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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 ' c$ m( I0 O$ @0 ~% n
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解释的不错1 O, `( t& P2 W" G' i1 I

" K' P2 N* |' C( I6 u递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。6 n+ H8 r( N& A& i- ~
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关键要素0 K3 |' s* F* e/ ], Y- n6 ^2 i
1. **基线条件(Base Case)**) {+ Z! B& ]& m1 N/ \2 X* K8 F; h
   - 递归终止的条件,防止无限循环
; m3 w1 B  O: l9 U1 e, F   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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2. **递归条件(Recursive Case)**
( f& F- J# Y7 {: \   - 将原问题分解为更小的子问题
3 q  E9 _' J) D   - 例如:n! = n × (n-1)!6 B* J0 {0 `+ c6 E9 B% n+ A
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经典示例:计算阶乘) M: U" ~2 M4 h* t
python$ B# D- t7 v& C, S% t7 g
def factorial(n):# |4 Z' [/ v+ i6 a# g7 J
    if n == 0:        # 基线条件0 T& l2 G$ Z1 w: `8 |: Z" {
        return 1" x: f% X+ y3 M# N, ?: D
    else:             # 递归条件# n- Z4 u' G, G& g  K
        return n * factorial(n-1)/ @. z. H! y  b9 J; H
执行过程(以计算 3! 为例):
3 _: e0 E# s0 i: U) Z9 B4 ]factorial(3); }+ [0 @% ~! s6 {+ p
3 * factorial(2)
# d/ V% L8 r( R! r& o3 * (2 * factorial(1))
' [# z6 u/ ]2 N  v$ j" h8 }3 * (2 * (1 * factorial(0)))
. [8 I1 z  y" `; S& \3 * (2 * (1 * 1)) = 6& P% `  g$ J0 j
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递归思维要点7 S- F4 z$ \# |" B- G5 R
1. **信任递归**:假设子问题已经解决,专注当前层逻辑
. u( C# u; c; B2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
: m5 G7 @: q" ?: q, J0 R0 Z6 ?3. **递推过程**:不断向下分解问题(递)
1 K( E# @  ]4 ^& K: o/ O4. **回溯过程**:组合子问题结果返回(归)
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注意事项' J0 i7 u1 k- I& G7 J
必须要有终止条件
( U* W' y% b& n3 d' |8 w递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
' J0 L  h) k# J: q4 C+ g某些问题用递归更直观(如树遍历),但效率可能不如迭代/ N) y3 ?7 s5 `. ^$ c9 ~/ d/ R
尾递归优化可以提升效率(但Python不支持)
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递归 vs 迭代
8 E6 h9 {8 ]+ k2 l5 p|          | 递归                          | 迭代               |
, n3 r- H3 K! @; E. U, ~|----------|-----------------------------|------------------|
+ q$ p0 ]6 S+ u5 C2 n, J| 实现方式    | 函数自调用                        | 循环结构            |, P& n3 M  i6 \
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |; D6 w3 V0 x& E+ H! L
| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
5 z! a& r7 s* R, w1 g| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |3 o: \1 A* y5 b8 H' O$ l- {

7 O' U' q' X$ N" b6 G. L: F, { 经典递归应用场景
7 \* z; y! B5 x1. 文件系统遍历(目录树结构)
; n' F* }+ A3 W' F* e+ M2 v2. 快速排序/归并排序算法
- q. g4 F( Z; k9 P: |3. 汉诺塔问题1 U- g  a0 P8 g1 h9 k' n, K
4. 二叉树遍历(前序/中序/后序)
, p; g. @; A+ c8 {* w# i9 c8 x5. 生成所有可能的组合(回溯算法)1 w; r3 H# [* B4 M, I( A
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试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,- S# ?$ O  ~+ i# Y1 Z" e
我推理机的核心算法应该是二叉树遍历的变种。
4 z0 ?( \0 _; I: G7 s9 g( Y/ r另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:& S/ U* c& j0 R' T* y
Key Idea of Recursion
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A recursive function solves a problem by:
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    Breaking the problem into smaller instances of the same problem.
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  g$ i9 ^& B! u9 [5 X/ ]# L    Solving the smallest instance directly (base case).
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    Combining the results of smaller instances to solve the larger problem.6 T  j7 Z# g+ z
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Components of a Recursive Function
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/ S1 ]- J  P: q1 l    Base Case:
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        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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        It acts as the stopping condition to prevent infinite recursion.+ J# D2 l2 P+ y% \( t

5 J3 E, C, K" F        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    Recursive Case:
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# V" q$ Q6 H( q" l: m        This is where the function calls itself with a smaller or simpler version of the problem.
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        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).. M# w) B% e7 V$ ?8 @4 V" N0 g

9 c! v2 ?& L. kExample: Factorial Calculation" e: {5 C2 K, l3 g
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:! k! L: N% B; j4 ]" X; ~

8 _. P2 I! O; b3 Y; r/ {* }    Base case: 0! = 1
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  e# ?; g: A: c' f4 v  ]    Recursive case: n! = n * (n-1)!
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Here’s how it looks in code (Python):
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% v4 e1 k) b7 U7 j( Ddef factorial(n):2 P2 f: @+ D" k/ z
    # Base case! n: F7 Z; W5 o, L
    if n == 0:: }* [) g4 a, R9 h' X# A
        return 1& Z6 W+ p& _6 y
    # Recursive case3 e0 J; e. \* d3 |) h. E2 A
    else:
5 `- a7 Y. f/ l% U4 c        return n * factorial(n - 1)7 H, v1 M# i# z5 r) u( q
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# Example usage9 ~1 F8 B, N9 n
print(factorial(5))  # Output: 120  r! s; Z2 T6 ~

5 a# c5 m  f* `" p' j* x4 {How Recursion Works4 x  J! _' d- g/ c
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    The function keeps calling itself with smaller inputs until it reaches the base case.: Q' Q3 q2 X1 H
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    Once the base case is reached, the function starts returning values back up the call stack.7 `; V  ?& c! }6 P  Y8 |1 J- T
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    These returned values are combined to produce the final result.
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For factorial(5):* R* \7 q0 |6 p) B9 D/ T/ a; o
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factorial(5) = 5 * factorial(4)( T1 P- Z, }6 u: K
factorial(4) = 4 * factorial(3)
% Q1 y; u- z* C) yfactorial(3) = 3 * factorial(2): y$ J. ?: [: p5 x; u! |: O
factorial(2) = 2 * factorial(1)
, ~! `1 o& G2 b- J1 Q1 L+ q5 Qfactorial(1) = 1 * factorial(0)
" @2 l) u! w, H, sfactorial(0) = 1  # Base case. c. R( y0 j5 X1 i. f

+ N6 J3 S+ ~; `$ lThen, the results are combined:( \" w, x% _% p9 _) B" m( \

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factorial(1) = 1 * 1 = 1
+ ]* u- o6 Z: ~4 _2 {factorial(2) = 2 * 1 = 2! A; U1 v' [- h5 ]- d6 ]& F" o
factorial(3) = 3 * 2 = 6" t( g( @# Z# r8 ~9 q* a
factorial(4) = 4 * 6 = 24' s+ V1 r8 u7 l: L
factorial(5) = 5 * 24 = 120
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% _4 P9 E0 e/ `Advantages of Recursion
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) s0 Q( z7 S# }- e  _; n- ~3 C, H% K+ Z    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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8 e/ q4 p' f. v5 j4 l! [    Readability: Recursive code can be more readable and concise compared to iterative solutions.6 M. N0 @- L( M# G

8 K" E% j9 D4 c1 SDisadvantages of Recursion
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. C" N7 e: L0 G) k2 H0 {4 m    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion." ~* G0 D. f0 F9 M/ g% l+ ^$ E+ P

8 n8 R$ {  [: f6 W$ {% }, n9 `: ~    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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% P. ~- w9 l, T1 J! ]- U# cWhen to Use Recursion: x4 I4 o$ d$ H2 E$ p& h2 m

9 S" |$ R! ]$ w    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).6 O) R+ U+ W' N0 G

- i, S' L- Z3 _8 G1 D: a/ c3 R    Problems with a clear base case and recursive case.
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Example: Fibonacci Sequence
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The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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    Base case: fib(0) = 0, fib(1) = 1) D' o& m6 B/ A% o! k$ P& M

' ~7 `8 s9 S" `" k6 A    Recursive case: fib(n) = fib(n-1) + fib(n-2)6 \, A: E' E7 S# l
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python
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9 k. z* V2 l. d4 M; kdef fibonacci(n):
7 l( ]  ^, |$ t! ?! k( |6 u    # Base cases
+ q! b. ]1 Z6 x' u$ ^% O    if n == 0:
5 x% u, v' k9 `6 j        return 0
& J9 X/ a5 a' O/ D    elif n == 1:$ T  s% _- K4 s
        return 1
( D7 R' Q+ p1 E) j6 [& U: |8 t$ J: e    # Recursive case
- n1 O$ T0 l3 p( l8 c    else:
* y3 w# U* a8 n5 W" l- w: |+ n        return fibonacci(n - 1) + fibonacci(n - 2)- \7 Q& Y6 c  E  q4 `2 u" C
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# Example usage& ]2 ~% l6 G# o2 K7 ]
print(fibonacci(6))  # Output: 8
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Tail Recursion
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).# l1 J  O3 @0 x( D! Y

; W0 [2 u" M$ r1 uIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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