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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 5 u+ M5 b* i& U4 V7 w# v

  S) Q8 p4 I% k/ M% ?6 I" G! P" O解释的不错7 e' N$ [: Q! L* T

* U  d: ^1 w: m% p6 w) M递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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关键要素& Z2 _4 y3 }; Y" S9 V6 Q# H
1. **基线条件(Base Case)**
" M  v8 s1 I1 G! }% G' P* I4 [   - 递归终止的条件,防止无限循环
$ b' E4 ~4 t( g" O   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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# C6 x: @* H( v4 f% L* V4 K2. **递归条件(Recursive Case)**
% j+ A$ t5 c: D: v$ y( J0 h   - 将原问题分解为更小的子问题
1 z0 _5 j' m9 v   - 例如:n! = n × (n-1)!
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经典示例:计算阶乘1 d+ |" B1 ?' W" _( \+ O
python
. ^" m8 g5 Q3 Rdef factorial(n):/ n0 o2 e' K1 X! i2 F
    if n == 0:        # 基线条件5 x6 L& S2 H) x2 ?5 Z* z/ L
        return 1# }7 ]7 b/ n" S2 `' k$ v& I
    else:             # 递归条件1 R- d# ]8 G$ B4 o3 }6 m9 |: A, x
        return n * factorial(n-1)* Q& [# {" V# b
执行过程(以计算 3! 为例):
. f, l9 x3 C7 w% Lfactorial(3)
! f% e! Z$ p, w4 a, K4 Q3 * factorial(2). ~- R8 O, f, {/ V- ?
3 * (2 * factorial(1))8 [0 u# N- A' Z& X9 Z
3 * (2 * (1 * factorial(0)))% H0 e$ h9 `6 f( s4 \
3 * (2 * (1 * 1)) = 60 E0 r5 b& ^! z5 m+ T, H" d  o/ x
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递归思维要点' P+ W; R! T0 o" X1 a/ Q
1. **信任递归**:假设子问题已经解决,专注当前层逻辑) o% L2 H/ E1 u! L* g; p" c
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
' i5 B5 m% A3 C- y3. **递推过程**:不断向下分解问题(递)
: l9 O+ Y3 Y' _# f0 E  d0 l4. **回溯过程**:组合子问题结果返回(归)- _* }/ Z0 v* Y$ U: X' i

; D0 d! I. S" A/ X# u/ k 注意事项
: f7 D3 \; {; f9 r1 d3 h* f  e必须要有终止条件9 ?, Z" k& W# O6 g& m
递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
" s9 {& D  I: c% R+ C某些问题用递归更直观(如树遍历),但效率可能不如迭代
* K$ V$ k5 V6 K$ }8 k& f尾递归优化可以提升效率(但Python不支持)
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递归 vs 迭代. J) q; b. w; u9 ~$ a; ^/ ?# G. r1 m
|          | 递归                          | 迭代               |2 d/ C+ A8 v" ]  G) j8 [6 Z6 M
|----------|-----------------------------|------------------|: l8 A  [( Q8 w4 T6 s) f
| 实现方式    | 函数自调用                        | 循环结构            |5 }8 ]; S; P: o) q3 E
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |# I1 _9 [7 r" x( z
| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |) t( o2 d0 d- I( L/ Q
| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
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  F# d# D+ a$ l0 k3 |4 }5 g 经典递归应用场景
8 g9 G7 B2 ~- i; U: b# `7 J1. 文件系统遍历(目录树结构)0 E  f" }" n$ X6 X
2. 快速排序/归并排序算法: l7 u) i7 a9 Z6 A, R0 a
3. 汉诺塔问题
3 x+ |  R3 ^; U7 x4. 二叉树遍历(前序/中序/后序)- S' [0 \5 S7 [; Y
5. 生成所有可能的组合(回溯算法)$ U6 k' c5 W& f' U6 h" e, F

6 O/ _2 z1 E2 |$ o9 z+ S试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
# G; N& H% ~3 c6 [我推理机的核心算法应该是二叉树遍历的变种。5 X3 E/ u. v& Q* c
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:5 K6 S' e# s2 _+ \
Key Idea of Recursion
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A recursive function solves a problem by:
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% G; C$ U* T4 J  M    Breaking the problem into smaller instances of the same problem.
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    Solving the smallest instance directly (base case).
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    Combining the results of smaller instances to solve the larger problem.
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  O8 m; z* N0 i9 p" R7 z! FComponents of a Recursive Function
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    Base Case:
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        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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$ @" \$ R. R+ T. {. G  _* K5 b; C        It acts as the stopping condition to prevent infinite recursion.
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. h# p" j. f1 b2 b        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    Recursive Case:
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        This is where the function calls itself with a smaller or simpler version of the problem.
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, P! R( P0 ]% Z# w        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).6 |8 R) g- g( i( y1 C- C
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Example: Factorial Calculation* r' r9 ]4 E4 V9 a7 X
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:# h8 q5 N9 `0 A& y2 A# q& Q

* r+ P4 ]4 F7 y" h% w( I' v    Base case: 0! = 18 a1 K4 l' W% q5 L: j2 ]
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    Recursive case: n! = n * (n-1)!
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, |: c7 K. Y* L% ~- N# `6 T: a3 AHere’s how it looks in code (Python):+ ^9 E' G+ a: p- {
python
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& [; J8 a9 b7 R% h& |def factorial(n):
) g2 J) v! {. _    # Base case0 _" b5 d2 R9 f! c% E/ m
    if n == 0:- B7 m4 |5 o. [; G
        return 1
0 t+ c: b8 @  A$ o/ L7 l    # Recursive case! T4 ]0 a2 p$ [1 h$ U
    else:9 i& C3 }! k: O6 j. F
        return n * factorial(n - 1); U; ?, ^  x$ v8 E4 D

5 P  S% c9 q8 c- a9 v+ W' q* X+ q# Example usage
  r' K. H) \8 ^print(factorial(5))  # Output: 120
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1 H  j2 Z7 c4 r" gHow Recursion Works9 i8 o8 m6 `- F4 B
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    The function keeps calling itself with smaller inputs until it reaches the base case.. G0 V/ V7 W( J& @" X' }

. L1 V. ^3 b# p4 q6 g; b    Once the base case is reached, the function starts returning values back up the call stack.
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    These returned values are combined to produce the final result.3 k, h0 q" i/ A

1 `# Q  A; ^: n+ k& i! LFor factorial(5):, C8 [  a- H/ u; w5 F/ F# z
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3 A) y1 r* I' i, y" jfactorial(5) = 5 * factorial(4), P. I9 G: ]" h/ k
factorial(4) = 4 * factorial(3)8 {1 Z& _7 A, ^1 o+ g
factorial(3) = 3 * factorial(2)
& j8 Q( w" E" K7 l) m" j- Lfactorial(2) = 2 * factorial(1)" U. g4 J4 C$ R6 |' }
factorial(1) = 1 * factorial(0)1 m: N- P1 g* d% O' |
factorial(0) = 1  # Base case
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Then, the results are combined:9 h! P4 Y) u/ q1 t5 Y5 S* E$ B, Q
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factorial(1) = 1 * 1 = 1
. M3 `+ n# {# b; f( Sfactorial(2) = 2 * 1 = 2
3 `5 t, U/ N/ W: {* r6 Y8 [( ffactorial(3) = 3 * 2 = 64 P. l% }. H  {( Z' m/ b/ ^2 p
factorial(4) = 4 * 6 = 245 ?) ]  i1 ]2 F8 X2 q* b
factorial(5) = 5 * 24 = 120
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) n) m% `8 A: b  s( G5 `! ^Advantages of Recursion" T& U; a% X- Z3 {) G

2 R# q, d' r  @* W! t- Z    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).2 _8 p* Z( `7 y. ]8 _

# u$ P% R! Z" L1 z# y  J    Readability: Recursive code can be more readable and concise compared to iterative solutions.. e: Q' _3 A/ q4 x5 `& _0 j, K
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Disadvantages of Recursion
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    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).' k7 v8 h. s" f3 x, m3 ?  ?4 s$ a
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When to Use Recursion2 c# T) c$ E/ q1 K' e" p* e6 q

7 A4 M0 N7 v/ O# V; `1 W    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
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    Problems with a clear base case and recursive case./ d5 m( _$ d8 M9 G" z2 j; m

5 F* F% _) b3 k# x- K$ z. |Example: Fibonacci Sequence
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The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:, `' V( U5 E! ]5 i; E& b

" X; K# e0 x. |! v0 Y/ O* k8 F    Base case: fib(0) = 0, fib(1) = 1' @$ X* ?" Z/ k( m/ X
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    Recursive case: fib(n) = fib(n-1) + fib(n-2), E0 d; O; E% w8 \' ^0 v( Y4 p

) y  h. y% \# \& I, p; Q' A4 B& Q4 dpython
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def fibonacci(n):
, i7 n( |' C. D5 R! z    # Base cases( e: K, R! k! Z* F
    if n == 0:
. q1 n$ e1 [  i- q7 O        return 0
2 g8 y" J- ]- }: Q# |# d    elif n == 1:
  d8 j& n, x  \: ]% x        return 1( P. j3 r' W4 I/ k
    # Recursive case
$ f7 A- e8 ~* {    else:& G  r# `9 c& m
        return fibonacci(n - 1) + fibonacci(n - 2)
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) Z4 [% P* N: }1 y4 L: Y4 W# Example usage
/ n& R3 [# b) w% Q! Kprint(fibonacci(6))  # Output: 8' U) v! R" }( j8 C" L
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Tail Recursion0 Y5 e- F% f+ _# H6 _9 H* {
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).) t% h) c& g4 V

# I( J$ D( W" ~In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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