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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑
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解释的不错0 t, X9 u$ I, P. `+ r1 m
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递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。* W, Q8 \4 m# v$ b9 m% h

9 C' U, V1 I9 c, g 关键要素0 T% |4 u! [7 @+ Q
1. **基线条件(Base Case)**
: i5 }; G7 ]) S- m   - 递归终止的条件,防止无限循环3 u) h4 B! L1 w; d1 \6 [
   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1- E) s9 N: [/ m( B

) U$ O2 `! ?; y2. **递归条件(Recursive Case)**6 ]# p! ]- |4 o3 v1 G
   - 将原问题分解为更小的子问题# T% R8 Y# `( D6 p8 w/ `
   - 例如:n! = n × (n-1)!
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经典示例:计算阶乘& E" h) d! ]9 d, v* b
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def factorial(n):' L4 ~* c* E* P0 s6 F' Y
    if n == 0:        # 基线条件% a7 t- o, |% A/ e1 N' ^6 M. ^
        return 1
6 d& c+ u9 V, w+ P" `    else:             # 递归条件" B0 m) m2 @* i2 k: H. q% n! H  w* _
        return n * factorial(n-1)% g5 I: e# B9 B) V2 Y! i4 Y' S! x
执行过程(以计算 3! 为例):6 A2 X7 U7 Y4 V5 V. |" j4 y" ~( z0 u- N
factorial(3)
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3 * (2 * factorial(1))
  g" e; N% E; E& C" ?3 * (2 * (1 * factorial(0)))& K0 ^7 Q$ f4 G5 D1 a- p- u
3 * (2 * (1 * 1)) = 6
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递归思维要点9 P0 Q- R/ k4 u- y- W
1. **信任递归**:假设子问题已经解决,专注当前层逻辑* u" h' W7 |. B" I; @/ v2 v: c* a0 z
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
8 o* k  c3 N8 _3. **递推过程**:不断向下分解问题(递)- D8 l, J9 G* m6 |! j
4. **回溯过程**:组合子问题结果返回(归)
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2 t4 z  R9 g/ b8 P 注意事项
. S" g* H+ ]& G$ N  d+ h+ w必须要有终止条件( W3 j) o7 j& m4 \: C, N
递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
1 N. q: R4 L1 S" Y' ?某些问题用递归更直观(如树遍历),但效率可能不如迭代
' v1 H6 B! _3 m7 e* H# F* K尾递归优化可以提升效率(但Python不支持)3 G2 D; v: b, v" |% D7 E
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递归 vs 迭代; A8 Q! m# O9 V5 ^
|          | 递归                          | 迭代               |
# Q( f8 l5 a( A5 `. ^2 x1 m+ }|----------|-----------------------------|------------------|5 C* {3 C8 [( a  b, k
| 实现方式    | 函数自调用                        | 循环结构            |. D& @+ Q7 N8 Y  R2 b* d6 N1 ^: ~1 j! ^+ u
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
5 R* k4 y6 r8 [8 `( R| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |+ z2 I4 \5 u2 D6 ^8 r! @
| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
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7 ^9 \: A+ R% w$ ^1 q 经典递归应用场景
9 F# ^) D. M* s9 n, l% `8 O7 r1. 文件系统遍历(目录树结构)
1 T( s; S% K' t: W4 u9 Z7 W2. 快速排序/归并排序算法
$ H/ O; O) J! o. Z5 [  O6 u5 O4 t3. 汉诺塔问题
+ q- W- {' H+ j1 V4. 二叉树遍历(前序/中序/后序)) r) p5 u4 F7 w# h
5. 生成所有可能的组合(回溯算法)$ D. `1 p. g% b* ^& r7 s% S! v" Y4 p
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试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒," y9 `& ?8 k6 ^; u+ S5 X; q0 `
我推理机的核心算法应该是二叉树遍历的变种。
! D4 _: _  C2 s) [" v另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:$ T4 B7 n6 L( P7 s
Key Idea of Recursion
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* o% B! M$ s- i% M+ q+ {0 QA recursive function solves a problem by:
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' ^; H' Z/ d2 v    Breaking the problem into smaller instances of the same problem.% \, G- X7 W& F+ d& f; E2 V9 t

/ M/ E0 _. ^7 c1 w% ~    Solving the smallest instance directly (base case).) G# e6 W0 f3 C% \9 Y8 t8 M! b$ ?
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    Combining the results of smaller instances to solve the larger problem.
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Components of a Recursive Function! {& E" ]+ H( U
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    Base Case:
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8 S0 \( S  K5 v0 m) v, _        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.5 R* w/ y8 ~4 G0 @1 g& z+ L
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        It acts as the stopping condition to prevent infinite recursion.
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$ ~. V( N# ~5 L( x% n. k" _        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.4 Y" q; q1 K  _. c- q) e/ ]5 v1 Z

# y: i3 m, @* c# D) h    Recursive Case:
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        This is where the function calls itself with a smaller or simpler version of the problem.) j  n7 o7 T+ i6 Z
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        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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Example: Factorial Calculation
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:: S3 c* W) E6 ^& e. ]1 A; W# e$ z

: h. z( C2 y- w* h* K1 y2 B/ P    Base case: 0! = 1, P. w  W6 i( C! B* [9 X4 k
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    Recursive case: n! = n * (n-1)!$ U+ ^$ {, K4 F7 p8 ]
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Here’s how it looks in code (Python):3 r# y# ~" v3 [) ~/ Q
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, W/ U1 c' C, [( H+ Xdef factorial(n):
. x% \$ a) r4 u" N    # Base case
0 X% ~+ _$ F! H) b# w' q    if n == 0:
0 \$ l7 J) v) s8 k- G) x3 h        return 1
0 h9 ?/ D6 J& z1 s7 E    # Recursive case
" k& `, R! F8 [    else:
5 A& {0 @+ W- G5 M        return n * factorial(n - 1)+ D) g: `( a0 s5 g& m8 Y

% Q0 x) \* [% ~# C2 J# Example usage  Q- F8 R% g7 V) l
print(factorial(5))  # Output: 120  A+ d) w6 [6 B* W) u' Z/ x" |
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How Recursion Works
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    The function keeps calling itself with smaller inputs until it reaches the base case.% @5 s+ G0 r( q! {0 P' ]( Y+ S
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    Once the base case is reached, the function starts returning values back up the call stack.
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    These returned values are combined to produce the final result.7 t7 [  P/ G9 F5 q! I

& \* Q+ B6 Z9 U( v3 ^1 CFor factorial(5):
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  N, H3 `2 Y$ ifactorial(5) = 5 * factorial(4). L8 B& k; W7 b0 H" Q( b0 M5 v
factorial(4) = 4 * factorial(3)
* M% x2 S% e+ L; vfactorial(3) = 3 * factorial(2)
$ U- E% T7 u2 E/ L# t$ xfactorial(2) = 2 * factorial(1)
1 r1 z+ Z% z3 L" }/ `/ Ffactorial(1) = 1 * factorial(0)
# r. O7 {% Z$ E2 m+ Z( I1 d2 Cfactorial(0) = 1  # Base case. H  k  E0 d" a3 f: d" O

- @( l3 r$ U2 }# l1 \. vThen, the results are combined:
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factorial(1) = 1 * 1 = 1
6 O! [4 g. ^6 ]factorial(2) = 2 * 1 = 2
; O$ M6 P) C% Z$ {) S: [factorial(3) = 3 * 2 = 67 m2 F- t8 F- n. ~+ [+ m1 \/ S
factorial(4) = 4 * 6 = 24
3 o) G5 Y) ~' s7 L8 Mfactorial(5) = 5 * 24 = 120
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Advantages of Recursion8 }7 |, g3 }: J) |. ~: q# }4 a

! _; Q; p% b8 h$ {' v    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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Disadvantages of Recursion$ d1 S+ X5 r% D# I- J- E

4 }2 H: G$ q; [- z    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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When to Use Recursion/ `% e- I( w- O
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    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).0 C% ?6 R: H4 x4 A
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    Problems with a clear base case and recursive case.4 V, G0 _- R  F5 k9 E
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Example: Fibonacci Sequence
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8 @, L% C- U# pThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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3 [" C# ^$ y( H# A$ y    Base case: fib(0) = 0, fib(1) = 1* L( B( F" Z& d; e
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    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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def fibonacci(n):
) U  ?0 P  ?3 T, p    # Base cases( E. Y) f  e+ V* F6 [9 G/ Q; O8 b7 v/ f
    if n == 0:/ P0 e, |/ B: u  E# c6 {( {
        return 0
$ I% E3 D; h6 ^, u1 _    elif n == 1:+ G8 i' g2 `* z+ X7 F' G9 Y' K
        return 17 \5 e: I; I6 G" v+ f
    # Recursive case' W  y0 a. x6 }, ]" J4 b! E
    else:
$ {- H. k  ?" Z$ l! q0 b        return fibonacci(n - 1) + fibonacci(n - 2)$ a( j& b. C& q0 F1 A

4 j5 Y/ Z4 Y1 g( t' S/ i3 l. W  @# Example usage
4 ^( J" x- o3 I# b5 wprint(fibonacci(6))  # Output: 83 z: `# U2 G* h" @+ ^
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Tail Recursion
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).* t- Z: g6 Q. C, g2 G
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In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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