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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 % \5 T. t0 C: m: }, i- k/ |, J

0 P! ^: W/ E3 \解释的不错
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递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。% K& O: g9 b% [

" f+ X3 v4 W. I6 w. X8 h% d) S# p 关键要素
6 b9 U1 u6 \1 P7 m1 h+ D! I1. **基线条件(Base Case)**
" N- }8 `+ s4 a' G7 R   - 递归终止的条件,防止无限循环% u6 Y2 l3 T$ O8 b4 j" S( V
   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1& ^/ L7 p, c% A# M
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2. **递归条件(Recursive Case)**
2 J* A1 H9 u6 j7 ~% U' d   - 将原问题分解为更小的子问题" T: U* {* t7 z7 j) P- p3 T
   - 例如:n! = n × (n-1)!
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9 h# a+ d7 l3 P5 z6 s 经典示例:计算阶乘
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def factorial(n):- D# X; z2 w( B% [4 ^
    if n == 0:        # 基线条件8 _9 C& Q5 _2 |7 y/ X
        return 1& H" @4 _  m# |+ s6 _* C1 t
    else:             # 递归条件
" `/ p+ {( Q" n3 Y2 X- T        return n * factorial(n-1)
% Y: }$ u& Y. _$ e" Z- F' }% i, s执行过程(以计算 3! 为例):
3 }8 B* [+ K# v, ffactorial(3)
7 z( n" Z+ |0 @3 * factorial(2)
* c$ e5 _# L& F! j+ X$ n2 f+ z3 * (2 * factorial(1))
9 l  I! D5 R4 w3 * (2 * (1 * factorial(0)))+ b  \/ {5 I) J
3 * (2 * (1 * 1)) = 6
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$ `1 D* T% G4 J  | 递归思维要点
6 X, p3 K7 g( ]. `8 v1. **信任递归**:假设子问题已经解决,专注当前层逻辑' f- M. A. O9 G: Y; g
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
( [9 ?/ o# @; O+ a! b: x. q/ t0 [3. **递推过程**:不断向下分解问题(递)
- T: S$ g* l* ]4. **回溯过程**:组合子问题结果返回(归)
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* e2 J% v0 w- a- L$ [* H, C 注意事项
/ T  {; r( i" V+ n+ {1 _1 z必须要有终止条件
; y: w, i# Q5 d+ l: v- k* Y递归深度过大可能导致栈溢出(Python默认递归深度约1000层)3 N1 Z' d3 f2 A- T; @+ Q$ p
某些问题用递归更直观(如树遍历),但效率可能不如迭代
! h+ F* M3 }" `% `; y- k) S$ {8 o尾递归优化可以提升效率(但Python不支持): j- ~+ g: |- I

) o7 `. C% ?8 d4 | 递归 vs 迭代8 h% M) A; K4 q( s# q/ s
|          | 递归                          | 迭代               |
2 {- m+ N0 ~8 X  o& X|----------|-----------------------------|------------------|& H8 p8 F' U8 R$ S) A8 X
| 实现方式    | 函数自调用                        | 循环结构            |9 O" w' v  L6 B) i" U; e
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
! C9 C; }# u9 Y| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
& u! x$ R# z4 }+ |* c% p| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |1 ~' h2 g0 u: m! d' o
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经典递归应用场景5 M! w0 N) W/ l  e3 N# J" |# j
1. 文件系统遍历(目录树结构)
+ F5 h5 r# q2 S5 M, a2. 快速排序/归并排序算法+ I# F# P8 N8 v4 w1 h8 e
3. 汉诺塔问题
" ^! B# O! ^% }4. 二叉树遍历(前序/中序/后序)
9 v: J" k8 j/ }( R' f( Q* X5 R5. 生成所有可能的组合(回溯算法)
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4 k* ?7 Y7 s6 Q+ L试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
' s" Q7 E' ?. Y% Q0 d3 `我推理机的核心算法应该是二叉树遍历的变种。
$ K6 [% w. m7 Q9 W+ M6 V另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
7 O  K; x# N) q' a, a( A- u2 qKey Idea of Recursion
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A recursive function solves a problem by:
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    Breaking the problem into smaller instances of the same problem.
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/ D3 @& ]+ P5 z* o/ u  E1 X    Solving the smallest instance directly (base case).
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5 j1 d/ h& K/ j' h# i1 H    Combining the results of smaller instances to solve the larger problem.0 c$ A' y) Z7 a, @

6 U( Q; T  E4 a' K% }Components of a Recursive Function* N) V) R2 O$ V6 ?( ~
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    Base Case:
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        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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        It acts as the stopping condition to prevent infinite recursion., R: N! W: P% E* @$ w8 m" G
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        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.( e' O" q, ]8 }% r' P) H: {3 y3 j
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    Recursive Case:7 p- j8 L/ I* k+ h! Y

- l- w8 i3 L2 |$ G) J        This is where the function calls itself with a smaller or simpler version of the problem.; {) s7 H+ d! `/ a! l/ f

! a) C9 }1 J2 V- p        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).' V$ E6 Q4 `% h) Z

; i8 e8 R4 E+ E5 {% oExample: Factorial Calculation4 }8 x3 o  U' W; I1 N6 V! R
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:$ A% U$ T$ V2 |. D

$ v& F8 A5 h* \) C2 |8 W    Base case: 0! = 1
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3 \7 s1 C, [- U1 e0 }0 p    Recursive case: n! = n * (n-1)!
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3 `' A; z$ c1 @& Q' N* X: ^6 THere’s how it looks in code (Python):' \+ X8 ^6 A' U/ W
python# V' ^- L9 h; q1 |/ d' z
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* D7 z+ y9 g9 d  ?( a# pdef factorial(n):) r7 t1 k) p* \$ u
    # Base case9 A1 @4 d6 H6 Y! Q9 ^2 I
    if n == 0:; k5 T* m3 E8 s0 s3 C9 p
        return 1
  \( b4 n7 `  D" M) I0 p    # Recursive case
: Z; D* I7 k' V0 X( B/ [) v8 ?5 i% W- J& t9 w    else:
+ s5 x# N; ^5 P! b7 u0 P) @' l. A        return n * factorial(n - 1)
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& [6 d+ l: s: e7 j1 Z, j8 N# Example usage7 V5 E. u- E4 q4 Z4 B0 u! ?! |9 F
print(factorial(5))  # Output: 120% x. v1 i; z% m. K! a- s  y: _

; S, q% g& j; Y3 z8 e2 PHow Recursion Works
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& z5 x) l6 t6 k& x4 K. K    The function keeps calling itself with smaller inputs until it reaches the base case.
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    Once the base case is reached, the function starts returning values back up the call stack.
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2 w- p3 M! E& `/ z7 a. u% B    These returned values are combined to produce the final result.
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, M1 t0 e* A; ~For factorial(5):5 m9 s* M$ T0 ^

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9 Y( J- L# |0 Kfactorial(5) = 5 * factorial(4)6 b0 ]# [9 z$ H. W  r0 A( g
factorial(4) = 4 * factorial(3)0 [9 B2 F! k8 }, C2 v
factorial(3) = 3 * factorial(2)
4 e; g. m% q# q; [2 J! W. j: }factorial(2) = 2 * factorial(1)9 Z5 r! `1 H# U- ~+ ~2 |
factorial(1) = 1 * factorial(0)7 o* |6 ?. R( J+ p- ^. R
factorial(0) = 1  # Base case
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/ h; c8 |4 K. x$ O% T- ^Then, the results are combined:3 D0 g+ U/ w  N4 q  O! S+ |
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factorial(1) = 1 * 1 = 1
) M" y6 V, F  A! g  c, U4 bfactorial(2) = 2 * 1 = 2
$ K+ e* L2 w- afactorial(3) = 3 * 2 = 6
6 R' n* ~# h0 Ffactorial(4) = 4 * 6 = 24: u  j" G8 O5 N- K& {/ i! E
factorial(5) = 5 * 24 = 1204 T, ~2 i$ S: {) w/ C
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Advantages of Recursion
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5 ]! z# N" L$ U4 F    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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1 ^1 S2 s% b5 r& v- o! d    Readability: Recursive code can be more readable and concise compared to iterative solutions.5 y6 {! {# L5 [* y- p) y4 X
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Disadvantages of Recursion0 B/ ?, X* p& ^5 b2 y
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    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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When to Use Recursion
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! M' L: ?. ]9 X- b; y7 V; G    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
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    Problems with a clear base case and recursive case.. i5 u- ]2 w* Y( q9 x' }
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Example: Fibonacci Sequence8 |# p/ b3 U6 C; H& [) r8 y
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The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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    Base case: fib(0) = 0, fib(1) = 12 P8 a0 @( V  P* {: Q% _: X, h5 a4 Z

" n. }, o3 e. Y/ g; {4 G& k$ G0 M    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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7 u- `7 ~" T3 f3 c, B* ]3 rdef fibonacci(n):3 o, @- j) @' V6 A2 v
    # Base cases
) E& N" M$ }" u# t: _: ?* q! H0 Z    if n == 0:
* a" N. [9 N2 B9 L2 l        return 0
. ^3 K! r6 H7 p& O/ ^# ~1 j; l    elif n == 1:
, @! ]8 X3 M. k# B  K9 v: I8 E        return 1
( K. H; k- b& I3 v" L    # Recursive case
9 F2 p% e/ ?5 y+ n# }" l- p* R    else:
, h8 ^- \# Y8 d        return fibonacci(n - 1) + fibonacci(n - 2)
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# Example usage. i& q; ?3 A3 [
print(fibonacci(6))  # Output: 8& u4 g' E: s+ @" X: f
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Tail Recursion
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).1 S/ r; L9 i5 I5 p- a
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In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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