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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑
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+ P7 Z  D( p+ v$ A解释的不错
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递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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关键要素5 a, q; k' V7 s1 Y$ |! F9 E" a
1. **基线条件(Base Case)**# k8 F4 }8 R6 p
   - 递归终止的条件,防止无限循环
) R# q. w: q! y! e+ ]% i  ~+ _   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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2. **递归条件(Recursive Case)**9 E( t9 a1 A" w! Z3 v$ \
   - 将原问题分解为更小的子问题
3 w4 d1 h7 W! n9 ~" k9 a$ \3 ]   - 例如:n! = n × (n-1)!! e$ z+ B2 A; W# V2 K
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经典示例:计算阶乘( N% ]2 y( X& F- W# p! ?7 f
python5 y6 z( h- Y2 \( ^2 p
def factorial(n):
1 L- x  Z8 M1 p    if n == 0:        # 基线条件( l. }4 V: Y" A" e  b. h
        return 13 y* i9 J. J2 @* k& |
    else:             # 递归条件& t2 g( c5 n: O3 l3 ?0 W2 b
        return n * factorial(n-1)4 D9 y3 j: ?/ }1 Y8 ?
执行过程(以计算 3! 为例):! L! m% ?8 w# P8 p6 A, z% i
factorial(3)
1 \! `9 l. b9 g6 L3 n3 * factorial(2)' U- o3 \' W- h; c0 p0 i9 q7 A
3 * (2 * factorial(1))
& c  G* a: S9 d# }, V: S3 * (2 * (1 * factorial(0)))% `" }9 D! r0 f, G) {
3 * (2 * (1 * 1)) = 6
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递归思维要点, |' G9 L& J8 ^" }0 [7 u8 c
1. **信任递归**:假设子问题已经解决,专注当前层逻辑
; L/ x/ R* @/ }7 N3 m+ }4 s1 p4 {( n% G2. **栈结构**:每次调用都会创建新的栈帧(内存空间)" J3 B; Y9 \% |" u9 N) Y+ F
3. **递推过程**:不断向下分解问题(递)
( I  \( ]; s) _4. **回溯过程**:组合子问题结果返回(归). G/ h7 R: {: W: _1 a, C* ^

9 Z# R2 i( u- h& I. i' D' `5 l 注意事项
. m/ H# L" Z3 r/ C" ~; B必须要有终止条件
7 t! l' W( w% w2 |& J/ l8 K1 e递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
7 K/ D7 ^4 T& j  J8 y某些问题用递归更直观(如树遍历),但效率可能不如迭代
8 |2 s4 i: i( _3 u- G尾递归优化可以提升效率(但Python不支持)8 a+ f  y4 `% d. k! w. v" o
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递归 vs 迭代5 u, y+ I. U" K2 t
|          | 递归                          | 迭代               |8 s; n0 D, d5 ^. q6 D/ j% ~' y; J
|----------|-----------------------------|------------------|# K+ {* F5 `7 m  \
| 实现方式    | 函数自调用                        | 循环结构            |
% N7 s  t7 i3 d. w| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
' U8 B1 U7 ?2 K3 H0 y| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |' c8 j% U* f6 _. N: l
| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |% h4 m% J" a# @! t" K8 u* F- z/ n
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经典递归应用场景5 h7 l$ M4 O, H4 o
1. 文件系统遍历(目录树结构)
+ K4 h  F' r0 l9 k; C' ^; I2. 快速排序/归并排序算法6 g: B/ }" _. f
3. 汉诺塔问题
+ _0 u2 @$ V9 e1 _# x) e* q1 o8 B9 j4. 二叉树遍历(前序/中序/后序)
+ B6 P$ g% k2 f0 x5. 生成所有可能的组合(回溯算法)
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试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,9 P% B3 H: m9 f6 r- N* @# ~
我推理机的核心算法应该是二叉树遍历的变种。. H! w0 t5 b$ W
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
5 W# {: d# P  J0 E. ZKey Idea of Recursion
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; r/ f0 I; P9 S3 a! V9 p- |A recursive function solves a problem by:
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8 w$ [& J$ y* _* q/ ^    Breaking the problem into smaller instances of the same problem.: q2 j; P9 t- m/ T

9 R: _* v# |7 j' {    Solving the smallest instance directly (base case).
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( _4 K! u9 r( U    Combining the results of smaller instances to solve the larger problem.
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. z. u3 f5 B9 `3 D1 I0 E, [6 dComponents of a Recursive Function( m7 k( }3 A2 s( m7 {! D: A

4 k( a5 w! g* }5 ~    Base Case:0 l& p& M! ^7 ~1 X$ G8 C0 _

( k" q* p) ]! C- t9 F" g( u! n        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.  J- n  {7 Q% y6 L; k" K8 y( b

! h) w$ t4 y& M; N# k5 W% x        It acts as the stopping condition to prevent infinite recursion.! r3 j9 m1 \% [; `# P; ^* ^

0 T9 V" U4 Z- r        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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3 S0 I( @+ t/ y    Recursive Case:
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4 J3 M& q0 N# S& c) c        This is where the function calls itself with a smaller or simpler version of the problem.
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1 ~" H' E) J# ^3 U: Y0 L0 B        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).0 t1 R2 N# ]" U; d
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Example: Factorial Calculation
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' G6 D# W( a3 f7 _" @' q- G; wThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
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% a& n) v( r- o6 L5 `. `    Base case: 0! = 11 Y4 _/ @$ F/ o8 r) R. D8 a( f
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    Recursive case: n! = n * (n-1)!* s5 L- ]4 p5 p, L0 b+ g( E
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Here’s how it looks in code (Python):8 x" Q  B6 V# |# v) w1 v0 s! [! c2 R
python
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# e7 ~) C8 b# f! W6 H) ?def factorial(n):
& r9 v; `" p- U  }7 ~; }    # Base case
! X: d1 ]$ C' J2 W. `    if n == 0:
! `' {5 y7 t) R: t        return 1' J" R2 ^  e. l# K
    # Recursive case
. Y  t" Q3 G! K  S' U4 P    else:* S$ n& |2 l2 V# V  `0 v" H
        return n * factorial(n - 1)
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( t! P, Y" g9 e) U& u- p9 Q, y: @# Example usage/ @. a: s/ N0 [' Y, R1 [# p
print(factorial(5))  # Output: 120
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8 o' u# e, [2 rHow Recursion Works
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    The function keeps calling itself with smaller inputs until it reaches the base case.( i% p/ E* j$ x  K4 x

) O: V3 O1 i7 |0 A$ h    Once the base case is reached, the function starts returning values back up the call stack.
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    These returned values are combined to produce the final result.) K" t+ b. Y7 A5 Q6 t/ ?2 S

7 i( |' Z, r7 ^; bFor factorial(5):  \, U) O7 i8 U+ x- L1 Y8 h; [
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factorial(5) = 5 * factorial(4)
3 g! D& o8 g8 V3 L9 dfactorial(4) = 4 * factorial(3)
: o$ S" ?+ h1 ]: ?5 h+ i  Afactorial(3) = 3 * factorial(2)
  _. E! p  b& c: G6 T; E8 y, Hfactorial(2) = 2 * factorial(1)
. d; S# G$ K+ Bfactorial(1) = 1 * factorial(0)  g' ]6 d+ K3 y5 f, P
factorial(0) = 1  # Base case. @; x+ ?# T2 D8 r; {0 q- g& J
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Then, the results are combined:; `; O3 B5 O) n8 I: Z. a

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2 S4 ~6 K- y+ s( I6 zfactorial(1) = 1 * 1 = 1$ f7 L0 I' s9 K, _1 G/ Q7 {
factorial(2) = 2 * 1 = 26 ]. _5 W/ r7 Z9 O# D
factorial(3) = 3 * 2 = 6
/ M5 I# t3 G" k( u# x9 nfactorial(4) = 4 * 6 = 245 x: ?) x7 ]- N( V$ w( b: _/ Y
factorial(5) = 5 * 24 = 120
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Advantages of Recursion
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    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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Disadvantages of Recursion
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    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.  \% ^5 V, \) v6 n! q$ B

  O; V! }6 j0 @7 B3 J/ e; Q. Q& o1 P    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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When to Use Recursion
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    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).0 K" o" Z9 V- @6 e# x
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    Problems with a clear base case and recursive case.
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Example: Fibonacci Sequence
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The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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: M- H! ^' A' o0 M4 f4 D& n    Base case: fib(0) = 0, fib(1) = 1
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/ v3 c5 r9 }2 t7 G+ ~    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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% `0 z* `: C* g& Zdef fibonacci(n):
- u: Y8 i$ r! C% M    # Base cases
1 m2 }- d3 Q# a- d+ [+ [0 b; x' ^    if n == 0:  H% j5 X/ i4 I5 T! X3 s) V
        return 0
; W; c; E- d4 p    elif n == 1:
  X9 Z+ F! h) z# S        return 1* X- G5 o4 A0 T9 x0 t' F. p1 b" R
    # Recursive case# M9 c4 c* L8 q
    else:
; L( G( p& _! p9 Y        return fibonacci(n - 1) + fibonacci(n - 2)
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# Example usage+ X8 I9 C( i7 T
print(fibonacci(6))  # Output: 8: F1 a; k9 P& ^3 L
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Tail Recursion8 A# P3 `7 j! K- E5 G' J! k

6 ^' A2 Q0 X. a& ETail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
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" b6 x; |6 i* b2 c9 JIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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