R- z; H% ^9 t% X1 ~8 `6 C1 x
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)5 V, l( Z) c5 O; m
    3. **递推过程**:不断向下分解问题(递)4 Y. i7 q% b/ q& e5 V) E6 a( X
    4. **回溯过程**:组合子问题结果返回(归)
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    - O( ?. T$ i4 @3 i 注意事项! _. r; U5 p, D1 |6 K' O3 f" `
    必须要有终止条件
    & n% Y. [$ x4 W$ y) }- [递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    1 h6 V4 K! V4 F某些问题用递归更直观(如树遍历),但效率可能不如迭代
    & g: M& U, k, i1 m尾递归优化可以提升效率(但Python不支持)
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      S4 q, n$ r9 g( Q& j* X  [' ^ 递归 vs 迭代& X9 B# v  n0 b5 b  j5 m) G8 j
    |          | 递归                          | 迭代               |
    : Z1 {% n$ x# |7 h& X|----------|-----------------------------|------------------|
    & Q5 b% d6 _( s0 g$ n* L| 实现方式    | 函数自调用                        | 循环结构            |- s, N' o, _. O' X
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |$ O1 G5 M# W; r6 F7 L; @# g+ i
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ! W1 O, h' d1 f( Q| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |- H( b/ J( e, Z. ]
      ^) }9 T+ k+ E7 }  |2 [) G
    经典递归应用场景
    ) L) `7 |; h0 |9 Z  y1. 文件系统遍历(目录树结构)
    ' e0 t: ~0 y' ^, G2. 快速排序/归并排序算法
    & |! h  _4 Q$ ~3. 汉诺塔问题- `' k- m! P/ j- F" h
    4. 二叉树遍历(前序/中序/后序)
      m/ O& W, o5 R- w5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 06:55
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,1 H! c6 l$ k1 |
    我推理机的核心算法应该是二叉树遍历的变种。8 ]  ^) ~( T" M: Z% [8 I; B+ P8 Y
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:* Z, k& M! V5 z* J# D; b
    Key Idea of Recursion" S1 }" [: y7 p0 d8 g6 S: @

    / q) @' W- Q" C9 l1 g2 z6 IA recursive function solves a problem by:9 `- b" y$ y  Q+ v# l2 q9 u& K) X

    $ g7 L2 |/ D5 A    Breaking the problem into smaller instances of the same problem.
    " k9 n! d' V4 [) h& _3 J
    1 o$ H2 \0 L& _* `    Solving the smallest instance directly (base case).
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    4 i2 T. v* x" _8 [* n    Combining the results of smaller instances to solve the larger problem." N* A, s. H1 c& y/ I7 Y3 ]& I

    " i+ ?! ]* H. H6 O0 LComponents of a Recursive Function5 I/ k3 M5 P, W8 g" i9 r0 ~

    " b  C) @0 H  A    Base Case:
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    4 M/ m8 M2 t1 X% @# n        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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    - A1 z$ h. {* J" U        It acts as the stopping condition to prevent infinite recursion.
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    / e8 V* X7 V. B" ~" E6 E        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    ! Z5 R( r$ M& f6 n    Recursive Case:
    ' p4 R, W, U5 P  F* s4 p% C/ m; b. [; o/ c! _5 R/ B/ ], _0 j& z* V
            This is where the function calls itself with a smaller or simpler version of the problem.- o& c. T$ X' P# {
    3 _2 _" x+ X, g9 S- A
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).; d! X2 v% y$ a4 X; P' y8 i
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    Example: Factorial Calculation( w6 ^' |0 v9 x2 |. x% n# y
    + x4 \6 g# h9 B- p8 R7 Y
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    ; U$ k  W5 G' k% u' \% u; V! ?. R. j/ _" l/ _, b
        Base case: 0! = 1- ^7 T% @6 B& `; H
    : d, m2 _' J: ]% a9 U8 x
        Recursive case: n! = n * (n-1)!
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    $ o. L1 N2 x, E: b/ D3 ?3 ^Here’s how it looks in code (Python):
    9 ]6 s; b; p, n0 Y% h& b) rpython! y1 [# \0 O" e% f
    ( C1 |5 u2 B6 J7 @3 R+ G* ]' V

    0 F" f% Z2 J- H8 ?. x# X, `% xdef factorial(n):0 B; a& ~, d0 P' S
        # Base case$ s9 l5 s1 z# r. A  W
        if n == 0:
    $ X5 l; h& Q, x4 b0 @# q- p1 T        return 1
    ) z6 A* L+ {3 M; i0 H    # Recursive case- z" V* n% F* I8 X6 C1 t
        else:, w* y' y3 s- ]# n5 B
            return n * factorial(n - 1)
    + d) k0 Y! b3 g% Z" [( l9 i1 ]  W8 P% Y- L6 m
    # Example usage
    4 E6 Q7 _$ Y  K& r# Lprint(factorial(5))  # Output: 120
    5 s4 D$ _  ^& b! M% o5 c* t' m) t; t1 n# K
    How Recursion Works
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        The function keeps calling itself with smaller inputs until it reaches the base case.6 @7 R  n" e- c) z8 e
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        Once the base case is reached, the function starts returning values back up the call stack.
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        These returned values are combined to produce the final result.8 `: Z1 m1 B' _( ?- c
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    For factorial(5):; A" Z- _: X0 _

    * c; ?, A1 x: f( \; i' C
    $ X; C; F9 K$ Z7 D; z2 xfactorial(5) = 5 * factorial(4)
    8 {# i0 A% S3 p- S$ E+ X3 Jfactorial(4) = 4 * factorial(3)
    ' b' s( e" X0 s4 Mfactorial(3) = 3 * factorial(2)
    ; P5 b* s& D" I' @/ B3 _factorial(2) = 2 * factorial(1)
    % n+ d+ m7 m; A7 C% gfactorial(1) = 1 * factorial(0)1 a/ V% `) J9 o
    factorial(0) = 1  # Base case7 g" j# J" b' E) Q* Y7 q
    , [, Y( p" X1 o
    Then, the results are combined:
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    4 w$ Q2 F3 M- _& W
    factorial(1) = 1 * 1 = 1  V+ y) G. F# Z
    factorial(2) = 2 * 1 = 2' w! D, w% B( t8 j/ E
    factorial(3) = 3 * 2 = 6
    1 N6 R8 N' S* Ffactorial(4) = 4 * 6 = 242 \6 j+ ~# V8 ?2 W. O6 ?
    factorial(5) = 5 * 24 = 1200 n" m2 U! m3 V
    2 n. v; a7 |+ t$ C
    Advantages of Recursion
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        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    $ [0 v6 `  T9 U( k9 }2 Q+ u/ _4 J. Q. h. R( H
        Readability: Recursive code can be more readable and concise compared to iterative solutions.! y/ b/ a9 r2 ?9 T
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    Disadvantages of Recursion
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    5 b$ a7 f# \6 v( q# V0 W, {: J    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.0 ]4 l; ^9 n) }2 K

    7 L* k9 V0 ]3 i! h6 b. k  \+ A" O    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    " _; p( D7 h: b% M5 i, d( u$ Y0 [2 |/ _/ X
    When to Use Recursion
    5 V* z5 e# D' ~+ M
    - t0 j5 A8 p" n% q8 d    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).1 ~1 \; H/ g0 [, s$ Z$ O

      \' m$ g1 t  p7 C, x5 }    Problems with a clear base case and recursive case.
    6 \/ v' E$ b6 Q5 H
    7 W& Y( k5 ]+ VExample: Fibonacci Sequence  y! s9 c, w6 f! _% ~. e! s

    8 A2 {/ g3 u' g$ aThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:; g" {3 N5 t! X, v& Q+ _8 Q

    8 y( g. e1 T) X. F    Base case: fib(0) = 0, fib(1) = 1
    ( U) Y7 `+ q( I/ H2 ~
    1 y* }( m) P4 _( K3 |    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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    0 y4 Y1 ^5 F5 C  O! D: H: ~5 Tpython/ C$ G& H4 I& \+ r4 _4 G+ s

    / }6 ]  f+ q8 F6 o$ y- ?7 j, O0 v. L* I7 T+ B  Q6 g
    def fibonacci(n):
    % b& G  O8 U% q9 p- i  y    # Base cases6 Z- i4 ?* v* p3 p) w
        if n == 0:) X3 W+ }7 [1 g# M& a
            return 0" _! A4 K$ B( H* e  u$ D
        elif n == 1:# p) q3 \4 v9 P$ B4 _& X- B  X
            return 1% M- L- k, ?; w* @# [* X9 s5 F" ?
        # Recursive case
    2 @) B' [: ~" a9 B    else:
    ' l; e1 b( u  `7 A* A        return fibonacci(n - 1) + fibonacci(n - 2)
    & D' \( V; W5 L0 U" q" N$ v2 {
    , G. V$ f3 E7 g1 o) e) X0 }# Example usage
    * T! K; W; \( j# y3 ]; a& ]print(fibonacci(6))  # Output: 87 Q8 m: A- h  f2 ]. w" U
    4 V, H, V! R( [. {
    Tail Recursion5 G! k+ a4 V5 g  a4 k, R

    : w' g# a: }! \' \3 N! ETail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).2 }" a: r4 b+ C1 e  {

    0 V; @+ V- K5 R* VIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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