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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 7 i2 y- ]9 p1 [& ^

    , u. `' K& P, r$ d+ x0 p$ `解释的不错
    / U7 ?4 R- X5 H* F5 M
      [  v' J, s; k6 Z3 O! S$ J5 @递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
      X+ e- ^) C! H" X3 w1 x) J
    ; W6 W8 F& Z# u- F! L; {, | 关键要素& V& N/ o6 g+ F) i' F7 l
    1. **基线条件(Base Case)**
    3 P: i! ~0 c& c6 s: {( C4 y- I, z! S   - 递归终止的条件,防止无限循环
    * k- q( F. }) F' ]+ _' O   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    , ]9 ^  a" H+ Z; {
    / B2 H! v3 F+ b: W, v+ V8 @3 r3 ^( J  C2. **递归条件(Recursive Case)**- q# B0 U* U  b" j! @8 o& r
       - 将原问题分解为更小的子问题
      ~* }& D- N3 H9 ^8 |5 }2 v* Y   - 例如:n! = n × (n-1)!
    . {2 H  ?9 d! j; P7 T: x4 x0 S( R& c! q  O& O  b+ _4 _: ~
    经典示例:计算阶乘
    4 ^; d( N6 }" M+ Gpython; J6 d4 y' S! R
    def factorial(n):
    4 `* r" s- W7 p3 O3 d5 m    if n == 0:        # 基线条件: b* V! W9 V1 T# Y
            return 1  L. |& k- p: R# D  g  K/ K% I# E
        else:             # 递归条件
    / L4 Y# B, {' s2 f' c% B! H. }' X        return n * factorial(n-1)
    $ e2 W3 l" m- N执行过程(以计算 3! 为例):
      x# I5 P' u7 V- {8 l( _factorial(3)8 r/ E" |: H! F6 t: J3 |
    3 * factorial(2)
    # D  d" v3 ]5 ^, h4 h3 * (2 * factorial(1))
    & k/ @9 m8 y: H9 E3 * (2 * (1 * factorial(0)))
    - J) C/ t' w$ l5 |, `3 * (2 * (1 * 1)) = 6( G" A% a5 W+ Z0 q9 B+ s- `

    1 I) C) g1 G0 f# c4 U; g 递归思维要点) \2 x# G7 @3 |/ h9 T! l3 N
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    + Y" C; Y4 ?3 B2. **栈结构**:每次调用都会创建新的栈帧(内存空间)9 w1 [/ @1 s0 Q* H- y3 x- j" |
    3. **递推过程**:不断向下分解问题(递)
    ) N$ [( K! Y' S: V& d4. **回溯过程**:组合子问题结果返回(归)3 J5 u9 l5 c+ s2 S+ b" s8 i1 F2 u

    ( ^# c5 }( d) k' b- T  |% \ 注意事项
    3 I0 N9 @1 z0 e必须要有终止条件. t& _3 e$ x: o1 G  ]& D" j8 P/ K# v
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    8 b' Z2 i9 ^$ K6 f0 d+ k某些问题用递归更直观(如树遍历),但效率可能不如迭代
      n0 W# d. O' d# |+ `0 }/ W3 p尾递归优化可以提升效率(但Python不支持)
    " L( [/ w8 q3 Y% I  {/ w- U0 L( ]4 Z& u( A
    递归 vs 迭代
    , e$ p  E1 M3 G/ l* z/ K6 C|          | 递归                          | 迭代               |4 b2 g* }+ C/ [) V3 B, B4 y
    |----------|-----------------------------|------------------|
    ( y' p. O6 W$ |* R2 M| 实现方式    | 函数自调用                        | 循环结构            |1 ~2 q5 O/ Y7 _4 {7 `
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    " z" w7 }4 P! ]8 }| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |% D3 B: c$ M- I: _1 ~( {
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    , b- i/ J6 ~0 o5 j  i4 j+ q5 m9 c# A9 x
    经典递归应用场景
    / B& a- J$ G* J. x1. 文件系统遍历(目录树结构)
    1 R4 [+ d1 m* J4 ~5 L; c2. 快速排序/归并排序算法% \1 k, H, n0 r( g6 r# D, L
    3. 汉诺塔问题' V4 q6 h& k+ j1 G3 E8 v% k/ u
    4. 二叉树遍历(前序/中序/后序)
    ; j/ r+ T& b; D- J, w5. 生成所有可能的组合(回溯算法)
    $ O4 b8 O) H" P5 k/ w
    5 o$ R: X6 @+ n试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    $ W* u) S/ t# G! \5 r1 I. k我推理机的核心算法应该是二叉树遍历的变种。
    5 Y- p, C! v, P) r另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    ) I: U# p! O7 J. o, ^1 [8 mKey Idea of Recursion
    ' M. k& r" f+ d/ V
    " a8 g  @' c5 v: I& X- i( DA recursive function solves a problem by:
    * a% o( q3 @$ A! l# h5 x
    ! A" m( H% l0 B% ^2 ~0 q. \  x' Z) t    Breaking the problem into smaller instances of the same problem.
    * T' Z) c2 C: \* f% J: o  q0 n9 r( |1 |! d" K8 T5 w
        Solving the smallest instance directly (base case).8 N5 a+ v  o3 @- k- r# b" e

    ; U$ ^  N4 \& J& v  F/ Z# m    Combining the results of smaller instances to solve the larger problem.8 m0 _, ~/ m3 e. ]) \) ^, ~9 y
    * B* {% h9 b0 R6 A: F2 n# `
    Components of a Recursive Function
    ; j' |6 c5 @+ X- K9 }$ _$ E- @) `' N* ^' n( v0 t
        Base Case:
    $ T4 d$ g2 }4 z' I. Z0 a; g, f7 H6 j! f% i) }
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.* z" {8 w& ~( M+ O0 [1 P5 y

    6 g9 v% e( g5 S! z# Z# H        It acts as the stopping condition to prevent infinite recursion.
    0 h: [2 P: X* f6 V3 [. u# p/ ]7 u5 b2 ?! z9 q/ o, m
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.5 H3 q0 Y1 K1 W/ O1 D1 Q
    - K0 N9 W5 p# A
        Recursive Case:
    : D8 `+ h' e# x' e1 ~9 j, v( E6 ~9 W( _/ y: S& B
            This is where the function calls itself with a smaller or simpler version of the problem.
    9 x( {4 e- y6 K  ?  e# F
    % b+ R/ Y+ n4 {8 ^        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).3 G1 Q; I! k& A& r1 E/ e/ |( O
    ; w+ y1 j! m: b6 J/ h- `
    Example: Factorial Calculation5 `7 L0 b/ b$ J/ x" G& [  z# a

    % e& h  h% B7 r0 |( @The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    3 c' v/ x( N& e3 }) R7 M! l
    1 t  i+ R2 M0 T! A5 u5 f* h    Base case: 0! = 1/ [8 ]0 R: ?& Y' ]% ?

    + L/ v, j: n6 ^. \: p! s. c! \; |    Recursive case: n! = n * (n-1)!
    8 O& ~6 f/ U2 B7 m) d8 B; \1 R: Y: v8 E- W2 T
    Here’s how it looks in code (Python):" Q4 O& O% D- E. H  R/ e7 J
    python
    # k) g' j6 ?+ U- r; F+ m1 _) m6 _* c( u; D: w+ U7 i8 ]

    ! o# X1 D7 T$ j/ h) C7 l; s) Qdef factorial(n):# B7 J% D+ F* _# U
        # Base case+ t" w' a/ z6 R! a, I% ]/ ]3 t
        if n == 0:2 O, F) u: w1 b/ d; f
            return 13 }1 ?* i8 w  C& T- z: w6 U
        # Recursive case
    3 l5 {: M/ K; n4 T8 n* i    else:0 k4 j' a7 V; }# b  J. L& i8 `
            return n * factorial(n - 1)
    7 s, \1 d0 Z* b0 j' v7 G9 K* ^8 J9 q: L' C" ?
    # Example usage) L$ z8 Z6 w2 @* \* n5 K# e7 Y3 l
    print(factorial(5))  # Output: 1201 W* W) ?0 P0 z2 ]8 B* U

    : x( {8 S6 f% ^" ]How Recursion Works0 u  H+ t1 o8 V2 U% i, \) i6 d

    , g$ z& v6 t" V. n$ z7 A8 p    The function keeps calling itself with smaller inputs until it reaches the base case.: }, ^4 z3 w! N: ^  n

    6 ^2 b: t- i1 s, }  T1 L    Once the base case is reached, the function starts returning values back up the call stack.
    % O  j( i) k) v3 _# s/ h$ e3 s" n9 V: N1 `; y; M
        These returned values are combined to produce the final result.! V( K( c! }8 L8 Y+ I

    7 Y0 A' v6 S7 ?9 L9 GFor factorial(5):4 L8 w- e2 K& K
    ' I6 }8 E" ?+ T

    : ~* r  |7 Z; ofactorial(5) = 5 * factorial(4)
    8 ]5 Z! I( r( e. O: g$ Lfactorial(4) = 4 * factorial(3): L5 \+ i& A$ r0 _( ?. s
    factorial(3) = 3 * factorial(2)
    ) |" j5 V# h* W( v# yfactorial(2) = 2 * factorial(1)4 q- b% G4 Z) s8 e! o
    factorial(1) = 1 * factorial(0)
    ( P- y; K/ q( C3 ]; i  sfactorial(0) = 1  # Base case
      L: {7 P  l) k1 Z9 r
    : D' h  C: P: J) r, UThen, the results are combined:. H3 J# q( n. }/ z

    ; H, l) W+ z) c0 I) A2 M. P) F0 c4 z
    factorial(1) = 1 * 1 = 1+ `) s% O$ f& N
    factorial(2) = 2 * 1 = 2
    3 F$ K( o5 v  H% d1 J4 Bfactorial(3) = 3 * 2 = 6  Q7 [; A' Y/ o- b* M' |; n
    factorial(4) = 4 * 6 = 249 j' N9 i6 n& a9 d
    factorial(5) = 5 * 24 = 120
    2 e0 `9 Y6 C7 V+ w4 u
    # f4 c) t" L( E0 |' ]Advantages of Recursion
    : c' L  q6 C/ |6 R$ o; H8 `  \
    ! w3 Z: K$ t$ c) A    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    8 R$ N! r8 }  F9 b+ a- p* ^& u) r, s( l- i- z% H! D
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    % Y2 z+ z, o2 p) B* I  g( U$ h" a2 @# G) J
    Disadvantages of Recursion! N4 ], {1 o( u, X+ e0 P
    7 d+ a- g( m' E, u  _5 m
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.  H: n( ^8 C: |, S7 S2 _% L

    7 x" e" F2 L0 O    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ) ]8 Z5 ?/ Z0 S$ F% Z
    ' e$ W6 ^( g& h' K) GWhen to Use Recursion/ T4 h' ?8 R2 X( M7 ^$ J! b

    4 s! G& Q( i8 [4 u: M7 B    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).& Y" W. U- |' N5 G4 f4 l; R- Q
    + M( N( X  G3 D7 V  n
        Problems with a clear base case and recursive case.4 C# z9 ]. n2 y& E0 p

    * Q+ |# c0 |& kExample: Fibonacci Sequence5 I) K$ x- o. [6 C& O0 U" D2 i

    : N2 y4 ~' e" d- |) Z2 r: n) L+ OThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:% {! a2 F6 |% u0 [: y+ K
    2 M* @$ f6 r  ~0 y
        Base case: fib(0) = 0, fib(1) = 1( o  ^. b5 ~' @8 O$ Q6 v
    0 a* v/ d% R/ p5 N3 o( w+ g3 U( B
        Recursive case: fib(n) = fib(n-1) + fib(n-2)9 l) t3 F1 C9 @  s, N9 q
    ! W* J9 D: K$ z+ L& b5 }$ n; ~6 b
    python
    ( L) Z) X' h( o/ A' I& g6 X; w8 Q; c  ~
    $ k9 M: e6 ^3 \- b! M) Z
    def fibonacci(n):+ y# [! T  Q7 |) x
        # Base cases6 C0 e0 L% t/ s9 J6 O; G- W7 }
        if n == 0:
    6 V. M6 U$ Z+ z* l" r* t        return 0; E: F& K' \+ O6 k$ d+ P
        elif n == 1:* A8 G* D1 r$ M. I+ V
            return 1( e# ~" ^" R' Z8 \+ R
        # Recursive case+ }' |  P4 b! X; h8 I, w
        else:7 `$ U" ^* |0 ^; A- _
            return fibonacci(n - 1) + fibonacci(n - 2), r6 D& K) b( M( s0 J1 s& v* v% ^
    - m( [$ u! J5 U5 p9 P
    # Example usage, T& k' g& ?1 y; P4 I: J
    print(fibonacci(6))  # Output: 8
    ; @0 r1 ]: r3 P. s6 d7 T; j* ^  S
    3 H- I% H- f$ V7 nTail Recursion
    & z, D& I" e3 u$ \& Y$ w- }# F2 i
    " m# m5 ?+ r) v% \$ l: {2 qTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).' v- _5 k. X3 ~9 ?3 U

    / ~* a0 F# \; H3 \* _In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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