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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 + {+ e5 |  T) k' m2 c
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解释的不错; M# b- P' f( [. P

! x+ q8 o/ |  o! O, ]递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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关键要素7 V0 I7 @! ]' D: \
1. **基线条件(Base Case)**
9 M6 y+ w" Q, E& ^- i- U# f8 e   - 递归终止的条件,防止无限循环
* w6 q' S/ v0 a) ~   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1) |3 [! z9 R! Q) k" b6 T8 j$ X
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2. **递归条件(Recursive Case)**( D5 {0 |5 ?- Y7 J- f3 b
   - 将原问题分解为更小的子问题' d6 V9 [3 _" L( l0 {
   - 例如:n! = n × (n-1)!
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经典示例:计算阶乘* s( z! g9 K! n
python
' P( i& `* U, x8 g9 w& o" Idef factorial(n):8 t4 \, w% ~* H  J( ~
    if n == 0:        # 基线条件7 h+ X; T6 e# Y! K
        return 1
/ i' ], K- X! Z    else:             # 递归条件  H; v0 o! N' v& E/ G
        return n * factorial(n-1)
$ D  c( U. g  |, \- H0 v执行过程(以计算 3! 为例):
( y8 g1 t3 \; T7 ~5 \, e9 Yfactorial(3)
6 L4 m- G: D$ o3 l! l: b: u3 * factorial(2)3 z8 Q9 x: X/ y8 Y. X0 a' m
3 * (2 * factorial(1))
  n( W& Z& ?" q3 * (2 * (1 * factorial(0)))
4 }$ Y- O) D& d5 @5 l3 * (2 * (1 * 1)) = 6
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: ]6 q: M( Q9 h/ T4 B 递归思维要点
# m1 d) m5 t* m1. **信任递归**:假设子问题已经解决,专注当前层逻辑4 k% A6 E4 D' _) s% j
2. **栈结构**:每次调用都会创建新的栈帧(内存空间): p6 J& d; R- d7 x& J) c5 p4 S  Q
3. **递推过程**:不断向下分解问题(递)
3 g2 B% G; \& E' a, z4. **回溯过程**:组合子问题结果返回(归)3 q$ j  m0 V- P1 N! \5 ?4 A
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注意事项+ I" ^; p, U# I, |
必须要有终止条件; U6 u+ x3 b' K1 H2 G6 f  u, S) ]' f
递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
' g4 N4 u" U: o, t& E& H% T某些问题用递归更直观(如树遍历),但效率可能不如迭代8 \  G2 I$ o' s' ^
尾递归优化可以提升效率(但Python不支持)
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' x$ z; i( Z* i7 ^ 递归 vs 迭代
  P. i6 G' R. T$ l) ]|          | 递归                          | 迭代               |2 {4 x% B+ j& g/ [, N& F/ z& M  ~
|----------|-----------------------------|------------------|
9 K. r" S* T! |0 U! B" T' F( v| 实现方式    | 函数自调用                        | 循环结构            |5 _! f& p( }* F& {& y
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |4 t/ Z- m  H0 l( D# }( T3 z% c
| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |0 n! p: G( ~) k+ q) k
| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
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5 ~' U# x/ e$ J. K- F, P 经典递归应用场景
7 E/ t# s8 r& P; U, }' A6 }1. 文件系统遍历(目录树结构)
( b. x2 D) |7 t& y2. 快速排序/归并排序算法' v* E0 N5 B8 w0 }& O
3. 汉诺塔问题
) I* [: ~0 v2 F5 h  g' i0 V& X4. 二叉树遍历(前序/中序/后序)
5 E: o: E7 j7 n& W3 E$ _5. 生成所有可能的组合(回溯算法)7 A$ i% t; ]4 f/ l  q7 r5 I

% h' y6 ?9 O8 H. n- B+ G" Z8 Z7 z7 b试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,1 r  S- r9 o1 x6 b8 J& ^: h6 m
我推理机的核心算法应该是二叉树遍历的变种。
, }5 N6 }& K* u; d' l. K另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
. e9 w4 i. |7 v$ I' JKey Idea of Recursion0 \) @' E! g, J) U9 A3 ?2 m; }' R5 d
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A recursive function solves a problem by:
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    Breaking the problem into smaller instances of the same problem.  \; j: X6 @- t( @

* O( M( s) k/ s) [* r8 w    Solving the smallest instance directly (base case).2 a' Z' _# ?; u# d+ K. w  t

/ I4 v8 ^/ k3 [    Combining the results of smaller instances to solve the larger problem.% g0 {) x8 Q' Q& B, r- L' E

. ^* D3 f6 M2 D5 W; XComponents of a Recursive Function
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    Base Case:
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" D6 I1 b8 B) }        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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        It acts as the stopping condition to prevent infinite recursion.
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        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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, G7 `9 }7 C2 g3 Q8 @2 j3 [: V    Recursive Case:
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1 F3 }4 }1 Y+ K5 t: K) J( F        This is where the function calls itself with a smaller or simpler version of the problem.
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3 G  J% {* r& C/ l5 X2 l        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)., h! r. n9 k1 g
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Example: Factorial Calculation
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
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    Base case: 0! = 1
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    Recursive case: n! = n * (n-1)!4 Z- ~( u( N* J1 z# S9 s/ {
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Here’s how it looks in code (Python):& t; s+ p/ c3 q. v' q9 E! N" L; ~
python
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  Q: P2 n# m  y$ D, w% vdef factorial(n):
5 R$ x& \0 S; N7 l+ |% `    # Base case
: ^/ w1 ~5 D7 X5 }+ }    if n == 0:7 l' c4 g2 [+ K/ V) a
        return 1( J' G0 M) O# k9 y
    # Recursive case
. C' ^+ T8 `  x; Q8 T- v    else:  s; K) c; C: r/ ?
        return n * factorial(n - 1)4 J6 X4 c2 O7 o4 g7 I) U
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# Example usage; K0 a6 r+ d) o) h, _0 J  R
print(factorial(5))  # Output: 120
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How Recursion Works! ^3 ]$ _) u& S9 ?

+ j% Z- l! B0 |# c8 l    The function keeps calling itself with smaller inputs until it reaches the base case.
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8 o6 s2 o4 z, F3 a$ O- U3 p    Once the base case is reached, the function starts returning values back up the call stack.* y" f+ b' d/ t/ i" y+ B+ b3 X* p

& L8 `  L; Z' z$ c  y  d    These returned values are combined to produce the final result.
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( S8 W% w+ {1 P5 k- X# n: eFor factorial(5):
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factorial(5) = 5 * factorial(4)9 ^# u( X" K5 c8 s3 D
factorial(4) = 4 * factorial(3)
3 v0 C) d* K( N# g: J3 P, \1 Kfactorial(3) = 3 * factorial(2)( W$ N2 N5 }  B: w+ u* K- ?- _3 ~
factorial(2) = 2 * factorial(1)! T, z3 H, j5 h( k1 R/ L/ }
factorial(1) = 1 * factorial(0)! y2 m5 ^" N$ I8 G2 K
factorial(0) = 1  # Base case
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Then, the results are combined:! Q7 Q4 [" y# `! Y' Z, r, q- \6 y
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factorial(1) = 1 * 1 = 1
5 {5 B9 r$ H8 }6 N9 D7 I# N" f8 zfactorial(2) = 2 * 1 = 2
$ S7 k1 P5 }0 h) w+ lfactorial(3) = 3 * 2 = 62 b  v  n& o% P5 ?( \- M
factorial(4) = 4 * 6 = 24% y- l: I! X% o' E: y) W- @3 {
factorial(5) = 5 * 24 = 1207 j0 K1 w' P( w1 y# H! y
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Advantages of Recursion2 t1 G8 F  F# s6 t4 z9 F* C
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    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).( K' D; [4 H( u$ U
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    Readability: Recursive code can be more readable and concise compared to iterative solutions.0 _: ^% @9 ~" B1 z4 l9 v
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Disadvantages of Recursion
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    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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1 q4 N# _( j5 e1 w* b2 D+ x$ \    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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When to Use Recursion7 d# a' u8 P1 ?/ J) c# [6 i
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    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
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2 N+ ~. ~0 i% a# m    Problems with a clear base case and recursive case.% L9 m5 w7 |) h7 }& r
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Example: Fibonacci Sequence9 R# e' r( t; K

; d' w. ~" ]" LThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:* G. Z! p9 W- }+ F+ F( i) ]
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    Base case: fib(0) = 0, fib(1) = 10 {3 O; |# s- O8 r; Z

& z% z7 W$ o  Y8 G* f1 {    Recursive case: fib(n) = fib(n-1) + fib(n-2)4 Q: {. z. D2 j! D+ m9 F7 U

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. u* R2 M7 J4 r  B# A9 Hdef fibonacci(n):3 B3 Z# n' z; {; g9 y
    # Base cases
! I( K: u, B& S8 [8 t" I    if n == 0:( H% R5 v$ }. B3 E! k
        return 0
% d' Q- o; j& B# Z    elif n == 1:# h7 S0 ?) l) t( v+ C
        return 1& v* V" c0 H5 C; K( u/ q
    # Recursive case
1 [/ I5 c) m/ J& j# a: T    else:
; B3 x  _; m+ l9 y        return fibonacci(n - 1) + fibonacci(n - 2)( f# Y, h7 B; s, M8 s: ]) |: T
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# Example usage
( P6 _1 k7 n  ]* Y7 wprint(fibonacci(6))  # Output: 8
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1 M& |8 V4 m% ^/ C0 Y; W) U/ D/ YTail Recursion2 q. y. ?: T5 E7 m9 z  q# y

2 [% @5 T/ _  |( z+ Q! e8 M, Y; HTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
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( g8 |3 s- b$ Y) H+ S$ A" j* yIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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