TA的每日心情 | 擦汗 2016-4-17 12:18 |
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签到天数: 1 天 [LV.1]炼气
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本帖最后由 tingsanguo 于 2014-5-2 14:01 编辑 # `0 ~2 m8 w. a4 T5 H
水风 发表于 2014-5-2 01:57 * z0 Y5 Q) t9 Z
再次重温自己与数学天才们之间的差距有多大了。解出来了,我还看不懂思路 ... 7 |1 Y! z& C. {6 t3 ]% P: k7 Y
9 ~" O1 A! d/ gfixed point f(X) = X = (1-n), where n is the number of people who divide the coconut.
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4 {3 ]' k" q+ v" m% M' [The least number of coconut before dividing is Z = [n^(n+1) + X], i.e., always divide (n+1) times.- J- S# {3 C0 a4 }2 C; s
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After being divided (n+1) times, Z becomes 1, since X is fixed point.
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# b/ c- T1 B R8 G2 Y! X9 an n^(n+1)+X, n^(n)+X, n^(n-1)+X, n^(n-2)+X
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